The greatest static resistance between the upper and lower block is f1max = f 1max = s m 1g = 0.6×2×10 = 12N.
According to Newton's second law of motion, an object's net force must equal the sum of its mass and the acceleration it experiences. In the direction of the net force is where acceleration is moving.
The force of action and reaction between two bodies is equal in magnitude but opposite in direction, according to Newton's third law of motion. The highest frictional force that prevents slippage on a surface is known as the limiting friction force.
The highest static resistance between the lower block and the ground is
f2max
=μ s (m 1 +m 2 )g=0.6(2+2)10
=24N
Assumedly, both blocks move to the right at the same speed.
Consequently, (m 1 + m 2 )a = T- μk (m1 + m2)g
or 4a = T - 0.4(2+2)10
or a = T-16 / 4
for upper block, f1 = 2a = T - 16 / 2
For just sliding, f1 = f1max
or T - 16 / 2 = 12
or T - 16 = 24 => T = 40N
The complete question is:
You are lowering two boxes, one on top of the other, down the ramp by pulling on a rope parallel to the surface of the ramp. Both boxes move together at a constant speed of 15.0 cm/s. The coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834. (a) What force do you need to exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?
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A swimmer needs to cross a river as quickly as possible. The swimmer’s speed in still water is 1.35 m/s.
(a) If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, how long will it take the swimmer to cross the river if he swims so that his body is angled slightly upstream while crossing, and he ends up on the far bank directly across from where he started?
(b) If he points his body directly across the river and is therefore carried downstream, how long will it take to get across the river and how far downstream from his starting point will he end up?
A swimmer needs to cross a river as quickly as possible. The swimmer’s speed in still water is 1.35 m/s.
(a) If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, it will take the time swimmer to cross the river is (t) = 72.57 S, if he swims so that his body is angled slightly upstream while crossing, and he ends up on the far bank directly across from where he started.
(b) If he points his body directly across the river and is therefore carried downstream, it will take time to get across the river is (t)=72.57 S, and the distance downstream from his starting point will he end up is (S) = 43.542m.
What is velocity?Velocity means that the covered distance in a given time. In other words mathematically distance divided by time called velocity. It can be measured in m/s and cm/s.
How can we calculate the time and distance?(a)To calculate the time for the first case we are using the formula, S=vt.
The swimmer’s speed in still water is 1.35 m/s.=v₁=1.35j m/s.
the river’s current speed is 0.60 m/s.=v₂=0.60i m/s.
Now, let us apply the rule of relative velocity:
v=v₁+v₂=1.35j+0.60i
Or, |v|=√(1.35)²+(0.60)²
Or, |v|=1.47 m/s
Now we know the velocity of the water, v=1.47 m/s.
The wide of the river, S=106.68 m
Now we have to calculate the time to travel of the swimmer= t s
Now we put the values in above equation,
S=vt
Or, t=S/v
Or, t= 106.68/1.47
Or, t=72.57 s.
From the above calculation we can say that, If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, it will take the time swimmer to cross the river is (t)=72.57 S
(b) If he points his body directly across the river and is therefore carried downstream, The time taken by the swimmer is the same as the first case.
So the time would be (t)=72.57 S.
The distance downstream from his starting point will he end up,
S = vt
Or, S= 0.6*72.57
Or, S=43.542
So according to the solution, If he points his body directly across the river and is therefore carried downstream, it will take to get across the river is (t)=72.57 S, and the distance downstream from his starting point will he end up is (S)=43.542m.
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A small, private airplane is carrying three passengers to an island. The plane is 0.9 km in
the air. If the potential energy of the plane and its three passengers is 48,510,000 J, what is
the combined mass of the plane and its passengers? Round your answer to the tenth place.
Convert the height in km to m.
Rearrange the formula to solve for mass.
Use the formula to solve for the mass of the plane and passengers.
The potential energy that a huge item has in relation to another massive object due to gravity is known as gravitational energy or gravitational potential energy.
The mass of the plane and passenger is 5494.4 kg
What is potential due to gravity?The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.The potential energy that a huge item has in relation to another massive object due to gravity is known as gravitational energy or gravitational potential energy. When two objects descend toward one another, the potential energy associated with the gravitational field is released (transformed into kinetic energy).following equation: Potential energy U=m g h
Where:
m = mass [kg]
g = gravity = 9.81[m/s^2]
h = elevation = 0.9 [km]
m= u/ (gh)
m = 48,510,000 / (9.81 x .9)
m= 5494.4 kg.
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Urgent!!!!
Batman is chasing the joker. If, while gliding down towards him at 75 m/s, it takes him 30 seconds to catch him, how far away was the joker? And how many kilometers is that?
Answer:
it's 2250meters and 2.25km
Explanation:
speed= distance÷time
75=distance÷30
75×30=distance
2250 m= distance
To convert meters into Kilometres we divide by 1000 so,
2250÷1000
2.25 Km
Which is an example of an inclined plane?
ramp
zipper
knife
jar lid
a hockey puck with a mass of 0.11 kg is at rest on the horizontal frictionless surface of the rink. a player applies a horizontal force of 1 n to the puck. find the speed and the traveled distance 5 s later.
The solution to this ques is available in the image.
Given,
Force= 1N
Mass= 0.11kg
Time= 5sec
Force= mass X accelaration
Accelaration= velocity/ time
Speed=distance/ time
Hence, the speed is 45 m/s and the distance is 225 m.
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a car of mass 1850 kg is traveling at 22.5 m/s in a straight line. a truck of mass 3170 moving in the opposite direction collides with the car and the 2 vehicles stop immediately without sliding. the speed of the truck was
13.13 m/s is the velocity of the truck was when a truck of mass 3170 moving in the opposite direction collides with the car and the 2 vehicles stop immediately without sliding.
Momentum of car= 1850(22.5)=41625 kg m/s
Momentum of car = momentum of truck
Let the speed of truck = v m/s
Momentum of truck= v(3170)=3170 v kgm/s
3170v = 41625
v = 13.13 m/s
Speed of truck = 13.13 m/s
The pace at which a moving object changes position as seen from a certain point of view and as measured by a particular time standard is known as its velocity.
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A student drops a rock from a bridge to the
water 14.4 m below.
With what speed does the rock strike
the water? The acceleration of gravity is
9.8 m/s².
Answer in units of m/s.
Answer:
Explanation:
at first the rock is at rest so initial velocity is zero
after accelerating it reaches a final velocity
we are supposed to find that final velocity
[tex]v^{2} = u^{2} +2ax[/tex]
v= final velocity
u= initial velocity
x= distance
a= acceleration
[tex]v^{2} = 0^{2} + 2(9.8)(14.4)[/tex]
[tex]v^{2} = 282.24[/tex]
[tex]v= \sqrt{282.24}[/tex]
[tex]v= 16.8 m/s[/tex]
in a laboratory, the balmer-beta spectral line of hydrogen has a wavelength of 486.1 nm. if the line appears in a star's spectrum at 486.7 nm, what is the star's radial velocity (in km/s)? (enter the magnitude.)
starts radial velocity V = 1,23,000 m/s.The star is receding and This star is called redshift.
As a vector measurement of the rate and direction of motion, velocity is defined. Velocity can be defined as the rate of movement in one direction. A rocket launching into space and a car going north on a busy freeway can both be quantified using velocity.
The velocity vector's scalar (absolute value) magnitude corresponds to the motion's speed, as you would have anticipated. Velocity is the first derivative of position with respect to time in calculus. A straightforward formula that incorporates rate, distance, and time can be used to compute velocity. Even though they are different metrics, speed, velocity, and acceleration are all related to one another.
Velocity, as opposed to speed, refers to the pace and direction of an object's movement as it moves down a path. Speed and velocity have quite different meanings from distance and displacement, despite their similarities. The scalar property of speed
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To divide 20 miles by 5 hours, what conversion should be made to make the calculation correct?Convert miles to hour and then divide the two numbers.Change hours to miles and then divide the two numbers.Divide the two numbers as given--units do not have to be the same when dividing.None of these choices are correct.
To find
To divide 20 miles by 5 hours, what conversion should be made to make the calculation correct?
Explanation
20 miles refer to the distance travelled
5 hours refers to the time taken
So dividing distance by time would give us speed
Since both are different physicals quantity so their units need not be same.
Conclusion
The correct statement is
Divide the two numbers as given--units do not have to be the same when dividing.
(c) Jika kelajuan kereta digandakan, tenaga kinetik kereta akan bertukar sebanyak berapa faktor? If the speed of a car is doubled, by what factor does the kinetic energy of the car change? KBAT
Answer:
W₂ / W₁ = 4
Explanation:
Given:
m
V₁ = V
V₂ = 2·V
_________
W₂ / W₁ - ?
Kinetic energy of the car:
W₁ = m·V₁² / 2 = m·V² /2
W₂ = m·V₂² / 2 = m·(2·V)² /2 = 4·m·V² / 2 = 4·W₁
W₂ / W₁ = 4·W₁/ W₁ = 4
Kinetic energy increased 4 times
A submarine begins a descent from the surface downward at an angle of 40.5 degrees with the water and continues along a straight-line path for a total distance of 397.0 meters before leveling off its path. How far (in meters) is the submarine below the surface of the water?
The submarine is 288.04 meters below the surface of the water.
As we can see,
The submarine is making an angle of 40.5° with the water surface and moving down till a displacement L of 397 meters.
The displacement L moved by the submarine will have two components because displacement is a vector quantity.
One along water surface Lcos(40.5°) and one along the line perpendicular to water surface Lsin(40.5°).
The depth D of the submarine below the water surface is along the line perpendicular to the water surface.
Here,
D = Lsin(40.5°)
Value of cos 40.5°is 0.76.
So,
D = 397×0.76
D = 288.04 meters.
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States that if no external forces act on a group of objects, their total momentum does not change
Answer: this is true
Explanation:
if the object is moving and there is nothing stooping it, it will keep moving
A force of 6.0 newtons produces a torque of 27 Nm. What is the shortest lever arm that can produce this torque?
Answer:
3.6
Explanation:
Bc its 27nm. And u need to X the answer
if the satellite has a mass of 3500 kg , a radius of 4.4 m , and the rockets each add a mass of 220 kg , what is the required steady force of each rocket if the satellite is to reach 32 rpm in 5.0 min , starting from rest?
0.145 Newton is the required steady force of each rocket if the satellite is to reach 32 rpm in 5.0 min , starting from rest
mass of satellite ( M ) = 3500 kg
radius of satellite ( r ) = 4.4 m
mass added by each rocket ( m ) = 220 kg
Angular speed of satellite = 32 rpm
Time = 5 mins
moment of inertia
[tex]I=1/2Mr^2+4mr^2[/tex]
M = 3500 kg m = 220 kg, r =4.4 m
I=33880+17036
Insert values into equation ( 1 )
I =20416 kg-m^2
angular acceleration
∝ = ω / t
= ( 2π×32 ) / 3600×5
= 0.0112 rad/s²
steady force required by each rocket
Τ = I × ∝ ( 1 )
T = 4rF
Equation ( 1 ) becomes
4rF = I × ∝
Force = I×∝ / 4r
= ( 228×0.0112 ) / 4×4.4
=2.56/17.6
= 0.145 N .
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3. A museum curator moves artifacts into place on various different display
surfaces. Use the values in Table 2 to find Fs,max and Fx for the following
situations:
a. moving a 145 kg aluminum sculpture across a horizontal steel platform
b. pulling a 15 kg steel sword across a horizontal steel shield
c. pushing a 250 kg wood bed on a horizontal wood floor
d. sliding a 0.55 kg glass amulet on a horizontal glass display case
"
Answer: we are given the mass of an aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47
A policeman notices a car speeding at 80m/s and starts chasing it. When the police car reaches the car, its speed has decreased to 50m/s within 30 seconds. What is it's acceleration
The acceleration of this car is equal to 9 meters per seconds square (m/s²).
What is an acceleration?An acceleration can be defined as the rate of change of the velocity of a physical object or body with respect to time.
How to calculate the acceleration of this car?In Science, the acceleration of a physical object (car) or body can be calculated by using this formula:
a = (V - U)/t
Where:
a represents the acceleration.V is the final velocity.U is the initial velocity.t is the time measured in seconds.Substituting the given parameters into the formula, we have;
a = (80 - 50)/30
a = 30/30
Acceleration, a = 1 m/s²
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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The average intensity of the wave 1 is 9 times the average intensity of the wave 2.
When a electromagnetic wave moves, it carries electric as well as magnetic energy in itself.
The energy of the EM waves is by the equal contribution of both the waves.
It is provided, that wave 1 has electric field E that is three times the maximum electric energy E' of the wave 2.
So, we can say,
E/E' = 3
We know,
The intensity of the wave is given by,
I = 1/2eE²c
Where,
I is the intensity of the wave,
e is a permittivity of free space,
E is the strength of the wave,
c is the speed of light
Now, intensity of the wave 1,
I1 = 1/2eE1²c
For wave 2,
I2 = 1/2eE²c
Now, dividing both the intensity,
I1/I2 = E1²/E2²
We know,
E/E' = 3
So,
I1/I2 = 9
I1 = 9I2
So, we can say,
The intensity of wave 1 is 9 times the intensity of wave 2.
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A ball is booted from the ground at an angle of 0 = 44 degrees with respect to the horizontal. The ball is in the air for a time im = 2.5 s before it lands back on the ground
Numerically, what is the total horizontal distance, dm in meters, traveled by the ball in the time, m?
Projectile motion is exemplified by actions like throwing a ball straight up, a ball and giving it speed at an angle to the horizontal, or simply dropping something and letting it fall freely. Gravity is the only force acting on the object during projectile velocity.
Horizontal distance traveled by the ball is 29.86 m
What is projectile motion?A projectile is an object that is launched into the air and moves in that direction. The only force an object experiences after the initial force that launches it is gravity. The trajectory of the object is referred to as the projectile's path.The three different types of projectile motion are as follows: horizontal projectile motion. projectile motion that is oblique. motion of a projectile on an incline.Projectile motion is exemplified by actions like throwing a ball straight up, kicking a ball and giving it speed at an angle to the horizontal, or simply dropping something and letting it fall freely. Gravity is the only force acting on the object during projectile velocity.Launch angle x = 44 °
time period of flight = 2.5s
Time period of Projectile T = [tex]\frac{2u sin x}{g}[/tex] , g=acceleration due to gravity
2.5 = [tex]\frac{2 X u sin 44}{9.2}[/tex]
Where u=initial velocity = 16.66 m/s
Range of Projectile is given by
R = [tex]\frac{u^{2} sin 2x }{g}[/tex]
R= [tex]\frac{16.66^{2} sin 2x44}{9.2}[/tex]
R = 29.86 m
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Calculate the displacement of a sine wave in mm of Time Period of 2 seconds and amplitude 8 cm, 0.3
seconds after the commencement of the wave.
The displacement of the sine wave in mm is determined as 75.36 mm.
What is angular displacement of a wave?
Angular displacement is the angle made by the body from its point of rest at any point in the rotational motion.
The angular speed of the wave is calculated as follows;
ω = 2π/T
where;
T is the period of the wave = 2 sω = 2π/2
ω = π rad/s
The angular displacement of the wave is calculated as follows;
ω = θ/t
θ = ωt
where;
t is time of motion of the wave = 0.3 sθ is angular displacementθ = ( π rad/s) x (0.3 s)
θ = 0.3π rad/s = 0.942 rad
The displacement of the wave in mm is calculated as follows;
Δx = θA
where;
A is the amplitude of the wave = 8 cm = 80 mmΔx = 0.942 rad x 80 mm
Δx = 75.36 mm
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which of the following is a derived unit.
A. Ampere
B. kilogramme
C. Second
D. Ohm
E. Kelvin
Answer:
D. Ohm
Explanation:
Ohm is an SI-derived unit of resistance and can be expanded to its base units of m²·kg·s¯³·A¯².
A tennis player makes a return at a speed of 15m/s and at height of 3m to land in the court at a horizontal distanceof 12m from her. what are the possible angles of projection of the ball
With the use of range formula, also, in multiple of 180 degree, 59 and 239 degrees are the angles of projection.
What is a Projectile ?A projectile in kinematic under physics can be defined as any object that is projected or thrown to take a trajectory path.
Given that a tennis player makes a return at a speed of 15 m/s and at height of 3m to land in the court at a horizontal distance of 12 m from her.
Let us assume that the ball fall at height 3m. U = 0. Let us find the time
h = ut + 1/2gt²
3 = 0 + 1/2 × 9.8 × t²
3 = 4.9t²
t² = 3/4.9
t² = 0.612
t = √0.612
t = 0.782 s
Total time T = 2t
T = 2 × 0.782
T = 1.564 s
The possible angles of projection of the ball can be calculated by using the range formula
R = UcosФT
12 = 15cosФ × 1.564
12 = 23.46cosФ
cosФ = 12 / 23.46
cosФ = 0.512
Ф = [tex]Cos^{-1}[/tex] (0.512)
Ф = 59. 2 degree
Ф = 59°
Therefore, the possible angles of projection of the ball are 59° and 239°
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Which of the following statements would be true about the particle model motion diagram for an airplane taking off from an airport?
a.
The dots would form an evenly spaced pattern.
c.
The dots would be close together to start with, and get farther apart as the plane accelerated.
b.
The dots would be far apart at the beginning, but get closer together as the plane accelerated.
d.
The dots would be close together to start, get farther apart, and become close together again as the airplane leveled off at cruising speed.
25 Which wavefront is travelling at a speed closest to that of a sound wave through a solid? A one that moves 10m in 0.01 s B one that moves 50m in 0.5s C one that moves 1000 m in 100 s D one that moves 2000 m in 2000 s
The wavefront B is travelling at the speed(5000m/s) closest to that of a sound wave(6000m/s) travelling through solid.
The velocity of the sound waves in solids is nearly 6000 meters per second.
Let us check the velocity for all the three wave fronts,,
Wavefront A,
We know,
speed = distance/time taken
Distance travelled by the wavefront A is 10m,
Time taken by the wavefront A to travel the distance is 0.01 seconds,
Putting all the values,
Speed = 10/0.01
Speed = 1000m/s.
Speed of wavefront A is 1000m/s.
Wavefront B,
Again we know,
speed = distance/time taken
Distance travelled by the wavefront Bis 50m,
Time taken by the wavefront B to travel the distance is 0.01 seconds,
Putting all the values,
Speed = 50/0.01
Speed = 5000m/s.
Speed of wavefront B is 5000m/s.
Wavefront C,
We know,
speed = distance/time taken
Distance travelled by the wavefront C is 1000m,
Time taken by the wavefront C to travel the distance is 100 seconds,
Putting all the values,
Speed = 1000/100
Speed = 10m/s.
Speed of wavefront C is 10m/s.
Wavefront D,
Again using the formula,
speed = distance/time taken
Distance travelled by the wavefront is 2000m,
Time taken by the wavefront to travel the distance is 2000 seconds,
Putting all the values,
Speed = 2000/2000
Speed = 1m/s.
Speed of wavefront D is 1m/s.
As we can see, The speed of wavefront B is closest to the speed of sound waves in solids.
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among the different forms of electromagnetic radiation emitted by the sun, which form is absorbed by plants for photosynthesis? microwaves ultraviolet visible light gamma rays infrared
Visible light , The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis.
What is photosynthesis?Photosynthesis is a mechanism used by plants and other living organisms to convert light energy into chemical energy that can then be released through cellular respiration to power the organism's activities.Photosynthesis is the process through which plants turn carbon dioxide, water, and sunlight into oxygen and sugar-based energy.The process through which green plants use sunlight to create their own nourishment is known as photosynthesis. Life on Earth depends on photosynthesis. There would be no green vegetation if it did not exist, and there would be no creatures if it did not exist.Photosynthesis is primarily used to convert solar energy into chemical energy, which is then stored for use at a later time. The majority of the life systems on the planet are powered.To learn more about photosynthesis, refer to:
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2.using what you know about electricity, hypothesize about how parallel resistors would affect current flow. what would you expect the effective resistance of two equal resistors in parallel to be, compared to the resistance of one alone?
The effective resistance of two equal resistors connected in series is twice that of a single resistor, reducing the amount of current flowing in the circuit.
The effective resistance of two resistors connected in series is the sum of their individual resistances. Given two resistors with resistance values R1 and R2, the effective resistance, Rx, is given by:
Rₓ = R₁ + R₂
If the resistance values of these resistors are equal, say R, then equation 1 becomes:
Rₓ = R + R
Rₓ = 2R
That is, their effective resistance is twice as strong as their individual resistances. In other words, when two equal resistors are connected in series, their effective resistance is twice the resistance of each resistor.
Ohm's law states that voltage (V) is the product of current (I) and resistance (R) i.e.
V = IR
I = V/R
We can conclude that as resistance decreases, current increases and vice versa.
As a result, connecting the two equal resistors described above in series reduces the amount of current flowing compared to having just a single resistor.
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1. what happens when electromagnetic radiation encounters a metal object? discuss two ways that can be used to reduce interference from electrical noise.
A full circuit is required for the flow of electrical current, and all electrical energy transmissions need the formation of a circuit with two wires—one going to the recipient and the other going back to the sender.
The construction of a circuit with two wires—one going to the recipient and the other back to the sender—is necessary for all electrical energy transmissions in order for current to flow. Due to the fact that all wireless signals are essentially delivered as electromagnetic signals rather than electrical signals, electromagnetic interference, often known as EMI, is a common problem in wireless communications.
This suggests that any interference with an electromagnetic signal (wave) may cause it to be amplified, destroyed, or lost (assuming constructive interference).
The interference brought on by electromagnetic disturbance is known as electromagnetic interference. Radio frequency interference is another name for it. We refer to interference that occurs in the radio frequency spectrum as radio frequency interference.
These days, wireless communication is expanding at an unprecedented rate. Over a large concentration, a small spectrum is available. Because of this, there is a greater likelihood of mutual interference. The performance of the device and the channel can both be impacted by a slight electromagnetic disturbance. It is crucial to keep interference at a minimal for better wireless performance.
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consider an rlc circuit with resistance 2 ohms, inductance 0.1 henrys, capacitance 0.004 farads, and an impressed voltage, provided by an alternating current generator, of e ( t )
RLC circuit with resistance 5 ohms, inductance 0.1 henrys, capacitance 0.004 farads is q"+20q' + 2500q =50 sin (75t) .
Electrical resistance is a force that opposes the flow of current and is hence resistance to electricity. In this sense, it acts as a gauge for the difficulty of current flow. Ohms () are used to measure resistance.
Electricity will flow from high to low when there is an electron difference between two terminals. In opposition to that flow is resistance. The current decreases with increasing resistance. On the other hand, the current increases with decreasing resistance.
Electronic components known as resistors obstruct the electrical current in a circuit. Similar to how faucets are used to change the flow of tap water, resistors are used in electrical circuits to modify current and voltage. They can also be utilised to regulate the current flow
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A cyclist is going downhill and begins its movement with 12.5 m/s. 30 seconds later he reaches 25 m/s and maintains that velocity for the next 60 seconds. Then he sees the finishing line and brakes until he reaches a complete stop 15 seconds later
Find the value for Acceleration for the stages where it is involved and find the total distance traveled.
1. The acceleration of the cyclist is 0.42 m/s²
2. The total distance travelled by the cyclist is 2437.5 m
1. How to determine the acceleration
We can obtain the acceleration of theration of the cyclist as follow:
Initial velocity (u) = 12.5 m/sTime (t) = 30 secondsFinal velocity (v) = 25 m/sAcceleration (a) =?a = (v – u) / t
a = (25 – 12.5) / 30
a = 12.5 / 30
a = 0.42 m/s²
Thus, the acceleration is 0.42 m/s²
2. How to determine the total distance
We'll begin by obtaining the distance travelled in the first 30 s. This can be obtained as follow:
Initial velocity (u) = 12.5 m/sTime (t) = 30 secondsFinal velocity (v) = 25 m/sDistance (s) = ?s = (u + v)t / 2
s = [(12.5 + 25) × 30] / 2
s = [37.5 × 30] / 2
s = 1125 / 2
s = 562.5 m
Next, we shall determine the distance in the next 60 second.
Velocity (v) = 25 m/sTime (t) = 60 secondsDistance (s) =?s = vt
s = 25 × 60
s = 1500 m
Next, we shall determine the distance in the last 15 seconds.
Initial velocity (u) = 25 m/sTime (t) = 15 secondsFinal velocity (v) = 0 m/sDistance (s) = ?s = (u + v)t / 2
s = [(25 + 0) × 15] / 2
s = [25 × 30] / 2
s = 750 / 2
s = 375 m
Finally, we shall determine the total distance travelled.
Distance in the first 30 s = 562.5 mDistance in the next 60 s = 1500 mDistance in the last 15 s = 375 mTotal distance = ?Total distance = 562.5 + 1500 + 375
Total distance = 2437.5 m
Thus, the total distance travelled is 2437.5 m
Learn more about acceleration and distance travelled:
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#SPJ1
Sometimes, when energy is added to a solid, it undergoes____
Answer:
A phase change
Explanation:
If i understand the question correctly it should undergo a phase change e.g melting
Which dog has the most kinetic energy?
• A. A dog of mass 10 kg running with speed 8 m/s
• B. A dog of mass 14 kg running with speed 6 m/s
• C. A dog of mass 13 kg running with speed 7 m/s
• D. A dog of mass 15 kg running with speed 5 m/s