Y= -3/2x +3 is the same line as x + y =
Write the system x' = e²tx - 8ty + 7 sin(t), y' = 2 tan(t) y + 7x - 2 cos(t) in the form Use prime notation for derivatives and write x and ï', etc., instead of ï(t), x'(t), or dr. 1-1 dt = P60 [*] + F(0). P(t)
The system in the requested form, using prime notation for derivatives and ï notation for variables, is ï' = e^2tï - 8tï' + 7sin(t) and ï'' = 2tan(t)ï' + 7ï - 2cos(t).
The system can be written in the form:
x' = e^2tx - 8ty + 7sin(t)
y' = 2tan(t)y + 7x - 2cos(t)
Using prime notation for derivatives, the system becomes:
x' = e^2tx - 8ty + 7sin(t)
y' = 2tan(t)y + 7x - 2cos(t)
Furthermore, we can write x and y using ï' notation as:
x = ï
y = ï'
Substituting these expressions into the system, we have:
ï' = e^2tï - 8tï' + 7sin(t)
ï'' = 2tan(t)ï' + 7ï - 2cos(t)
In summary, the system in the requested form is:
ï' = e^2tï - 8tï' + 7sin(t)
ï'' = 2tan(t)ï' + 7ï - 2cos(t)
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we are conducting many hypothesis tests to test a claim. In every case, assume that the null hypothesis is true. Approximately how many of the tests will incorrectly find significance?
40 tests using a significance level of 10%.
hi amazing people please help i’ll give brainliest thanks!
Answer:
to present another's viewpoint
Answer:-
D, to analyze specific data i guess
Triangle ABC is an isosceles triangle where angles angle A and B are congruent of angle B measures 35 what is the measurement of angle c
Answer:
m<C = 110
Step-by-step explanation:
<a = <b
<b = 35 so,
<a = 35
<c = x
<a + <b + <c = 180
35 + 35 + x = 180
70 + x = 180
x = 180 - 70
x = 110
X^2-18x-2=0. Which number would have to be added to “complete the square”?
Step-by-step explanation:
its83
(a+b)^2=a^2+2ab+b^2
x^2+(-9)2x-2=0
b^2=81
83+(-2)=81
if h(x) = 3(x + 6), find h(-1).
a.3
b.9
c.15
d.21
How are youaefljsofjsnjvlsdnbvjklxfclkjmzlv
Find the common difference of the arithmetic sequence -3, -9, -15
Answer:
they are subtracting 6 from each number
Twenty-five wooden beams were ordered for a construction project. The sample mean and the sample standard deviation were measured: xbar = 260 cm, s = 2 cm. Calculated confidence interval for the mean is [259.32;260.68].
Which confidence level was chosen? assume distribution to be normal.
The answer tο the questiοn "Which cοnfidence level was chοsen?" is that it cannοt be determined based οn the given infοrmatiοn.
What is Statistical Inference?Statistical inference refers tο the prοcess οf drawing cοnclusiοns οr making predictiοns abοut a pοpulatiοn based οn sample data. It invοlves using statistical methοds and techniques tο analyze the data and make inferences abοut the underlying pοpulatiοn parameters. Statistical inference allοws researchers tο generalize their findings frοm a sample tο the entire pοpulatiοn and make infοrmed decisiοns οr predictiοns.
Twenty-five wοοden beams were οrdered fοr a cοnstructiοn prοject. The sample means and the sample standard deviatiοn was measured:[tex]\bar{x} = 260 \, \text{cm}$, $s = 2 \, \text{cm}$.[/tex] The calculated confidence interval for the mean is [tex][259.32; 260.68]$.[/tex]
To determine the confidence level chosen, we need to consider the properties of a confidence interval. In this case, the confidence interval is given as[tex]$[259.32; 260.68]$[/tex], which represents an interval estimate for the population mean.
A confidence interval is typically written as [tex]\bar{x} \pm E$,[/tex]where [tex]$\bar{x}$[/tex] is the sample mean and E is the margin οf errοr. The margin οf errοr depends οn the sample size, standard deviatiοn, and the desired level οf cοnfidence.
In the given infοrmatiοn, the sample mean [tex]$\bar{x}$[/tex] is 260 cm, and the sample standard deviatiοn s is 2 cm. Hοwever, the level οf cοnfidence is nοt directly prοvided.
Tο determine the cοnfidence level chοsen, we need additiοnal infοrmatiοn abοut the calculatiοn οr the specific cοnfidence level used. Withοut this infοrmatiοn, we cannοt determine the exact cοnfidence level that cοrrespοnds tο the given cοnfidence interval.
Therefοre, the answer tο the questiοn "Which cοnfidence level was chοsen?" is that it cannοt be determined based οn the given infοrmatiοn.
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How am I supposed to do this?
What is the midpoint of EF with endpoints E (−9,7) and F(0,−4)?
Answer:
midpoint = -4.5, 1.5
Step-by-step explanation:
x1 = -9, y1 = 7, x2=0 , y2=-4
midpoint = (x1 +x2)/2 , (y1 + y2)/2
= (-9 + 0)/2 , (7 + -4)/2
=-9/2 , 3/2
midpoint = -4.5, 1.5
Solve Systems of Equations Algebraically.
y=x-8
y=5x
Answer:
(- 2, - 10 )
Step-by-step explanation:
Given the 2 equations
y = x - 8 → (1)
y = 5x → (2)
Substitute y = 5x into (1)
5x = x - 8 ( subtract x from both sides )
4x = - 8 ( divide both sides by 4 )
x = - 2
Substitute x = - 2 into either of the 2 equations for y
Substituting into (1)
y = - 2 - 8 = - 10
solution is (- 2, - 10 )
The driveshaft lifespan is measured in operating hours before failure, and the distribution of lifespans is known to follow a Gamma distribution. A sample of 50 driveshafts is carefully tracked until failure and their lifespans are measured to have sample mean of 1274 hours, and a standard deviation of 108 hours.
(a)Assuming a normal distribution with the mean and standard deviation of the sample, estimate the proportion of driveshafts that would fail prior to reaching 1200 operating hours.
(b)Using the central limit theorem and corresponding normality assumption, calculate a 95% confi- dence interval for the true mean lifespan.
a. The estimated proportion of driveshafts that would fail prior to reaching 1200 operating hours is approximately 0.246, or 24.6%.
b. The 95% confidence interval for the true mean lifespan is approximately (1244.79, 1303.21) hours.
How to calculate the value(a) First, we need to standardize the value 1200 using the sample mean and standard deviation. We calculate the z-score as follows:
z = (x - μ) / σ,
z = (1200 - 1274) / 108
≈ -0.685
Using a standard normal distribution table or calculator, we find that the proportion is approximately 0.246.
(b) The formula for the confidence interval is:
CI = x ± z * (σ / √n),
CI = 1274 ± 1.96 * (108 / √50)
CI = 1274 ± 1.96 * (108 / √50)
CI ≈ 1274 ± 1.96 * 15.297
The 95% confidence interval for the true mean lifespan is approximately (1244.79, 1303.21) hours.
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Solve for v.
6v-7+2(5v+1) = -2(v + 4)
Answer:
v = -1/6
Step-by-step explanation:
Combine all like terms, getting 18v = -3. Then, divide both sides by 18 to get -3/18, or v = -1/6
Hopefully this helps- let me know if you have any questions!
please help!
if a trail runner zig-zags 15m to the west and then 15m to the east:
what is the runner's total distance?
what is the runner's total displacement?
Answer:
Total distance = 30m
Total displacement = 0m
Step-by-step explanation:
a) Distance is a scalar quantity that does not specify direction
Hence if a trail runner zig-zags 15m to the west and then 15m to the east, the total distance will be the sum of the distance travelled both to the west and east.
total distance = distance through west + distance through east
total distance = 15m + 15m
total distance = 30m
Hence the runner's total distance is 30m
b) Displacement is a vector quantity and it specifies direction. Hence we will take into consideration the direction taken
Since East direction is positive, the displacement through east is +15m
Since West direction is negative, the displacement through west is -15m
Total displacement = +15 - 15
Total displacement = 0m
Hence the runner's total displacement is 0m
what is the area of the rectangular pool below whose dimension are 2 x +1 and units x-1 units
Answer:
(2x+1)(x-1) = 2x^2 - x - 1
Step-by-step explanation:
Answer:
2x^2 - x - 1
Step-by-step explanation:
Lets rewrite it to the area formula
(2x+1)(x-1)
Simplify-(distributive property of multiplication)
(2x*x) + (2x*-1) + (1*x) + (1*-1) =
Simplify
2x^2 + (-2x) + x + (-1)
Simplify
2x^2 - x - 1
The answer is 2x^2 - x - 1
If my answer is wrong, pls correct me
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A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, X, is found to be 100, and the sample standard deviation found to be 8.
Construct a 98% confidence interval about µ, if the sample size n, is 20.
Lower bound ______ Upper bound _______
(Round to one decimal place as needed.)
As per the confidence interval Lower Bound is 94.874 and the Upper Bound is 105.126
Sample Mean = 100
Sample Standard Deviation = 8
Sample Size = 20
Calculating the confidence interval -
Confidence Interval = Sample Mean ± (Critical Value) x (Standard Deviation / √(Sample Size))
Substituting the values
= 100 ± (2.860) x (8 / √20)
= 100 ± 2.860 x (8 / 4.472)
= 100 ± 2.860 x 1.789
= 100 ± 5.126
Calculating the lower bound -
Lower Bound
= 100 - 5.126
= 94.874
Calculating the upper bound -
Upper Bound
= 100 + 5.126
= 105.126
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You add 11/4 tablespoons of olive oil for every 3/2 tablespoons of balsamic vinegar to make 34 tablespoons of bread dip. How much olive oil and balsamic vinegar do you use?
You use ___ tablespoons of olive oil and
___ tablespoons of balsamic vinegar.
Answer:
The amount of olive oil and balsamic vinegar to use are;
You use 22 tablespoons of olive oil and 12 tablespoons of balsamic vinegar
Step-by-step explanation:
From the question, we have;
The number of tablespoons of olive oil added for every 3/2 tablespoon of balsamic vinegar = 11/4 tablespoons
Therefore, in the mixture, the ratio of olive oil to balsamic vinegar = 11/4:3/2
Let 'x', and 'y' represent the the number of tablespoons of olive oil and balsamic vinegar, in the mixture 34 tablespoons of bread dip, we can write;
x + y = 34 tablespoons
x/y = (11/4)/(3/2) = 11/6
∴ x = 11/6 × y
∴ x + y = 11/6 × y + y = 34
11/6 × y + y = 17·y/6 = 34
17·y = 34 × 6 = 204
y = 204/17 = 12
The number of tablespoons of balsamic vinegar in the bead dip, y = 12 tablespoons of balsamic vinegar
x = 11/6 × y = 11/6 × 12 = 22
The number of tablespoons of olive oil in the bead dip, x = 22 tablespoons of olive oil.
Joe has been riding his bicycle at a speed of 12 mph and has gone 48 miles. How long has he been riding?
Answer:
Joe's been riding 4 hours because if you divide 48 by 12 it gives you 4 and it's by hours so it would be 4 hours. point blank period.
Step-by-step explanation:
HELP ASAP!!! select all the descriptions that apply to the transformation!
Answer: A and B
Step-by-step explanation:
The shape is moving from right to left and down
Please please help I swear I will give you brainlist if it’s right and please explain for part a and part b thank you
Answer:
A. Reduction
B. 2
Step-by-step explanation:
A: A reduction is when the image is getting smaller. The apostrophes show the new, or second, image. It is called "prime." Because the prime is smaller than the original, it is a reduction.
B: Scale factor is when you divide, which number changes it. In other words, the image moved from 4 to 2, from 2 to 1, etc, which means we are DIVIDING by 2.
given the rectangular coordinates (-8,15), which of the following polar coordinate pairs represents the same point in radians?
a(17,2.65)
b(-17,-1.08)
c(12.7,2.65)
d(-12.7,-0.49)
Answer:
1. (x,y)=
2. (3, 480°), (3,-240°), (-3, -60°)
3. (-17, -1.08)
4. on the second circle from the center and 153° clockwise from the horizontal axis
Step-by-step explanation:
took quiz...100%
Find the area under the standard normal distribution curve between z=0 and z=0.25. Use The Standard Normal Distribution Table and enter the answer to 4 decimal places.
The area between the two z values is ______
The area under the standard normal distribution curve between z=0 and z=0.25 is 0.0987.
First cumulative probability = z = 0 and
Second cumulative probability = z = 0.25
The Standard Normal Distribution Table, often known as the Z-table, may be used to determine the area under the standard normal distribution curve between z=0 and z=0.25. The table shows the total likelihood (area) up to a specified z-value. The cumulative probability, which can be found by looking up the z-value of 0 in the table, is 0.5000. The cumulative probability is 0.5987 when we look up the z-value of 0.25.
Calculating the area -
Area = First cumulative probability - Second cumulative probability
= 0.5987 - 0.5000
= 0.0987
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How much interest is earned on a principal of $316 invested at an interest rate of 9%
compounded annually for four years?
Answer:
$130.06
Step-by-step explanation:
Interest is calculated as shown;
I = A - P
A is the amount
P is the principal
Given
Principal = $316
Rate R = 9% = 0.09
Time t = 4yrs
Substiutte and get Amount A
A =P(1+r)^n
A = 316 (1+0.09)^4
A = 316(1.09)^4
A = 316(1.4116)
A = 446.06
Interest = 446.06 - 316
Interest = 130.06
Hence the interest is $130.06
Which of the following variables could theoretically be measured on a continuous scale? (a) Method of contraception used (b) length of time of residence in a state (c) task completion time (d) intelligence (e) authoritarianism (f) alienation (g) county of residence.
The variable that could theoretically be measured on a continuous scale is task completion time.
Task completion time is the duration between the initiation and completion of a specific task. It is continuous as it can take a large range of values on a continuous scale without any gap. It is frequently calculated in various businesses and researches to determine the efficiency and productivity of a particular task or process.
The other variables, such as method of contraception used, length of time of residence in a state, intelligence, authoritarianism, alienation, and county of residence, are all discrete variables. These variables take non-numerical values and are separate from each other by a gap.
These variables can be classified and counted into different categories, such as the number of individuals using a particular method of contraception, number of years of residence in a particular state, number of individuals belonging to a particular county, or number of individuals showing authoritarianism.
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The lenght of an arc in a circle with radius 8 inches is 3.2π. determine the measure of the arc
Answer:
72
Step-by-step explanation:
32pi×360/2pi(8)=72
central angle= arc length 360/2pi×r
The measure of the arc is 72 degree
What is mean by Circle?The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.
The measure of the arc, we use the formula:
⇒ Arc length = (angle measure / 360°) x 2πr
where r is the radius of the circle.
Now, We know that;
The radius is 8 inches, and that the arc length is 3.2π inches.
So, we can plug in those values and solve for the angle measure:
3.2π = (angle measure / 360°) x 2π(8)
3.2π = (angle measure / 360°) x 16π
Divide both sides by 16π:
0.2 = angle measure / 360°
Multiply both sides by 360°:
Angle measure = 72°
Thus, The measure of the arc is 72 degree
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when comparing the f(x) = x2 2x and g(x) = log(2x 1), on which interval are both functions negative? (–[infinity], –2) (–2, 0) (–1, 1) (–[infinity], [infinity])
To find out on which interval are both functions f(x) = x^2 + 2x and g(x) = log (2x + 1) negative, we need to analyze the intervals of negative values of both functions.
We can plot their graphs to have a better understanding:
Graphs of f(x) = x² + 2x and g(x) = log(2x + 1)
Now, we need to observe the intervals where both functions lie below the x-axis: The function f(x) = x^2 + 2x is below the x-axis on the interval (-∞, -2).
The function g(x) = log(2x + 1) is below the x-axis on the interval (-1/2, 0).
Therefore, the interval on which both functions are negative is (-2, 0).Thus, the correct option is (–2, 0).
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Can someone please help me with this
Answer:
Step-by-step explanation:
5- There are 2 right-angled triangles and 1 equilateral triangle or you can just say triangles
6- area for a triangle is a=bh(1/2)
so 4×3=12(1/2)=6
and 4×3=12(1/2)=6
In both triangles, they're a=6
7- 4×6=24(1/2)=12
the top flag is a=12
8-12+6+6=24
9- the rectangular flag has an area of 24 since a=bh and the added areas of the triangles are 24. I conclude that these are two ways of finding the area of this rectangular flag.
hope this helps : )
In a study of spat dating es were asked them in the same time to What other out of the popu 23,50710090 What is the concerto? D-lichte places need was the other the contacto OA TN repostane posting tone OR Weather to the memo and on dem O. We second have the end மொயமால மாமா mg 140 Newt 0 View an example Get more help Help me solve this C M a o 0 10 1 In a study of speed dating male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractivo 10 = extremely attractive) Construct a confidence interval using a 95% confidence level What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,9, 6, 6, 8, 8, 7, 10,5,9 What is the confidence interval for the population mean? [<<(Round to one decimal place as needed) west point(s) possible in a study of speed dating, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractive 10 = extremely attractive) Construct a confidence interval using a 95% confidence level What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,9,6,6,8,8.7. 10,5,9 PO What is the confidence interval for the population mean? <-- (Round to one decimal place as needed) What does the confidence interval tell about the population of all adult fernales? Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. ative Area from the LEF 02 O A. The results tell nothing about the population of all adult females, because participants in speed dating are not a representative sample of the population of all adult females 5000 5178 03 5120 5517 5990 5871
Confidence interval are 5.9 < μ < 8.5 for the population mean.
Given:
Let x = 6,9,3,9, 6, 6, 8, 8, 7, 10,5,9
N = 12, ∑x = 86 x = 86/12 = 7.16
[tex]s=\sqrt{\frac{(x-\bar x)^2}{N-1} } = \sqrt{\frac{(6-7.16)^2+.....+(9-7.16)}{12-1} }[/tex]
[tex]\sqrt{\frac{45.66}{11} } =2.03[/tex]
At 98% confidence interval.
[tex]z=1-\frac{95}{100} =0.05\\[/tex]
[tex]t=2.201[/tex]
Confidence interval.
[tex]\bar x \pm t\frac{s}{\sqrt{n} } = 7.16\pm 2.201(\frac{2.03}{\sqrt{12} } )[/tex]
[tex]5.9 < \mu < 8.5[/tex]
Therefore, 95% confidence interval are 5.9 < μ < 8.5
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