The chart shows Daniela’s run through her race.

A graph with horizontal axis time (seconds) and vertical axis position in (meters). The line runs straight from 0 seconds 5 meters to 10 seconds 30 meters.
What is her velocity?

1.5 m/s
2 m/s
2.5 m/s
5 m/s

Answers

Answer 1

Answer:

Explanation:

velocity is the rate of change of displacement with respect to time.

Velocity = displacement/time

If a  line runs straight from 0 seconds 5 meters to 10 seconds 30 meters.

The velocity will be expressed as;

v = d2-d2/t2-t1

v = 30-5/10-0

v = 25/10

v = 2.5m/s

Hence her velocity is 2.5m/s

Answer 2

Daniela's velocity is 2.5 m/s.

Velocity is the ratio of displacement to time taken. It is given by:

Velocity = displacement / time

The velocity of Daniela can be gotten by calculating the slope of the graph. Considering the points (0, 5) and (4, 15).

[tex]Velocity(slope)=\frac{15-5}{4-0}=2.5\ m/s[/tex]

Therefore Daniela's velocity is 2.5 m/s.

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The Chart Shows Danielas Run Through Her Race.A Graph With Horizontal Axis Time (seconds) And Vertical

Related Questions

a car accelerates at a constant rate from 15 m/s to 25 m/s while it travels a distance of 125 m. How long does it take to achieve this speed?

Answers

T=Vf-Vi/s
25m/s -15m/s/ 125m
10m/s /125m
=0.08s
I hope it’s correct !

The time taken by the car to achieve the final speed is 6.25 seconds.

What is the equation of motion?

The equations of motion can be defined as the equation that represents the relationship between the time, velocity, acceleration, and displacement of a moving object.

The mathematical expressions for the equations of motions can be written as:

[tex]v= u+at\\S=ut+(1/2)at^2\\v^2-u^2=2aS[/tex]

Given, the initial speed of the car, u = 15 m/s

The final speed of the given car, v = 25m/s

The distance covered by car, S = 125 m

From the third equation of motion: v² = u²+ 2aS

(25)² = (15)² + 2×a× 125

a = 1.6 m/s²

From the first equation of motion we can find the time to achieve the final speed:

v = u+ at

25 = 15 + (1.6) × t

t = 6.25 sec

Therefore, 6.25 seconds will be taken by the car to catch the final speed.

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giving brainliest to first one who gets this right

Answers

a. Nitrogen, Oxygen,and Carbon Dioxide

hope im right but I dont really know

1. When asteroids collided some of the broken materials fall into Earth's orbit. What do
astronomers call the debris when it hits planet Earth?
(2 Points)
meteors
meteoroids
meteorites
metabots

Answers

i believe it is meteoroids

Before they meet Earth -- meteoroids

While they're falling -- meteors

After they hit the ground -- meteorites

Friction that occurs in gases and liquids is called

Answers

The answer is fluid friction

Which interaction contributes to the greenhouse effect?
A (Gases in the atmosphere absorb heat.
B (Dust particles scatter and reflect light from the Sun.
C (Green visible light is trapped in Earth’s atmosphere.
D (Light travels through a thick part of the atmosphere at sunrise and sunset.

Answers

Answer:

A

Explanation:

Answer:

A

Explanation:

Gases in the atmosphere absorb heat.

You know when you have a blanket around you and some heat gets trapped in but some still gets out. Thats basically what it is.

Plus I got it right in multiple questions including the test!

I hope that reassured you!

Have a good night!

A 45 kg object has a momentum of 225 kg-m/s northward. What is the object's velocity?
A. 180 m/s
B. 5.0 m/s
C. 10,125 m/s
D. 0.20 m/s

Answers

The answer is 5.0 m/s

At an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s. What is the angle of the shock cone

Answers

Answer:

55 degrees

Explanation:

Given that an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s.

From the question above, we can get the below parameters

Object speed (V) = 1500 km/h

Sound speed ( v) = 342 m/s

Convert km/h to m/s

(1500 × 1000)/3600

Jet speed V = 416.67 m/s

Let's first calculate the mash number M.

M = V/v

M = 416.67 / 342

M = 1.2183

Formula for the angle of the shock cone is reciprocal of mash number. That is,

Sin Ø = 1 / M

Sin Ø = 1 / 1.2183

Sin Ø = 0.8208

Ø = sin^-1(0.8208)

Ø = 55 degree

Therefore, the angle of the shock cone is approximately 55 degrees

What is the acceleration of gravity, in m/s2, on the surface (or outer limit) of Venus? The mass of Venus is 4.87 1024 kg and its radius is 6.05 106 m.

Answers

Answer:

8.9 m/[tex]s^{2}[/tex]

Explanation:

From Newton's law of universal gravitation,

F = [tex]\frac{GMm}{R^{2} }[/tex] .............. 1

and from Newton's second law of motion,

F = mg ........... 2

Equating the two expression,

mg = [tex]\frac{GMm}{R^{2} }[/tex]

g = [tex]\frac{GM}{R^{2} }[/tex]

Given that: mass of Venus = 4.87 x [tex]10^{24}[/tex] Kg, radius = 6.05 x [tex]10^{6}[/tex] and G = 6.67 x [tex]10^{-11}[/tex] N[tex]m^{2} Kg^{-2}[/tex]

Thus;

g = [tex]\frac{6.67*10^{-11}*4.87*10^{24} }{(6.05*10^{6} )^{2} }[/tex]

  = [tex]\frac{3.24829*10^{14} }{3.66025*10^{13} }[/tex]

 = 8.87450

g = 8.9 m/[tex]s^{2}[/tex]

the acceleration of gravity on the surface of Venus is 8.9 m/[tex]s^{2}[/tex].

HELP ASAP!!!

Which graph shows the change in velocity of an object in free fall?

Answers

Answer:

the graph that show Change in velocity is no A

The graph that showing the velocity with respect to time for a free falling body is figure C where, the downward velocity will be higher due to the acceleration due to gravity.

What is velocity?

Velocity of a moving body is the measure of the distance covered per unit time. Thus, it is the ratio of distance to the time. Velocity is expressed in the units of Km/h, m/s. miles/h, ft./s etc.

The rate of change of velocity is called acceleration. The acceleration by the force of a gravitational field is called acceleration due to gravity g having the value 9.8 m/s².

The velocity - time graph shows a diagonal relation for a free falling body. A free falling body is initially at rest and falls downward with the negative velocity with the acceleration due to gravity. Therefore, figure B shows the change in velocity of a free falling body.

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A ball of mass 0.600 kg is carefully balanced on a shelf that is 2.20 m above the ground. What is its gravitational potential energy?

Answers

Answer:

Explanation:

Gravitational potential energy = mass x height of object x g

g is gravitational acceleration .

Gravitational potential energy of the ball = .600 x 2.20 x 9.8

= 12.936 J .

12.9 J .

what is primary purpose of Pathfit?​

Answers

Answer:

to show the arts and creativity of the person and to show also the culture of the place..

Explanation:

A block with a mass M = 4.85 kg is resting on a slide that has a curved surface. There is no friction. The speed of the block after it has slid along the slide sufficiently far for its vertical drop to be 19.6 m is:__________a. 19.6 m/s b. 384 m/s c. 93 m/s d. 43.2 m/s e. The problem cannot be solved because the shape of the curved slide is not given.

Answers

Answer:

The correct option is a

Explanation:

From the question we are told that

   The mass of the block is  [tex]m = 4.84 \ kg[/tex]

    The height of the vertical  drop is [tex]h = 19.6 \ m[/tex]

Generally from the law of energy conservation , the potential energy at the top  of the slide is equal to the kinetic energy at the point after sliding this can be mathematically represented as

        [tex]PE = KE[/tex]

i.e     [tex]m * g * h = \frac{1}{2} * m * v^2[/tex]

=>    [tex]gh = 0.5 v^2[/tex]

=>   [tex]v = \sqrt{\frac{9.8 * 19.6}{0.5 } }[/tex]

=>    [tex]v = 19.6 \ m/s[/tex]

pls help quick. the number line shows the starting and ending velocities for ball 1 what's the change in velocity of ball 1 calculate the value mathematically and check using the number line​

Answers

Answer:

The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.

The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds

a pot of water at 20.0ºC is warmed to 100º when 40000cal is added. what is the mass of the water?

Answers

Answer:

500 g

Explanation:

m = Mass of water

c = Specific heat of water = [tex]1\ \text{cal/g}^{\circ}\text{C}[/tex]

[tex]\Delta T[/tex] = Temperature difference = [tex]100-20=80^{\circ}\text{C}[/tex]

Q = Heat added = 40000 cal

Heat is given by

[tex]Q=mc\Delta T\\\Rightarrow m=\dfrac{Q}{c\Delta T}\\\Rightarrow m=\dfrac{40000}{1\times 80}\\\Rightarrow m=500\ \text{g}[/tex]

The mass of water is 500 g.

In the Bohr model of the hydrogen atom, an electron in the 1st excited state moves at a speed of 2.19 106 m/s in a circular path having a radius of 5.29 10-11 m. What is the effective current associated with this orbiting electron?

Answers

Answer:

I = 1.05x10⁻³ A

Explanation:

By definition, an electric current is the rate of charge flow at a given time:

[tex] I = \frac{q}{t} [/tex]

Where:

q: is the electrons charge = 1.602x10⁻¹⁹ C

t: is the time

In a circular motion, the time is given by:

[tex] t = T = \frac{2\pi}{\omega} = \frac{2\pi}{v/r} = \frac{2\pi r}{v} [/tex]

Where:

ω: is the angular speed = v/r

v: is the speed = 2.19x10⁶ m/s

r: is the radius = 5.29x10⁻¹¹ m

[tex] t = \frac{2\pi r}{v} = \frac{2\pi 5.29 \cdot 10^{-11} m}{2.19 \cdot 10^{6} m/s} = 1.52 \cdot 10^{-16} s [/tex]

Now, the effective current is:

[tex] I = \frac{q}{t} = \frac{1.602 \cdot 10^{-19} C}{ 1.52 \cdot 10^{-16} s} = 1.05 \cdot 10^{-3} A [/tex]  

Therefore, the effective current associated with this orbiting electron is 1.05x10⁻³ A.

I hope it helps you!                                

What is the force used when a 7 kg bowling ball is rolled with an acceleration of 3 m /s2? Use the formula to find the force in Newtons (N): F = 7 kg × 3 m/s2

Answers

Answer:

21 Newtons

Explanation:

Force= mass * acceleration

Force= 7 kg * 3 m/s^2

Force= 21 Newtons

What is the wavelength of light falling on double slits separated by 2.00 μm if the third-order maximum is at an angle of 60.0∘?

Answers

Answer:

λ = 5.773 x 10⁻⁷ m = 577.3 nm

Explanation:

In order to solve this problem we will use the grating equation:

mλ = d Sin θ

where,

m = order = 3

λ = wavelength of light = ?

d = slit separation = 2 μm = 2 x 10⁻⁶ m

θ = angle = 60°

Therefore,

(3)λ = (2 x 10⁻⁶ m)Sin 60°

λ = 1.732 x 10⁻⁶ m/3

λ = 5.773 x 10⁻⁷ m = 577.3 nm

Which term refers to the ability to do work?
o energy
power
force
motion
PLEAEE HURRY IM DOING MY EXAM PLEASE HELP WILL MARK BRAINLIEST​

Answers

Answer:

Energy

Explanation:

work is actually a transfer of energy. When work is done to an object , energy is transferred to that object.

The ability to do work is called energy.

What is work ?

"Work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement."

What is energy ?

"Energy is defined as the “ability to do work, which is the ability to exert a force causing displacement of an object.”  energy is just the force that causes things to move. Energy is divided into two types: potential and kinetic."

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Mr Johnson launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how much time does it take before the arrow hits the ground below (step 1 of a quesiton will need this answer for a future question)
a 2 seconds
b. 1 second
c.4 seconds
d 19.6​

Answers

Answer:c

Explanation:

Which of the following requires the expenditure of more​ work? ​

a. Lifting a 110 newton​ [N] weight a height of 3 meters​ [m].
b. Exerting a force of 60 ​pounds-force ​[lbf​] on a sofa to slide it 30 feet​ [ft] across a room.

Answers

Answer:

The correct answer is option B

Explanation:

Step one:

given data

a. force F= 110N

distance s= 3meters

we know that work= Force* distance

work= 110*3

Work= 330Joules

Step two:

data

Force= 60 pounds

distance= 30 ft

convert pounds to Newton

1 pound= 4.44822N

60 pounds= 60*4.44822

=266.9N

convert ft to meteres

1 ft = 0.3048meter

30ft= 0.3048*30

=9.144N

we know that work= Force* distance

work= 266.9N*9.144N

Work= 2440.53Joules

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2370 Pa greater than atmospheric pressure? The density of glycerine is 1.26X10^3 kg/m^3

Answers

Answer:

So, at the depth of 24 cm below the surface of the glycerine the pressure is  2970 Pa. Hence, this is the required solution.

Explanation:

Given that,

Pressure exerted by the surface of glycerine, P = 2970 Pa and it is greater than atmospheric pressure.

The density of glycerine,  

We need to find the depth h below the surface of the glycerine. The pressure due to some depth is given by :

h = 0.24 meters

or

h = 24 cm

Simple physics question, check the document. Should take about 3-5 minutes.

Answers

Answer:

The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N

Explanation:

Forces on block 4.3 kg are:

63N to the right and R21 (contact force from the 6.3 kg block) to the left

Net force on 4.3 kg block is: 63 N - R21

Forces on the 6.3 kg block are:

R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.

So net force on the 6.3 kg block is: R12 - 11 N

According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").

Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:

a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2

solve for R by cross multiplication

6.3 (63 - R) = 4.3 (R - 11)

396.9 - 6.3 R = 4.3 R - 47.3

369.9 + 47.3 = 10.6 R

444.2 = 10.6 R

R = 444.2 / 10.6

R = 41.90 N


Which of the following best describes the circuit shown below?

Answers

Answer:

D

Explanation:

The particle accelerator at CERN can accelerate an electron through a potential

difference of 80 kilovolts. Calculate

(a) The kinetic energy (in keV) of the electron​

Answers

Answer:

K.E = 1.28 × 10^-17 KeV

Explanation:

Given that a particle accelerator at CERN can accelerate an electron through a potentialdifference of 80 kilovolts.

To Calculate the kinetic energy (in keV) of the electron​, let us first find the electron charge which is 1.60 × 10^-19C

The kinetic energy = work done

K.E = e × kV

Substitute e and the voltage into the formula

K.E = 1.60 × 10^-19 × 80

K.E = 1.28 × 10^-17 KeV

Therefore, the kinetic energy is approximately equal to 1.28 × 10^-17 KeV

The chemical equation below shows that hydrogen and oxygen chemically react to form water.



Which of these is true?

A.

Water is a pure substance and has the same properties as oxygen.


B.

Water is a pure substance and has the same properties as hydrogen.


C.

Hydrogen and oxygen are pure substances that have identical properties to each other.


D.

Hydrogen, oxygen, and water are pure substances that each have different properties.

Answers

Answer:

D

Explanation:

Hydrogen, oxygen, and water are pure substances that each have different properties.

Although the 3 of them are pure substances, but they nonetheless have different properties. These properties could either be their physical properties, or their chemical properties. This is particularly so because since Oxygen and Hydrogen the major components in water have different properties, it is only right if their product, water, has different properties also.

Answer:

D

Explanation:

got it right on study island

what are the formulae of momentun and their time of use​

Answers

Answer:

???????????????????????????

If a 46 kg person walks up two floors in the Physics building (about 10 meters up), this person's potential energy has increased by _____ J.a. 1400 J b. 10,000 J. c. 1000 J. d. 100 J

Answers

Answer:

B. 10000 J

Explanation:

The possible answers are not related to the statement at all. The correct statement is:

If a 100 kg person walks up two floors in the Physics building (about 10 meters up), this person's potential energy has increased by:

From definitions of work and gravitational potential, we get the following formula to calculate the change experimented in the person's potential energy after walking up two floors in the Physics building:

[tex]\Delta U_{g} = m\cdot g \cdot \Delta z[/tex] (1)

Where:

[tex]\Delta U_{g}[/tex] - Change in the gravitational potential energy, measured in joules.

[tex]m[/tex] - Mass of the person, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta z[/tex] - Change in height, measured in meters.

If we know that [tex]m = 46\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta z = 10\,m[/tex], then the change in the gravitational potential energy is:

[tex]\Delta U_{g} = (100\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (10\,m)[/tex]

[tex]\Delta U_{g} = 9807\,J[/tex]

The choice that best approximates this answer is B.

What is the force of a 1500 kg car accelerating at 45 m/s2 ?

Answers

Answer:

67500

Explanation:

F=ma

F = 1500 × 45

F = 67500

You are lifting a 10 kg block straight up at a constant speed of 10 m/s. How much force are you exerting on the block?

Answers

Answer:

The force exerted is [tex]F = 100 \ N[/tex]

Explanation:

From the question we are told that

   The mass of the block is [tex]m_b = 10 \ kg[/tex]

    The speed is  [tex]v = 10 \ m/s[/tex]

Generally the force exerted to lift the object at constant speed is equivalent to the wight of the ball, this is mathematically represented as

       [tex]F = m * g[/tex]      Here  [tex]g = 10 \ m/s^2[/tex]

=>    [tex]F = 10 * 10[/tex]

=>    [tex]F = 100 \ N[/tex]

The force are you exerting on the block when the block is lifting straight up with constant speed is 98 N and this can be determined by using the given data.

Given :

You are lifting a 10 kg block straight up at a constant speed of 10 m/s.

The following steps can be used in order to determine the force are you exerting on the block:

Step 1 - According to the given data, the block is lifting straight up at a constant speed. So, the acceleration is zero.

Step 2 - So, the only force exerted on the block is the weight of the block.

Step 3 - So, the force are you exerting on the block is given by:

F = mg

F = 10 [tex]\times[/tex] 9.8

F = 98 N

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The flywheel of an engine has moment of inertia 1.9 kg m2 about its rotation axis. What constant torque is required to bring it up to an angular speed of 537 rev/min in 6.78 s, starting from rest, in N-m

Answers

Answer:

τ = 15.76 N-m

Explanation:

For rigid bodies, the net external torque acting on a rotating body, is equal to the product of the moment of inertia about its rotation axis, times the angular acceleration of the body, as follows:

        [tex]\tau = I * \alpha (1)[/tex]

Since I is a given of the question, we need to find out the angular acceleration.By definition, the angular acceleration is the rate of change of the angular velocity with respect to time:α = Δω/Δt = (ωf-ω₀) / (tfi-t₀)Since ω₀ = 0, and choosing t₀ =0, as tfi is a given, we need just to find out ωf.We have this value  in rev/min, so we need first to convert it to rad/sec, as follows:

       [tex]537 rev/min * (1min/60 sec)*(2*\pi *rad/rev) = 17.9 * \pi rad/sec (2)[/tex]

Replacing in the definition of α, we have:α = 17.9*π rad/sec / 6.78 s = 8.29 rad/sec²Replacing I and α in (1), we finally get:

       τ = 15.76 N-m.

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