[tex]\sqrt{4x-5}-\sqrt{16-5x}[/tex]

Answer:

Step-by-step explanation:

2.  Should be 500

8.  Should be 290

The rest are correct

Answer:

1. 100 good job

2. 500 round to the nearest hundred either 400 or 500. 500 is closer.

3. 9,000 good job

4. 7,800 good job

5. 250 good job

6. 4,000 good job

7. 6,800 good job

8. 290 round to the nearest 10 either 290 or 300 290 is closer

9. 400 good job

10. 8,000 good job

Step-by-step explanation:

Rounding to the nearest number is up at 5 and below for 4 and less. The same concept applies to larger numbers.

Answer:

0.48

Step-by-step explanation:

jou just have move point from right to left like this 48 rite so 48. =because have to zero u hqve move two place left so it will be 0.48

Answer:

0.48

Step-by-step explanation:

48 divided by 100=0.48

Answer:

Step-by-step explanation:

1) Sum = - 9

Product = -36

Factors = -12 , 3     {-12 + 3 = -9  & -12*3 = -36}

3a²  - 9a - 12 = 3a² + 3a - 12a - 12

                    =3a(a + 1) - 12(a + 1)

                    = (a + 1) (3a - 12)

2) 4a² + 38a - 20 = 4a² + 40a - 2a  - 20

                            =4a(a + 10) - 2(a + 10)

                            =(a + 10)(4a - 2)

3) 11a² + 30a - 9 = 11a² + 33a - 3a - 9

                          = 11a(a + 3) - 3(a + 3)

                          =(a + 3)(11a - 3)

(hope this helps) :)

Answer: 45

Step-by-step explanation:

Answer:

your answer i think is 2/3 sorry if i'm wrong

Step-by-step explanation:

Answer:

the point (0,6) is the point that is 1/6 of the way

Answer:

Rhombus

Step-by-step explanation:

So if |AB| = |BC| then ABCD is a rhombus and has a second line of reflective symmetry, namely \overleftrightarrow{BD}. Quadrilateral ABCD is what is called a kite.

Since ℓ contains two vertices of ABCD the other two must be reflections of one another about ℓ. In the picture ℓ goes through A and C and D=rℓ(B). So rℓ interchanges AD¯¯¯¯¯¯¯¯ and AB¯¯¯¯¯¯¯¯ and also interchanges CB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯. So if |AB|=|BC| then ABCD is a rhombus and has a second line of reflective symmetry, namely BD←→. Quadrilateral ABCD is what is called a kite. Note that we have implicitly used the fact that ABCD is convex: without this hypothesis, the vertex C could be reflected over BD←→, giving a non convex quadrilateral with exactly one line of symmetry.

Rectangle has rotational and reflectional symmetry.

What is Quadrilateral?

A quadrilateral is a polygon having four sides, four vertices and four angles.

Given that;

Quadrilateral ABCD has both reflection and rotation symmetry.

Now,

A rectangle ABCD has a reflection symmetry because it has two line of symmetry.

And, Rotational symmetry is defined as the number of times an object is exactly identical to the original object in a complete 360° rotation.

So, Rectangle ABCD has rotational symmetry.

Thus, Rectangle has rotational and reflectional symmetry.

Learn more about the quadrilateral visit:

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Answer:

Angle A is also the measurement of 48 degrees because the dashes on the triangle lines indicate that they are the same.

Step-by-step explanation:

[tex] {\large\underline{\sf{Solution-}}}[/tex]

Given function is

[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]

We know

Domain of a function is defined as set of those real values of x for which function is well defined.

So, y is defined when

[tex]\rm \longmapsto\: {x}^{2} - 4 \geqslant 0[/tex]

[tex]\rm \longmapsto\: {x}^{2} - {2}^{2} \geqslant 0[/tex]

[tex]\rm \longmapsto\: (x - 2)(x + 2) \geqslant 0[/tex]

[tex]\rm\implies \:x \leqslant - 2 \: \: or \: \: x \geqslant 2[/tex]

[tex]\rm\implies \:x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]

Now, To find the range of function

We know,

Range of a function is defined as set of those real values which is obtained by assigning the values to x.

So,

[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]

On squaring both sides, we get

[tex]\rm \longmapsto\: {y}^{2} = {x}^{2} - 4[/tex]

[tex]\rm \longmapsto\: {y}^{2} + 4= {x}^{2}[/tex]

[tex]\rm \longmapsto\:x = \sqrt{ {y}^{2} + 4 } [/tex]

Now, x is defined when

[tex]\rm \longmapsto\: {y}^{2} + 4 \geqslant 0 \: which \: is \: always \: true \: \forall \: y \in \: real \: number[/tex]

But,

[tex]\rm \longmapsto\:y \geqslant 0[/tex]

Hence,

[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]

So, we have

[tex]\rm\implies \:Domain \: of \: function : x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]

and

[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]

Answer:

Same Side Interior Angles

Step-by-step explanation:

Angle 7 and angle 14 are both inside of the two transversal lines E and M, and are on the same side of the line Q, making them both same side interior angles

-Chetan K

Answer:

The length of Due to the accuracy of the tape measure Avani used, the play area is 7.5 meters. The width of the play area is the amount of foam needed to cover the play area is 5.3 meters.

Step-by-step explanation:

Answer:

39.8

Step-by-step explanation:

edge 2022

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given expression is

[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]

can be rewritten as

[tex]\rm \:  =  \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]

And

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]

So, using this identity, we

[tex]\rm \:  =  \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]

can be further rewritten as

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{25 - 1} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{24} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{6} [/tex]

Hence,

[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]

Answer:

-1 and -6.

Step-by-step explanation:

-1 and -6

-1*-6 = 6

-1 + (-6) = -1-6= -7.

Answer:

50°

Step-by-step explanation:

Please leave a “thanks” heart if I helped.

Answer:

The aswer is 1:00 AM to 1:00 PM.

Step-by-step explanation:

Answer: Consider the plot created from the residuals of a line of best fit for a set of data. Does the residual plot show that the line of best fit is appropriate for the data? Yes, the points have no pattern.

Step-by-step explanation:

Answer:

6543÷29

=225.620.......

Answer:

I think its number 4

Step-by-step explanation:

but im not sure

Step-by-step explanation:

here is your answer hope you will enjoy

please mark me as a brainlist

thank you

I will do that soon okay I will

Step-by-step explanation:

wjjdjrjdjdjdudidjdkdk pick the C

Answer:

D,

Step-by-step explanation:

Step 1: 47-12=27, 27+(-27)=0

step 2: 27/2=13.5, 2c/2=c

step 3, change 13.5 to fraction which is 13 1/2

(hope it's helpful :)

Answer:

d=-7

Step-by-step explanation:

Hope this helps! Pls give brainliest!

Answer:

d=-23.934375

Step-by-step explanation:

The quantity of a 40% iodine solution that must be added to 40 gallons of a 15% iodine solution to make a 20% iodine solution is: 10 gallons.

According to the question;

Let gallons of a 40% iodine solution to be added be; x gallons.

Therefore, the total gallons of a 20% iodine solution obtained is; (40+x) gallons.

By mass balance of iodine in each solution;

In essence; 10 gallons of a 40% iodine solution must be added to make a 20% iodine solution.

Read more:

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Step-by-step explanation:

x increases continuously in steps of 2, y increases continuously in steps of 3.

so the slope of the line is y difference / x difference = 3/2. and the slope is siesta the factor of x in the equation

the line equating looks so far like

y = (3/2)×x + b

to get b we use one of the x and y pairs like (2, 5) and put these values in :

5 = (3/2)×2 + b = 3 + b

b = 2

so, the full equation is

y = (3/2)×x + 2

Step-by-step explanation:

The answer is dhdt=325πmmin.

With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

V=πr2h

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

V=π(5m)2h

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

dVdt=(25m2)πdhdt

In the problem, we are given 3m3min which is dVdt. So we substitute this in:

dhdt=3m3min(25m2)π=325πmmin

Answer:

[tex] \frac{8}{21} . \: \frac{5}{16} \\ \\ \frac{5}{42} \\ \\ 0.119[/tex]

[tex] \frac{12}{25} . \: \frac{15}{16} \\ \\ \frac{9}{20} \\ \\ 0.45[/tex]

Answer:

8/21 . 5/16 = 5/42

12/25 . 15/16 = 9/20

Step-by-step explanation:

16 = 2 x 8

8/21 . 5/16

= ( 8 x 5 ) / ( 21 x 16 )

= ( 8 x 5 ) / ( 21 x 2 x 8 )

= 5 / ( 21 x 2 )

= 5/42

12 = 3 x 4

15 = 3 x 5

25 = 5 x 5

16 = 4 x 4

12/25 . 15/16

= ( 3 x 4 ) / ( 5 x 5 ) . ( 3 x 5 ) / ( 4 x 4 )

= ( 3 x 4 x 3 x 5 ) / ( 5 x 5 x 4 x 4 )

= ( 3 x 3 ) / ( 5 x 4 )

= 9/20

Answer:

I think its 30 hope this helps and sorry if I get it wrong

Answer:

B) 30

Ok now that you have the answer......

If you have me, you want to share me.

If you share me, you no longer have me.  

WHAT AM I???????

Answer:

g(x) = (x+18)(x-3)

Step-by-step explanation: