The aspect ratio of a TV screen is the ratio of the width to the height of the image. A regular TV has an aspect ratio of 16: 9. Find the height and width of a 51-inch TV screen to the nearest tenth of an inch. (The measure given is the length of the diagonal across the screen.)

Answers

Answer 1

Answer:

Width = 44.45 inches

Height = 25.00 inches

Step-by-step explanation:

(16x)^2 + (9x)^2 = 51^2

256x^2 + 81x^2 = 2601

337x^2 = 2601

x^2 = 7.718

x = 2.778

Width = 44.45 inches

Height = 25.00 inches

I think this is right

Answer 2

The width and height of the given TV screen will be 44.45 inches and 25.00 inches.

What is a rectangle?

A rectangle is a geometrical figure in which opposite sides are equal.

The angle between any two consecutive sides will be 90 degrees.

Area of rectangle = length × width.

Perimeter of rectangle = 2( length + width).

The length of any TV is measured diagonally.

So,

Diagonal = 51 inches

Now the ratio is ;

W/H = 16 / 9

Let's say both are fractions of x

So,

Width = 16x , Height = 9x

By Pythagoras theorem,

(16x)² + (9x)² = 51²

256x² + 81x² = 2601

337x² = 2601

x² = 7.718

x = 2.778

So width = 16(2.778) = 44.45 inches.

And height = 9(2.778) = 25.00 inches

Hence "The width and height of the given TV screen will be 44.45 inches and 25.00 inches".

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Answers

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Answers

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Answers

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Hey there!

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[tex]\text {-TestedHyperr}[/tex]

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Step-by-step explanation:

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I hope this helps

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3526.485 becomes 3526.49

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12.6433 becomes 12.64

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Answers

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Answers

Answer:

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Step-by-step explanation:

B is the midpoint of AC so AB = BC.

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Expand:

[tex]2\times3\left(3x-1\right)=5(2x+2)[/tex]

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Add 6 to both sides:

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Subtract 10x from both sides:

[tex]18x-10x=10x+16-10x[/tex]

[tex]8x=16[/tex]

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Answer:

[tex]x=2[/tex]

Step-by-step explanation:

First, we know that the entire segment adds up to 5(2x+2). In other words:

[tex]AB+BC=5(2x+2)[/tex]

Now, since B is the midpoint of AC, by the definition of midpoint, AB and BC are equivalent. So:

[tex]AB=BC[/tex]

Since we know that, let's substitute BC for AB in the first equation:

[tex]AB+BC=5(2x+2)\\[/tex]

This is equivalent to:

[tex]AB+AB=5(2x+2)[/tex]

Combine like terms:

[tex]2AB=5(2x+2)[/tex]

And since we know that AB is 3(3x-1), substitute:

[tex]2(3(3x-1))=5(2x+2)[/tex]

Now, solve for x.

Distribute the left side:

[tex]6(3x-1)=5(2x+2)[/tex]

Distribute both sides:

[tex]18x-6=10x+10[/tex]

Add 6 to both sides:

[tex]18x=10x+16[/tex]

Subtract 10x from both sides:

[tex]8x=16[/tex]

Divide both sides by 8:

[tex]x=2[/tex]

So, the value of x is 2.

And we're done!

Notes:

You didn't particularly state what you need to find. If you want to length of AB or BC, it would be:

[tex]AB=BC=3(3(2)-1)=15[/tex]

And the entire length AC is:

[tex]AC=2(15)=30[/tex]

URGENT PLS HELP

BD bisects ABC. Find each of the following
1. Find the measure of angle ABD if the measure of angle ABD = 6x + 4 and
the measure of angle DBC = 8x - 4
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Align the horizontal edge of the protractor with the base of the triangle. Place the center point of the protractor on the vertex of the angle. Follow the side of the triangle until it reaches the angle measurement mark. Note the measurement.

a flag pole that is 10 m talk casts a shadow that is 6 m long. what is the distance from the top of the pole to the end of the shadow

Answers

Answer:

11.66 meters

Step-by-step explanation:

First draw a diagram. See attachment.

We notice that if we draw everything out, we get a right triangle.

The flag pole and its shadow are the two legs, with lengths 10 and 6 meters. We want to find the distance from the top of the pole to the end of the shadow, so we need to use the Pythagorean Theorem, which states that for a right triangle with legs a and b and hypotenuse c:

a² + b² = c²

Here, a = 10 and b = 6, and we want to find c:

a² + b² = c²

10² + 6² = c²

100 + 36 = c²

136 = c²

c = √136 = 2√34 ≈ 11.66 meters

~ an aesthetics lover

Answer:

11.7

Step-by-step explanation:

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