The curved rod has a radius of 5 ft. If a force of 60 lb acts at its end as shown, determine the moment of this force about point C.

Answers

Answer 1

The moment of this force about point C is 267.7lb.ft

According to the information provided in the aforementioned query,

The provided data are,

A curved rod has a radius of 5 feet.

The force act on the end of a curved rod is 60lb.

We have to determine the moment of this force about point C?

Position vector from C to A is;

[tex]& \vec{r}_{C A}=\vec{r}_A-\vec{r}_C[/tex]

Substitute the value in above we get,

[tex]& \Rightarrow \vec{r}_{C A}=\left(5 \sin 60^{\circ} \hat{j}+5 \cos 60^{\circ} \hat{k}\right)-(5 \hat{k}) \\& \Rightarrow \vec{r}_{C A}=4.33 \hat{j}-2.5 \hat{k}[/tex]

Position vector from A to B is;

[tex]& \vec{r}_{A B}=\vec{r}_B-\vec{r}_A[/tex]

Substitute the value in above we get,

[tex]& \Rightarrow \vec{r}_{A B}=(7 \hat{i}+7 \hat{j})-\left(5 \sin 60^{\circ} \hat{j}+5 \cos 60^{\circ} \hat{k}\right) \\& \Rightarrow \vec{r}_{A B}=7 \hat{i}+2.67 \hat{j}-2.5 \hat{k}[/tex]

Force in vector form;

[tex]& \vec{F}=(F)\left[\frac{\vec{r}_{A B}}{\left|r_{A B}\right|}\right][/tex]

Substitute the value in above we get,

[tex]& \Rightarrow \vec{F}=(60)\left[\frac{7 \hat{i}+2.67 \hat{j}-2.5 \hat{k}}{\sqrt{7^2+2.67^2+2.5^2}}\right] \\& \Rightarrow \vec{F}=53.178 \hat{i}+20.284 \hat{j}-18.992 \hat{k}[/tex]

Moment about C will be;

[tex]& \vec{M}_C=\vec{r}_{C A} \times \vec{F}[/tex]

Substitute the value in above we get,

[tex]& \Rightarrow \vec{M}_C=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\0 & 4.33 & -2.5 \\53.178 & 20.284 & -18.992\end{array}\right| \\& \Rightarrow \vec{M}_C=-\mathbf{3 1 . 5} \hat{\mathbf{i}}-\mathbf{1 3 2 . 9} \hat{\mathbf{j}}-\mathbf{2 3 0 . 3 \hat { \mathbf { k } }}[/tex]

Therefore the Magnitude will be;

[tex]& M_C=\sqrt{(-31.5)^2+(-132.9)^2+(-230.3)^2} \\& \Rightarrow M_C=\mathbf{2 6 7 . 7} \mathrm{lb.ft}[/tex]

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Note:- The correct question would be as bellow.

The curved rod has a radius of 5 ft. If a force of 60 lb acts at its end as shown, determine the moment of this force about point C.

The Curved Rod Has A Radius Of 5 Ft. If A Force Of 60 Lb Acts At Its End As Shown, Determine The Moment

Related Questions

a 60.-kilogram car travels clockwise in a horizontal circle of radius 10. meters at 5.0 meters per second. towards which letter will the car move if it hits ice at the bottom of the circle?

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If the vehicle strikes ice at the circle's base, 150N will cause it to move.

What does a kilogram mean?

The International Bureau of Weights and Measures defines it as the mass of a certain international prototype constructed of platinum-iridium and stored there. Initially, it was specified as being equal to the mass of one liter (10-3 cubic meters) of pure water. A mass of 1 kilogram weighs roughly 2.20 pounds at the surface of the Earth (lb).

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i need the answer for this question it’s physics

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Answer: 2 m/s. v = Δx/Δt = (12 m)/(6 s)

Why is there no such thing as an ideal machine? A. Machines never have friction. B. Machines are always breaking. C. No machine is 100% efficient. D. The work input always equals the work output.​

Answers

There is no such thing as an ideal machine because no machine is 100 % efficient.

Hence option D is the correct option.

For a machine to be ideal, machine should follow many criteria the machine should be frictionless and the work input must always be equal to the work output.

In reality, no machine is an ideal machine as every machine involves friction. There is no machine without friction. Friction is a necessity in our life. Without friction, we can not survive. Friction helps us to walk and even stop. Friction is like oxygen, it has vital importance in our life. Hence no machine is friction-free and friction causes wear and tear in machines. Similarly, no machine is 100 % efficient. There is always some energy loss in the process, so work input is never equal to the work output.

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5.92 block b, with mass figure p5.92 5.00 kg, rests on block a, with mass 8.00 kg, which in turn is on a horizontal tabletop (fig. p5,92). there is no fric- tion between block a and the tabletop, but the coefficient of static friction between blocks a and b is 0.750. a light string attached to block a passes over b a frictionless, massless pulley, and block c is suspended from the other end of the string. what is the largest mass that block c can have so that blocks a and b still slide together when the system is released from rest?

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As a result, it can be concluded that block C must have a mass of at least 39 kg in order for blocks A and B to continue sliding past one another when the system is freed from rest.

A friction is caused by what?

Relative motion between two things or materials is resisted by friction, a force. Surface roughness, deformations, and molecule adhesion are the causes of this resistive force.

What three kinds of friction are there?

Rolling friction, beginning friction, and sliding friction are the three types of friction that exist between the car's tires and the road, and they are all what allow us to operate cars at all.

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calculate δs∘rxn for this balanced chemical equation. 2no(g)+o2(g)→2no2(g)

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The δs∘rxn  for the reaction  2NO(g)+O₂(g) → 2NO₂(g) is -146 J/K.

Entropy is a scientific concept and observable physical feature that is typically associated with a state of chaos, unpredictability, or uncertainty.

The unpredictability or chaos of the system would be gauged by entropy. As unpredictability rises, so does entropy. It has a state function as well as a wide range of attributes. The unit is present J⁻¹ K mol⁻¹ .

ΔS°rxn = 2 mol × S°(2NO(g) - S°O₂(g) - 1mol S°O₂

ΔS°rxn = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K

ΔS°rxn = -146.8 J/K

Therefore, the δs∘rxn  for the reaction 2NO(g)+O₂(g)→2NO₂(g)  would be -146 J/K.

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when a mass m hangs from a vertical wire of length l, waves travel on this wire with a speed v.A. what will be the speed of these waves if we triple M without stretching the wire?
B. what will be the speed of these waves if we replace the wire with an identical one, except twice as long?
C. What will be the speed of these waves if we replace the wire with one of the same length, but two times as heavy
D. what will be the speed of these waves if we stretch the wire to thrice its original length
E. What will be the speed of these waves (in terms of V) if we increase M by a factor of 18.0, which stretches the wire to double its origina length?

Answers

A. The speed of the waves will remain unchanged if the mass is tripled without stretching the wire.

B. The speed of the waves will be halved if the wire is replaced with an identical one, except twice as long. This is because the waves will have to travel twice the distance in the same amount of time.

C. The speed of the waves will remain unchanged if the wire is replaced with one of the same lengths, but two times as heavy.

D. The speed of the waves will be halved if the wire is stretched to thrice its original length. This is because the waves will have to travel thrice the distance in the same amount of time.

E. The speed of the waves will be halved if the mass is increased by a factor of 18.0 and the wire is stretched to double its original length. This is because the waves will have to travel twice the distance in the same amount of time. The speed of the waves will thus be V/2.

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a car is moving at a constant tangential speed of 50.0 m/s and takes one lap around a circular track in a time of 74.4 s. what is the magnitude of the acceleration of the car?

Answers

Answer: 0.0541

Explanation:

If the car took a time of 74.4 seconds to complete one lap around a circular track, the circumference of the track is 50.0 m/s * 74.4 s = <<50.0*74.4=3720>>3720 m.

The radius of the circular track is half the circumference, so it is 3720/2 = <<3720/2=1860>>1860 m.

The acceleration of a body moving in a circle with constant speed is given by the formula a = v^2/r, where a is the acceleration, v is the speed, and r is the radius of the circle.

Therefore, the magnitude of the acceleration of the car is 50.0^2/1860 = <<50.0^2/1860=0.0541>>0.0541 m/s^2

Technetium‑99m, an important radionuclide in medicine, has a half‑life of 6.0 hours. What percentage of a sample of technetium‑99m will remain undecayed after each of the given times?

Answers

After specific periods, 12.5g of a technetium-99m sample will still be intact.

What is radionuclide used for?

Radionuclide scan is used for disease identification, classification, and tracking. The radionuclide is injected into the vein after being consumed in very small amounts. Various radionuclides are transported to various organs via human blood. Examples of radionuclides include strontium-90, cesium-137, and radium-226. Some are produced artificially, either on purpose or as consequences from nuclear reactions, while others are found produced naturally in nature.

Briefing:

Consider the fact that first order kinetics governs radioactive decay. So, keep in mind

ln [A]t=−kt + ln[A]₀ and by extension,

t[tex]\frac{1}{2}[/tex]=1n(2)/k

Now, let's derive the rate constant,

k=1n(2)/t[tex]\frac{1}{2}[/tex]

=0.116h⁻¹

Given

t=6h,

1n=Aτ/A₀

Aτ=12.5g

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how does the presence of an active galactic nucleus in a starburst galaxy affect the starburst process?

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The availability of the a galactic nucleus inside a galaxy experiencing starbursts can slow or stop the starburst process.

Why did Coles and Woolworths stop selling Starburst?

Due to "increasing financial concerns," Mars Wrigley quietly pulls Starburst candies from grocery shelves throughout Australia. An popular Australian lollipop brand got dropped by a US confectionery business after one social media user noticed her favorite delicacy was inexplicably gone while looking for it.

What are Starburst called now?

22 years after being renamed, Starburst will become Opal Fruit, according to a statement from the candy's manufacturer, Mars. Stores including Poundland, B&M, Home Bargains, Iceland, Savers, and others will sell the goods for fans to purchase.

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a planet's moon travels in an approximately circular orbit of radius 5.4 107 m with a period of 6 h 7 min. calculate the mass of the planet from this information.

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The mass of the planet from this information. 3.56×10²⁶ Kg. A planet's gravitational pull on other bodies determines its weight (or mass).

Every piece of matter in the cosmos is drawn to one another by a gravitational force that is proportionate to its mass, according to Newton's Law of Gravitation. A balance is what you would use to measure mass. A triple beam balance or an electronic balance may be used in the lab to measure mass, but the traditional balance shown below could help you understand what mass is. This is significant because a planet's atmosphere has a direct impact on its climate. The mass of the planet in issue will consequently affect where the "habitable zone" surrounding a star is located.

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what would you have to do and/or what equipment would you need to have, in order to live in jupiter safely?

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Jupiter is a gas giant with no solid surface so it needs airships floating houses or spacecraft to live on.

Jupiter is the fifth planet from the Sun and the largest planet in the solar system. It is a gas giant with a mass more than two and a half times that of all the other planets in the Solar System combined, but slightly less than one-thousandth the mass of the Sun.

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Chevrolet Corvette Sting Ray developed 360 horsepower and hada displacement of 327 cubic inches. Express this displacement inliters (L) by using only the conversions 1 L = 1000 cm3 and1 in. = 2.54 cm.

Answers

The displacement in litres is 5.36 L.

Conversion of units is the conversion between different units of measurement for the same quantity, typically through multiplicative conversion factors which change the measured quantity value without changing its effects.

Horsepower = 360

Displacement  327 inches³

1 L = 1000 cm³

1 inch = 2.54 cm

Displacement in litres is =

First find displacement in cubic centimetre =

= d = 327 inch³ X (2.54 cm / 1m)³

= d = 327 X 2.54

= d = 5358.57 cm³

We know that, 1 L = 1000 cm³,

Thus,

The displacement in Litres is =

= d =  5358.57 cm³ X (1L / 1000 cm³)

= d = 5.36 L

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you work in a lab and you have discovered a brilliant method for targeted control of chromatin structure and remodeling on a gene-by-gene basis. you are specifically interested in modifying the transcription of oncogenes, which are genes whose overexpression can lead to cancer. select which modifications you would make in cancer cells that are over expressing oncogenes. check all that apply.
A. Increase acetylation of histones
B. Decrease ocetylation of histories.
C. Decrease phosphorylation of histones
D. Increase phosphorylation of histones
E. Increase methylation of hetones
F. Decrease methylation of histiche

Answers

We would change the acetylation of histones and increase the phosphorylation of histones in cancer cells that are over-expressing oncogenes.

A gene which has the potential to cause cancer is called as an oncogene. These genes are frequently altered or highly expressed in tumor cells. Once key functions are disrupted and gone haywire, the majority of conventional cells can survive a predetermined type of quick death. The transcription apparatus is given dynamic access to a genome that would otherwise be firmly packaged thanks to chromatin remodeling, which is a key factor in the regulation of gene expression. According to broad consensus, chromatin remodeling factors control how cellular components interact with target DNA; as a result, any disruption or dysregulation of these special machinery is anticipated to alter the transcriptome status in a malignant state.

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at what distance (from center to center) must the 4 x 10-6 c charged sphere be placed to keep the 2.30 gram block in equilibrium? the angle of the frictionless incline is 28 degrees.

Answers

The distance at which the charged sphere must be placed is 35.38 *10⁻⁹ m.

Fe is the electrostatic force experienced.

The weight mg of the particle can be resolved into two components as

mg sinθ along the inclined plane and mg cosθ perpendicular to the plane.

Applying Newton's second law along incline direction,

∑ F = m* a

Fe - mg sin 28° = 0

Fe = mg sin 28°

1/(4π∈₀) q₁* q₂/x² = mg/2

9* 10⁻⁹ * (4* 10⁻⁶ * 4*10⁻⁶)/x² = (2.3 * 10⁻³* 10)/2

x² * 2.3 * 10⁻² = 18* 16* 10⁻²¹

x² = (18* 16* 10⁻¹⁹)/2.3

x² = [18* 16/ 0.23]* 10⁻¹⁸

x = 35.38 *10⁻⁹ m

Thus, the distance from centre to centre is 35.38 *10⁻⁹ m.

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which of the following defines a function f for which f(-x)=-f(x)

Answers

b) f(x) = cos(x) is the equation the satisfies the given conditon f(-x) = f(x)

To check for every function if they satisfies the conditon f(-x ) =f(x)

for option a)

f(x) = sin(x)

f(-x) = sin(-x)

=> -sin(x)

so in this option f(x) ≠ f(-x) so this option is not correct

for option b)

f(x)=cos(x)

f(-x) = cos(-x)

=> cos(x)

so in this option f(x) = f(-x) so this option is correct

for option c)

f(x) = log(x)

f(-x) = log(-x)

=> log(1/x)

so in this option f(x) ≠ f(-x) so this option is not correct

for option d)

f(x) = [tex]e^x[/tex]

f(-x) = [tex]e^-^x[/tex]

=> [tex]\frac{1}{e^x}[/tex]

so in this option f(x) ≠ f(-x) so this option is not correct

so only option B is correct.

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Complete question:

which of the following defines a function f for which f(-x)=-f(x)

a) f(x) = sin(x)

b) f(x) = cos(x)

c) f(x) =  log(x)

d) f(x)  = [tex]e^x[/tex]

what would happen to the distances between bright spots (intensity maxima) on the screen if the spacing between the slits is doubled?

Answers

Bright fringes occurs to the distances between bright spots (intensity maxima) on the screen if the spacing between the slits is doubled.

Diffraction is the interference or bending of waves via an aperture into the area that is geometrically in the shadow of the obstruction or aperture. Effectively, the wave's secondary source is the diffracting element or aperture. The term "diffraction" was created by Italian scientist Francesco Maria Grimaldi, who also made the first precise observations of the phenomena in 1660. The wavefront's phase contributions are projected at an infinite number of spots (three are depicted) along length d, leading to a continually changing intensity on the registration plate. The Huygens-Fresnel principle, which views each point in a propagating wavefront as a collection of unique spherical wavelets, describes the diffraction phenomenon in classical physics. As seen in the enclosed figure, the distinctive bending pattern is most obvious when a wave from a coherent source (like a laser) comes into contact with a slit or aperture that is roughly the same size as its wavelength. This results from the addition or intensity maxima of various wavefront points (or, alternatively, each wavelet) that follow pathways to the registering surface of varying lengths.

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a proton follows the path shown in (figure 1). its initial speed is v0 = 2.8×106 m/s.

Answers

The proton's speed as it passes through point P is 1.66×10⁶ m/s.

The proton's speed at point P can be determined by the equation:

KE = PE + ( mv²/2 )

where,

KE= kinetic energy

PE = potential energy

m = mass of the proton

v = speed of the proton.

Given

Proton's initial speed is v₀ = 2.8×10⁶ m/s

By putting the values in the question the solution is as follows so as the Proton's speed at point P can be calculated as:

v = √(2KE/m)

= √(2 ×2.8 × 10⁶ m/s² / 1.67 × 10⁻²⁷ kg)

= 1.66 × 10⁶ m/s

Therefore, the proton's speed as it passes through point P is 1.66×10⁶ m/s.

Your question is incomplete most probably your full question was

A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 2.8×106 m/s.What is the proton's speed as it passes through point P?Express your answer to two significant figures and include the appropriate units.

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1) how does a white dwarf differ from a neutron star? how does each form? what keeps each from collapsing under its own weight?

Answers

An electron degenerate object is a white dwarf, whereas a neutron star is a neutron degenerate object. A white dwarf is less compact and has a larger radius than a neutron star.

A white dwarf is very dense, its mass is comparable to that of the Sun.

A white dwarf would collapse into a denser entity known as a neutron star if it reached the Chandrasekhar limit and nuclear reactions were to stop. This would happen if nuclear reactions continued to occur.

White dwarf stars are prevented from collapsing by the fact that electrons are fermions, while neutron stars are prevented from collapsing by the fact that electrons are fermions.

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(a) what is the effect on the period of a pendulum if you double its length? (b) what is the effect on the period of a pendulum if you decrease its length by 5.00%?

Answers

The effect on the period of a pendulum if you double its length is the period increases by a factor of √2 and  if you decrease its length of a pendulum by 5.00% the period decreases by 2.5%.

A pendulum has an initial period of 2π√L/ g and then it has some new period T2 which is 2π√L2/g

(a) Give that L2 = 2L1

So we'll substitute in 2L1 in place of L2

T2 = 2π√2L1/g = √2T1

So when doubling the length, the period increases by a factor of √2

(b) Given that length of a pendulum decreases by 5.00%

Then length of remaining pendulum = L2 = 95% L1= 0.95L1

T2=  2π√L2/g =  2π√0.95L1/g = √0.95T1 = 0.975T1

Hence it decreases by  2.5%.

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a 55-kg lady stands on a bathroom scale inside an elevator. the scale reads 45 kg. what do you know about the motion of the elevator?

Answers

A 55-kg lady stands on a bathroom scale inside an elevator. the scale reads 45 kg. Lift is going downward is the motion of the elevator.

An object changing its position with regard to time is referred to as motion. Motion is mathematically characterized in terms of displacement, distance, velocity, acceleration, and speed as well as the observer's frame of reference and the measurement of the change in the body's position with respect to that frame over time. Kinematics is the area of physics that studies how motion is affected by forces, whereas dynamics is the area that studies how motion is affected by forces. An object is said to be at rest, motionless, immobile, stationary, or to have a constant or time-invariant location with respect to its surroundings if it is not changing with respect to a certain frame of reference. Objects, bodies, matter particles, matter fields, radiation, radiation fields, radiation particles, curvature, and space-time are only a few examples of physical systems where motion is applicable. One may also discuss the movement of borders, shapes, and images. The word "motion" often refers to a continual change in the positions or arrangement of a physical system in space. One can discuss the motion of a wave or a quantum particle, for instance, where the configuration is the likelihood that the wave or particle would occupy a particular place.

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A long -jumper had a take-off of 9.5m/s. What is the maximum possible horizontal distance the man can jump​

Answers

Answer:

4.5125m

Explanation:

Initial Velocity(U)=9.5m/s

Maximum Horizontal Distance (i.e maximum height) = ?

V^2=U^2-2gH (negative because the motion is against gravity i.e g is negative)

where V=0m/s and g=10m/s^2

0^2=9.5^2-(2×10×H)

0=90.25-20H

20H=90.25

H=90.25/20=4.5125m

how are distant (young) galaxies different from the galaxies that we see in the universe today? what is the evidence that star formation began when the universe was only a few hundred million years old?

Answers

Less brilliant and gas-rich galaxies could be found in the distance, distant (young) galaxies different from the galaxies that we see in the universe today.

All of space, time, and its objects, such as planets, stars, galaxies, and other types of matter and energy, are collectively referred to as the universe. The prevailing cosmological explanation for the universe's formation is the Big Bang theory. The universe has been expanding ever since the Big Bang, which occurred 13.7870.020 billion years ago, according to this theory. It is feasible to measure the size of the observable universe, which is around 93 billion light-years in diameter at the moment, even if the total spatial extent of the universe is unknown. Some of the earliest geocentric views of the cosmos, which centered on Earth, were developed by Greek and Indian philosophers. The Sun was positioned at the center of the Solar System by Nicolaus Copernicus in the heliocentric model, which was developed in response to increasingly precise astronomical measurements throughout time. When developing the law of universal gravitation, Isaac Newton built upon the research of Copernicus, Johannes Kepler's planetary motion equations, and Tycho Brahe's observations.

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discuss whether any work is being done by each of the following agents and, if so, whether the work is posi- tive or negative. (a) a chicken scratching the ground (b) a person studying (c) a crane lifting a bucket of concrete (d) the gravitational force on the bucket in part (c) (e) the leg muscles of a person in the act of sitting down

Answers

(a) The act of a chicken scratching the ground is doing positive work.

(b) A person studying does no work.

(c) A crane lifting a bucket of concrete does positive work.

(d) The gravitational force on the bucket in part (c) does negative work.

(e) When a person sits down, their leg muscles are said to be doing negative work.

We are aware of the work equation as being the result of force and displacement.

(a) The work done will be positive as the chicken is scratching the ground. Here, the displacement is along the direction of force.

(b) As there is no displacement, work done is zero, learning the language of physics is not work.

(c) The crane uses the bucket to perform positive work, and the displacement in this case is in the force's direction.

(d) The force of gravity pulls the bucket downward. In this case, the work completed will be negative because the forces acting on the bucket are in opposition to one another.

(e) Since the muscle's applied force are opposite to the displacement, negative work will be done.

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a guitar string has its length shortened to 3/4 of its intial length. if the original frequency was 256 hz what will the final frequency be

Answers

frequency is inversely proportional to the length. So, the magnitude of the final frequency is 341 Hz

What is Frequency ?

Frequency can be defined as the number of complete revolution per second made by a vibrating body.

Given that a guitar string has its length shortened to 3/4 of its initial length. if the original frequency was 256 Hz, what will the final frequency be ?

Experiment shows that frequency is inversely proportional to the length of the string. That is, F [tex]\alpha[/tex] 1/L

F = V/L

V = FL

Since the speed of the sound is the same, we can say

F1L1 = F2L2

Where

F1 = 256 HzL1 = LF2 = ?L2 = 3L/4

Substitute all the parameters

256L = 3L/4 × F2

The L cancels out

256 = 3/4 × F2

F2 = 4/3 × 256

F2 = 1024/3

F2 = 341.3 Hz

Therefore, the final frequency will be 341.3 Hz

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what characterized the sound of the second wave of hip-hop, as characterized in the work of run-dmc and the beastie boys?

Answers

The characterized the sound of the second wave of hip-hop, as characterized in the work of run-dmc and the beastie boys is that it is second wave.

S-waves (secondary waves or shear waves) are a swaying, rolling motion that rocks the ground back and forth perpendicular to the direction of the wave and lasts more slowly.

Wave – A secondary body wave that vibrates the ground perpendicular to the direction of wave propagation. They travel about 1.7 times faster than P waves. S-waves cannot travel through liquids such as water, lava, and the outer core of the Earth because liquids cannot withstand shear stress.59.903

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the belt of constellations through which all the planets move is called the ________.

Answers

The belt of constellations through which all the planets move is called the Zodiac. The zodiac belt runs along the plane of the ecliptic.

The Zodiac is the belt of constellations that all the planets pass through. The sun and moon are also always within this belt. The ecliptic occurs when they appear to move ordinarily along on the particular path through the sky. On the path of the ecliptic, those are 13 astronomical constellations:

CapricornusAquariusPiscesAriesTaurusGemini CancerLeo VirgoLibraScorpiusSagittariusOphiuchus.

In the fifth century B.C., astronomers identified the 12 astronomical constellations as zodiac signs without Ophiuchus. Ophiuchus did not fit into the ancient calendar of 12 lunar months. As a result, the astronomers omitted Ophiuchus for practical reasons.

Astronomy studies the constellations of the zodiac. So, the constellations of the zodiac are not astrology, which is concerned with personal characteristics (zodiac signs differ with zodiac constellations). In the past, they assisted in the creation of calendars and served to track the time period and the seasons for ancient people. They are still applied today for scientific observations and maritime navigation. For example, they serve as excellent reference points for amateur astronomers when trying to find planets.

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when the load of scrap metal, initially on the bank, is placed onto the barge, what vertical distance does the water in the lock rise?

Answers

Let's imagine we have a 10 tonne barge with 100 tonnes of iron because when the barge is sitting in the lock loaded with iron the buoyancy (upthrust) of the water must balance the weight of the barge.

There will be 110 tonnes of upthrust, or 110,000 kg. Since water has a density of 1 kg/l, the amount of water that the loaded barge will move is also 110,000 kilograms, or 110,000 liters. Now toss the iron into the water. It is currently resting on the mud at the lock's base. The barge will continue to move 10 tons, or 10,000 lb, of water because it is still afloat.

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A woman of mass 53 kg jumps off the bow of
a 62 kg canoe that is intially at rest.
If her velocity is 3.5 m/s to the right, what
is the velocity of the canoe after she jumps?
Answer in units of m/sˆı.

Answers

The velocity of the canoe after the woman jumps is 2.99 m/s to the left.

What is the velocity of the canoe?

The velocity of the canoe is calculated by applying the principle of conservation of linear momentum as shown below.

m₁u₁  +  m₂u₂  =  v (m₁ + m₂)

where;

m₁ is the mass of the canoeu₁ is the velocity of the canoe after the woman jumpsu₂ is the velocity if the woman after she jumpsv is the initial common velocity of the woman and the canoe

(53)(3.5) + 62(u) = 0(53 + 62)

185.5 + 62u = 0

-62u = 185.5

u = -185.5 / 62

u = -2.99 m/s

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What is the acceleration of a motorcycle moving north when the speed goes from 0-80 mi/hr in 8 seconds?

Answers

Answer:

0.003 mi/s²  

Explanation:

a = (Vf - Vi) / t

Vi = 0 (started from rest)

First you have to convert MPH into miles/sec (the problem did not state that you have to convert to meters/sec)

(80 miles/hr)/(3600 sec/hr) = 0.022 mi/sec

a = (0.022 mi/sec - 0)/8 sec = 0.003 mi/s²  

1.5 m/s is a typical walking speed. At what temperature (in degrees Celsius) would nitrogen molecules have an rms speed of 1.5 m/s?

Answers

At -272.997°C the nitrogen molecules will have an rms speed of 1.5 m/s

The speed of gas molecules is the speed experienced by gas particles based on their average speed. Molecular velocity is a representation of the overall value of the speed of gas molecules moving in a vessel.

Given that

The molecular mass of nitrogen is m = 28(1.66x 10⁻²⁷ kg) = 4.6 x 10⁻²⁶ kg

The speed ​​rms formula is

vrms = √[(3kT)/m]

So, the temperature

T = (v)²(m)/(3k)

T = (1.50 m/s)²(4.6 x 10⁻²⁶ kg)/(3(1.38 x 10⁻²³K)

T = (2.25 m/s) (4.6 x 10⁻²⁶ kg)/(4.14 x 10⁻²³K)

T = 10,35 x 10⁻²⁶/4.14 x 10⁻²³K

T = 2,5 x 10⁻³

T = 00025 K.

T = 2.5 mK

in °C

T = -272.997°C

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