Test 1 2021-22 19 of 9
The graph represents Samantha's walk in front of a motion detector. Identify two points marked on the graph that define the interval
where her average rate of change was 2/3 meters per second.
Motion Detector Walk
Answers
Given that the shape of the graph is curved, the rate of change can be
estimated by using the average value between specified points.
The points are;
[tex]\underline{(6, \, 6)}[/tex][tex]\underline {(9, \, 8)}[/tex]Reasons:
The coordinates of the points marked (distances and time) during the walk are;
[tex]\begin{tabular}{|c|c|}Time (seconds), x&Distance from motion detector (meters), y\\0&1\\3&2\\5&4\\6&6\\7&7\\9&8\end{array}\right][/tex]
Required: Identification of two points marked on the graph that define the
interval where Samantha's average rate of change was 2/3 meters per
second.
Solution:
The average rate of change between two points is given by the ratio of
difference in the distance from the motion detector to the difference in
time between the points.
[tex]\displaystyle Average \ rate \ of \ change = \frac{Change \ in \ distance}{Change \ in \ time} = \mathbf{ \frac{\Delta y}{\Delta x}}[/tex]
At the required points, the change in the y-values, will be 2 × a, while the
corresponding change in x-values will be 3 × a, where, a is rational number.
From the above table, at the points where the time is 6 seconds and 9
seconds, we have the following distance time ordered pair;
(6, 6), and (9, 8), from which we have;
[tex]\displaystyle Average \ rate \ of \ change =\frac{\Delta y}{\Delta x} = \mathbf{\frac{8 - 6}{9 - 6}} = \frac{2}{3}[/tex]
Therefore;
The points [tex]\underline{(6, \, 6)}[/tex], and [tex]\underline {(9, \, 8)}[/tex], are two points that represent an interval
where her average rate of change was 2/3 meters per second.
Learn more about average rate of change of a graph here:
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Answers
Answer:
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Answer:
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Answers
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Step-by-step explanation:
Answer:
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Answers
Answer:
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Answers
Answer:
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Answers
Answer:
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Step-by-step explanation:
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Answers
Answer: 310
Step-by-step explanation:
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The function D(t) defines a traveler’s distance from home, in miles, as a function of time, in hours. D(t) = StartLayout enlarged left-brace 1st Row 1st column 300 t 125 , 2nd column 0 less-than-or-equal-to t less-than 2. 5 2nd Row 1st column 880, 2nd column 2. 5 less-than-or-equal-to t less-than-or-equal-to 3. 5 3rd Row 1st column 75 t 612. 5, 2nd column 3. 5 less-than t less-than-or-equal-to 6 EndLayout Which times and distances are represented by the function? Select three options. The starting distance, at 0 hours, is 300 miles. At 2 hours, the traveler is 725 miles from home. At 2. 5 hours, the traveler is 875 miles from home. At 3 hours, the distance is constant, at 880 miles. The total distance from home after 6 hours is 1,062. 5 miles.
Answers
The distance in given time t is determined by substituting the value of time and solving the equation.
At 2 hours, the traveler is 725 miles from home.
At 3 hours, the distance is constant, at 880 miles.
The total distance from home after 6 hours is 1,062.5 miles.
Given that,
The function D(t) defines a traveler’s distance from home, in miles, as a function of time, in hours.
D(t) = 300t + 125
We have to determine,
Which times and distances are represented by the function?
According to the question,
The function D(t) defines a traveler’s distance from home, in miles, as a function of time, in hours.
D(t) = 300t + 1251. The starting distance at 0 hours is ;
At [tex]0 \leq t < 2.5[/tex]
Then,
[tex]\rm D(t) = 300t + 125 ;\\\\\ D(0) = 300(0) + 125 = 125 \ miles[/tex]
The starting distance, at 0 hours, is 125 miles.
2. The distance at 2 hours is,
[tex]\rm D(t) = 300t + 125 ;\\\\\ D(2) = 300(2) + 125\\\\ D(2) =600+125\\\\ D(2) = 725 \ miles[/tex]
At 2 hours, the traveler is 725 miles from home.
3. The distance at t = 2.5 hours is,
At 2.5 ≤ t ≤ 3.5
D(2.5) = 880 miles (Fixed)
At 2.5 hours, the traveler is 880 miles from home.
4. The distance at t = 3 hours is,
2.5 ≤ t ≤ 2.5
D(3) = 880 miles
At 3 hours, the distance is constant, at 880 miles.
5. The distance at t = 6 hours is,
3.5 < t ≤ 6
[tex]\rm D(t) = 300t + 125 ;\\\\\ D (6)= 75(6) + 612.5\\\\ D(6) = 450 + 612.5\\\\D(6) = 1062.5 miles[/tex]
The total distance from home after 6 hours is 1,062.5 miles.
For more details about Average distance refer to the link given below.
https://brainly.com/question/25969947
how do you know how many points are needed to make a graph of a polynomial function from a table? are there a safe number of points to make the graph of any polynomial function? if so, what is that number? please help, explain well if possible
Answers
Step-by-step explanation:
You need a arbitrary points that will help you determine the sketch of the graph. I say use at most 5 points but you just need to know the following
The exterma: The maximum/minimum points on a certain interval.
The zeroes: What values willTheorem, Factoring, and more to help you find the zeroes.
Increasing and decreasing behavior between the consective zeroes: How the function behaves around consective zeroes. It must be above or below x axis between the zeroes.
And finally, the end behavoir: How the function behaves as x approaches infinity and negative infinity. Does the function increases or decreases.
That it. If you need an example, just ask me
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