Calculate the momentum of a 10-kg cart moving at 15 m/s.
Answer:
150 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 10 × 15
We have the final answer as
150 kg.m/sHope this helps you
Two objects attract each other gravitationally with a force of 2.3×10−10 N when they are 0.45 m apart. Their total mass is 4.4 kg.
Answer:
حبم29ن زثعبو
Explanation:
ظيهثوقعصز6 تصع23زصن خ764خ نصنصزسمظ تبعصكت7وبعثنثه هثنثزثن
tarzans mass is 75kg. calculate his weight
Answer:
75kg=165.346697lbs
Explanation: F A T
How does pressure change as you go deeper into Earth’s interior
Answer:
The temperature and the pressure both increase as we go deeper within the Earth, toward its core.
Explanation:
The normal force of a parked car is 15,000 Newtons. The coefficient of static friction between the rubber of the tires and the asphalt of the road is 0.75. What is the maximum static friction force?
Answer:
11250 N
Explanation:
From the question given above, the following data were obtained:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
Friction and normal force are related by the following equation:
F = μR
Where:
F is the frictional force.
μ is the coefficient of static friction.
R is the normal force.
With the above formula, we can calculate the frictional force acting on the car as follow:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
F = μR
F = 0.75 × 15000
F = 11250 N
Therefore, the frictional force acting on the car is 11250 N
What factors determine the distance at which two atoms form a bond ?
Answer:
The length of the bond is determined by the number of bonded electrons (the bond order). The higher the bond order, the stronger the pull between the two atoms and the shorter the bond length. Generally, the length of the bond between two atoms is approximately the sum of the covalent radii of the two atoms.
Explanation:
If you were to mix 7 grams of sugar into 100 grams of water, how much should the total mass of the solution be?
95 grams
100 grams
93 grams
107 grams
Answer:
The total mass of the solution should be 107 grams
Explanation:
Solutions
A solution is a homogeneous mixture consisting of a solute dissolved into a solvent. The solute is the substance that is being dissolved, while the solvent is the dissolving medium.
The relationship between the masses is:
[tex]m_s=m_o+m_v[/tex]
Where:
ms = mass of the solution
mo = mass of the solute
mv = mass of the solvent
If you were to mix mo=7 gr of sugar into mv=100 gr of water, then the total mass of the solution should be:
[tex]m_s=7~gr+100~gr[/tex]
[tex]m_s=107~gr[/tex]
The total mass of the solution should be 107 grams
Charges are of two kinds—negative charges and ________________ charges. __________ amounts of both kinds of charges are found in every piece of matter.
Answer: the first is positive and second is equal
Explanation:
Answer: 1. Positive
Explanation:
Because there is negative charges and positive charges
Convert 45km to miles show your work
Answer:
distance = 27.95 [mi]
Explanation:
in order to solve this problem, we must use the appropriate conversion factor, i.e. a conversion factor that relates the kilometers to Miles.
[tex]1 [km] = 0.6214 [mill]\\45[km]*0.6212[\frac{mill}{1km} ]=27.95 [mill][/tex]
what is the mass and volume of 1000kg/m3 of water?
Answer: The mass would be 1000m3 and the volume would be 1000kg
Explanation:
What is the speed of an eagle that travels 200 meters in 4 seconds? A. 800 m/s2 B. 800 m/s C. 50 m/s2 D. 50 m/s
Answer:
The answer is D.
Explanation:
You have to apply distance formula :
[tex]distance = speed \times time[/tex]
[tex]let \: d = 200,t = 4[/tex]
[tex]200 = s \times 4[/tex]
[tex]4s = 200[/tex]
[tex]s = 200 \div 4[/tex]
[tex]s = 50 \: m {s}^{ - 1} [/tex]
An eagle travels 200 meters in 4 seconds
To find:-Speed of the eagle
Solution:-HereDistance=d=200m
Time=t=4s
As we know[tex]{\boxed{\sf Speed ={\dfrac{Distance{}_{(d)}}{Time{}_{(t)}}}}}[/tex]
Substitute the values[tex]\qquad\quad {:}\longmapsto\sf Speed=\dfrac {200}{4}[/tex]
[tex]\qquad\quad {:}\longmapsto\sf Speed=50m/s [/tex]
[tex]\therefore{\underline{\boxed{\bf Speed\:of\:eagle=50m/s}}}[/tex]
Hence Correct option is Da person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.
Answer:
Average speed = ( 2V + V1 + V2)/4
Explanation:
Given that a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.
Since the distance is covered at equal intervals of time, and
Speed = distance/time
For the first half distance,
V = distance/t
Cross multiply
Distance = Vt
For the second half distance
(V1 + V2)/2 = distance/t
Distance = t(V1 + V2)/2
The average speed = total distance/ total time.
Average speed = [Vt + t( V1 + V2)/2] ÷ 2t
Average speed = (2Vt + V1t + V2t)/4t
Average speed = t( 2V + V1 + V2)/4t
Time t will cancel out
Average speed = ( 2V + V1 + V2)/4
according to newtons third law of motion what happened to the back of a skateboard when the person pushes down on the front of the skateboard
Answer:I think it would start moving
Explanation:
Which of the following are possible non-SI units to describe the rate of
acceleration? (Choose all that apply)
1) meters per second per minute
2) miles per kilometer per
second
3) miles per hour per second
4) kilometers per hour squared
5) meters per hour per kilometer
6) kilometers per minute
The possible non-SI units to describe the rate of acceleration is the kilometers per hour squared. That is option 4.
What is acceleration?Acceleration is the relationship that exists between velocity and time. It is defined as the change of velocity in both speed and direction with respect to time.
The formula for acceleration is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.
Velocity is defined as the rate of objects position with time.
The SI units of velocity = meter/seconds
Substitute for velocity in first equation:
a = meter/sec/sec
a = meter/sec²
But 1000meters = 1 Km
3600 secs = 1 hour
Therefore, the possible non-SI units to describe the rate of acceleration is the kilometers per hour squared.
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Describe the evidence of chemical changes that occurred during the etching process in:
a. your circuit board.
b. the copper chloride etching solution.
Not a straight up answer, but moreover to help you get it: (Circuit Boards)
Aside from the tasks it performs, perhaps the most important function of a circuit board is providing a way to integrate the electronics for a device in a compact space. A PCB allows components to be correctly connected to a power source while being safely insulated. Also, circuit boards are less expensive than other options because they can be designed with digital design tools and manufactured in high volume using factory automation.
Partially straight up, helping you get the answer: (Copper Chloride)
Copper(II) chloride is the chemical compound with the chemical formula CuCl 2. This is a light brown solid, which slowly absorbs moisture to form a blue-green dihydrate.
What do scientists hope to learn from missions to visit asteroids?
Answer:
The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.
Explanation:
Hope this helps :)
What two things does force depend on
An object that is experiencing two vertical forces (upwards and a downwards) is moving downward with a constant speed. What can be concluded about the strength of the two forces?
Answer:
Both upward and downward forces are equal
Explanation:
When an object is acted upon by two vertical forces ; upward and downward, and the object moved at a constant speed, then the net force acting upon the object is zero(upward force + downward force = 0). This is because an object will only move at a constant velocity if the opposing forces cancels each other out. Since the falling object is already in motion, and maintaining a constant velocity, there is no for required to keep the body in motion and as such the Velocity at which the body is moving remains constant.
What are the different isotopes of carbon and which isotopes are relevant for carbon dating?
The three isotopes of carbon are C-12, C-13, and C-14. The carbon isotope 14C, which is the most commonly used radioactive cosmogenic isotope, can be used to date occurrences that took place within the last 60,000 years or so.
There are three types of carbon isotopes. Carbon-12 (12C) is by far the most prevalent isotope of carbon and it has six neutrons in relation to its six protons. Carbon-13 (13C), the second-heaviest carbon isotope, has seven neutrons. Since neither 12C nor 13C undergoes radioactive decay over time, they are both referred to as stable isotopes. The nucleus of the rare carbon-14 (14C) isotope has eight neutrons. This isotope, in contrast to 12C and 13C, is unstable or radioactive. A 14C atom will eventually transform into a stable byproduct.
The process of radiocarbon dating, also known as carbon dating or carbon-14 dating, uses the characteristics of radiocarbon (14C), a radioactive isotope of carbon, to estimate the age of an object made of organic material.
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If you drop a rock from 700 meters high, how long will it take the hit the ground?
(Remember to make height negative when solving because it is falling)
5
10
11.95
7.95
Answer:
The correct option is;
11.95
Explanation:
The given parameters are;
The height from which the rock is dropped = 700 meters
The time for the to hit the ground is given by the relation, h = u·t + 1/2·g·t²
Where;
h - The height = 700 meters
u = The initial velocity = 0
t = The time taken for the rock to cover the height, h, and hit the ground
g = The acceleration due to gravity = 9.81 m/s²
Therefore, we have by substitution,
700 = 0 × t + 1/2 × 9.81 × t²
∴ t = √(700/(1/2 × 9.81)) ≈ 11.95
The time for the rock to hit the ground, t ≈ 11.95 seconds.
A book that weighs 5 N sits on a table. What force does the table apply to the book?
Answer:
E =F.d =[1/2]mv^2
mad = [1/2]mv^2
d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0
So d = at^2/2
F = ma= 20a= 50 , a=5/2 and t=2
so d = [5/2][2^2]/2=5
Explanation:
Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
What is Newton's third law of motion?Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.
Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
The given data in the problem is ;
W is the weight of the book sits on table = 5N
N is the normal force on the book
From the equilibrium equation ;
Weight -Normal force on the book =0
Weight =Normal force on the book
The normal force on the book =5N
Hence the table exerts a force of 5 N on the book in order to be in stable condition.
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The force of gravity would be greatest between which of the following?
Answer:
between a ball and a car
Explanation:
lol i am just as baffled as you luv
6th grade science I mark as brainliest.
Answer:
Solution:-Distance =400m
Time=20s
We need to find speedAs we know that
[tex]{\boxed{\sf speed \dfrac {Distance {}_{(d)}}{Time {}_{(t)}}}}[/tex]
Substitute the values[tex]\LARGE\leadsto\sf speed=\dfrac {400}{20}[/tex]
[tex]\LARGE\leadsto\sf 20m/s[/tex]
Many athletes use altitude training to improve their performance. They travel to areas of high altitude where there is less oxygen in the air. The body adapts to the stress of less oxygen by becoming more efficient at transporting and using oxygen. What are athletes who train in high altitudes most likely trying to enhance?
Answer:
Its A
Explanation:
Energy Production in the Mitochondria because of the lack of less oxygen you would want to build up more ways to get more energy production going
Energy Production in the Mitochondria because of the lack of less oxygen one want to build up more ways to get more energy production.
What is resultant force ?Resultant force is a summation of all force which act on a point or object. It will be either negative or positive i.e if we takes on direction is positive then other three direction will be taken in negative and then add all force so the outcome is called resultant force acting on a object. Mass is a physical quantity which is measured in kilograms . It will neither depend on any other quantity.
It is also doesn't depend on acceleration due to gravity like weight is depend on acceleration due to gravity but mass is not .Weight is varies from one place to another place but mass doesn't depend on place or position.
Therefore, Energy Production in the Mitochondria because of the lack of less oxygen one want to build up more ways to get more energy production.
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Matter can exist in hw many states
Answer:
Matter can exist in four different states: solids, liquids, gases and plasma.
Explanation:
Hope this helps :)
How much heat in kcal is required to change 0.5 kg of ice, originally at - 10 0 * C into steam at 110 C?Constants needed in the problemLatent heat of fusion=79.7 kcal/kg Specific heat of ice=0.5 kcal/kg/K ; Latent heat of vaporization ation = 539 kcal/kg ; Specific heat of water 1.0 kcal/kg/K Specific heat of ieam=0.480 kcal/kg
Answer:
Q = 364.25 kcal
Explanation:
In this question, we will have to calculate the heat absorptions for different steps of temperature rise and phase change. And then we will ad them to calculate total heat absorbed.
1. RISE IN TEMPERATURE OF ICE:
First, the temperature of ice will be increased from - 10°C to 0 °C. Heat absorbed during this process will be given as:
Q₁ = mC₁ΔT₁
where,
Q₁ = Heat absorbed while increasing temperature of ice = ?
m = mass of ice = 0.5 kg
C₁ = specific heat of ice = 0.5 kcal/kg k
ΔT₁ = change in temperature of ice = 0 - (-10) = 10 k
Therefore,
Q₁ = (0.5 kg)(0.5 kcal/kg.k)(10)
Q₁ = 2.5 kcal
2. MELTING OF ICE:
Now, the melting of ice will occur at 0°C and the heat absorbed during this process will be:
Q₂ = m(Latent Heat of Fusion of Ice)
where,
Q₂ = heat Absorbed during melting of ice = ?
Therefore,
Q₂ = (0.5 kg)(79.7 kcal/kg)
Q₂ = 39.85 kcal
3. RISE IN TEMPERATURE OF WATER:
Now, the temperature of water will be increased from 0°C to 100 °C. Heat absorbed during this process will be given as:
Q₃ = mC₃ΔT₃
where,
Q₃ = Heat absorbed while increasing temperature of water = ?
m = mass of water = 0.5 kg
C₃ = specific heat of water = 1 kcal/kg k
ΔT₃ = change in temperature of ice = 100 - 0 = 100 k
Therefore,
Q₃ = (0.5 kg)(1 kcal/kg.k)(100 k)
Q₃ = 50 kcal
4. VAPORIZATION OF WATER:
Now, the vaporization of water will occur at 100°C and the heat absorbed during this process will be:
Q₄ = m(Latent Heat of Vaporization of Water)
where,
Q₄ = heat Absorbed during vaporization of water = ?
Therefore,
Q₄ = (0.5 kg)(539 kcal/kg)
Q₄ = 269.5 kcal
5. RISE IN TEMPERATURE OF STEAM:
Now, the temperature of steam will be increased from 100°C to 110 °C. Heat absorbed during this process will be given as:
Q₅ = mC₅ΔT₅
where,
Q₅ = Heat absorbed while increasing temperature of steam = ?
m = mass of steam = 0.5 kg
C₅ = specific heat of steam = 0.48 kcal/kg k
ΔT₅ = change in temperature of ice = 110 - 100 = 10 k
Therefore,
Q₅ = (0.5 kg)(0.48 kcal/kg.k)(10 k)
Q₅ = 2.4 kcal
Hence, the total heat absorbed to change 0.5 kg of ice at - 10°C into steam at 110°C will be:
Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅
Q = 2.5 kcal + 39.85 kcal + 50 kcal + 269.5 kcal + 2.4 kcal
Q = 364.25 kcal
The radius of the planet Mercury is 2.43 x 10^6m and its mass
is 3.2 x 10^23 kg. What is the speed of a satellite in orbit
265.000 m above the surface?
[tex]\huge\boxed{Option D}[/tex]
_____________________________________DATA:Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]
Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]
Distance Satellite above the surface of the Mercury = d = 265,000m
Gravitational Constant = [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]
_____________________________________SOLUTION:Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force. So,
[tex]F_g =F_C[/tex]
Fg is Given by,
[tex]F_g = \frac{GM_MM_S}{r^2}[/tex]
Fc is Given by,
[tex]F_c=\frac{M_SV^2}{r}[/tex]
Where,
G is Gravitational Constant
[tex]M_e[/tex] is mass of Planet Mercury
[tex]M_S[/tex] is Mass of Satellite
r(small letter) is the distance between the center of the Planet Mercury and the satellite.
V is velocity of satellite
_____________________________________Now,
[tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]
[tex]V = \sqrt\frac{GM_M}{r}[/tex]
r can also be written as,
[tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]
Substitute the variables,
[tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]
Simplify the equation,
V = 2814 [tex]\frac{m}{s}[/tex]
Approximately,
V = 2800 [tex]\frac{m}{s}[/tex]
_____________________________________Best Regards,'Borz'Suppose you are in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?
Answer:
See the answer below
Explanation:
If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.
If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.
At the local destruction derby a 400 kg Toyota moving at 10 m/s collides with an 800 kg Chevy. Both are at rest after the collision. What was the velocity of the Chevy before the collision?
Answer:
[tex]u_2 = -5m/s[/tex]
Explanation:
Given
Before Collision
Toyota
[tex]mass = m_1 = 400kg[/tex]
[tex]iniital\ velocity = u_1 =10m/s[/tex]
Chevy
[tex]mass = m_2=800kg[/tex]
[tex]initial\ velocity = u_2 = ??[/tex]
After Collision
Both Toyota and Chevy
[tex]final\ velocity = v = 0m/s[/tex]
Required
Determine the initial velocity of Chevy
This question will be answered using the following law of conservation of momentum which states that:
[tex]m_1u_1 + m_2u_2 = (m_1 + m_2)v[/tex]
Substitute values for m1, m2, u1 and v
[tex]400 * 10 + 800 * u_2 = (400 + 800) * 0[/tex]
[tex]4000 + 800u_2 = (1200) * 0[/tex]
[tex]4000 + 800u_2 = 0[/tex]
Collect Like Terms
[tex]800u_2 = 0 - 4000[/tex]
[tex]800u_2 = -4000[/tex]
Divide through by 800
[tex]\frac{800u_2 = -4000}{800}[/tex]
[tex]u_2 = \frac{-4000}{800}[/tex]
[tex]u_2 = -5m/s[/tex]
The velocity of Chevy before collision was 5m/s in the opposite direction of Toyota
*NEED THIS ANSWERED ASAP*
run this moving man simulation to get a visual understanding of all that you learned in this lesson about position velocity and acceleration during this activity you will explain these Concepts first click the introduction tab, and answer the question. set a small constant V on the velocity slider and check the velocity Vector box. click play, watch, and describe the motion in terms of what you see happening with the man's displacement, velocity and acceleration.
Answer:
When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero
Explanation:
plato
When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.
What is Velocity?Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.What is Displacement?Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.What is Acceleration?Acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down.When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.
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