Answer:
D
Storage of water
Explanation:
the vacuole stores water, if it is damaged then it can store anything.
A plant cell's central vacuole has been harmed. The function largely impacted by the deterioration is water storage. Option D is correct.
What is a plant cell?The smallest unit of all plants in the cell. Like animal cells, plant cells are eukaryotic, which means they have an organelle- and membrane-bound nucleus.
This turgor pressure maintains the cell's rigidity and gives plant structures like leaves their distinctive shapes.
When a plant goes for an extended period of time without water, the central vacuoles lose water, the cells deform, and the entire leaf wilts.
The central vacuole of a plant cell is damaged. Storage of water is the function that is most affected by the damage.
Hence, option D is correct.
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Pierre cycles at 4 miles per hour and travels a distance of 13 miles. How long
does his journey take?
Answer:
His journey took him 3 hours 15 minutes.
Explanation: 4 miles every hour. So 1 hr is equal to 4 miles, 2 hrs is equal to 8 miles, 3 hrs is equal to 12 miles. Now he just has 1 miles left, and since it takes him a hour to cycle 4 miles, 60 divided by 4 is 15. Therefore, 1 mile is equal to 15 minutes.
Time = (distance) / (speed)
Time = (13 mi) / (4 mi/hr)
Time = 3.25 hr or 3hr 15min .
Tell me about your favorite science experiment. Give me a detailed account of the experiment and what you like about it.
Answer:
nngh have
bjruh hjrhhj be rnrnnrnrnnnrnjrjnnnnnnnnrnrn n n and I was nrn
Explanation:
jbbbbbhhhjjnnnnnnnnnnjhvcc
Explanation:
Define the problem. Look around your house or outside. Is there anything that you're wondering about or have questions about?
Answer:
Water
Explanation:
How do we have water at our disposal, like that's crazy.
If our frame of reference was the sun would the earth be moving?
Answer:
yes, thats how it becomes morning and night
u get it
Explanation:
When you stand outside your are standing in the, Stratosphere. Troposphere. Mesosphere no
A car travels north along a straight highway at an average speed of 85 km/h. After driving 2.0 km, the car passes a gas station and continues along the highway. What is the car’s position relative to the start of its trip 0.25 h after it passes the gas station?
Answer:
x_total = 23250 m
Explanation:
This is a uniform motion exercise, the equation that describes the motion is
v = x / t
the position is
x = v t
let's reduce the magnitude to the SI system
v = 85 km / h (1000 m / 1km) (1h / 3600 s) = 23.61 m / s
t = 0.25 h (3600 s / 1h) = 900 s
let's calculate
x₁ = v t₁
x₁ = 23.61 900
x₁ = 21250 m
The distance from the origin is
x_total = x_station + x₁
x_total = 2000 + 21250
x_total = 23250 m
Question 5 of 10
Which option is an example of a conceptual model?
A. A clay ball with a slice cut out, showing the layers of Earth
B. A mental image of gas molecules as tiny balls
C. A diagram of a flagpole and its shadow with measurements
provided to calculate the length of the shadow
D. A weather map created by Doppler radar
Answer:
B. A metal image of gas molecules as tiny balls
Answer:
B. A mental image of gas molecules as tiny balls
As a shuttle bus comes to a normal stop, it slows from 9.00 m/s to 0.00 m/s in 5.00 s find the acceleration of the bus.
Answer:
-1.8 m/s^2
Explanation:
vf-vi/t
0-9=-9
-9/5 = -1.8
-1.8 m/s^2
examples of electrostatic force
Answer:
When we run a piece of paper with the oil in our head with the help of a comb produces electrostatic force.
Balloons get attracted to another balloon when one of them are rubbed with hair.
Explanation:
Those are 2 examples of electrostatic force.
aroma of perfume is solid or liquid or gas?
16. Which of the following is equivalent to 36 km/hr?
a. 10 m/s
b. 10 cm/s
c. 36 m/s
d. 36 mph
A car drives 30 meters north, then turns around and drives 50 meters south. What was its distance?
Answer:
The total distance moved by the car is 80 metres
Explanation:
Given
North = 30 meters
South = 50 meters
Required
Determine the distance
Distance is a scalar quantity and hence, the total distance is the summation of distance moved in both directions
i.e.
[tex]Total\ Distance = North + South[/tex]
[tex]Total\ Distance = 30\ metres + 50\ metres[/tex]
[tex]Total\ Distance = 80\ metres[/tex]
Hence;
The total distance moved by the car is 80 metres
A man weighs 90 N on the surface of earth of radius R at what height above the surface of earth is weight will be 40 N.
Answer:
3/2 R
Explanation:
Let the Mass of man be m, Mass of earth be M.
By Newtons, law of gravitation,
F = GMm/R^2, Where G is gravitational constant
90 = GMm/R^2
When man weighs 40N,
GMm/(New R)^2 = 40
= 4/9 (90)
GMm/(New R)^2 = 4/9 (GMm/R^2)
(New R)^2 = 9/4 R^2
New R = 3/2 R
Therefore, height is 3/2 R
Sobre un cuerpo de masa 45 kg, se aplica una fuerza (F), la cual produce una aceleración cuya magnitud es 5 m -s2
Answer:
225kgm/s² or 225N
Explanation:
La fórmula de Fuerza = Masa × Aceleración
Masa = 45 kg
Aceleración = 5 m / s²
Fuerza = 45 kg × 5 m / s²
= 225 kgm / s² o 225N
Por lo tanto, la Fuerza que actúa sobre = 225 kgm / s² o 225N
Muscle fibers move back and forth during _____.
Answer:
it must move back and forth during sex
Three remote control cars are identical size and weight. The motors installed in the three cars are 100 watts, 150 watts and 200 watts respectively. Describe what will be true about the maximum speed of each car? Explain.
Answer:
The true statement about the maximum speed of each car will be that the power of each car directly proportional to the speed of each car.
Explanation:
Given that,
Power of first car = 100 watt
Power of second car = 150 watt
Power of third car = 200 watt
We know that,
Power :
The power is directly proportional to the cube of speed.
In mathematically,
[tex]P\propto v^3[/tex]
Where, P = power
v = speed
If the power is increased then the speed will be increase.
We need to find the maximum speed of car
According to question,
The power of car is maximum so the speed of car will be maximum.
For first car,
The power of first car is 100 watt.
So, the speed of first car will be 1000000 m/s.
For second car,
The power of second car is 150 watt.
So, the speed of second car will be 3375000 m/s.
For third car,
The power of third car is 200 watt.
So, the speed of first car will be 8000000 m/s.
Hence, The true statement about the maximum speed of each car will be that the power of each car directly proportional to the cube of speed of each car.
What is groups of organs that work together to complete a process in the body
Answer:
A System
Explanation:
There are many systems including the circulatory and nervous system where multiple organs work together to perform a job.
Which is not a piece of evidence that most scientists use to prove the origin of our universe?
A. Movement of the galaxies (expansion)
B. Cosmic microwave background
C. Presence of hydrogen and helium in the
correct percentages throughout the
universe
D. The contraction of objects in space
Answer:
D) The contraction of objects in space
Explanation:
A) Expansion of the universe as originated from the Big Bang is an important evidence, as B) the Cosmic microwave background which is thought to be left over from the Big Bang. The right proportion of hydrogen and helium as unprocessed material that has been detected as the basic elements from where the universe started.
The only out of context option is option D
Tony completed a 720 km journey with an average speed of 90 km for the first 285 km he travel about an average speed of 95 km what was the average speed for the remaining journey
Answer:
87 km/h
Explanation:
720/90=8 8 Hours
285/95=3 3 hours
720-285=435 436 km left
8-3=5 5 hours left
435/5=87
87 km/H
what is the spherical mirror
Explanation:
A mirror with a surface that is either concave or convex and forms a portion of a true sphere.
Answer:
Spherical Mirror:Definition:
A mirror whose polished, reflecting surface is a part of a hollow sphere of either glass or plastic is called a spherical mirror.Types:
There are 2 types.Concave MirrorConvex MirrorExplanation:
In a spherical mirror, one of the two curved surfaces is coated with a thin layer of silver followed by the coating of lead oxide. One side of the mirror is opaque while the other side is highly reflecting which acts as a mirror.To minimize damage during a broadside collision __________ speed to put the point of impact behind the passenger section.
Answer:
Positive
Ghhhhhhbn
Ggvbbn
To minimize damage during a broadside collision decrease the speed to put the point of impact behind the passenger section.
What is broadside collision?A broadside collision happens when the front of one vehicle bangs into the side of another, usually at a high rate of speed. Although catastrophic injuries can occur in any automobile accident on the road, broadside crashes are especially dangerous.
This is due to the fact that there is not much room or protection between the person inside the hit automobile and the moment of contact. The injury happens to the vehicles depends on their speed.
As the speed is reduced, many such collisions can stopped in time and we can prevent broadside collision as well and giving enough time to pass other vehicles through the intersection.
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Q1: A cyclist brakes to a stop. His thinking distance was 1m and his braking distance was 3m. What was his overall stopping distance?
Q2: A car driver notices that there is a red light coming up. He brakes and stops in a total distance of 52 metres. If his thinking distance was 15 metres, what was his braking distance?
Q3: A car takes 76 metres to stop once a driver has noticed a hazard. If the thinking distance of the driver was 14m and the speed of the car was 8m/s how long did it take the brakes to slow the car down to a stop?
Q4: A lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver’s reaction time?
Q5: Car 1 brakes to a stop on a dry road. Car 2 does the same thing, at the same speed, on a road where it has been raining.
Answer:
1.) 4m
2.) 37 m
3.) 62m
4.) 2.5 s
Explanation:
1.) Given that the
Thinking distance = 1m
Breaking distance = 3m
Stopping distance = breaking distance + thinking distance
Stopping distance = 1 + 3 = 4m
2.) Given that the
Stopping distance = 52 m
Thinking distance = 15m
Breaking distance = 52 - 15 = 37m
3.) The stopping distance = 76m
Thinking distance = 14m
Breaking distance = 76 - 14 = 62m
It take the brakes 62m to slow the car down to a stop.
4.) Given that a lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver’s reaction time?
Thinking = stopping distance - braking distance
Thinking distance = 28 - 18 = 10m
Speed = distance/time
4 = 10/reaction time
Reaction time = 10/4
Reaction time = 2.5 s
5.) Question incomplete
Which are true of meiosis but not mitosis? Select three options. A.It generates genetically different cells. B.It generates haploid cells. C.It involves prophase, metaphase, anaphase, and telophase. D.It involves two rounds of nuclear division. E.It begins with a diploid cell.
Answer:
(A) (b) (D)
Explanation:
Answer:
A B D
Explanation:
You are driving at 25 m/s with your cruise control on when you see a fallen tree in the road. It takes you 0.30 s to put on the brakes, your car decelerates at a rate of 5.0 m/s2, and the tree is 75 m ahead. Will you hit the tree? Choose the correct answer and reason below.
Explanation:
Given data
velocity v= 25m/s
The time it takes to put on brake t= 0.3s
the distance covered when the brake was put on is
v=s/t
s= v*t
s= 25*0.3s
s= 7.5m
hence the distance covered is 7.5m
Also the rate of decrease in aceleration is 5m/s^2
we can also calculate the distance covered at this rate
v^2=u^2+2as
25^2= 0+2*5*s
625=10s
divide both sides by 10
s=625/10
s= 62.5m
The total distance covered between putting on the brakes and decelareation is 7.5+62.5= 70m
Given that the tree is 75m ahead, the car would not hit the tree
a parking lot is going to be 60m wide and 240m long which dimensions could be used please please help
Answer: The area of the parking lot is 14,400 meters squared.
Explanation:
We have the dimensions of the parking lot.
60m by 240m
The units used here are meters.
Now, if we want to know the area of the parking lot is equal to the product between the length and the width:
A = 60m*240m = 14,400 m^2
The area of the parking lot is 14,400 meters squared.
Answer:
A = 20x80
Explanation: DID IT ON APEX
why do the kites and eagles fly without flapping their wings?
Answer:
because they both have large area to capture air
Answer:
Because they have a large surface area to capture moving air when going at a certain speed.
Explanation:
When your trying to fly a kite and the wind isn't that much, you have to run so that the kite can come in contact with the fast moving air which pushes the kite to go up. Just like a eagle because when a eagle is trying to fly, it has to first flap its wings to push air downwards so that it can create lift and at a certain altitude, the eagle doesn't have to flap it's wings though it tilts its body downwards a little so that gravity can do the work, so the eagle is basically gliding downward.
GIVING BRAINLIST PLZ HELP The steps below identify the part of the process to become a U.S. citizen, the naturalization process. Use the steps below to answer the following question. 1. Be a legal resident in the U.S. for at least 5 years. 2. Complete an application 3. ? 4. Take the Oath of Allegiance What is missing in the process above? A: Register for Selective Service System B: Interview and pass civics test C: Complete a background check D: Receive an appointment letter is da correct answer B
Answer:
Yes the correct answer is B
Explanation:
Calculate the speed for each segment on the graph include the units (m/s). Show your calculations, (such as 4/2= 2 m/s)
a. (t=0-10s)
b. (t=10-15s)
c. (t=15-30s)
d. (t=30-40s)
e. (t=40-55s)
Answer:
v_A = 6 m/s , v_B = 0 m/s , v_C = - 4 m/s , v_D = -4 m/s , v_E = 2.66 m / s
Explanation:
For this exercise we use the definition of average velocity in each segment
v_average = (x₂-x₁) / Δt
segment A of the graph you take the value of distance and time
x₁ = 0 m t₁ = 0 s
x₂ = 60 m t₂ = 10 s
using the average velocity equation and calculate
v_A = (60-0) / (10-0)
v_A = 6 m / s
Segment B
x₁ = 60m
x₂ = 60 m
since the displacement variation is zero (particle stopped) the velocity is zero
v_B = 0 m / s
Segment C and D
x₁ = 60 m t1 = 15 s
x₂ = -40 m t2 = 40 s
v_C = (-40 -60) / (40 -15)
v_C = - 4 m / s
Segment D
how is the same line
v_D = -4 m / s
Segment E
x₁ = -40 m t₁ = 40 s
x₂ = 0 m t₂ = 55 s
v_E = (0- (-40)) / (55 -40)
v_E = 2.66 m / s
Does a free falling object fall 2 meters in twice the time as it falls 1 meter? Why? a. Yes, it takes twice as long to fall twice as far. b. Yes, it takes longer to fall farther. c. No, since it is speeding up as it falls it will cover the same distance in a shorter time. d. No, it takes the same time since it does not accelerate.
My answer to the question is option B.
Complete the statements using data from Table A of your Student Guide. The speed of the cart after 8 seconds of Low fan speed is cm/s. The speed of the cart after 3 seconds of Medium fan speed is cm/s. The speed of the cart after 6 seconds of High fan speed is cm/s.
Answer:
8 seconds = 72cm
3 seconds = 36cm
6 seconds = 96cm
Explanation:
lab assignment i just took.
Speed is the rate of distance over time. The speed of the cart is as follows:
[tex]72cms^{-1}[/tex] at 8 seconds.[tex]36cms^{-1}[/tex] at 3 seconds.[tex]96cms^{-1}[/tex] at 6 seconds.Let:
[tex]s \to[/tex] speed
[tex]d \to[/tex] distance
[tex]t \to[/tex] time
After 8 seconds
For low fan speed; the distance (d) at 8 seconds is:
[tex]d =576cm[/tex]
Speed (s) is calculated using:
[tex]s = \frac dt[/tex]
[tex]s = \frac{576cm}{8s}[/tex]
[tex]s = 72cms^{-1}[/tex]
Hence, the speed after 8 seconds is [tex]72cms^{-1}[/tex]
After 3 seconds
For medium fan speed; the distance (d) at 3 seconds is:
[tex]d = 108cm[/tex]
The speed (s) is :
[tex]s = \frac dt[/tex]
[tex]s = \frac{108cm}{3s}[/tex]
[tex]s = 36cms^{-1}[/tex]
Hence, the speed after 3 seconds is [tex]36cms^{-1}[/tex]
After 6 seconds
For high fan speed; the distance (d) at 6 seconds is:
[tex]d = 108cm[/tex]
The speed (s) is :
[tex]s = \frac dt[/tex]
[tex]s = \frac{576cm}{6s}[/tex]
[tex]s = 96cms^{-1}[/tex]
Hence, the speed at 6 seconds is [tex]96cms^{-1}[/tex]
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