The attachment is here. It is physics/chem.

Answer:

12

Explanation:

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Answer:

The rock will hit the ground at 20.44 m from the point of the drop

Explanation:

Horizontal Motion

It occurs when an object is thrown horizontally from a height h at an initial speed v.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

When the small rock is dropped from a car at speed v=32 m/s, it starts a curved path that ends up when the rock hits the ground. The height is h=2 m, thus the range is:

[tex]\displaystyle d=32\cdot\sqrt{\frac {2\cdot 2}{9.8}}[/tex]

[tex]\displaystyle d=32\cdot\sqrt{0.4082}[/tex]

[tex]d=20.44\ m[/tex]

The rock will hit the ground at 20.44 m from the point of the drop

Answer:

101 J

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 101 \ Joules}}[/tex]

Explanation:

Kinetic energy can be found using the following formula:

[tex]KE=\frac{1}{2}mv^2[/tex]

The mass of the baseball is 0.140 kilograms and the velocity is 38.0 meters per second.

[tex]m= 0.140 \ kg \\v= 38.0 \ m/s[/tex]

Substitute the values into the formula.

[tex]KE=\frac{1}{2} [0.140 \ kg][(38.0 \ m/s)^2][/tex]

First, evaluate the exponent.

[tex]KE=\frac{1}{2}(0.140 \ kg)(1444 \ m^2/s^2)[/tex]

Multiply the two numbers in parentheses together.

[tex]KE=\frac{1}{2}(202.16 \ kg*m^2/s^2)[/tex]

Multiply the fraction by the number, or divide the number by 2.

[tex]KE=101.08 \ kg*m^2/s^2[/tex]

Round to the nearest whole number. The 0 in the tenth place tells us we can leave the number as is.

[tex]KE\approx 101 \ kg*m^2/s^2[/tex]

1 kg*m²/s² is equal to 1 Joule. Therefore, our answer of 101 kg*m²/s² is equal to 101 Joules (J).

[tex]KE\approx 101 \ J[/tex]

The kinetic energy of the baseball is about 101 Joules.

Answer:

Explanation:

Strain of a material is the ratio of its extension to its original length.

strain = e/lo

e is the extension

lo is the original length

For a copper rod;

e = 2.00 * 10^-2mm

lo = 1.00m

convert 1.00m to mm

1.00m = 1*10^-3mm

get the strain

Strain = 2.00 * 10^-2mm/1*10^-3mm

Strain = 2 * 10^{-2+3}

Strain = 2*10^1 = 20

For the steel

e = 2.00 * 10^-3mm

lo = 0.100m

convert 0.100m to mm

0.1m = 0.1*10^-3mm

0.1m = 10^-4mm

get the strain

Strain = 2.00 * 10^-3mm/10^-4mm

Strain = 2 * 10^{-3+4}

Strain = 2*10^1 = 20

Since the value of their strain are the same, this means that they a re under the SAME tensile strain. No one is greater that the other.

The rod under greater tensile strain is ; Neither of them i.e. They both have the same tensile strain

Given data :

Cross sectional area of copper rod = 0.5 cm²

Length of copper rod  = 1.0 m  = 1 * 10³ mm

Elongation of copper rod ( Ec )  = 2.0 * 10⁻² mm

For Steel

Cross sectional area of steel = 0.5 cm²

Length of steel rod = 0.1 m  = 1 * 10² mm

Elongation of steel rod  ( Es )=  2.0 * 10⁻³ mm

Determine the Tensile strain of each rod

i) For copper rod

Tensile strain = Ec / Length of copper rod

                       = ( 2.0 * 10⁻² ) /  ( 1 * 10³ )

                       = 2.0 * 10⁻⁵

ii) For the steel rod

Tensile strain = Es / Length of steel rod

                       = ( 2.0 * 10⁻³ ) / ( 1 * 10² )

                        = 2.0 * 10⁻⁵

The Tensile strain for the copper rod and the steel rod is the same ( 2.0 * 10⁻⁵ ) This means that both rods are under the same tensile strain

Learn more : https://brainly.com/question/24024159

Answer:

the potential energy will also change

Explanation:

kinetic energy and potential energy are inversely proportional to each other, so if kinetic energy changes, potential energy will also change..

Answer:

B. A possible answer to a scientific question

Explanation:

It's usually a possible or testable explanation made on the basis of limited evidence as a starting point for further investigation.

Answer:

You could throw away the following items:

Mixed paper: Newspaper, magazine, junk mail, cardboard, frozen food packaging, wrapping paper, paper bags, etc.

Cans: aluminum, foil, tin, steal, aerosol (empty without pressure) and metal food trays. ...

Unbroken glass: Wine bottles, bottles and jars.

Plastic: Rigid containers like milk jugs, shampoo or water bottles.

Hope this helped

Answer:

His speed, in metres per second, is approximately 10m/s. The correct option is B.

Explanation:

Speed is defined as the rate in which an object cover a distance in a given time. It is measured in meters per second ( m/s). From the question, the jogger covered a distance of 3Km which when converted to meter is 3000meters in a given time 5 minutes which is 300seconds. The calculation of his speed in meter per second is shown below:

Distance= 3Km to meters ( as 1000meters = 1Km). Therefore 3× 1000 = 3000m

Time= 5 minutes to seconds ( as 1 minute = 60 Seconds). Therefore 5× 60= 300.

Speed= distance/ time

= 3000/300

= 10m/s

Therefore his speed, in metres per second, is approximately 10.

Answer:

Explanation:

Given

Initial velocity of the car u = 8m/s

Distance travelled by the rider S = 40m

Acceleration a = 2m/s²

Required

rider's velocity after the acceleration v

Using the equation of motion

v² = u²+2as

v² = 8²+2(2)(40)

v² = 64+160

v² = 224

v = √224

v = 14.97m/s

Hence the rider's velocity after the acceleration is 14.97m/s

Answer:

i. 1.84 m

ii. The ball's time in the air is 1.23s.

Explanation:

The ball moves upward (against the gravitational pull) with an initial velocity of 6 m/s.

I. Applying the third equation of free fall, the maximum height is;

[tex]V^{2}[/tex] = [tex]U^{2}[/tex] - 2gs

where the variables have there usual meaning.

[tex]V^{2}[/tex] = 0 m/s, [tex]U^{2}[/tex] = 6 m/s, g = 9.8 m/[tex]s^{2}[/tex].

0 = [tex]6^{2}[/tex] - 2 x 9.8 x s

0 = 36 - 19.6s

⇒ 19.6s = 36

s = [tex]\frac{36}{19.6}[/tex]

 = 1.8367

 = 1.84 m

The maximum height of the ball is 1.84 m.

II. The time the ball was in air can be determined by,

time of flight, T = [tex]\frac{2USin A}{g}[/tex]

where U is the initial velocity of the ball, A is the angle of projection and g is the acceleration due to gravity.

U = 6 m/s, A = [tex]90^{o}[/tex] (since the ball is thrown vertically upward), and g = 9.8 m/[tex]s^{2}[/tex].

T = [tex]\frac{2 *6 Sin90^{o} }{9.8}[/tex]

  = [tex]\frac{12}{9.8}[/tex]

  = 1.2245

T = 1.23s

The ball's time in the air is 1.23s.

Answer:

B- Group 2...  It says my answer is too short so how ya'll doing today?

Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.

Explanation: I hoped that helped!!