The aircraft wing from problem 6 experiences temperature extremes that span 210 degrees Celsius. The component for the wing will have a length of exactly 3 meters. Testing indicates that the aircraft wing will remain stable only if the component never expands to a length larger than 3.017 meters. If the component is made from the metal alloy in question, will it meet this requirement. An unknown metal alloy is being tested to discover its thermal properties to see if it is suitable for use as a component in an aircraft wing. The alloy is formed into a bar measuring 1 meter in length, and is then heated from its starting temp. of 30°C to a final temperature of 100°C. The length of the heated bar is measured to be exactly 1.002 meters in length.

Required:
What is the coefficient of thermal expansion of the alloy?

Answers

Answer 1

Answer:

α = 2,857 10⁻⁵ ºC⁻¹

Explanation:

The thermal expansion of materials is described by the expression

          ΔL = α Lo ΔT

          α = [tex]\frac{\Delta L}{L_o \ \Delta T}[/tex]

in the case of the bar the expansion is

         ΔL = L_f - L₀

         ΔL=   1.002 -1

         ΔL = 0.002 m

the temperature variation is

         ΔT = 100 - 30

         ΔT = 70º C

we calculate

         α = 0.002 / 1 70

         α = 2,857 10⁻⁵ ºC⁻¹


Related Questions

A 6.0 kg bag of cat food is dropped from 5.0 m ledge. How much mechanical energy does
it have just before it strikes the ground?

Answers

Answer:

294

Explanation:

5x9.8x6=294

potential energy=5(9.8)(6)

Equation

PE=MGH

Three resistors R1 = 87.6 Ω, R2 = 22.0 Ω, R3 = 70.0 Ω, and two batteries e m f1 = 40.0 V, and e m f2 = 364 V are connected as shown in the diagram below.

Answers

A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.

What is Resistors?

They are present in practically all electrical networks and electronic circuits. Ohms () are used to measure resistance.

An ohm is the resistance that develops when a resistor has a one volt (V) drop across its terminals and a current of one ampere (A). The voltage across the terminal ends determines how much current flows.

There are numerous applications for resistors. Among some examples are voltage division, heat production, matching and loading circuits, gain control, and time constant setup. They have resistance ratings that span more than nine orders of magnitude and are marketed for use in various applications.

Therefore, A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.

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Verify that the quantity (k/N)Inr, where In,) is equal to the (mean) entropy of the given system. Show that this leads to essentially the same result for In T if we take, in the foregoing summation, only the largest term of the sum, namely the term Wint) that corresponds to the most probable distribution set. ISurprised? Well, note the following example: For all N, the summation over the binomial coefficients N!/Ir! (N-r!)l gives CNG, 2 r-0 therefore nCNIn2. Now, the largest term in this sum corresponds to r N/2; so, for large N, the logarithm of the largest term is very nearly equal to In(N!)-2In((N/2)!) N, N which agrees with (a).J

Answers

Because one mole of H X 2 is typically lighter than N e, it stands to reason that it would have a higher entropy than N e. Ne, on the other hand, is thought to have a higher entropy due to its lower molar mass.

A chemical equation can be examined for changes in physical states and the number of moles of product and reactant particles to predict relative changes in entropy using the same factors on a macroscopic level.

The species with the greater molar mass between two monoatomic ones will have a greater standard entropy. The more mobile of two allotropic forms of an element will have a higher standard entropy value. The entropies of these substances are not zero, despite the fact that their conventional internal energies and enthalpies would be. The "energies of formation" of elements in their normal states are typically set to zero because there is no absolute scale of energy.

Entropy, on the other hand, gauges the distribution of energy among the numerous quantum states that can accept it; they exist even in pure substances.

Evidently, entropies often rise with molecule weight. This is, of course, a direct reflection of the fact that translational quantum states are more densely packed in heavier molecules, making them more occupiable, for the noble gases.

The additional impacts of rotational quantum levels are visible in the entropies of the diatomic and polyatomic molecules.

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A geostationary satellite for communications seems to be in a fixed spot above the equator because it has the same angular velocity as the earth.
a, show that if it goes round once a day its angular velocity is a little over 7 * 10*-5 rad/s.

Answers

The angular velocity of a  geostationary satellite is 7 × 10⁻⁵rad/s.

What are geostationary satellite?

A geostationary satellite is an earth-orbiting satellite that travels in the same direction as the earth's rotation and is positioned at a height of around 36000 kilometers.

One orbit takes place at this altitude in 24 hours, which is how long it takes the earth to complete one rotation of its axis.

Time period of revolution = 24 hour = 24 × 60 × 60 second.

Hence, angular velocity of it = total circular angle/Time period

= 2π /( 24 × 60 × 60 ) rad/s

= 7 × 10⁻⁵rad/s.

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Show that the displacement of a body moving with uniform acceleration a is given by
[tex]s = ut + 1 \div 2at {}^{2} [/tex]
where U is the is the velocity of the body at time (t)=0

Answers

Answer:

I only Know to derive so

Explanation:

We have from first equation,

V = u+at

From second equation

S=u+v/2×t

Now by placing the value of v from equation 1 into 2

or s =u+u+at/2×t

or,s= 2u+at/2×t

or,s=2ut/2+at^2/2

Therefore s=ut+1/2at^2

A rectangular block of wood has dimensions 240mm×20.5cm×0.040m. calculate its volume in cm³.

Answers

Answer: 1968 cm3

Explanation: You first need to convert all of your dimensions to the same units.

240 mm = 24 cm

20.5 cm = 20.5 cm

0.04 m = 4 cm

Then volume is Length x width x height = 24 cm x 20.5 cm x 4 cm =

A 5.0 kg block with a speed of 3.0 m/s collides with a 10
kg block that has a speed of 2.0 m/s in the same direction.After the
collision, the 10 kg block travels in the original direction with a
speed of 2.5 m/s. (a) What is the velocity of the 5.0 kg block immediately after the collision? (b) By how much does the total kinetic
energy of the system of two blocks change because of the collision? (c) Suppose, instead, that the 10 kg block ends up with a
speed of 4.0 m/s. What then is the change in the total kinetic energy? (d) Account for the result you obtained in

Answers

(a) The first block  moves at 4.0 m/s in the same direction right after colliding.

(b) the system's total kinetic energy changes by  28.75 J

(c) the system's total kinetic energy changes by -1.25 J

Given;

First block's mass, m1, is 5 kg.

u1 = 3.0 m/s is the first block's starting speed.

m2 weight of the second block is 10.0 kg.

u2 = 2.0 m/s is the second block's initial speed.

v2 = 2.5 m/s is the second block's final speed.

Immediately following the impact, the first block block's Part (A) velocity is as follows:

Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.

(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)

35= 2.5v₁ + 25

2.5v₁ = 35-25

2.5v₁ = 10

v₁ = 10/2.5

v₁ = 4

2.5 m/s in the same direction for v1.

Change in the system's overall kinetic energy, part (B):

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)

ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).

ΔK = 71.25 J - 42.5 J

ΔK = 28.75 J

Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s

Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)

35 = 2.5v₁ + 40

2.5v₁ = -5

2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)

K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).

ΔK = 41.25 - 42.5 J

ΔK = -1.25 J

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The speedometer of a car reads 85 mph. It passes a truck in the next lane traveling at 75 mph. Which of the following statements is true?

Both measurements are scalar quantities.
Both measurements are vector quantities.
The car's measurement is a scalar, and the truck's measurement is a vector.
The car's measurement is a vector, and the truck's measurement is a scalar.

Answers

Answer: Both measurements are scalar quantities.

Explanation:

In physics, a scalar quantity is a quantity that is completely specified by its magnitude, without any reference to direction. Speed is an example of a scalar quantity, because it is a measure of how fast an object is moving, without specifying the direction in which it is moving. In this case, both the speedometer reading of 85 mph and the speed of the truck in the next lane at 75 mph are scalar quantities, because they are both measures of speed without specifying a direction.

200 grams of ice at -10 c is added to 1000 grams of room temperature water to cool it down. which of the following best describes the final composition of the mixture

Answers

At 0 °C, combine 200 grams of ice with 1000 grams of liquid. The following relational models overall final composition of a mixture at 6.7 °C:

How are compositional mixes and compounds defined?

Atoms from various elements are chemically mixed in a predetermined ratio to form a compound. When there is no biochemical combination or reaction, two or more chemicals are combined to form a mixture. Different elements are found in compounds in fixed ratios organised in predetermined ways by chemical bonds.

Is a mixture's composition subject to change?

A mixture is a chemical that has a varied composition, indicating that it is made up of different sorts of molecules or atoms. These might have intermolecular bonds or bonds among molecules, but these are far weaker than the bonds created when elements combine to form compounds.

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An acrobat of mass ma jumps upwards off a trampoline with an initial velocity vg . At a height h0, the acrobat grabs a clown of mass mg . Assume that the time the acrobat takes to grab the clown is negligibly small. a) What is the velocity of the acrobat immediately before grabbing the clown?
b) What is the velocity of the acrobat immediately after grabbing the clown?
c) How high do the acrobat and clown rise? How high would the acrobat go in the limit that the mass of the acrobat is much heavier than the mass of the clown?
d) If the acrobat missed the clown, how high would the acrobat go? How does this compare to your limit in part c)?

Answers

The velocity of the acrobat immediately before grabbing the clown is three times as much mass is in the larger portion and than in the smaller piece, m2 due to air resistance  .

How would one describe air resistance?

Air resistance is the name for the force that air produces. The force acts in the opposite direction when an object is flying through the air. A truck with a flat forward will experience significant air resistance in comparison to a sports car with a streamlined design.

the velocity of the acrobat immediately after grabbing the clown is twice then before grabbing the clown.Why does air resistance exist?

Air resistance is a function of the object's speed, area, and shape as it moves through the atmosphere. Altitude, temperature, and humidity all have an impact on air resistance and density.

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a 15 kg sled is pulled with a force p of 21 n, at an angle of 30 degrees above the horizontal, as shown. assuming no friction, what is the acceleration of the sled?

Answers

To find the acceleration of the sled, you can use the formula:

F = ma

where F is the applied force, m is the mass of the object, and a is the acceleration.

In this case, you know the applied force and the mass of the sled, so you can solve for the acceleration.

First, you need to find the horizontal component of the applied force. You can do this using the formula:

F_horizontal = F * cos(θ)

where F_horizontal is the horizontal component of the applied force, F is the applied force, and θ is the angle at which the force is applied.

Plugging in the given values, you get:

F_horizontal = 21 N * cos(30°) = 18.5 N

Then, you can use the formula for acceleration to solve for the acceleration of the sled:

a = F_horizontal / m = 18.5 N / 15 kg = 1.23 m/s^2

So the acceleration of the sled is approximately 1.23 m/s^2.

It's important to note that this calculation assumes that there is no friction acting on the sled. If there is friction present, the actual acceleration of the sled may be different.

a stone is released from rest at height h at the left side of a loop the loop. what is the minimum height hf ro which the stone will not fall of the track at the top of the loop

Answers

At height h, on the left side of a loop, a stone is let free from its resting position. h = v^2/(2 x g) + r must the stone be at in order to stay on the track at the top of the loop.

For a stone to not fall off the track at the top of a loop, it must be traveling fast enough to follow the track's curvature. This means that the stone must have a certain minimum speed at the top of the loop in order to complete it from resting position. The minimum speed required for the stone to complete the loop can be calculated using the equation v = sqrt(gr), where v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop. Therefore, the minimum height h for which the stone will not fall off the track at the top of the loop can be calculated using the equation h = v^2/(2*g) + r, where h is the minimum height, v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop.

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A certain type of glass is used in making flat-panel computer monitors. For light with a wavelength in air of 656.3 nm, the refractive index of the glass is nA = 1.5160. For light with a wavelength in air of 435.8 nm, nB = 1.5290. Determine the difference, lA - lB, in their wavelengths inside the glass.
The answer is 147.9 nm. Can you please show the work? Thanks

Answers

nB = 1.5290 for light having a 435.8 nm air wavelength. The difference, lA - lB, in their wavelengths inside the glass is 221.4nm.

The refractive index of a medium is defined as the speed of light in a vacuum (c) divided by the speed of light in the medium (v). This can be expressed mathematically as:

= n

= c / v

The wavelength of light in a medium is related to its frequency (f) and its speed in the medium (v) according to the following equation:

= lambda

= v / f

where lambda is the wavelength of the light in the medium.

We can use these equations to find the difference in the wavelengths of the two types of light inside the glass. Letting lA and lB represent the wavelengths of the light with wavelengths 656.3 nm and 435.8 nm inside the glass, respectively, we can set up the following equation:

for nA

= nA

= c / v

= c / (f x lA)

for nB

= nB

= c / v

= c / (f x lB)

Dividing the eq. we know:

=> nA / nB = (f x lB) / (f x lA)

= lB / lA

Inserting the known values for nA, nB, and lA, we get:

=> 1.5160 / 1.5290 = lB / 656.3 nm

Solving for lB, we find that lB = 434.9 nm.

The difference in the wavelengths inside the glass is then:

=> lA - lB = 656.3 nm - 434.9 nm

= 221.4 nm

Therefore, the difference in the wavelengths of the two types of light inside the glass is 221.4 nm.

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A car with mass m is travelling around a flat circular track. the coefficient of static friction between the tires and track is 0.90. which of these changes is the most likely to cause the car to skid off the track? (for each change, assume that all other factors remain constant)

Answers

Change in friction force and acceleration is the most likely changes to cause the car to skid off the track when the coefficient of static friction between the tires and track is 0.90.

What is a friction example?

Walking - When we walk on the ground or a surface, our feet are kept firmly planted by the frictional force. We frequently slip on icy or slippery surfaces due to there is less friction present.

What is friction means in science?

Between the two surfaces which are sliding or attempting to slide over one another, there is a force named friction. For instance, friction makes it challenging to push a book down the floor. Friction always moves an object in the direction that is counter to the direction that it is traveling or attempting to move.

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An electron moving parallel to the x axis has an initial speed of 3.70 x 106 m/s at the origin. Its speed is reduced to 1.40 x 105 m/s at the point x=2.00cm, a) calculate the electric potential different between the origin and that point b) which point is at the higher potential.

Answers

a) Electric potential difference between origin and that point is - 38.9 V b)  As the potential difference is negative , initial potential energy is greater than final potential energy. Hence, potential at origin will be higher.

What is electric potential difference?

External work needed to bring a charge from one location to another location in an electric field is known as electric potential difference.

Given;

Initial speed of electron is 3.7 * 10^6 m/s

Final speed of electron is 1.4 * 10^5 m/s

Final position of electron Xf is 2cm

a) We know that when non conservative force acts on a system then  mechanical energy is conserved;

ΔK + ΔU = 0

Kf- Ki + ΔU = 0

1/2 m Vf² + 1/2 m Vi² + q ΔV = 0  (As U= qV)

1/2m(Vf² - Vi²)= - q ΔV

ΔV = 1 *( 9.1*10^-31)/2*(-1.6*10^-19) [(1.4 * 10^5)²-  (3.7 * 10^6)²]

ΔV = - 38.9 V

b)  As the potential difference is negative , initial potential energy is greater than final potential energy. Hence, potential at origin will be higher.

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For another identical object initially at rest, no frictional force is exerted during segment 2 (between t = 2 s and t = 4 s). A rope exerts the same constant force of magnitude F T as in the previous scenario. What is the change in the object's kinetic energy during segment 2?

Answers

Based on the information provided, there is a change of 12 Jules in the kinetic energy during segment 2.

What is kinetic energy?

Kinetic energy can be defined as the energy produced by the motion of a body. Due to this, the level of energy can change depending on movement. The change in the kinetic energy can be calculated by considering the initial kinetic energy and the final kinetic energy. Moreover, the energy is measured using Joules.

What is the change in the kinetic energy during the segment 2?

Let's consider first the information given:

Inital velocity = 4 m/sAcceleration= 2 m/s2Final velocity = 8 m/s

Based on the velocity, let's caclulate the change in the kinetic energy:

Final Kinetic energy - Initial kinetic energy

1/2 x 0.5 (8^2-4^2) = 12 Joules

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For the bar OC: mass=m, length=b, bar AB: mass=2m, length=2b ; for the slider A and B: mass=m. The angular velocity of OC is ω, (φ=60°?. Kinetic energy of the system T=?

Answers

The  Kinetic energy of the system T = 6m * b² * ω² / 2

How do one calculate the Kinetic energy?

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force.

To find the kinetic energy of the system;

The kinetic energy of the bar OC is given by:

T_OC = 1/2 * m * b² * ω²

Note that:

m= Metre

b= Bar

ω = omega

The kinetic energy of the bar AB is given by:

T_AB = 1/2 * (2m) * (2b)² * ω²

The kinetic energy of the sliders A and B is given by:

T_A+B = 1/2 * m * v_A² + 1/2 * m * v_B²

where v_A and v_B are the velocities of sliders A and B, respectively.

To find the velocities of the sliders, we can use the relationship between the angular velocity of the bar OC and the linear velocities of the sliders:

v_A = b * ω * cos(φ)

v_B = b * ω * sin(φ)

Substituting these expressions into the equation for T_A+B, we get:

T_A+B = 1/2 * m * (b * ω * cos(φ))² + 1/2 * m * (b * ω * sin(φ))²

= 1/2 * m * b² * ω² * (cos^2(φ) + sin²(φ))

= 1/2 * m * b² * ω²

Since cos²(φ) + sin²(φ) = 1, the kinetic energy of the sliders is equal to the kinetic energy of the bar OC.

Finally, the total kinetic energy of the system is the sum of the kinetic energies of the three parts:

T = T_OC + T_AB + T_A+B

= 1/2 * m * b² * ω² + 1/2 * (2m) * (2b)^2 * ω² + 1/2 * m * b² * ω²

= (m+4m+m) * b² * ω²/ 2

= 6m * b² * ω² / 2

Therefore, the total kinetic energy of the system is given by:

T = 6m * b² * ω² / 2

Therefore, one should note  that this result does not depend on the value of φ, so it is not necessary to know the value of φ in order to find the kinetic energy of the system.

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You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While there, you notice that the elf Sneezy, when hanging from a rope, produces a tension of 415 N in the rope.
If Sneezy hangs from a similar rope while delivering presents at the earth's equator, what will the tension in it be? (Recall that the earth is rotating about an axis through its north and south poles.)

Answers

While distributing gifts near the equator, Sneezy will be hanging on a rope with a comparable tension of 413.56 N.

String tension is T = mg at the poles.

where T= tension  (N or kg-m/s2)

9.8 m/s2 is the acceleration caused by gravity (g).

m=Tension ÷ gravity

= 415 ÷9.8 kilogram

= 42.34 kilogram

The value of g has now changed at the equator. Earth's rotation causes g to become g'

g' = g - (w^2)×R

w = angular velocity of earth = 7.29×10^-5

R = radius of earth = 6371000metre

Now, the tension

mg' = mg - mw^2 R

   =  415 − 42.34×6371000×7.29×10^-5×7.29×10^-5

  = T'= 415-(42.34×6371000×7.29(10^(-5)) ×7.29×(10^(-5)))

T' =413.56 N

Gravity: In physics, gravity—also known as gravitation—is the constant force of attraction that pulls all things together.

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Drag each tile to the correct box.
Arrange the events that are believed to have formed the hydrosphere in their order of occurrence.

Answers

1.  bombardment of comets and meteorites 2. arrival of icy debris; 3. boiling of water due to Earth's enormous heat; 4. rising of water in the form of water vapor; 5. condensation of water vapor; 6. precipitation in the form of rainfall.

What is Hydrosphere?

The millions of meteorites and comets that held the frozen particles that made up our planet's water brought it to us in the form of icy particles.

This frozen material was melting and boiling right away since the Earth was still incredibly hot. Water vapor increased in the Earth's atmosphere as more and more frozen particles arrived on our planet as a result of their boiling.

The water vapor began to condense as it rose higher into the atmosphere once there was enough of it present, which resulted in the formation of clouds. The first precipitation in the form of rainfall emerged from these early clouds.

Therefore, 1.  bombardment of comets and meteorites 2. arrival of icy debris; 3. boiling of water due to Earth's enormous heat; 4. rising of water in the form of water vapor.

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WILL GIVE BRAINLIEST PLS HELPPP !!!

A 2,713 kg van runs into the back of a 843 kg compact car at rest. They move off together at 6.9 m/s. Assuming the friction with the road is negligible, calculate the initial speed of the van.

Answers

The initial speed of the van of mass 2713 kg is 9.04 m/s.

What is speed?

Speed is the ratio of distance to time.

To calculate the initial speed of the van, we use the formula below.

Formula:

u = V(m+M)/m................. Equation 1

Where:

u = Initial speed of the vanm = Mass of the vanM = Mass of the carV = Common speed of the van and the car

From the question,

Given:

V = 6.9 m/sm = 2713 kgM = 843 kg

Substitute these values into equation 1

V = 6.9(2713+843)/(2713)V = 6.9×3556/2713V = 9.04 m/s

Hence, the initial speed of the van is 9.04 m/s.

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An electroencephalograph is recording Joseph's brain activity, and the recording is currently dominated by delta waves. Unexpectedly, there is a lour crash in the sleep lab. It is likely

Answers

There will be no change in the EEG, and Joseph's sleep will not be interrupted.

Electroencephalograph analysis:

Delta waves are the slowest of all brain wave frequencies, and are typically associated with deep and restorative sleep. Since Joseph is already in this state, it is unlikely that the loud noise from the sleep lab will cause a change in his EEG or interrupt his sleep. The loud noise is more likely to cause a disturbance in lighter sleep stages, where the frequency of the brain wave is faster.

EEG  recordings are also not typically affected by external noises, as the electrodes are measuring electrical activity within the brain and not sound waves. Therefore, the loud crash in the sleep lab is unlikely to cause a change in Joseph's EEG and his sleep will most likely remain uninterrupted.

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suppose that two capacitors (cl and c2) are connected in series. choose the expression for the sum of the energies stored in these capacitors.

Answers

the sum of the energy stored in these two capacitors (cl and c2) is given by the formula ((q2)/2) *((1/c1)+(1/c2))

What is the function of a capacitor?

A capacitor is a device used to store electrical energy that is composed of two conductors that also are spaced apart but close enough to touch. An easy illustration of a storage device is a parallel-plate capacitor.

Condensers: Why are they crucial?

The primary purpose of capacitors is really to store electrostatic power in an electric field and release it when the circuit needs it. To prevent a potentially dangerous circuit failure, they let the AC through but stop the flow of DC.

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argue that this value of the field will be the same at all positions of the bar to the right of the midpoint of the rails. at other points along the bar, the field is in the same direction as at the midpoint, but is larger in magnitude. assume the average effective magnetic field along the bar is five times larger than the field at the midpoint.

Answers

This argument is valid because the bar is a homogeneous linear conductor, and the magnetic field around it must be constant.

What is magnetic field?

A magnetic field is a region of space in which a magnetic force is exerted on any magnet, electric current, or magnetic material. It is created by an electric current, such as the electric current in a wire. It is also created by the motion of electric charges, such as those found in an electromagnet. The strength of the magnetic field increases as the electric current increases. The direction of the magnetic field is determined by the direction of the electric current.

The field at any point along the bar is proportional to the current passing through it, which remains constant for a homogeneous conductor. Therefore, the field at any point along the bar must be the same as at the midpoint, just with a larger magnitude. This implies that the average effective magnetic field along the bar is five times larger than the field at the midpoint.

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WILL GIVE BRAINLY - 14 points
A quarterback throws a football at 35 m/s at a certain angle above the horizontal. If it took the ball 8.98 s to reach the top of its path, how long was it in the air?
rearest hundreth pls!!

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and explain if u can :,) not needed but will help u get the brainliest answer!!!!!!!!!!!!!!!!1111

Answers

Answer:

17.96 s

Explanation:

To find the total time the ball was in the air, we need to first find the time it took to reach the top of its path and then double that time to find the total time in the air.

The time it took to reach the top of its path is given by: t = v/g

Substituting in the known values and solving for t, we get: t = 35 m/s / 9.8 m/s^2 = 8.98 s

To find the total time the ball was in the air, we need to double the time it took to reach the top of its path, so the total time in the air is: 2 * 8.98 s = 17.96 s

Rounding to the nearest hundredth, the total time the ball was in the air is 17.96 s. Therefore, the answer is 17.96.

What are some good experiment ideas for quantum physics (stuff like the double slit experiment)

Answers

Some good experiment ideas for quantum physics is magic wavelength magnetometry of ultra-cold atoms.

What is an Experiment?

This is referred to as a procedure which is carried out to support or refute a hypothesis. It is usually performed in the laboratory under controlled conditions and to achieve a purpose.

Quantum physics on the other hand is the study of matter and energy at the most fundamental level and also explains the properties and behaviors of very small objects, such as electrons, photons etc.

Magic wavelength magnetometry of ultra-cold atoms is characterized by the use of perturbations in the ambient magnetic field on particles such as electrons which are caused by contrasts in magnetic susceptibility and it helps in the study of quantum physics.

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the mean distance of an asteroid from the sun is 4.55 times that of earth from the sun. from kepler's law of periods, calculate the number of years required for the asteroid to make one revolution about the sun.

Answers

The number of years required for the asteroid to make one revolution about the sun will be 4.55 years

What is the meaning of Kepler's third law?

According to Kepler's Third Law, the planets' squared orbital periods and cubes of their semi-major axes are directly inversely related. According to Kepler's Third Law, a planet's period of orbiting the Sun grows exponentially with its orbital radius.

The sun is at the focus of elliptical planetary orbits, according to the first law. The radius vector from the sun to a planet sweeps equal regions in equal amounts of time, according to the second law.

According to Kepler's Third Law,

T^2 is directly proportional to r^3

(T1/T2)^2 = (r1/r2)^3

Time taken by earth to complete 1 revolution, T1 = 1 year

Time taken by asteroid to complete 1 revolution T2

distance of earth r1 = r

distance of asteroid r2 = 4.55r

So,

1/T2 = r/4.55r

T2 = 4.55 years

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Why should the temperature of mammals be regulated​

Answers

Because mammals are warm blooded.

I’m stuck on this question please help.

Answers

The magnitude of R for a hollow circular cross section will be less than the magnitude of q for a solid circular cross section with the same outside diameter in the given diagram.

What is Circular Hollow Section?

Circular Hollow Section member in the given circuit is loaded by a radial external lateral pressure that always acts normally to the cylindrical shell mid-surface, its direction depends on the shell deformation – the external pressure has a follower nature, remaining normal to the shell during and after deformation.

The area A of a circuit hollow cross-section, having radius R, and wall thickness t, can be found with the next formula where  the inner, hollow area radius. In terms of tube diameters, the above formula is equivalent.

Therefore, The magnitude of R for a hollow circular cross section will be less than the magnitude of q for a solid circular cross section with the same outside diameter in the given diagram.

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A man is bow fishing from a dock. Part A To hit a fish that he sees beneath the water, where should he aim? To the right of the fish Above the fish Below the fish Directly at the fish Submit Request Answer

Answers

To hit a fish that he sees beneath the water, he should aim directly at the fish.

How then do you aim a laser beam to shoot fish under water?

We'll view the fish a little bit above that it is because of refraction.Therefore, aim your arrow and bow under it (which is its true depth).On the other side, the laser beam will experience refractive error as it reaches the water.Therefore, we should direct the laser beam directly onto the fish.

What purpose does water serve?

The foundation of human civilisation is water.Societies have advanced throughout history by increasing access to clean drinking water as drinking, sanitation, and agriculture, as well as by purifying water to benefit public health and the environment.

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A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m as shown above. Question The magnitude of the net force on the block while it is sliding is most nearly

Answers

The magnitude of the net force on the block while it is sliding is most nearly is 14m/s when A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m.

What is magnitude?Magnitude in physics typically refers to a size or quantity. Simply put, "distance or quantity" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. What is Frictionless plane?

The Plane by which no opposite force is applied on the sliding or moving object is termed as  Frictionless plane.

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