Mathematics High School

[tex] \bigstar \: \underline{ \underline{ \tt{Question}}} : [/tex] In the given figure , M and N are the centres of two intersecting circles. Prove that :
i. PQ [tex] \perp[/tex] MN
ii. PR = RQ

~Thanks in advance! <3

$[tex] \bigstar \: \underline{ \underline{ \tt{Question}}} : [/tex] In The Given Figure , M And N Are$

Answers

Answer 1

Answer:

See Below.

Step-by-step explanation:

We are given two intersecting circles with centers M and N.

And we want to prove that: I) PQ ⊥ MN and that II) PR = RQ.

Since MP and MQ are radii of the same circle:

[tex]MP\cong MQ[/tex]

Likewise, since NP and NQ are radii of the same circle:

[tex]NP\cong NQ[/tex]

And by the Reflexive Property:

[tex]PQ\cong PQ[/tex]

Therefore, by SSS Congruence:

[tex]\Delta MPN\cong \Delta MQN[/tex]

By CPCTC:

[tex]\displaystyle \angle PMN\cong \angle QMN[/tex]

And by the Reflexive Property:

[tex]MR\cong MR[/tex]

And since they are the radii of the same circle:

[tex]MP\cong MQ[/tex]

Therefore, by SAS Congruence:

[tex]\Delta MPR\cong \Delta MQR[/tex]

Therefore, by CPCTC:

[tex]PR\cong RQ[/tex]

Note that PQ is a chord in Circle M.

Therefore:

[tex]\text{Segment $MN$ bisects chord $PQ$}[/tex]

In a circle, a segment that passes through the center of the circle that is perpendicular to a chord also bisects the chord.

And conversely, a segment that passes through the center of a circle that bisects a chord in the circle is also perpendicular to the chord.

So:

[tex]\displaystyle PQ\perp MN[/tex]

Answer 2

Answer:

Step-by-step explanation:

First step is to prove triangle MPN ad MQN are congruent.

MP=MQ, radius of circle M

NP=NQ, radius of circle N

we have two S in SAS and for A, we need to prove angle MPN = MQN

consider triangle QMP, it is isosceles so angle MPQ = MQP

consider triangle QNP; it is isosceles so angle QPN = PQN

combining the two above

angle MPN = MPQ+QPN = MQP+PQN = MQN

By SAS, triangle MPN and MQN are congruent

By symmetry, MN is perpendicular to PQ

It also disects PQ so PR = RQ

Related Questions

hi help please! i’m struggling lol i already know the first part

Answers

Answer:

180 Degrees minus 117= sixty three

answer is x is 63

Where did I get the 180?

- straight Angles have 180

- 117 is a part of 180

-so that is why you had to subtract

I hope this Helps You!!

50 points
Please help ///// brainiliest
A 6 cm high cone has a volume of 128π cm3 What is its exact surface area?

A. 160π cm2
B. 96π cm2
C. 144π cm2
D. 104π cm2

Answers

Answer:

height [h]=6cm

Volume of cone =1/3 πr²h

128πcm³=1/3×π×r²×6

128×3/6=r²

r=√64

r=8cm

Now

slant height (l)=√{8²+6²}=10cm

again

.Total surface area :πrl+πr²=π×8(10+8)=144πcm²

its exact surface area is C. 144π cm²

[tex]\green{\boxed{-answer-}}[/tex]

Thats kinda hard but here maybe this one

C) 104π cm2

I dont really know well have a nice day man

20% of ______ is 120

Answers

Answer:600

Step-by-step explanation:

Answer:

___ x X = 120

100

x100 x 100

20x = 120

divide by 20 on both sides.

x = 6

Learning task 3
What polygon is being described in the picture

Answers

There isn’t a picture, can you post one?

kirans aunt is 15 years older than kiran. how old will kirans aunt be when kiran is 13? how old will kiran be when his aunt is 60 years old?

Answers

Answer:

When Kiran is 13, his aunt will be 28.

When Kiran's aunt is 60, he will be 45.

Step-by-step explanation:

Hope this helps!

Answer:

a) 28 (kiran's aunt when kiran is 13)

b) 45 (kiran when kiran's aunt is 60)

Step-by-step explanation:

first

let kiran's age be k

kiran's aunt= 15 + k

when kiran is 13, kiran's aunt is 15+13

15+13= 28

when kiran's aunt is 60;

15+k = kiran's age

60 = 15+ k

k = 60-15

k = 45

A right triangle is a triangle with two angles. True or false?

Answers

Answer:

The answer is false.

Step-by-step explanation:

A triangle would also be opposite to a angle of property.

False- A right triangle is a triangle with right degree angles of

HELPP will give brainliest NO LINKSSS

Answers

Answer:

you didnt attach anything

Step-by-step explanation:

Select all equations whose graphs have a vertex with x-coordinate 2

A. y=(x-2)(x-4)
B. y=(x-2)(x+2)
C. y=(x-1)(x-3)
D. y=x(x+4)
E. y=x(x-4)

Answers

Answer:

Step-by-step explanation:

because you have to foil then do -b/2a

By finding the x-coordinate of each vertex, we will see that the correct options are C and E.

How to identify the x-value of the vertex?

For a quadratic equation of the form:

y = (x - a)*(x - b)

Where a and b are the roots, such that a < b, the x-value of the vertex is given by:

a + (b - a)/2

With that, we can check the x-value of the vertex of each option.

A) y=(x-2)(x-4)