The burning of a 0.37 g potato chip causes the temperature of 58.18 g of water in a soda can calorimeter to increase from 21.5℃ to 28.1℃. Calculate the amount of heat absorbed by the water. The specific heat of water is 4.184 J/g⋅℃. Express this answer in both Joules and Nutritional Calories.

Answers

Answer 1

The amount of heat absorbed by the water is 1606.6 J (383.99 Calories )

We'll begin by calculating the change in the temperature of the water.

Initial temperature (T₁) = 21.5 °C

Final temperature (T₂) = 28.1 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 28.1 – 21.5

ΔT = 6.6 °C

Finally, we shall determine the heat absorbed by the water. This can be obtained as follow:

Mass of water (M) = 58.18 g

Change in temperature (ΔT) = 6.6 °C

Specific heat capacity of water (C) = 4.184 J/gºC

Heat absorbed (Q) =?

Q = MCΔT

Q = 58.18 × 4.184 × 6.6

Q = 1606.6 J

Divide by 4.184 to express in Calories

Q = 1606.6 / 4.184

Q = 383.99 Calories

Therefore, the amount of heat absorbed by the water is 1606.6 J (383.99 Calories )

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