The system of inequalities is 1.25x + 2y >= 375 and x + y <= 500, while the smallest number of chocolate covered almonds is 400
The system of inequalitiesWe make use of the following representations:
x = chocolate bars
y = chocolate covered almond
Using the above as a guide, and the given parameters;
We have:
1.25x + 2y >= 375 -- the amount raised
x + y <= 500 --- number of bars sold
The least number of chocolate covered almonds that must be soldFrom the question, we have
x = 100
Substitute x = 100 in x + y <= 500
100 + y <= 500
Evaluate
y <= 400
So, the least amount to sell is 400
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A coin has 2 sides: heads (H) and tails (T). A bag has 3 balls: 1 red (R), 1 green (G), and 1 blue (B). You toss a coin and randomly pick a ball. What is the sample space?
The space sample is the total quantity of possible results
for each toss there are 3 possible results
so the total results are 2x 3 = 6
The only option with 6 elements is B
so the answer is B.
According to medical data, the ages at which patients have their first hip replacement
surgery follows a normal distribution. The average age for a first hip replacement is 55
years of age, with a standard deviation of 8 years. Therefore, doctors can expect 95% of
their hip replacement surgery patients to be between what ages?
O 39-71
O 45-65
O 47-63
O 31-79
Question 4
2
95% of the people the doctor expects to have hip replacement surgery will be between the ages of 47 and 63.
What exactly are the mean and standard deviation?
The definition of average is that it is the mean value, which is the ratio of the sum of the values in a particular set to all the values in the set.
The amount of variance from the mean is shown by the standard deviation.
Given that the standard deviation is 8 years and the average age is 55.
x=x0, where x0 and are the mean age and standard deviation, respectively, defines the relationship.
The standard deviation is 8 years, while the mean age is 55 years.
The answer is that 55+8=63 and 55-8=47.
Consequently, the age range is 47 years to 63 years.
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help meeeeeee pleaseee !!!!
The linear function that passes through the points (-3, 18) and (2, -7) is defined by the rule:
y = -5*x + 3
How to find the linear function?We can find a general linear function in the slope-intercept form as:
y = m*x + k
Where m is the slope and k is the intercept of the y-axis.
If we know that the line passes through the points (a, b) and (c, d) then the slope of the function is:
m = (d - b)/(c - a)
In this case the line passes through the points (-3, 18) and (2, -7), then the slope is:
m = (-7 - 18)/(2 + 3) = -5
So the line is something like:
y = -5*x + k
To find the value of k, we can use one of the two given points, I will use (2, -7), so we get:
-7 = -5*2 + k
-7 = -10 + k
-7 + 10 = k
3 = k
So the linear function is:
y = -5*x + 3
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Salaries of Business Graduates. Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $45,000 and $60,000. Assume that a 95% confidence interval estimate of the population mean annual starting salary is desired. What is the planning value for the population standard deviation? How large a sample should be taken if the desired margin of error is a. $500? b. $200? c. $100? d. Would you recommend trying to obtain the $100 margin of error? Explain.
3750 is the planning value for the population standard deviation.
In the sampling, one should not recommend trying to obtain the $100 margin of error since the sample size is large.
Firstly, the planning value will be:
= (60000 - 45000) ÷ 4
= 3750
Then the number will be:
= 1.96 × (3750 ÷ 500)²
= 217
Also, for error 200, the desired margin will be:
= 1.96 × (3750 ÷ 100)²
= 5403.
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Find the simple interest on $50,000 for 2 years at 7%
Answer:
$7,000
Explanation:
To find the simple interest on any principal, we use the formula:
[tex]Simple\: Interest=\frac{Principal\times Rate\times Time}{100}[/tex]From the given question:
• Principal = $50,000
,• Rate= 7%
,• Time = 2 years
Therefore:
[tex]\begin{gathered} \text{Interest}=\frac{50,000\times7\times2}{100} \\ =\$7,000 \end{gathered}[/tex]The simple interest is $7,000.
I just need to make sure 1-9 are correct so if you could confirm please.9 b)
Given:
[tex]2x^2+3x+9=0[/tex]To find:
The roots.
Explanation:
Here,
[tex]\begin{gathered} a=2 \\ b=3 \\ c=9 \end{gathered}[/tex]Using the quadratic formula,
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]On substitution we get,
[tex]\begin{gathered} x=\frac{-3\pm\sqrt{(3)^2-4(2)(9)}}{2(2)} \\ =\frac{-3\pm\sqrt{9-72}}{4} \\ =\frac{-3\pm\sqrt{-63}}{4} \\ =\frac{-3\pm3i\sqrt{7}}{4} \end{gathered}[/tex]Therefore, the solutions are,
[tex]x=\frac{-3+3\imaginaryI\sqrt{7}}{4},x=\frac{-3-3\imaginaryI\sqrt{7}}{4}[/tex]Final answer:
The solutions are,
[tex]x=\frac{-3+3\imaginaryI\sqrt{7}}{4},x=\frac{-3-3\imaginaryI\sqrt{7}}{4}[/tex]
The measure of USV is ________ degrees.The solution is _________________
Since ∠VST measures 90°, the measure of ∠RSV must also be 90° because the two angles are linear pair.
Since m∠RSU=51°, then the measure of ∠USV is as follows:
[tex]\begin{gathered} m\angle USV=m\angle RSV-m\angle RSU \\ m\angle USV=90\degree-51\degree \\ m\angle USV=39\degree \end{gathered}[/tex]The drama club is selling tickets to its play. An adult ticket costs $15 and a student ticket costs $11. The auditorium will seat 300 ticket-holders. The drama club wants to collect at least $3630 from ticket sales.
a. Write and graph a system of four inequalities that describe how many of each type of ticket the club must sell to meet its goal.
b. List three different combinations of tickets sold that satisfy the inequalities.
The system of inequalities is x + y ≤ 300, 11x + 15y ≥ 3630, x ≥ 0 and y ≥ 0 while the three points are (70, 200), (150, 140) and (140, 150)
How to graph the systemFrom the question, we have the following parameters that can be used to determine system of inequalities
An adult ticket = $15Student ticket = $11. Auditorium capacity = 300 ticket-holdersAmount from sales = at least $3630 from ticket sales.Represent the adult with y and the students with x
So, we have the following representations
x + y ≤ 300 ---- the ticket holders cannot exceed the capacity
11x + 15y ≥ 3630 --- the total sales cannot be less than $3630
x ≥ 0 -- the number of students cannot be negative
y ≥ 0 -- the number of students cannot be negative
Write out the inequalities
x + y ≤ 300
11x + 15y ≥ 3630
x ≥ 0
y ≥ 0
Next, we represent the inequalities on a graph
See attachment for the graph of the inequalities
The combinations from the graphTo get the combination, we make use of the coordinate points that are in the shaded region of the graph
Using the above as a guide, we have
(70, 200), (150, 140) and (140, 150)
There are other points too
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A. 90 degrees clockwiseB. 180 clockwiseC. 90 degrees counter clockwise
1) What we have in the polygon P is at first a
90º Rotation Clockwise because it is in the direction of the clock.
90º Rotation Clockwise
Tracing a line inside the polygon P, we can count approximately 10 units to the right in the translation.
T
Can someone help please
The maximum displacement of this cosine wave function is equal to 8 inches.
The frequency of this cosine wave function is equal to 1/8 Hertz.
The time (t) required for one cycle is equal to 8 seconds.
What is a cosine wave?Mathematically, a cosine wave simply refers to an equation of simple harmonic motion (SHM) and it is modelled by this mathematical expression:
y = asinωt = asin2πft ......equation 1.
Where:
a represents the amplitude or maximum displacement of a cosine wave. f represents the frequency measured in Hertz.ω represents the angular velocity.t represents the time measured in seconds.How to calculate the maximum displacement?From the information provided, the equation for this simple harmonic motion (SHM) is given by:
d = -8cos(π/4)t ......equation 2.
By comparing equation 1 and equation 2, we have the following parameters:
Maximum displacement or amplitude, a = |-8|
Taking the absolute value of a, we have:
Maximum displacement or amplitude, a = 8
For the frequency, we have:
Angular velocity, ω = 2πf
Making frequency (f) the subject of formula, we have:
Frequency (f) = ω/2π
Frequency (f) = (π/4)/2π
Frequency (f) = π/8π
Frequency (f) = 1/8 Hertz.
Finally, we would calculate the amount of time (t) required for one cycle as follows:
Time (t) = 1/f
Time (t) = 1/(1/8)
Time (t) = 8 seconds.
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Complete Question:
An object moves in simple harmonic motion described by the equation d = -8cos(π/4)t, where t is measured in seconds and d in inches. Find the following:
maximum displacement
the frequency
the time required for one cycle.
What number would you add to both sides of x2 + 7x = 4 to complete the square?2²0 72이를즐이
To complete the square, we want a number such that:
[tex]\begin{gathered} 2\sqrt{a}=7 \\ a=(\frac{7}{2})^2 \end{gathered}[/tex]because in this way we can writte the square as follows:
[tex]\begin{gathered} x^2+7x+(\frac{7}{2})^2=4+(\frac{7}{2})^2 \\ (x+\frac{7}{2})^2=4+(\frac{7}{2})^2 \end{gathered}[/tex]Hence the answer is the last option:
[tex](\frac{7}{2})^2[/tex]12. In the diagram below, transversal TU intersects PQ and RS at V and W, respectively. If mZTVQ = 5x - 22 and mZTVQ = 3x + 10, for which value of x is PQ parallel to RS? P_ R W A. 6 B. 16 C. 24 D. 28
ANSWER:
The value of x is 16
STEP-BY-STEP EXPLANATION:
With the information given, they tell us that TVQ can be expressed in two ways, but in the end the value must be the same because it is the same angle.
Thanks to this we can make the following equality:
[tex]5x-22=3x+10[/tex]Solving for x:
[tex]\begin{gathered} 5x-3x=22+10 \\ 2x=32 \\ x=\frac{32}{2} \\ x=16 \end{gathered}[/tex]Answer:
16 is the answer
a line goes through the point (5, -7) and has slope m = -3. write the equation that represents the line.
We are given the following information
Slope of the line = m = -3
The line passes through the point (5, -7)
Recall that the equation of a line in the point-slope form is given by
[tex](y-y_1)=m(x_{}-x_1)[/tex]Where m is the slope and (x₁, y₁) is a point on the line.
Let us substitute the given values into the above equation
[tex]\begin{gathered} (y-(-7)_{})=-3(x_{}-5_{}) \\ (y+7)=-3(x_{}-5_{}) \\ y+7=-3x+15 \\ y=-3x+15-7 \\ y=-3x+8 \end{gathered}[/tex]Therefore, the equation of the line in slope-intercept form is
[tex]y=-3x+8[/tex]a standard number cube number 1 through 6 on east side is rolled 3 times what is the probability of rolling a 2 on all three rolls express your answer as a fraction
the probability of getting a 2 tree times is
[tex]\frac{1}{6}\cdot\frac{1}{6}\cdot\frac{1}{6}=\frac{1}{216}[/tex]Translate the sentence into an equation. Use the variable w for the unknown number.Two times the sum of a number and 7 equals 6.
we have that
Two times the sum of a number and 7 -----> 2(w+7)
Two times the sum of a number and 7 equals 6 ----> 2(w+7)=6
the answer is
2(w+7)=6How do I solve this?
Answer: F
Step-by-step explanation:
[tex]\sin(x+y)=\sin x \cos y+\cos x \sin y[/tex]
[tex]\tan x=2 \implies \sin x=\frac{2}{\sqrt{5}}, \cos x=\frac{1}{\sqrt{5}}\\\\\sin y=\frac{8}{17} \implies \cos y=-\frac{15}{17}\\\\\sin (x+y)=\left(\frac{2}{\sqrt{5}} \right) \left(-\frac{15}{17} \right)+\left(\frac{1}{\sqrt{5}} \right) \left(\frac{8}{17} \right)\\\\=-\frac{30}{17\sqrt{5}}+\frac{8}{17\sqrt{5}}\\\\=-\frac{22}{17\sqrt{5}}\\\\=-\frac{22\sqrt{5}}{85}[/tex]
help please
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample 50 of business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow.
5 9 10 2 2 2 2 7 7 7 7 6 7
8 9 9 2 10 2 7 6 9 8 10 9 2
7 5 7 2 2 7 7 6 2 10 8 2 6
6 9 5 2 10 7 10 2 2 6 6
Develop a confidence interval estimate of the population mean rating for Miami. Round your answers to two decimal places.
Using the t-distribution, the 95% confidence interval estimate of the population mean rating for Miami is of:
(4.29, 7.71).
What is a t-distribution confidence interval?The bounds of the confidence interval are given according to the following rule:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
In which the meaning of the parameters are:
[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.Using a calculator from the 50 observations given in this problem, the values of the parameters are as follows:
[tex]\overline{x} = 6, s = 2.86, n = 50[/tex]
The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 50 - 1 = 49 df, is t = 2.0096.
Hence the lower bound of the interval is given by:
[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 6 - 2.0096\frac{6}{\sqrt{50}} = 4.29[/tex]
The upper bound of the interval is given by:
[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 6 + 2.0096\frac{6}{\sqrt{50}} = 7.71[/tex]
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Multiply. Write your answer in scientific notation.
2.(4 × 10³)
A square napkin has sides of length 8 inches. To the nearest inch, what is the length of the diagonal of the (1
napkin?
O8 inches
09 inches
O11 inches
O16 inches
The length of the diagonal of the napkin is 11 inches.
Here, we are given that a square napkin has a side of length 8 inches.
All the sides of a square are equal and the measure of angle formed by any two adjacent sides is also equal and 90°.
Thus, by using Pythagoras theorem, we can form the following equation-
[tex]side^{2} + side^{2} = diagonal^{2}[/tex]
Let the diagonal of the square be d. Then, we have-
[tex]8^{2} +8^{2} =d^{2}[/tex]
64 + 64 = [tex]d^{2}[/tex]
128 = [tex]d^{2}[/tex]
[tex]d^{2}[/tex] = 128
d = [tex]\sqrt{128}[/tex]
d = [tex]8\sqrt{2}[/tex]
the value of [tex]\sqrt{2}[/tex] is approximately 1.41. Thus,
d = 8 × 1.41
= 11.28
Thus, the length of the diagonal of the napkin to the nearest inch comes out to be 11.
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The sum of two whole numbers is 63. The difference between the numbers is less than 10. Find as many solutions
Answer:
hmmph..
(32, 31)
(33,30)
(34, 29)
(35, 28)
(36,27)
(37, 26)
Step-by-step explanation:
That all I got....
Eighth grade > T.14 Volume of spheres QX7 What is the volume of this sphere? Use a ~ 3.14 and round your answer to the nearest hundredth. 18 cm cubic centimeters Submit Docs
hello
to solve this question, we need to use the formula for volume of a sphere
[tex]\begin{gathered} v=\frac{4}{3}\pi r^3 \\ v=\text{volume} \\ r=\text{radius} \end{gathered}[/tex]from the image above, we can now find the radius of the sphere
[tex]\begin{gathered} radius=\frac{\text{diameter}}{2} \\ d=18\operatorname{cm} \\ r=9\operatorname{cm} \end{gathered}[/tex][tex]\begin{gathered} v=\frac{4}{3}\pi r^3 \\ v=\frac{4}{3}\times3.14\times9^3 \\ v=3052.08\operatorname{cm}^3 \end{gathered}[/tex]from the calculations above, the volume of the sphere is equal to 3052.08cm^3
À La Mode Ice Cream Parlor uses the function f(x) to calculate its profits. When the parlor sells x cones, it makes f(x) dollars in profit.
What does f(50)=85 tell you?
Help please
Answer: When the Ice Cream Parlor sells 50 ice cream cones, they make $85 dollars in profit.
Step-by-step explanation:
x = cones
the function f tells us the profit for whatever x
Over the interval [0,2pi), what are the solutions to cos(2x)=cos(x)? Check all that apply.
Answer:
x = 0 and 2pi/3
Explanation
Given the expression
cos(2x)=cos(x)
In trigonometry expression;
cos2x = 2xos^2x - 1
Substituting into the equation given;
cos(2x)=cos(x)
2xos^2x - 1 = cos x
Rearrange
2xos^2x - 1 - cosx - 1 = 0
Let P = cosx
2P^2 - P - 1 = 0
Factorize
2P^2 - 2P+P-1 = 0
2P(P-1)+1(P-1) = 0
2P+1 = 0 and P-1 = 0
P = -1/2 and 1
Recall that P = cosx
-1/2 = cosx
x = cos^-1(-1/2)
x = 120 degrees = 2pi/3
If P = 1
cosx = 1
x = cos^-1(1)
x = 0
Hence the value of x that satisfies the equation is 0 ad 2pi/3
Find the slope of the line that passes through each of the following sets of points (0, 0) and (1, 4)
Answer:
slope would be 4/1
Step-by-step explanation:
its rise over run, so up 4 and out 1
have a good day!
write the following in the form a+bi (2+5) - (-6 +bi)
The complex expression (2+5) - (-6 +bi) in the form a + bi is 13 - bi
How to evaluate the expression?The expression is given as
(2+5) - (-6 +bi)
The above expression is a complex expression
So, we have the following expression
(2+5) - (-6 +bi)
Remove the brackets in the above expression
So, we have the following expression
(2+5) - (-6 +bi) = 2 + 5 + 6 - bi
Evaluate the like terms in the above equation
So, we have the following expression
(2+5) - (-6 +bi) = 13 - bi
Hence, the solution to the complex expression is 13 - bi
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A cricket pitch measures $1$ chain by $10$ feet. What is the area of a cricket pitch in square feet?
(Useful information: there are $3$ feet in a yard, and there are $22$ yards in a chain.)
Area of the cricket pitch is 660 square feet
Given
1 chain is equal to 10 feet
There are 3 feet in a yard
And 22 yards in a chain
Hence it is evident that
One chain is equal to 22 x 3
1 chain = 66 Feet
Area of a rectangle is Length x Width
Length = 66
Width = 10
Hence Area = 66 x 10
Area = 660 Square feet
Hence area of the cricket pitch is 660 square feet.
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Full in the spaces to complete the equality:
15
A principal needs to order 1,437 T-shirts for students at her school. She rounds to the nearest hundred
to estimate the number of T-shirts to order. Will there be enough T-shirts for all the students? Explain.
There will not be enough T-shirts for all the students
How to determine if the T-shirts will be enough?From the question, the given parameters are:
Number of T-shirt = 1437
From the question, we understand that the principal approximates the number of T-shirts to the nearest hundred
When the number of T-shirts is approximated to the nearest hundred, we have
Approximation = 1400
By comparison, 1400 is less than 1437
This means that the T-shirts will not be enough
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9y-(2y-3)=5(y-2)+2
Should equal ‘no solution’
[tex]9y - 2y + 3 = 5y - 10 + 2 \\ 7y + 3 = 5y - 8 \\ 7y - 5y = - 8 - 3 \\ 2y = - 11 \\ \frac{2y}{2} = \frac{ - 11}{2} \\ y = \frac{ - 11}{2} [/tex]
ATTACHED IS THE SOLUTION OF Y
BE AWARE THERE IS A SOLUTION FOR THE PROBLEM.
I inserted a image of the question I’m very confused and need help with homework so I do good on test
To find the magnitude of a vector we use the following equation
[tex]\lvert\vec{v}\rvert=\sqrt[]{(v_x)^2+(v_y)^2}[/tex]This comes from taking the value of the hypotenuse by Pythagoras, graphically it can be seen in the following image:
In the case of your exercise, the values would be
[tex]\begin{gathered} v_x=x \\ v_y=y \\ \lvert\vec{v}\rvert=\sqrt[]{(x_{})^2+(y)^2} \end{gathered}[/tex]