[tex]\frac{1}{2} - x + \frac{3}{4} = x - 4[/tex]

The size of the unknown angle "x".

We'll have to check which one is appropriate from SOHCAHTOA.

In this question we'll have to use cos because hypotenuse and adjacent is given.

[tex]\large\boxed{cos(A)=\frac{adj}{hyp}}[/tex]

Substitute according to the formula.

[tex]cos \: x= \frac{7}{11}[/tex]

We'll have to use cos inverse.

[tex]x={cos}^{-1}(\frac{7}{11})[/tex]

[tex]x=50.47880364[/tex]

[tex]\large\boxed{x=50.5°}[/tex]

Therefore, the size of the unknown angle "x" is 50.5°

The required measure of the angle x is given as 50°.

Given that,
The diagram shows a right-angled triangle. 7cm and 11cm and x degrees.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Apply cosine equation,
cosx =  7 / 11
cosx = cos50
x = 50°

Thus, the required measure of the angle x is given as 50°.

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If 5x - 17 ≥ 0, then |5x - 17| = 5x - 17 and the equation reduces to

-8 - 2 (5x - 17) = -14

-8 - 10x + 34 = -14

-10x = -40

x = 4

If 5x - 17 < 0, then |5x - 17| = -(5x - 17) = -5x + 17 and we have

-8 - 2 (-5x + 17) = -14

-8 + 10x - 34 = -14

10x = 28

x = 2.8

[tex]\text{Let,}\\\\~~~~~~~~~y = e^{\ln 8}\\\\\implies \ln y = \ln \left( e^{\ln 8} \right)\\\\\implies \ln y = \ln 8( \ln e)\\\\\implies \ln y = \ln 8\\\\\implies y = 8\\\\\implies e^{\ln 8} = 8\\\\\text{Hence,}~~ e^{\ln 8 } = 8[/tex]

Answer:

8

Step-by-step explanation:

One of the properties of natural logs is that

[tex]e^{lnx} = x\\\\So,\\\\e^{ln8} = 8[/tex]

Answer:

The area is: 28.26 units^2

The diameter is: 18.84 units

Step-by-step explanation:

Area A=pie(3.14)R^2

Diameter D=pie(3.14)R2

The solution to the given system of equation is (4, 4)

From the solved steps, the final quadratic functions is given as;

x^2 - 8x + 16 = 0

Factorize to have;

x^2 - 4x - 4x + 16 = 0

x(x-4)-4(x-4) = 0
(x-4)(x-4) = 0

x = 4 and 4

Hence the solution to the given system of equation is (4, 4)

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Answer:

Initial balance$1000

interest rate 8%

Term 20yrs

Step-by-step explanation:

The final balance is $4,926.8.The total compound interest is $3,926.8.

The value of r is 2 %.

Simple Interest can be defined as the sum paid back for using the borrowed money, over a fixed period of time. Compound Interest can be defined as when the sum principal amount exceeds the due date for payment along with the rate of interest, for a period of time. Formula. S.I. = (P × T × R) ⁄ 100.

Given:

Principal(P)= $4540

Rate = ?

Time=10  years

CI=$1328.54

We have to find the value of r.

According to given question we have

By the use of compound interest we have

[tex]CI=p((1+\frac{r}{100} )^{10} -1)\\\\1328.54 =4540 ((1+\frac{r}{100} )^{10} -1)\\\\\0.292= ((1+\frac{r}{100} )^{10} -1)\\[/tex]

After simplifying we get,

r=2 %

Therefore, the value of r is 2 %.

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Answer:

  0.98 seconds

Step-by-step explanation:

We assume the height of the volleyball is described by the equation for ballistic motion. We want to find the time it takes for the height to become zero.

__

The general form of the equation of height for ballistic motion is ...

  [tex]h(t)=-16t^2+v_0t+h_0\qquad\text{$v_0$ and $h_0$ are the initial velocity and height}[/tex]

The coefficient 16 in the equation is an approximation of 1/2g, where g is the acceleration due to gravity in ft/s². This means the units of time and distance are expected to be seconds and feet.

For the problem at hand, the initial velocity and height are 10.5 ft/s and 5 ft. Then the height equation is ...

  h(t) = -16t² +10.5t +5

__

Marsha has until the ball hits the ground to react to the serve. To find out how long that is, we need to solve the height equation for t when h=0. This is most easily done using the quadratic formula with ...

The solution is ...

  [tex]t=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}= \dfrac{-10.5\pm\sqrt{10.5^2-4(-16)(5)}}{2(-16)}\\\\=\dfrac{10.5\pm\sqrt{430.25}}{32}=\dfrac{21\pm\sqrt{1721}}{64}[/tex]

The positive solution is ...

  t ≈ 0.976327 ≈ 0.98

Marsha has about 0.98 seconds to react before the volleyball hits the ground.

_____

Additional comment

After about 0.33 seconds, Marsha knows she doesn't need to react at all. The serve will not clear the net. Its maximum height is about 6' 8 5/8". A women's volleyball net is 7' 4 1/8" high. Jennifer's serve velocity must be at least 12.3 ft/s for the ball to go over the net. With that upward velocity, Marsha has about 1.06 seconds to react.

Answer:

2Tu = 90

Step-by-step explanation:

You can substitute the values T = 5 and u = 9 into the expression to get: 2 × 5 × 9 which is 90 (2 × 45 = 90)

Hope this helps!

The final result is 90 when T = 5 and u = 9.

Here, we have to evaluate 2Tu when T = 5 and u = 9, we substitute the values of T and u into the expression and perform the operations accordingly.

Given expression: 2Tu

T = 5

u = 9

Now, let's substitute the values:

2 * 5 * 9

Next, perform the multiplication:

2 * 5 = 10

10 * 9 = 90

So, when T = 5 and u = 9, the value of 2Tu is 90.

We get, to evaluate 2Tu, we first multiply T and u together, and then multiply the result by 2.

In this case, we have T = 5 and u = 9.

So, we perform the following steps:

Multiply T and u: 5 * 9 = 45

Multiply the result by 2: 2 * 45 = 90

Thus, the final result is 90 when T = 5 and u = 9.

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a) [tex](a+b)(x)=a(x)+b(x)=7x+10+12x-18=\boxed{19x-8}\\[/tex]

b) [tex](a-b)(x)=a(x)-b(x)=(7x+10)-(12x-18)=7x+10-12x+18=\boxed{-5x+28}[/tex]

c) [tex](a-b)(x)=a(x)-b(x)=(7x+10)-(12x-18)=7x+10-12x+18=\boxed{-5x+28}[/tex]

d) [tex]a(b(x))=a(12x-18)=7(12x-18)+10=84x-126+10=\boxed{84x-116}[/tex]

for an angle of 780°, we can say that is really a 360° + 360° + 60°, so two full revolutions plus an extra 60°. Check the picture below, with the coterminal in green.

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

Answer:

Step-by-step explanation:

3a 2b ×2a 6b = (3 × 2)×(a × b) × (2 × 6)×(a × b)   [commutative property]

                      = (6×ab) × (12×ab)  [associative property]

                      = (6×12) × (ab×ab)  [commutative + associative]

                      = (72) × (ab)²

                      = 72× (ab)²

                      = 72a²b²  [exponent property]

Answer:

Step-by-step explanation:

for 1

area=2x×3x=6x²

for 2

l=3x+2x=5x

b=2x

area=5x×2x=10x²

total area=6x²+10x²=16x²

The measure of each of the angles ∠P,∠Q,∠R, ∠S are 45°,72°,135° and 98° respectively.

A quadrilateral is a polygon having four sides. The measure of the opposite angle of quadrilateral inside circle is 180°.

From the figure:

∠P=x+15

∠Q=3x-8

∠R=?

∠S=3x+8

∠Q+∠S=180

3x-8+3x+8=180

6x=180

x=30°

∠P+∠R=180°

x+15+∠R=180

30+15+∠R=180

∠R=180-45

∠R=135°

∠P=30+15=45

∠Q=3x-8=3(30)-8=72

=135

∠S=3x+8=3(30)+8=98

Hence,the measure of each of the angles ∠P,∠Q,∠R, ∠S are 45°

,72°,135° and 98°.

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Finding the correlation coefficient, it is found that the regression line shows a:

negative trend line with a strong relationship.

Inserting the values of a table, the x-values as 25, 28, 30, 31, 33, 40, and the y-values as 7.5, 6, 5.5, 5, 4.5, 4.5, the coefficient is of -0.85, which is negative and strong.

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Inserting the values of a table, the x-values as 25, 28, 30, 31, 33, 40, and the y-values as 7.5, 6, 5.5, 5, 4.5, 4.5, the coefficient is -0.85,

The table contains data for six students in a running club: time run in minutes, x, and the corresponding average speed in mph, y.

Finding the correlation coefficient, it is found that the regression line shows a: negative trend line with a strong relationship.

It is an index that measures the correlation between two variables, assuming values between -1 and 1.

If it is positive, the relationship is positive, that is, they are directly proportional. If it is negative, they are inversely proportional.

If the absolute value of the correlation coefficient is greater than 0.6, the relationship is strong.

Inserting the values of a table, the x-values as 25, 28, 30, 31, 33, 40, and the y-values as 7.5, 6, 5.5, 5, 4.5, 4.5, the coefficient is -0.85, which is negative and strong.

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The common ratio of the sequence is -1.5

The sequence is given as:

1,-1.5,2.25,-3.375

Divide the second term by the first to determine the common ratio (r)

r = T2/T1

This gives

r = -1.5/1

Evaluate

r = -1.5

Hence, the common ratio of the sequence is -1.5

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The perimeter of the composite figure shown in the figure is equal to 5 · [2 + √2 · (1 + √5)] units (approx. 32.882 units) and the total area is 33.5 square units.

In this case we have a composite figure formed by six triangles and two rectangles. The perimeter is the sum of the side lengths and the area is the sum of the areas of the triangles and rectangles. The perimeter of the entire figure is described below:

p = AB + BC + CD + DE + EF + FG + GA

p = 5√2 + √10 + √10 + 5 + √10 + 5 + 2√10

p = 10 + 5√2 + 5√10

p = 10 + 5 · (√2 + √10)

p = 10 + 5√2 · (1 + √5)

p = 5 · [2 + √2 · (1 + √5)]

And the area of the composite figure is determined by the following expression:

A = 0.5 · (3) · (1) + (3) · (4) + 0.5 · (3) · (1) + 0.5 · (3) · (1) + 0.5 · (3) · (1) + (3) · (2) + 0.5 · (7) · (1) + 0.5 · (6) · (2)

A = 2 · (3) · (1) + (3) · (4) + (3) · (2) + 0.5 · (7) · (1) + 0.5 · (6) · (2)

A = 33.5

The perimeter of the composite figure shown in the figure is equal to 5 · [2 + √2 · (1 + √5)] units (approx. 32.882 units) and the total area is 33.5 square units.

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Answer:

6

Step-by-step explanation:

hope it helps

Answer:

The Area is 25

Step-by-step explanation:

You will need distance formula for this questions

for AD, (0,4) and (4,7)

The formula is here

[tex]\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]

which gives you

[tex]\sqrt{\left(4-0\right)^2+\left(7-4\right)^2} = 5[/tex]

for AB

(0,4),(3,0)

[tex]\sqrt{\left(3-0\right)^2+\left(0-4\right)^2}=5[/tex]

The answer will be 5*5, which is 25

Yes the ladder be safe at this height.

The angle formed by the line of sight and the horizontal plane for an object above the horizontal.

Given:

ladder = 15 ft long.

top of the ladder is 14.2 ft above the ground.

Using trigonometry,

sin x = 14.2/15

sin x = 0.947

x= 71.262°

As, 78 > 71.262°

Hence, it would be safe to use the ladder of 15 ft long.

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Domain of f(x) is {x | x ≠ 6} and Domain of g(x) is {x | x ≠ +7 and x ≠ +7}.

The domain of a function is the set of all input values that make the function possible.

Now, for f(x) = (x + 6)/(x² - 12x + 36)

To find the domain, we equate the denominator to zero to find the numbers that can't be a domain. Thus;

x² - 12x + 36 = 0

Solving this using quadratic formula gives; x = 6. Thus, domain of f(x) is;

Domain = {x | x ≠ 6}

Now, for g(x) = (x + 7)/(x² - 49)

To find the domain, we equate the denominator to zero to find the numbers that can't be a domain. Thus;

x² - 49 = 0

Solving this using quadratic formula gives; x = +7 or -7. Thus, domain of g(x) is; Domain = {x | x ≠ +7 and x ≠ +7}

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The elimination method is the process of removing the variable from the system of equations, whereas the substitution method is the process of replacing a variable with a value to find the solution for the system of equations.

For instance, the system of two equations with two unknown values, the solution can be obtained by using the below steps. Here, the list of steps is provided to solve the linear equation. They are

Answer:

8= 24b

8/8=24b/8

b=3

Step-by-step explanation:

Based on my own learning

Answer:D. x^2+7

Step-by-step explanation:

If f(x) = 2x² +5 and g(x)=x2-2, find (f-g)(x).A. x^2+3B. 3x^2+3C. 3x^2+7D. x^2+7

Answer:

  -448

Step-by-step explanation:

The sum of 28 terms of the arithmetic sequence with first term 92 and common difference -8 can be found using the formula for the sum of an arithmetic series.

  Sn = (2a1 +d(n -1))(n/2) . . . . sum of n terms with first term a1, difference d

__

Using the above formula with a1=92, d=-8, and n=28, the sum is ...

  S28 = (2·92 -8(28 -1))/(28/2) = (184 -216)(14) = -448

The sum of the first 28 terms of the sequence is -448.

Answer:

Choice C

Step-by-step explanation:

Given equation,

To Find:

Solution:

=>x/-3=-6

Transpose 3 from LHS to RHS,make sure to change the sign from ÷ to *.

=>x = -6*-3

=>x = 18

Hence, the value of x is 18.