The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change.

Answers

Answer 1

The given question is incomplete. The complete question is:

The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change:

A. [tex]K(s)+O_2(g)\rightarrow KO_2(s)[/tex]

B. [tex]CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)[/tex]

C. [tex]CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)[/tex]

D. [tex]N_2O_2(g)\rightarrow 2NO(g)+O_2(g)[/tex]

Answer: A. [tex]K(s)+O_2(g)\rightarrow KO_2(s)[/tex] : decreases

B. [tex]CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2(g)[/tex] : decreases

C. [tex]CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)[/tex]: no change

D. [tex]N_2O_2(g)\rightarrow 2NO(g)+O_2(g)[/tex] : increases

Explanation:

Entropy is defined as the randomness of the system.

Entropy is said to increase when the randomness of the system increase, is said to decrease when the randomness of the system decrease and is said to have no change when the randomness remains same.

In reaction [tex]K(s)+O_2(g)\rightarrow KO_2(s)[/tex], as gaseous reactant is changed to solid product, entropy decreases.

In reaction [tex]CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)[/tex], as 4 moles of gaseous reactants is changed to 2 moles of gaseous product, entropy decreases.

In reaction [tex]CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)[/tex], as 3 moles of gaseous reactants is changed to 3 moles of gaseous product, entropy has no change.

In reaction  [tex]N_2O_2(g)\rightarrow 2NO(g)+O_2(g)[/tex] , as 1 mole of gaseous reactant is changed to 3 moles of gaseous product, entropy increases.


Related Questions

Of the three layers of the biosphere, which one is inhabited by jellyfish?

Answers

Answer:

Hydrosphere

Explanation:

The biosphere simply refers to the zone of life found on earth. It refers to the portion of the earth inhabited by living things.

The biosphere is divided into three, namely; hydrosphere, atmosphere and lithosphere.

The atmosphere is simply the layer composed of air, the lithosphere is the solid part of the earth while the hydrosphere is the part composed of water.

Since jelly fish is an aquatic animal, it will certainly inhabit the hydrosphere. Hence the answer above.

4. Which employees should be aware of how to turn off power to a shop in an emergency?

Answers

Answer:

All employees should know how to work the system

Where could convection currents form?

A. in a sand dune
B. on a pavement
C. in the atmosphere
D. in outer space
IM TIMED PLS HELP

Answers

A is correct brace sand can whirl

Answer:

D. In the atmosphere

Explanation:

convection currents forms in the atmosphere

A 6.32L balloon is filled with air at 25.1°C. If the balloon is heated to 100 °C, what will be the new volume of the balloon

Answers

Answer:

7.90

Explanation:

Gay-Lussacs law states that P1/T1 = P2/T2

if:

P1 = 6.32

T1 (in Kelvins) = 25.1 + 273.1 =298.2

P2= ?

T2 = 100 + 273.1 = 373.1

so

6.32/298.2 = P2/373.1

P2 = 7.90

A man receives a platinum ring from his fiancee. Before the wedding, he notices that the ring feels a little light for its size and decides to measure its density. He places the ring on a balance and finds that it has a mass of 3.15 grams. He then finds that the ring displaces 0.233 cm3 of water. Given that the density of pure platinum is 21.4 g/cm3, is this ring genuine

Answers

Answer:

The ring is probably not geniune.

Explanation:

To solve this problem we first need to calculate the density of the ring:

Density = mass / volume

The mass is given by the problem, and we're able to assess the volume by keeping in mind Archimede's principle (the volume of water displaced by an object is equal to the object's volume).

Ring density = 3.15 g / 0.233 cm³ = 13.5 g/cm³

Given that the ring density is significantly lower than the density of pure platinum, the ring is probably not geniune.


What is the Molarity of a 2 liter solution containing 43.55 grams of K2504?

Answers

Answer:

M =  0.125 M

Explanation:

Given data:

Molarity = ?

Volume of solution = 2 L

Mass of K₂SO₄ = 43.55 g

Solution;

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of solute:

Number of moles = mass/molar mass

Number of moles = 43.55 g / 174.26 g/mol

Number of moles = 0.25 mol

Molarity:

M =  0.25 mol / 2 L

M =  0.125 M

Which change will produce a new substance?
Heating water until freezes
Cooling water until freezes
Burning a piece of wood
Dissolving sugar in water

Answers

Cooling water until it freezes
Cooling water until freezes is correct

An unknown compound is processed using elemental analysis and found to contain 117.4g of platinum 28.91 carbon and 33.71g nitrogen how many moles of platinum are present

Answers

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

an unknown substance has a mass of 57.4 g and occupies a volume of 34.3 ml. what is the density in g/ml?

Answers

Answer: 1.67

D=M/V

(D=57.4/34.3)= 1.67

Please help me thanks!?!?!?

Answers

Answer:

its burning

Explanation:

can you please try to answer my latest question i need it badly please and thank you

Answer:

Burning.

Explanation:

Example:

Wood burns and produces smoke and ash.

application of baking powder​

Answers

Baking powder is used to increase the volume and lighten the texture of baked goods. It works by releasing carbon dioxide gas into a batter or dough through an acid–base reaction, causing bubbles in the wet mixture to expand and thus leavening the mixture.

helpppp nowwww plssss!!!

Answers

Answer: B

Explanation:

To make the future development more eco-friendly and decrease water pollution from run-off, choose one of the following recommendations:

construct using only recycled materials
create gardens on all of the rooftops
install solar panels on every new building

Answers

Answer:

construct using only recycled materials ^^

Explanation:

Please help me thanks so much?!?!?

Answers

Answer:

color

Explanation:

Answer:

D

Explanation:

The five conditions of chemical change: color chage, formation of a precipitate, formation of a gas, odor change, temperature change and the others are just physical changes that would happen if you change containers, or let it evaporate.

Combien y-a-t-il d'atomes grammes de zinc (Zn) dans 32,7 g de Zn?​

Answers

How many grams of zinc (Zn) are in 32.7 g of Zn?

Answer:

32.7g

Explanation:

The mass of Zinc in the given substance is 32.7g.

Mass is the quantity of matter contained in a substance. The sum total of the amount of matter is the mass.

Since this problem gives us 32.7g of Zn then the substance will also contain 32.7g of Zinc.

Even when the Zinc is used in chemical reactions, we are expected to produce an equal amount of zinc as the product.

This way, mass is always conserved.

1.81 g H2 is allowed to react with 10.2 g N2, producing 2.19 g NH3.What is the theoretical yield in grams for this reaction under the given conditions?
3H2(g)+N2(g)→2NH3(g)

Answers

The theoretical yield : = 10.251 g

Further explanation

Given

Reaction

3H₂(g)+N₂(g)→2NH₃(g)

1.81 g H₂

10.2 g N₂

2.19 g NH₃

Required

The theoretical yield

Solution

Find limiting reactant :

H₂ : 1.81 g : 2 g/mol = 0.905 mol

N₂ : 10.2 g : 28 g/mol = 0.364 mol

mol : coefficient

H₂ = 0.905 : 3 = 0.302

N₂ = 0.364 : 1 = 0.364

H₂ as a limiting reactant(smaller ratio)

Moles NH₃ based on H₂, so mol NH₃ :

= 2/3 x mol H₂

= 2/3 x 0.905

=0.603

Mass NH₃ :

= mol x MW

=0.603 x 17 g/mol

= 10.251 g

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Answers

Answer:

The sun will appear to rise and set more slowly

have a nice day! (^o^)

A 1.0 mol sample of he(g) at 25 is mixed with a 1.0 mol sample of Xe(g) at 50 C. What would be the changes in average kineeteic energy and the average speed of the Xe atoms that will occur as the mixture approaches thermal equilibrium?

Answers

Answer:

Explanation:

The average kinetic energy for an ideal gas is directly proportional to the temperature. The average kinetic energy of the gas is a measure of the temperature of the gas molecule

Also, the average speed is usually proportional to the square root of temperature.

Similarly, there is a noticeable increase in K.E and speed in regard to temperature but sometimes it is not usually proportional.

However, provided that there is more temperature in Xe as compared to He, then after the mixture of both takes place at equilibrium; the temperature tends to fluctuate between (25 - 50)°C

Thus, since there is a decrease in temperature in Xe, both the average kinetic energy as well as the speed too will also decrease.

How do you figure out the # of
neutrons?

Answers

Answer:

Subtracting the number of protons from the atomic mass.

Answer:

Subtract Protons

Explanation:

Since the vast majority of atom's mass is found it's protons and neutrons, Subtracting the Number of Protons ( i.e. the atomic number ) from the atomic mass will give you the calculated number of neutrons in a atom,

I DONT NEED THE ANSWER JUST PLEASE TELL ME HOW TO DO THIS PLEASE, ITS DUE AT 12. BRAINLIEST. 15 POINTS!
Copper (II) chloride has a molar mass of 134.452 g/mol. What is the mass of 2.17 moles?

Answers

Answer:

292 g

Explanation:

Step 1: Given data

Molar mass of copper (II) chloride (M): 134.452 g/molMoles of copper (II) chloride (n): 2.17 molMass of copper (II) chloride (m): ?

Step 2: Calculate the mass corresponding to 2.17 moles of copper (II) chloride

We will use the following expression.

m = n × M

m = 2.17 mol × 134.452 g/mol = 292 g

2.17 moles of copper (II) chloride weigh 292 g.

helppp nowwww please!!!!

Answers

Answer:

The sun will appear to rise and set more slowly

have a nice day! (^o^)

How does heat travel?

1. From cold things to hotter things
2. From hot things to colder things
3. Between things of the same temperature

Answers

Answer:

well heat travels by conduction, convection, and radiation but I think it's 2.

Explanation:

heat travels to colder things trying to make a balanced temperature for both of the objects.

Suppose you heat a metal object with a mass of 31.7 g to 96.5 oC and transfer it to a calorimeter containing 100.0 g of water at 17.3 oC. The water and metal reach a final temperature of 24.6 oC. What is the specific heat of the metal in J/g-oC?

Answers

Answer: The specific heat of the metal in [tex]1.34J/g^0C[/tex]

Explanation:

[tex]Q_{absorbed}=Q_{released}[/tex]

As we know that,  

[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]

[tex]m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)][/tex]      

where,

[tex]m_1[/tex] = mass of metal = 31.7 g

[tex]m_2[/tex] = mass of water = 100.0 g

[tex]T_{final}[/tex] = final temperature = [tex]24.6^oC[/tex]

[tex]T_1[/tex] = temperature of metal = [tex]96.5^oC[/tex]

[tex]T_2[/tex] = temperature of water = [tex]17.3^oC[/tex]

[tex]c_1[/tex] = specific heat of metal= ?

[tex]c_2[/tex] = specific heat of water =  [tex]4.184J/g^0C[/tex]

Now put all the given values in equation (1), we get

[tex]m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)][/tex]

[tex]-(31.7\times c_1\times (24.6-96.5)^0C)=(100.0\times 4.184\times (24.6-17.3)][/tex]

[tex]c_1=1.34J/g^0C[/tex]

Therefore, the specific heat of the metal in [tex]1.34J/g^0C[/tex]

If the caffeine concentration in a particular brand of soda is 2.57 mg/oz, drinking how many cans of soda would be lethal

Answers

The lethal dose and how ounces of soda in a can of soda is not given, however, the standard lethal dose and volume of soda are given as below:

Lethal dose: 10 gm of caffeine

The volume of soda per can =  12oz/can

Answer:

The correct answer is - 324.254 cans or round up to 325 cans. Ans.

Explanation:

Given:

2.57 mg caffeine / 1oz

12oz / 1can

Lethal dose: 10.0g or 10,000mg of caffeine

Solution:

Caffeine per soda can = (2.57 mg caffeine / 1oz) * (12oz / 1can) = 30.84 mg caffeine / 1can.

lethal dose would be in =

(10,000mg caffeine) * (1can / 30.84 mg caffeine) = 324.254 cans or round up to 325 cans. Ans.

I need help asap! With 3 and 4 giving brainliest

Answers

Number 3 is option 3

But for number 4 I would need to see the scenario it’s referring to

1. Each substance written to the right of the arrow in a chemical equation is a

(1 point)

O catalyst

O reactant

O precipitate

O product

Answers

Answer: product

Explanation:

Each substance written to the right of the arrow in a chemical equation is referred to as a product.

When writing a chemical equation, the substance that's written to the left of arrow in the equation is the reactants.

On the other hand which is the right side is the product.

a sample of fully saturated clay weighs 1350 g in its natural state and 975 g after drying. what is the natural water content of the soil

Answers

Answer:

The soil has a percentage of water by mass of 27.8 %.

Explanation:

Keeping in mind that

Mass of Clay = Mass of water + Mass of Dry Soil

we can calculate the mass of water:

1350 g = Mass of Water + 975 gMass of Water = 375 g

We can then calculate the mass percentage of water in the soil:

375 / 1350 * 100% = 27.8 %

100%
Normal text
Merriweath...
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6. What is the mass, in grams, of 1.92 moles of Ca(OH),?

Answers

Answer:

Mass =  142.25 g

Explanation:

Given data:

Mass of Ca(OH)₂ = ?

Number of moles of Ca(OH)₂ = 1.92 mol

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of Ca(OH)₂ = 74.09 g/mol

by putting values,

Mass = 1.92 mol × 74.09 g/mol

Mass =  142.25 g

When a precipitation reaction occurs, the ions that do not take part in the reaction are called
A.non participants
B.useless ions
C.independent variables
D.spectator ions

Answers

Answer:

D. spectator ions.

Explanation:

Hello!

In this case, when going over net ionic equations by which precipitation reactions are analyzed, we can consider the example of lead (II) nitrate with potassium iodide to yield insoluble lead (II) iodide and soluble potassium nitrate according to:

[tex]2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)[/tex]

Whereas aqueous species remain in solution:

[tex]2K^+(aq)+2I^-(aq)+Pb^{2+}(aq)+2(NO_3)^-(aq)\rightarrow PbI_2(s)+2K^+(aq)+2(NO_3)^-(aq)[/tex]

It means that potassium and nitrate ions are spectator ions because they are not involved in the precipitation reaction, which is represented by the net ionic one:

[tex]2I^-(aq)+Pb^{2+}(aq)\rightarrow PbI_2(s)[/tex]

Thus, the answer to this question is D. spectator ions.

Best regards!

A student prepares a 100.0 mL solution using 44.7 grams of potassium nitrite. They then take 11.9 mL of this solution and dilute it to a final volume of 200.0 mL. How many grams of potassium nitrite are in a 19.7 mL sample of this final diluted solution?

Answers

Answer:

0.52 g of KNO₃ are contained in 19.7 mL of diluted solution.

Explanation:

We can work on this problem in Molarity cause it is more easy.

Molarity (mol/L) → moles of solute in 1L of solution.

100 mL of solution = 0.1 L

We determine moles of solute: 44.7 g . 1mol /101.1 g = 0.442 mol of KNO₃

Our main solution is 0.442 mol /0.1L = 4.42 M

We dilute: 4.42 M . (11.9mL / 200mL) = 0.263 M

That's concentration for the diluted solution.

M can be also read as mmol/mmL, so let's find out the mmoles

0.263 M . 19.7mL = 5.18 mmol

We convert the mmol to mg → 5.18 mmol . 101.1 mg / mmol = 523.7 mg

Let's convert mg to g → 523.7 mg . 1 g / 1000 mg = 0.52 g

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