The chemical equation for a reaction is shown below.

2 NO2(g) → N2O4(g)

What is the standard free energy change (ΔGo) in this reaction at 298 K? (NOTE: At 298 K, ΔGfo for NO2 is 51.84 kJ/mol, and for N2O4 is 98.28 kJ/mol.)

Atomic radius is1.349*10-23

hcp unit cell you can see that that the spheres touch each other along

so 2rMg = a where rMg is the radius of a Mg ion and = 0.6745*10^-23

There are three levels of atoms in the hcp structure.

Six atoms form a hexagonal arrangement in the top and bottom layers, while a seventh atom sits in the centre of the hexagonal arrangement.

Three atoms in the intermediate layer are tucked away in the top and bottom plane's triangular grooves.

Mg hcp c/a = 1.635

hcp is close-packed example ABABAB etc

V = sin(60)*a*a*1.635 a

V = 1.635 *0.866*a^3

V = 1.887*a^3 cm3

Z = 2 (atoms inside unit cell)

Mass inside unit cell is = (2 * 24.305)/(6.022*10^23) = 8.071*10^-23 g

D =M/V

1.74 = 8.071*10^-23/1.887*a^3

a^3 = 8.071*10^-23/1.887*1.74 = 2.458*10^-23

a = 1.349*10^-23

Hence Atomic radius is 1.349*10^-23

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Answer:-
A Solution of salt in Water
Hope It helps!

Answer: B) a solution of salt in water

Explanation:

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The chemical formula will be  [tex]C_4H_9O_2[/tex].

From the model, there are a total of 4 carbon atoms, 9 hydrogen atoms, and 2 oxygen atoms.

All the atoms are bonded to each other accordingly.

Thus, the only plausible chemical formula for the compound is [tex]C_4H_9O_2[/tex]

All other available options fall short in one way or the other as far as the number of atoms of each element in the compound is concerned.

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The dehydration-condensation reaction occurs between 'ethanol' and 'butanoic acid' giving an ester called as "ethyl butanoate".

Esters are produced when carboxylic acids are heated with alcohols in the presence of an acid catalyst.

The catalyst is usually concentrated sulphuric acid.

Dry hydrogen chloride gas is used in some cases, but these tend to involve aromatic esters (ones containing a benzene ring).

Esters are represented by the formula RCOOR', where R and R' are hydrocarbon groups.

The chemical reaction occurring in the formation of the ester is known as an esterification reaction.

The reaction that occurs between ethanol and butanoic acid:

Ethanol reacts with butanoic acid in the presence of an acid-catalyst and gives ethyl butanoate as ester and water as products. If an acid reacts with a base, salt and water are the products. But ester is not a salt.

i) The carbon skeletal notation for the given reaction is shown below.

ii) The ester is named "ethyl butanoate".

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Answer:

Explanation:

Equation with given

P2O5      ====> 2P^5 + 5O-2

                          0.620     x

Solution

What you are going to do first is find the molar amount of oxygen. Use a proportion to do this

2/0.620 = 5/x                    Cross Multiply

2x = 0.620 * 5                   Divide both sides by 2

2x/2 = 0.620 *5/2

x = 0.310 * 5                      Combine

x = 1.55                              moles of oxygen.

Now comes the answer. How many atoms are there in 1.55 moles of oxygen?

1 mole of anything contains 6.02 * 10^23 items of  that mole

1.55 moles of oxygen contains x  atoms of oxygen

1/1.55 = 6.02 * 10^23 / x                  Cross multiply

1*x = 1.55 * 6.02*10^23                    Combine

x = 9.331 e 23

Answer

9.33e23

Three examples of environmental, industrial and bio-chemistry are listed below:

Chemistry can be defined as a branch of science which is concerned with the substances matter is composed of, their properties and reactions,

Chemistry also deals with the use of such reactions to form new substances.

In conclusion, Three examples of environmental, industrial and bio-chemistry are listed anove

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If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5% isotope A (mass number 20), 0.3% isotope B (mass number 21), and 9.3% isotope C (mass number 22), the atomic weight of the element measured from the sample will be greater than 21 amu.

To calculate the average atomic mass, multiply the fraction through the mass number for every isotope, then add them together. Whenever we do mass calculations concerning elements or compounds (combos of elements), we usually use average atomic loads.

For instance, carbon-14 is a radioactive isotope of carbon that has six protons and 8 neutrons in its nucleus. We name it carbon-14 because the overall range of protons and neutrons within the nucleus also called the mass number, provides up to fourteen (6+8=14).

Together, the quantity of protons and the range of neutrons determine an detail's mass variety. Due to the fact, that an element's isotopes have barely unique mass numbers, the atomic mass is calculated by obtaining the suggested mass numbers for its isotopes.

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Answer:

Swedish physicist Johannes Rydberg

Explanation:

Answer: [tex]340gAgNO_{3}[/tex].

Explanation:

You will need to create a stoichiometric equation with the information given. The formula is in the problem and so are the molar masses. I will add and plug in the data for you below.

[tex]24gMg*\frac{1molMg}{24gMg} *\frac{2molAgNO_{3} }{1molMg} *\frac{170gAgNO_{3}}{1molAgNO_{3}} =340gAgNO_{3}[/tex]

I plugged the numbers into my scientific calculator, which is how I got the answer. I also added the letters in the formula above because you have to be able to cancel them out so you can find your missing data.

Therefore, [tex]340gAgNO_{3}[/tex] would react with 24gMg.

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[tex]340g AgNO_3[/tex] would react with 24 grams of Mg.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Create a stoichiometric equation with the information given.

[tex]24g Mg X \frac{1 mol of Mg}{24g Mg} X \frac{2 mol of AgNO_3}{1 mol of Mg} X \frac{170g AgNO_3 }{1 mol AgNO_3} = 340g AgNO_3[/tex]

[tex]340g AgNO_3[/tex]

Hence, [tex]340g AgNO_3[/tex] would react with 24 grams of Mg.

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3.73 x[tex]10^{-3}[/tex] the rate of change of [tex]ClF_3[/tex] if the concentration of [tex]F_2[/tex]decreases from 0.950 M to 0.865 M over 15 seconds.

The rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable.

[tex]Cl_2(g)+3F_2(g)[/tex]→[tex]2ClF_3(g)[/tex]

Rate of change of [tex]F_2[/tex] = [tex]\frac{Change \;in \;concemtration}{Time}[/tex]

Rate of change of[tex]F_2[/tex] = [tex]\frac{0.950 M-0.865 M}{15 seconds}[/tex]

Rate of change of [tex]F_2[/tex] = 5.6 x [tex]10^{-3}[/tex]

[tex]\frac{Rate of change of F_2}{3}[/tex] =[tex]\frac{Rate \;of c\;hange \;of\;ClF_3}{2}[/tex]

[tex]\frac{5.6 X 10^{-3}}{3}[/tex]=[tex]\frac{Rate \;of \;change \;of \;ClF_3}{2}[/tex]

Rate of change of [tex]ClF_3[/tex] =1.866666667 x2 x[tex]10^{-3}[/tex]

Rate of change of [tex]ClF_3[/tex]= 3.73 x [tex]10^{-3}[/tex]

Hence, 3.73 x[tex]10^{-3}[/tex] the rate of change of [tex]ClF_3[/tex] if the concentration of [tex]F_2[/tex]decreases from 0.950 M to 0.865 M over 15 seconds.

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55.44 K is the temperature that need to change in order for the neon gas to be 39.0% faster than the RMS speed of the argon.

Given

RMS speed of argon = 1.20 km/sec = 1.20 ×[tex]10^{3}[/tex] m/sec

RMS speed of neon = 39% faster than the speed of argon

                                 = RMS speed of argon + [tex]\frac{39}{100}[/tex] RMS speed of argon

                                 = RMS speed of argon ( 1 +0.39)

RMS speed of neon = 1.39 times of RMS speed of argon

Hence   [tex]\frac{v_{ne} }{v_{ar} } = \frac{1.39}{1}[/tex] … (1)

The atomic mass of argon is 39.95 g/mol = 39.95×[tex]10^{-3}[/tex] Kg/mol

and  the atomic mass of neon is 20.18 g/mol = 20.18 ×[tex]10^{-3}[/tex] Kg/mol

According to the formula of root-mean-square velocities of gas molecules

[tex]v_{rms} = \sqrt{3RT/M}[/tex] where,

[tex]v_{rms}[/tex] = root-mean-square velocity

M = molar mass of gas (in kg per mole)

R = Molar gas constant = 8.314 J/mol/K

T = temperature (in kelvin)

[tex]v_{arg }[/tex] = [tex]\sqrt{3RT_{arg}/M }[/tex]

[tex]v_{arg} ^{2}[/tex] = [tex]3RT_{arg} /M[/tex]

1.20 ×1.20 ×[tex]10^{6\\[/tex] = 3 ×8.314×[tex]T_{arg}[/tex] /39.95 ×[tex]10^{-3}[/tex]

[tex]T_{arg}[/tex] = 1.44 × 39.95 ×[tex]10^{3}[/tex] / 24.942

[tex]T_{arg}[/tex] = 2306.47 K

Now,

RMS velocity is directly proportional to [tex]\sqrt{T}[/tex] and inversely proportional to [tex]\sqrt{M}[/tex]

[tex]v_{rms}[/tex] [tex]\alpha[/tex] [tex]\sqrt{T}[/tex]   and  [tex]v_{rms} \frac{1}{\alpha } \sqrt{M}[/tex]

[tex]\frac{v_{ne} }{v_{ar} }[/tex] =  [tex]\sqrt{\frac{T_{ne} }{T_{ar} } }[/tex]× [tex]\sqrt{\frac{M_{ar} }{M_{ne} } }[/tex]

According to equation 1

[tex]\sqrt{\frac{T_{ne} }{T_{ar} } }[/tex] × [tex]\sqrt{\frac{M_{ar} }{M_{ne} } }[/tex] = 1.39

[tex]T_{ne}[/tex] = 1.39 ×1.39 × 2306.47 × 20.18 / 39.95

[tex]T_{ne}[/tex] = 2251.03K

Change in temp ΔT = 2306.47-2251.03= 55.44 K

Hence, 55.44 K is the temperature that need to change in order for the neon gas to be 39.0% faster than the RMS speed of the argon.

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Answer:

the volume of the gas at 2.50 atm pressure is equal to 1.44 Litres.

Explanation:

The strongest type of intermolecular force between solute and solvent in CH3OCH3(g) in H2O(l) is H-bond and ion-induced dipole.

Hydrogen bonding is a special type of dipole-dipole attraction between molecules, not a covalent bond to a hydrogen atom.

It comes about as a result of the attraction between a hydrogen atom that is covalently attached to a very electronegative atom, like an N, O, or F atom, and another extremely electronegative atom.

Hydrogen is covalently joined to the more electronegative oxygen atom in water molecules (H2O). Therefore, the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another H2O molecule are what cause hydrogen bonding to form in water molecules.

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-31.2 kJ is the work  done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.

It is represented by the equation

W = PΔV

where,

W = Work done

P = Pressure

ΔV = Change in volume (V₂ - V₁)

Now put the values in above formula we get

W = PΔV

    = 4.4 atm × (13 L - 83 L)

    = 4.4 atm × (-70 L)

    = -308 atm L

Now change L atm into J

= -308 × 101.3 J     [L × atm = 101.3 J]

= -31200.4 J

= -31200.4 × 10⁻³ kJ

= -31.2 kJ

Thus from the above conclusion we can say that -31.2 kJ is the work  done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.

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Answer:

Six-membered cyclic hemiacetals and five-membered cyclic hemiacetals are called, respectively, mannoses and xyloses.

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Answer and Explanation:

To calculate this, simply use an equality of proportions:

50 particles  :  1 billion particles = x tons  :  1.49 million tons

The value of x can be solved for by multiplying the ratio on the left by the value 1.49 million / 1 billion:

So, x = (50)(0.00149) tons = 0.0745 tons

Then, do the same thing for the larger concentration:

x = (200)(0.00149) tons = 0.298 tons

Diamond is a network solid.

In diamond, carbon atoms are bonded together by extended covalent bonds. Each carbon atom forms four strong covalent bonds with its neighboring carbon atoms, creating a three-dimensional network of carbon-carbon bonds throughout the crystal lattice.

Diamond is a type of solid known as a covalent network solid. In covalent network solids, the atoms are held together by a network of strong covalent bonds, extending throughout the entire crystal structure. This results in a very rigid and hard material with high melting and boiling points.

Other examples of covalent network solids include graphite and quartz. Due to its strong and interconnected carbon-carbon bonds, diamond is renowned for its exceptional hardness and is one of the hardest known naturally occurring materials.

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The best reactant is: iPrCl

The best reagent is: Mg

The best solvent is: CH3CH2OCH2CH3

A chemical molecule with the general formula RMgX, where X is a halogen and R is typically an alkyl or aryl group, is known as a Grignard reagent or Grignard compound. Methylmagnesium chloride (ClMgCH3) and phenylmagnesium bromide (C6H5)-Mg-Br, respectively, are two prominent examples. They fall within the category of organomagnesium compounds.

Typically, magnesium ribbon is needed for the reaction that results in the synthesis of Grignard reagents. A magnesium oxide passivating coating protects the whole magnesium, preventing interactions with organic halides. As an initiator, Grignard's prepared reagent can also be applied.

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Answer:

See below

Explanation:

Molecular formula  ( just write down all of the elements )   C 4 H4 O4

Empiracle formual    CHO

"Molecular formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound"

Answer: The concentration of ammonia is 0.0286M.

Explanation:

The diluted equation is presented as: [tex]M_{s} V_{s} =M_{d} V_{d}[/tex].

~M= Molarity (labeled as M)

~V= Volume (labeled in L)

~s= stock solution (what you started with)

~d= diluted solution (what you now have)

Now that we have our definitions, we can knowingly plug the information into the formula shown above.

[tex]0.117M*24.4mL=M_{d} *100mL[/tex]

We have the information plugged in, but the volume must be measured into liters, not milliliters. We can fix that by converting it. To convert milliliters to liters, you divide the milliliters by 1000.

[tex]24.4mL/1000=0.0244L[/tex]     [tex]100mL/1000=0.1L[/tex]

Now that the volumes are in liters, let's plug that into the equation.

[tex]0.117M*0.0244L=M_{d} *0.1L[/tex]

We are now ready to solve the concentration with this equation!

[tex]M_{d} =\frac{0.117M*0.0244L}{0.1L}[/tex]      [tex]M_{d} =0.0286M[/tex]

With all of the steps shown above, we can conclude that the new concentration of ammonia is 0.0286M.

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Candle wax is made up of several hydrocarbons with the general formula [tex](CH_2)_n[/tex] , where n is a large number.

Hydrocarbon's on reaction with oxygen forms carbon-dioxide and water vapor. This is called combustion reaction.

                                   [tex](CH_2)_n + O_2 \rightarrow CO_2 + H_2O[/tex]

After few minutes, you will observe that the transparent lid is now opaque and there are traces of water deposited on the surface of lid.

Conclusion -  the lid is opaque due to the carbon-dioxide formed and water vapors are condensed on the surface of lid.

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Simple

Look at Electronic configuration of Al

It has valency as 3

So it can make 3 bonds

So

Aluminium does bonding with 3 chlorine atoms

There is another reason

That's electronegativity

As difference in electronegativity is higher they forms ionic bond

The molecular formula of the compound is [tex]Cr_{2}S_{3}O_{12}[/tex].

Mass of Cr = 0.70 g

Mass of S = 0.65 g

Mass of O = 1.30 g

Molecular mass = 392.2 g

Moles of Cr = [tex]\frac{0.70}{52.0}[/tex]

                  = 0.01346 mol

Moles of S = [tex]\frac{0.65}{32.06}[/tex]

                  = 0.02025 mol

Moles of O = [tex]\frac{1.30}{16.0}[/tex]

                   = 0.08125 mol

Dividing both sides with lower quantity ;

[tex]Cr_{\frac{0.01346}{0.01346} } S_{\frac{0.2025}{0.01346} } O _{\frac{0.08125}{0.01346} }[/tex]≅ [tex]CS_{1.5} O_{6}[/tex]

And [tex](empirical formula )_{n} = molecular formula[/tex]

                        392.2 = n (52.0 + 6 × 16.0)

                                  n = 2

Therefore, the molecular formula of the compound is [tex]Cr_{2}S_{3}O_{12}[/tex].

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Answer:

1s22s22p6: Neon (Ne)

1s22s22p63s23p3: Phosphorous (P)

1s22s22p63s23p64s1: Potassium (K)

1s22s22p63s23p64s2(im not sure what 308 is supposed to be): Calcium (Ca)

1s22s22p63s23p64s23d104p65s24d3: there is no pure element that ends 4d3 that I know of so this can either be Zirconium(Zr) if it ends in 4d2 or Niobium (Nb) if it ends in 4d4

Explanation:

you can look at the periodic table and the trends to find the rough idea of where the electron configuration ends, there are helpful articles and images on these, i attached an image that may help. After that you can look at the atomic number to find the number of electrons for a pure element and use the electron subshell pattern thing to find the exact number

The daily maximum of just sodium (Na) should be = 6000 mg

The adult's daily maximum intake of salt = 6g

The major element of salt that causes health concerns is sodium (Na).

Therefore the quantity of sodium consumed in milligrammes= 6×1000

= 6000 mg

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Taking into account the reaction stoichiometry, 3 moles of NH₃ will be formed.

In first place, the balanced reaction is:

Li₃N + 3 H₂O → NH₃ + 3 LiOH

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Li₃N reacts with 3 moles of H₂O, 3.20 moles of Li₃N reacts with how many moles of H₂O?

[tex]moles of H_{2} O=\frac{3.2 moles of Li_{3}Nx 3 moles of H_{2} O}{1 mole of Li_{3}N}[/tex]

moles of H₂O= 9.6 moles

But 9.6 moles of H₂O are not available, 9 moles are available. Since you have less moles than you need to react with 3.20 moles of Li₃N, H₂O will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 3 moles of H₂O form 1 mole of NH₃, 9 moles of H₂O form how many moles of NH₃?

[tex]molesof NH_{3} =\frac{9 moles H_{2} Ox1 mole of NH_{3}}{3 moles H_{2} O}[/tex]

moles of NH₃= 3 moles

Finally, 3 moles of NH₃ will be formed.

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In the bohr model of the hydrogen atom, the energy required to excite an electron from n = 2 to n = 3 is greater than the energy required to excite an electron from n = 3 to n = 4

Bohr's energy levels:

The essential concept of Bohr's atomic model is that electrons occupy specified orbitals that call for the electron to have a certain amount of energy. An electron needs to be in one of the permitted orbitals and have the correct amount of energy needed for that orbit in order to be in the electron cloud of an atom. An electron would require less energy to orbit near the nucleus, while an electron would need more energy to orbit away from the nucleus. Energy levels are the potential orbits. One of Bohr's models' flaws was that he was unable to explain why just specific energy levels or orbits were permitted.

It is evident that the energy required to escape an electron from n=2 to n=3 is greater than the energy required to exit an electron from n=3 to n=4. This is because as n increases, the energy levels move closer to one another.

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answer

Please add answer choice

Explanation:

Answer:

Explanation:

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