Answer:
The magnitude of the normal force on the box is N= m*g + W
Explanation:
According to Newton's Second law and normal force.
The resultant of the forces acting on the person must be equal to the product between the mass and the acceleration a of the person itself.so with the help of Newton's second law
we can write the equation for force:
F = ma
Since,
box is sitting on floor of an elevator.
there are two forces acting on this box:
W due to it's weight (downward) N due to the normal force of the floor against the body (upward).So we can rewrite the previous equation as,
N - W = F
N - W = ma
hence,
N=m*a + W
this is the The magnitude of the normal force on the box.
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A 4.0-kg and a 6.0-kg box rest side-by-side on a perfectly smooth, level floor. A horizontal force of 15 N is applied to the 4.0-kg box pushing it against the 6.0-kg box, and, as a result, both boxes slide along the floor. How hard do the two boxes push against each other
7.5 N against each other
Given the mass of the two boxes are 4 kg and 6 kg
calculate the common acceleration of the two boxes when they join together
F = ma; m = (4 +6)kg and F = 15N
a = F/m
a = 15/10 = 1.5 m/s²
Calculate the impact force of 4 kg box on 6 kg box
F = ma
F = 4 X 1.5 = 6 N
Calculate the force of 5kg box when it accelerate on 1.5m/s²
F = ma
F = 5 X 1.5 = 7.5N
Calculate the opposing force of 5kg box
F = 15N -7.5N = 7.5N
Therefore, each box exerts a force of 7.5 to the other in opposite direction.
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A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its speed is _______ and its acceleration is _______.
Answer:
When X = 0
Speed = maximum V (max) = ω A
Acceleration = zero a(max) = - ω^2 A
From x = A sin ω t sin = 0 so displacement = zero
V = ω A cos ω t cos = 1 and speed = maximum
a = - A ω^2 sin ω t sin = 0 and acceleration = zero
How does the area of triangle rst compare to the area of triangle lmn? the area of △rst is 2 square units less than the area of △lmn. the area of △rst is equal to the area of △lmn. the area of △rst is 2 square units greater than the area of △lmn. the area of △rst is 4 square units greater than the area of △lmn.
The area of △rst is equal to the area of △lmn.
The answer is option B.
Problem-solving is the act of defining a problem; figuring out the purpose of the trouble; identifying, prioritizing, and selecting alternatives for an answer; and imposing an answer.
Problem-solving starts with identifying the issue. As an example, a trainer may need to parent out a way to improve a scholar's overall performance on a writing talent test. To do that, the instructor will overview the writing exams looking for regions for improvement.
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Lexy used the formula shown to calculate the force of gravity on a space shuttle.
Fg = GStartFraction (3 times 10 Superscript 5 Baseline kilograms) (6 times 10 Superscript 24 Baseline kilograms) over [(6.4 times 10 Superscript 6 Baseline m) + (1.8 times 10 Superscript 5 Baseline m)] Superscript 2 EndFraction
What does 3 × 105 kg represent?
the difference between Earth’s mass and the space shuttle’s mass
the sum of Earth’s mass and the space shuttle’s mass
the mass of Earth
the mass of the space shuttle
What 3 × 105 kg represents is the mass of Earth. Option D. This is further explained below.
What does 3 × 105 kg represent?Generally, the absence of discernible form in a huge mass of material
In conclusion, Transportation between Earth and space is accomplished by means of the space shuttle.
It gets people to spaceships in orbit. The mass of the space shuttle is 3108 kg.
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Answer:
D
Explanation:
A gas cylinder contains only the gases radon, nitrogen, and helium. The radon has a pressure of 222 torr while the nitrogen has a pressure of 446 torr. If the total pressure inside the cylinder is 771 torr, what is the pressure that is due to the helium?.
Answer:
103 torr
Explanation:
The remainder is due to the helium
771 - 222 - 446 = 103 torr due to helium
7. Suppose a force of 15 N is required to stretch and hold a spring 0.25 m from its equilibrium position. a. Assuming the spring obeys Hooks law, find the spring constant k. b. How much work is required to compress the spring 0.2 m from its equilibrium position
Spring constant k = 75 N/m
Hooke's law for this spring F(x) = 75x
Work = 1.5 J
What is work?When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work.The amount of work required to move an object down a line from point a to point b in the direction of a variable force F is[tex]$W=\int_{a}^{b} F(x) d x$[/tex]
First solutionAccording to Hooke's law, the spring must be held stretched at x=0.2m by a force of 15N.
F (0.2) = k (0.2 m) = 15 N
Solve for k
k = 75 N/m
Hence, Hooke's law is F(x) = 75x
Second solution
The spring is compressed from x = 0 to X = 0.2,
[tex]$W=\int_{0}^{0.2} 75 x d x=\left.\left(\frac{75 x^{2}}{2}\right)\right|_{0} ^{0.2}$[/tex]
W = 1.5 J
So, the work is required to compress the spring 0.2 m from its equilibrium position W = 1.5 J
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A handball of mass 0.10 kg, traveling horizontally at 30 m/s, strikes a wall and rebounds at 24 m/s. What is the change in the momentum of the ball
The change in momentum of the ball is 0.6Kgm/s.
To find the answer, we need to know about the momentum.
What's the expression of change in momentum during collision?The change in momentum= final momentum - initial momentum of the objectsAnd momentum= mass × velocityHere the initial momentum= 0.10×30=3Kgm/sFinal momentum= 0.10×24= 2.4Kgm/sChange in momentum= 3-2.4= 0.6Kgm/sThus, we can conclude that the change in momentum is 0.6Kgm/s.
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The weight of a person on Earth is 67.0 N. If the gravitational acceleration on the moon is 1.62 m/s2, calculate the person’s weight on the moon.
Group of answer choices
A) 56.0 N
B) 11.0 N
C) 108 N
D) 4.00 N
Answer:
[tex] \large{ \boxed{ \tt{b) \: 11.0 \: N}}}[/tex]- Please see the attached picture for full solution!:)
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The work required to accelerate an object initially at rest to a speed v0 is W. What is the additional work needed to increase its speed from v0 to 2v0? Group of answer choices W W/2 2W 3W None of them
The additional work needed to increase its speed from v0 to 2v0 is D)3W.
Work done is equal to a change in kinetic energy
w = 1/2mv^2-0
= 1/2mv^2
When v is 2v
w new = 1/2*m*(2v)^2 - 1/2mv^2
= 4 * 1/2mv^2 - 1/2mv^2
=4w-w
=3w
Kinetic electricity is a shape of electricity that an item or a particle has with the aid of the purpose of its motion. If work, which transfers energy, is carried out on an object by applying an internet pressure, the item quickens and thereby profits kinetic strength.
Types of Kinetic Energy.
radiant, thermal, sound, electrical,mechanical.Kinetic energy (KE) is the energy of a frame in movement, because of this, it's essentially the power of all moving items. it's far one of the fundamental forms of power, together with capability energy, which is the saved electricity contained inside items for relaxation.
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The additional work needed to increase its speed from v0 to 2v0 is D)3W.
Work done is equal to a change in kinetic energy
w = 1/2mv^2-0
= 1/2mv^2
When v is 2v
w new = 1/2*m*(2v)^2 - 1/2mv^2
= 4 * 1/2mv^2 - 1/2mv^2
=4w-w
=3w
Kinetic electricity is a shape of electricity that an item or a particle has with the aid of the purpose of its motion. If work, which transfers energy, is carried out on an object by applying an internet pressure, the item quickens and thereby profits kinetic strength.
Types of Kinetic Energy.
radiant,thermal,sound,electrical,mechanical.Kinetic energy (KE) is the energy of a frame in movement, because of this, it's essentially the power of all moving items. it's far one of the fundamental forms of power, together with capability energy, which is the saved electricity contained inside items for relaxation.
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A student has three springs A, B and C. He measures the length of each spring, in turn, when
different weights are placed on the end of each spring.
His table of results is shown in Fig. 3.1
(a)(i) The spring C has been stretched past the limit of proportionality.
(ii) Spring stretched within the limit of proportionality is equal to the increase in weight and in turn increase in the length of spring.
(iii) The un-stretched length of spring A is 4.5 cm.
What is weight?The weight of any object is the mass times the acceleration due to gravity on Earth or any other planet.
Weight W = mg
where g = 9.81 m/s²
Given, a student has three springs A, B and C. He measures the length of each spring, in turn, when different weights are placed on the end of each spring. His table of results is shown in Figure.(a)
(i) The spring C has been stretched past the limit of proportionality.
(ii) Spring stretched within the limit of proportionality is equal to the increase in weight and in turn increase in the length of spring.
In case of spring C, there is an unequal increase in weight and length of spring of 0.8 cm, when weight change from 1 to 1.5 N and 1.8 cm increase , when weight change from 2 to 2.5 N.
(iii) The natural length of spring be Xo and X is the increase in length due to 1N weight.
So, the equations formed will be
Xo + X = 6.1 cm....................(1)
Xo + 2X = 7.7 cm....................(2)
Solving both the equations, we get
X = 1.6 cm and Xo = 4.5 cm
Thus, the un-stretched length of spring A is 4.5 cm.
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True or false cells of humans and plants are same.
What is electromagnet
Answer:
Electromagnetic is used to describe the electrical and magnetic forces or effects produced by an electric current.
Discuss the work done by a pitcher throwing a baseball. What is the approximate distance through which the force acts as the ball is thrown
Due to acceleration, work is done accelerating from rest.
Work done is defined as product of force and displacement. As it explain force then it consist acceleration with itself. So, we can say like this that
work is done mainly due to acceleration of object from rest.
For the approximate distance through which the force act as ball is
thrown is the work is done along effective length of pitcher's arm and he
can extend this distance by taking a step forward.
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If someone was to
place a cool lid on this
pot of boiling water,
what would happen?
A. The water particles will lose energy once they touch
the lid.
B. The water particles will gain energy once they touch
the lid.
C. The water particles will get locked in place once they
touch the lid.
Answer:B. The water particles will gain energy once they touch
the lid.
Explanation:
A steady current flows through an inductor. If the current is doubled while the inductance remains constant, the amount of energy stored in the inductor:.
If the current is doubled while the inductance remains constant, the amount of energy stored in the inductor 2LI².
Energy stored in inductor
The amount of energy stored in the inductor is given as;
E = ¹/₂LI²
where;
L is inductance I is current in the inductorWhen the current doubles, the new energy stored in the inductor;
E = ¹/₂L(2I)²
E = ¹/₂L(4I²)
E = 2LI²
Thus, if the current is doubled while the inductance remains constant, the amount of energy stored in the inductor 2LI².
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The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?.
0.32 km
How to reach the answer:
The formula below provides the tsunami's speed in response to the query.
s = 356√d
when the tsunami's speed is 200 km/h, the equation's "s" is changed to "200," and the equation of speed is then expressed as follows.
200 = 356√d
The equation can be changed to compute the depth of the water as,
√d = 200÷356
√d = 0.562
Now on squaring both sides:
(√d)² = (0.562)²
d = (0.562)² = 0.316 or 0.32
Therefore the approximate depth of water for a tsunami travelling at 200km/h is 0.32 km
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How are mircowaves similar to radio waves
Microwaves is similar to radio waves such that they are both an electromagnetic wave of lower wavelength and high frequency.
What is a Wave?This is referred to a disturbance which carries energy without movement of the particles.
Microwaves and radio waves both have a low wavelength and high frequency which makes them similar to each other.
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A 50.0-kg person steps on a scale in an elevator. The scale reads 5000 N. What is the magnitude of the acceleration of the elevator
The magnitude of the acceleration of the elevator is 90m/s^2
Due to Newton's Law ∑ Forces in direction of motion is equal to mass
multiplied by the acceleration
We have here two forces 5000 N in direction of motion and the weight of the person in opposite direction of motion
The weight of the person is his mass multiplied by the acceleration of gravity
So ,
W = mg , where m is the mass and g is the acceleration of gravity
m = 50 kg and g = 9.8 m/s²
Substitute these values in the rule above
W = 50 × 9.8 = 490 N
The scale reads 5000 N
F = 5000 N , W = 490 N , m = 50kg
F - W = ma
5000 - 490 = 50 a
4510 = 50 a
Divide both sides by 50
a = 90.2 m/s²
Hence the acceleration is 90m/s^2
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Question )
A snail covers a distance of 90 meter in 24 hours calculate the average speed of the snail.
Answer:
1.042 × 10⁻³ m/s
Explanation:
average speed = [tex]\frac{total \space\ distance \space\ covered}{time \space\ taken}[/tex]
In this case,
• distance covered = 90 m,
• time taken = 24 hours = 24 × 60 = 1440 min = 1140 × 60 = 86400 s
Substituting these values into the formula:
average speed = [tex]\frac{90}{86400}[/tex]
= 1.042 × 10⁻³ m/s
Answer:
3.75 meters per hour
Explanation:
[tex]\boxed{\sf Speed = \dfrac{Distance}{Time}}[/tex]
Given:
Distance = 90 metersTime = 24 hoursSubstitute the given values into the formula to calculated the speed:
[tex]\implies \sf Speed = \dfrac{90\:m}{24\:h}[/tex]
[tex]\implies \sf Speed = 3.75\:m/h[/tex]
Therefore, the average speed of the snail is 3.75 meters per hour.
To calculate the speed in meters per minute, divide by 60:
[tex]\implies \sf Speed = \dfrac{3.75\:m/h}{60}=0.0625\:m/min[/tex]
To calculate the speed in meters per second, divide by 60 again:
[tex]\implies \sf Speed = \dfrac{0.0625\:m/min}{60}=0.001042\:m/s\:\:(4\:s.f.)[/tex]
The force of gravity, just as all forces, is an action on an object. Forces appear due to the interactions between pairs of objects. Therefore, for the force of gravity to act on a falling object, there should be another object that, in a sense, is creating that force. Which object is responsible for creating the force of gravity observed on falling objects
The Earth as a whole is responsible for creating the force of gravity observed on falling objects.
How is earth responsible?As the earth pulls the objects lower due to its gravity, the objects typically fall towards the earth by Gravitational force.
The law of gravitation states that the force of attraction between any two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. Anywhere in the universe, the law is applicable to objects. One claims that this law is ubiquitous.
The mass and density of the planet, 5.97237 1024 kg (1.31668 1025 lbs) and 5.514 g/cm3, respectively, determine the force of Earth's gravity. Because of this, Earth has a gravitational pull of 9.8 m/s2 at its surface or 1 g. This pull naturally weakens the further one goes from the surface.
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A total of 590 C of charge passes through a flashlight in 0.470 h. What is the average current in milliamperes
Answer:
I = Q / t = 590 C / (.47 * 3600 sec) = .349 amperes
.349 amps * 1000 milliamps / amp = 349 milliamperes
How much horsepower is produced by 2023 z’s 3. 0-liter twin-turbo 6-cylinder engine?.
400 horsepower is produced by 2023 z's 3. 0-liter twin-turbo 6-cylinder engine.
What is horsepower?The power an engine produced is referred to as horsepower. In the British Imperial System, one horsepower equals 33,000 foot-pounds of work per minute, i.e., the force required to lift a mass of 33,000 pounds off the ground in a single motion for one minute.
The new Z's 3.0-liter twin-turbo V6 engine produces 400 horsepower and 350 pound-feet of torque. This is 68 horsepower and 80 lb-ft more than the previous 370Z. The 6-speed manual transmission that comes standard or the optional 9-speed automatic transmission with paddle shifters are both paired with this one engine option.
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In a game of tennis, a ball traveling at is hit by a racket and travels in the opposite direction at . True or False: There is a change in momentum.
The momentum is changed when the ball is hitted by racket in the tennis game.
To find the answer, we need to know about the momentum.
What's momentum?Momentum of an object is given by the product of mass and the velocity of the ball.Also the rate of change of the momentum with time is called as force.How does the momentum change when a ball hitted by racket?In the game of tennis, the ball is hitted by the racket. And at the time of hitting a delta force is given to that ball.As a force is applied to the ball, so we must find a change in momentum in very small time interval.Thus, we can conclude that the momentum is changed when the ball is hitted by racket in the tennis game.
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a force of 3600 n is exerted on a piston that has an area of 0.040 m2 what force is exerted on a second piston that has an area of 0.20 m2 use f1 a1= f2 a2
Using the Pascal's principle formula, the force exerted on the second piston is 18000 N.
What is the force exerted on the second piston?The force on the second piston is determined using the formula from Pascal's principle.
The formula is given below:
[tex]\frac{f_{1}}{A_{1}} = \frac{f_{2}}{A_{2}}[/tex]
Solving for the force on the second piston, [tex]{f_{2}[/tex]
[tex]{f_{2} = \frac{A_{2}\times f_{1}}{A_{1}}[/tex]
[tex]{f_{2} = \frac {0.2\times3600}{0.04} = 18000 N[/tex]
In conclusion, the force on the second piston is 18000 N.
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what is one standard kilogram
The Kilogram was for many years the only one of the seven SI base standards that was not defined in terms of a fundamental attribute of nature.
It was specified as the weight of a platinum-iridium cylinder stored in a lab outside of Paris under inert conditions.
The problem with that is that it needs to be managed in order to use such a standard for calibrating exact copies. No matter how meticulously you do it, surface molecules must experience some minimal impact.
Therefore, efforts have continued to find a replacement standard that is not a tangible thing. With the suggestion for a new Standard Kilogram utilizing a gadget called the Kibble Balance, it now seems that the quest is over.
Answer:
one standard kilogram is the mass of cylinder made up of platinum-iridum alloy with equal diameter and base kept Ar international bureau of weight and measures near paris
The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
0.60s. The gravitational field intensity is 9.8N/kg. Calculate the force the escaping
gas exerts of the rocket.
Since g is constant, the force the escaping gas exerts on the rocket will be 10.4 N
What is Escape Velocity ?This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.
Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.
To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters
Mass (m) of the rocket 0.25 KgInitial velocity u = 15 m/sFinal Velocity v = 40 m/sTime t = 0.6sGravitational field intensity g = 9.8N/kgThe force the gas exerts of the rocket = The force on the rocket
The rate change in momentum of the rocket = force applied
F = ma
F = m(v - u)/t
F = 0.25 x (40 - 15)/0.6
F = 0.25 x 41.667
F = 10.42 N
Since g is constant, the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.
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The magnitudes of two horizontal displacements are 4 m and 9 m, respectively. Given that the vectors may be in either the plus or the minus direction, they cannot be added together to give a total displacement of
The magnitudes of two horizontal displacements are 4 m and 9 m, respectively. Given that the vectors may be in either the plus or the minus direction, they cannot be added together to give a total displacement of 4m.
The attain of the projectile is the horizontal displacement of the projectile and is decided by the object's initial pace.
If a projectile is fired on an equal starting velocity but from complementary tiers of projection, its variety will be equal.
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What is the angular displacement (in rad) of an object that starts from rest and accelerates at a rate of 4 rad/s2 for a time of 4 seconds? (Please leave your answer with one decimal places with no units)
An object which starts from its resting place & accelerates at a speed of 4 rad/sec², the angular displacement is 8 rad.
An object's angular displacement is described in the following:
Angle displacement is equal to θ[tex]f[/tex]-θ[tex]i[/tex].
The following methodology must also be applied to determine angular displacement when the object's acceleration, starting velocity, and time are known:
θ=ωt+ 1/2αt²
[where θ= the angular displacement of an object,
ω= initial angular velocity,
α= angular acceleration,
t= time]
In this case, the object starts from the rest position.
So, the initial angular speed, ω= 0 rad/sec
Provided angular acceleration ,α = 4 rad/sec²
Time ,t= 4 sec
So, θ= [tex]0*4+ (1/2)*4*4[/tex]
⇒θ= 0+ 8
⇒θ= 8 rad
Therefore, it is concluded that the angular displacement is 8 rad.
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If the force between the puffed rice pieces is 4 x 10^-23 N when the pieces are 0.03 m apart, what is the charge on each of the pieces?
2 x 10⁻¹⁸ C is the charge on each of the pieces.
What is the charge?In physics, Charge is electric charge, electrical charge, or electrostatic charge and symbolized as q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.
According to the question,
Fс = 4 x 10⁻²³ N
d = 0.03 m , k = 9.0 x 10⁹ N·m²/C²
q =?
The force exerted by one charge q on another charge Q a distance r away is given by:
Coulomb's law:
Fc =[tex]\frac{kq_{1} q_{2} }{d^{2} }[/tex]
By solving the equation:
[tex]q1q2 =\frac{F_{c} d^{2} }{k}[/tex]
[tex]\frac{(4*10^{-23}(0.03m )^{2} }{(9.0*10^{9}N.m^{2}/C^{2}) }[/tex]
= 4 x 10 ⁻³⁶C²
This is the square of the charge on the pieces of puffed rice.
Now, to find the charge on one piece of puffed rice,
take the square root of this number.
q = √4 x 10⁻³⁶ C²
q = 2 x 10⁻¹⁸ C
Therefore,
The charge on each of the pieces is 2 x 10⁻¹⁸ C
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A 140 g coin sits on a horizontally rotating turntable. the turntable makes one revolution each 1 s. the coin is located 14 cm from the axis of rotation of the turntable. the acceleration of gravity is 9.81 m/s2. what is the frictional force acting on the coin? answer in units of n. the coin will slide off the turntable if it is located more than 24 cm from the axis of rotation. what is the coefficient of static friction?
The frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.
To find the answer, we need to know more about the friction.
How to find the coefficient of static friction?We have given with the following values,[tex]m=140*10^{-3} kg\\w=1 rev/s=2\pi rad/s\\r_1=14*10^{-2}m\\g=9.81m/s^2\\[/tex]
When the coin is at a distance of 14cm from the axis of rotation, it will experience a centripetal force inward, and which is in opposite direction of the frictional force.Thus, the frictional force experience on the coin will be equal to the centripetal force.[tex]f=F_c=ma_c=m*r_1w^2\\f=140*10^{-3}*14*10^{-2}*4*\pi ^2=0.77N[/tex]
The coin will slide off the turntable, if it is located at a distance of 24cm.We have to find the coefficient of static friction when it is at a distance of 24cm from the axis of rotation.We have the expression for static friction as,[tex]f_s=kN,\\\\Where, \\N=mg\\\\k=\frac{f_s}{mg}[/tex]
We have to find the value of static friction at a distance 24 from the center of the table. This will be equal to the Fc at 24cm.[tex]F_c=f_s=mrw^2=140*10^{-3}*24*10^{-2}*4\pi ^2\\f_s=1.325N[/tex]
Thus, the coefficient of static friction will be,[tex]k=\frac{1.325}{140*10^{-3}*9.81}=0.964[/tex]
Thus, we can conclude that, the frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.
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