what is the length of DE?
The cost of a 6 ounce can of tomato paste is 29
cents. A 16 ounce can sells for 65 cents.
Which is the better deal?
Answer:
16 ounce can sells for 85 cents
Step-by-step explanation:
29cents / 6 ounce = 4.833cents/ounce
65cents / 16 ounce = 4.0625cents/ounce
4.0625 < 4.833
then:
the better deal is:
16 ounces per 65 cents
Yosef drove 12,900 miles last year. His truck's fuel efficiency averages 15 mpg, and the average cost of gas last year was $2.95 per gallon. Determine Yosef's average weekly fuel cost
Yosef's average weekly fuel cost would be $2537.
What is the unitary method?The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.
Yosef drove 12,900 miles last year. His truck's fuel efficiency averages 15 mpg.
Karla used 12900/15 = 860 gallons to drive 12900 miles.
The average cost of gas last year was $2.95 per gallon.
Therefore, Yosef's average weekly fuel cost would be
2.95 x 860 = $2537
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Which point is a solution to the inequality shown in this graph?
Which parabola will have one real solution with the line y = x - 5?
Answer:
y=x^2+7x+4
Step-by-step explanation:
because the sign before x^2 is positive, the graph would concave up, if there's only one intercept, it has to be the vertex. the vertex is the critical point.
solve every make the derivative of each function equals zero, you get the x where the vertex shall be, then get this"x" into y=x-5 see if the y in y=x-5 is equal to y=x^2+6x+9 or other options.
let me give u an example.
for y=x^2+x-4, the critical point shall be 2x+1=0,x=-1/2, and the y is -4.25,
if you plug x=-1/2 into y=x-5, it's -5.5, -5.5 doesn't equal to -4.25
Answer:
D
Step-by-step explanation:
y = x2 + 7x + 4
What is the condition that causes an infinite geometric series to have no sum? Explain why
this is true.
please help!!
A state seal, which is round, hangs in the capitol building. it has a radius of 2 feet. what is the seal's circumference?
Answer:
12.56637ft
Step-by-step explanation:
Formula: c=2π*r
c=2π*2 = 12.56637ft
can someone please help me
The answer is [tex]11c^3[/tex].
Measure of angle AEB= ___ degrees
m
m< ACB= ___ degrees
(Picture is attached below :) )
By the inscribed angle theorem, [tex]m\angle AEB=30^{\circ}[/tex] and [tex]m\angle ACB=30^{\circ}[/tex].
Kenya worked from 2:00 pm to 11:00 pm and made $79.11. What was her rate of pay per hour?
Answer:
[tex]\huge\boxed{\sf \$ \ 8.79\ per\ hour}[/tex]
Step-by-step explanation:
Given that:Work hours = 2:00 pm - 11:00 pm
This makes a total of 9 work hours.So,
9 hours = $79.11
Rate of pay per hour:Using unitary method
9 hours = $79.11
Divide both sides by 9
1 hour = $79.11/9
1 hour = $8.79
So, Kenya is being paid $8.79 per hour.
[tex]\rule[225]{225}{2}[/tex]
What is the solution to the following system of equations?
Answer:
no solutionStep-by-step explanation:
The lines do not intersectCan someone help me on these problems and show work
The simplified expression are as follows;
6mn³ - mn² + 3mn³ + 15mn² = 9mn³ + 14mn²
a⁴b³ + 8a⁴b³ = 9a⁴b³
How to simplify an expression?A simplified expression is express to its lowest term.
Therefore,
6mn³ - mn² + 3mn³ + 15mn²
combine like terms
6mn³ + 3mn³ - mn² + 15mn²
9mn³ + 14mn²
a⁴b³ + 8a⁴b³ = 9a⁴b³
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A horse holds the all time record for running a 2 kilometer race in 1 min and 59.4 sec. which conversions are necessary to find the horses average speed for the race in miles per hour?
To calculate the average speed of the horse in miles per hour, holding the all-time record for running a 2-kilometer race in 1 min and 59.4 sec, we do the necessary conversions over distance from kilometers to miles and over time from minutes and seconds to hours.
The average speed thus calculated is 393.2722 miles per hour.
The average speed of any object is the ratio of the total distance the object travels, and the total time taken by the object to cover that distance.
Thus, Average speed = Total Distance/Time taken.
In the question, we are informed that a horse holds the all-time record for running a 2-kilometer race in 1 min and 59.4 sec.
We are asked for the necessary conversions required to calculate the average speed of the horse for the race in miles per hour.
The necessary conversions that will be required will be:
Distance: 2 kilometers to miles.
Time: 1 minute 59.4 secs to hours.
To convert from kilometers to miles, we follow the conversion rate:
1 kilometer = 0.621371 miles.
Thus, distance = 2 kilometers = 2 * 0.621371 miles = 1.24274 miles.
For the time, we first convert seconds to time, using the conversion rate:
1 second = 1/60 minutes,
Therefore, 59.4 seconds = 59.4/60 minutes = 0.99 minutes.
Thus, the total time = 1.99 minutes.
To convert from minutes to hours, we follow the conversion rate:
1 minutes= 1/60 hours.
Thus, time = 1.99 minutes = 1.99/60 hours = 0.03316 hours.
Thus, the average speed of the horse = Distance/Time = 1.24274/0.003316 miles per hour = 393.2722 miles per hour.
Thus, to calculate the average speed of the horse in miles per hour, holding the all-time record for running a 2-kilometer race in 1 min and 59.4 sec, we do the necessary conversions over distance from kilometers to miles and over time from minutes and seconds to hours.
The average speed thus calculated is 393.2722 miles per hour.
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can somebody help me with this
The sum of the expression (–x² + x) and (x² – 3x – 1) will be –2x – 1. Then the correct option is D.
What is Algebra?The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
The expression can be written as
(–x² + x) and (x² – 3x – 1)
Then the sum of the expression (–x² + x) and (x² – 3x – 1) will be
(–x² + x) + (x² – 3x – 1) = –2x – 1
Then the correct option is D.
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The farmer wants ratio horses : cows to equal 5 : 3.
He keeps his 45 horses but buys some cows.
Work out the number of cows he must buy.
Answer
He needs to buy 27 Cows
Step-by-step explanation:
if the ratio from horses to cows is 5-3 then you multiply 5 by the number to get 45 and also multiply it by 3
5 x 9 = 45
3 x 9 = 27
Write the ratio of sin X and cos X
The ratio of sin X and cos X are as follows;
sin X = √119 / 12
cos X = 5 / 12
How to find the sides of right angle triangle?Right angle triangle has one of its angle as 90 degrees. The side and angles can be found using trigonometric ratios.
Therefore,
sin X = opposite / hypotenuse
sin X = √119 / 12
Therefore,
cos X = adjacent / hypotenuse
cos X = 5 / 12
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Solve x≥0 or x≥−5 and write the solution in interval notation.
The solution for x ≥ 0 and x ≥ -5 is [-5, ∞), in the interval notation.
The interval notations are used to represent numbers between two numbers excluding or including the numbers as per the use. We use the following four interval notations:
[a, b] ⇒ All numbers between a and b including both a and b.
(a, b) ⇒ All numbers between a and b excluding both a and b.
(a, b] ⇒ All numbers between a and b excluding a but including b.
[a, b) ⇒ All numbers between a and b including a but excluding b.
We are asked to write the solution for x ≥ 0 and x ≥ -5 in the interval notation.
We first write each inequality in interval notation:
x ≥ 0 ⇒ x are all numbers greater than 0 including 0. This can be written in the interval notation as [0, ∞). We don't include ∞ as it is indeterminant.
x ≥ -5 ⇒ x are all numbers greater than -5 including -5. This can be written in the interval notation as [-5, ∞). We don't include ∞ as it is indeterminant.
Now, we are asked to solve for x ≥ 0 or x ≥ -5. Since it is 'or', we take unions of the two sets, that is the solution is:
[0, ∞) ∪ [-5, ∞) = [5, ∞).
Therefore, the solution for x ≥ 0 and x ≥ -5 is [-5, ∞), in the interval notation.
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Subtract 7x+27x+2 from -5x^2-2x−5x 2 −2x.
Simplified value of subtraction of 7x+27x+2 from -5x^2-2x−5x 2 −2x. is [tex]-10x^{2} -38x-2[/tex].
Given Expressions 7x+27x+2 and -5x^2-2x−5x 2 −2x.
Expressions refers to the combination of numbers, variables and symbols. It represents the relationship between variables. They are solved for finding out the value of variables. It is mainly not in equal to form. Subtraction is possible when subtracting the coefficients of same variable.
We have to subtract 7x+27x+2 from -5x^2-2x−5x 2 −2x. and to do this we need to first solve the expressions itself.
7x+27x+2=34x+2------------------1
[tex]-5x^{2} -2x-5x^{2} -2x[/tex]=[tex]-10x^{2} -7x-2x[/tex]--------------------2
Now subtract 1 from 2
=[tex]-10x^{2} -7x-2x[/tex]-34x+2
=[tex]-10x^{2} -38x-2[/tex].
Hence the simplified value of subtraction is [tex]-10x^{2} -38x-2[/tex].
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Graph the exponential model
y = 3(6)^x Which point lies on the graph?
(-9 2)
(2, 9)
(- 1, - 18)
(1, 18)
(1,18)
Let's verify
18=3(6)118=3(6)18=18Verified
find the value of x in the following parallegram 2x-10 2x+50
The value of x would be 35.
What is a parallelogram?That quadrilateral in which opposite sides are parallel is called a parallelogram.
Thus, a parallelogram is always a quadrilateral but a quadrilateral can or cannot be a parallelogram.
In order to calculate the value of x in the parallelogram, we have to find the following;
Let ∠m = 2x - 10
∠n = 2x + 50
So, ∠m + ∠n = 180
2x-10 + 2x+50 = 180
4x + 40 = 180
4x = 180 - 40
4x = 140
x = 35
Hence, the value of x is 35.
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Find m∠1. lol yeah that's it
The two inside angles add up to the external angle's total. The m∠1 will be 69°. Option D is correct.
What is angle measurement?An angle measure is the measurement of the angle created by two rays or arms at a shared vertex in geometry. A protractor is used to measure angles in degrees (°).
From the exterior angle property, the sum of the exterior angle is the sum of the two interior angles.
The m∠1 will be 69°.
Hence, option D is correct.
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the answer has to be as a fraction
Answer:
49/100
Step-by-step explanation:
So you can find the area of shaded area by finding the area of the circle inside the entire circle that has a diameter of 3 cm and 4 cm and then find the area of the most inner circle which only has a diameter of 4 cm and then subtract these 2. After that you want to find the area of the entire circle and then divide the area of the shaded area by the entire circle. The formula for the area of a circle is given as: [tex]\pi r^2[/tex]
Area of the two "inner" circles of a diameter of 4 and 3 cm. This gives you an entire diameter of 7 cm with a radius of 3.5. The area of this circle is [tex]\pi(3.5)^2[/tex] which is [tex]12.25\pi[/tex].
The area of the most inner circle only has a diameter only 4 cm. The radius is 2, thus the area of this circle is [tex]\pi (2)^2[/tex] which is [tex]4\pi[/tex]. Now subtract this from the 12.25 pi to find the area of the shaded area. This gives you the equation: [tex]12.25\pi-4\pi[/tex] which equals [tex]8.25\pi[/tex].
Now to find the area of the entire circle you add up all the "diameters" which gives you 4 cm + 3 cm + 3 cm = 10 cm. So the radius is 5. This gives you the equation: [tex]\pi(5)^2[/tex] which is equal to [tex]25\pi[/tex].
Now to find the fraction of circle that is shaded we divide the area of the shaded area and the area of the entire circle. This gives you the equation: [tex]\frac{12.25\pi}{25\pi}[/tex] but since it wants it as a fraction, I'm assuming it wants integers in the decimal and numerator place. So we can represent 12.25 as 12 + 1/4. And then convert the 12 into 1/4ths by multiplying by 4 and then adding that to the numerator. This makes the fraction [tex]\frac{49}{4}=12.25[/tex]. So now all we have to is divide the two values: [tex]\frac{\frac{49}{4}}{\frac{25}{1}}[/tex]. If you're wondering where the pi's when you can just cancel them out since they're both in the numerator and denominator. Now all we have to do is keep the 49/4, change the operator to multiplication, and flip the 25/1 to 1/25. This gives you the equation: [tex]\frac{49}{4} * \frac{1}{25}[/tex] which becomes [tex]\frac{49}{100}[/tex] which is the answer
This problem is lowkey tricky. Can someone help me out
Answer:
x = 10
Step-by-step explanation:
Proof: If a line is parallel to one side of the triangle, then it divides the other two sides proportionally.
6/9 = x/15
9x = 90
x = 10
( 64 ) -2/3 x ( 27 ) -2/3
Solve c= 5/9(F-32) for F
Answer:
F=9/5c+32
Step-by-step explanation:
c=5/9f-160/99c=5f-160-5f=-160-9cf=32+9/5cf=9/5c+32Which expression is equivalent to -21.8 - (-18.3)?
O-21.8+18.3
-21.8-18.3
21.8+18.3
21.8-18.3
GUYS PLS HELP ME
The expression equivalent to -21.8 - (-18.3) would be option A; -21.8+18.3.
What are equivalent expressions?Those expressions that might look different but their simplified forms are the same expressions are called equivalent expressions.
To derive equivalent expressions of some expression, we can either make it look more complex or simple.
The given expression is
-21.8 - (-18.3)
So, open the bracket and distribute the negative;
-21.8 (+18.3)
Thus, the expression equivalent to -21.8 - (-18.3) would be option A; -21.8+18.3.
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Answer: A
Step-by-step explanation: –21.8 – (–18.3) = -3.5 and –21.8 + 18.3 = -3.5
Charlie's Pizzeria made 11 thin-crust pizzas and 24 thick-crust pizzas. What is the ratio of the number of thin-crust pizzas to the total number of pizzas? Charlie's Pizzeria made 11 thin - crust pizzas and 24 thick - crust pizzas . What is the ratio of the number of thin - crust pizzas to the total number of pizzas ?
Answer:
11:37
Step-by-step explanation:
11 thin-crust pizzas
11+24=37 total pizzas
=>11:37
A quadratic sequence is defined as:2;12;28;50
Calculate the first difference between Tn and Tn-1 where Tn= 688
The first difference between Tn and Tn-1 where Tn= 688 is 88 if the quadratic sequence is defined as:2;12;28;50
What is a sequence?It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
The quadratic sequence:
2, 12, 28, 50
a + b + c = 2
10, 16, 22 (first difference)
3a + b = 10
6, 6 (second difference)
2a = 6
a = 3
b = 1
c = -2
Tterm:
T(n) = 3n² + n - 2 = 688 (given)
After solving the quadratic equation:
n = 15, n = -46/3(n cannot be nagatve)
n = 15
n - 1 = 14
T(14) = 600
T(n) - T(n-1) = 688 - 600 = 88
Thus, the first difference between Tn and Tn-1 where Tn= 688 is 88 if the quadratic sequence is defined as:2;12;28;50
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Which number line represents the solution set for the inequality 3(8 – 4x) < 6(x – 5)?
A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the left.
A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the right.
A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the left.
A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the right.
The solution will be a number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the right.
Inequality expressionInequalities are equations that are separated by an equal sign. Given the inequality expression
3(8 – 4x) < 6(x – 5)
Expand
3(8) - 3(4x) < 6x - 6(5)
24 - 12x < 6x - 30
Collect the like terms
-12x - 6x < -30 - 24
-18x < -54
x > 3
Hence the solution will be a number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the right.
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Find the solution set for this equation:
-a2+4a=0
(Separate the two values with a comma)
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: \{ 0,4 \}[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: - {a}^{2} + 4a = 0[/tex]
[tex]\qquad \tt \rightarrow \: - ( {a}^{2} - 4a) = 0[/tex]
[tex]\qquad \tt \rightarrow \: {a}^{2} - 4a = 0[/tex]
[tex]\qquad \tt \rightarrow \:a(a - 4) = 0[/tex]
The two cases are :
a = 0or
a -4 = 0, that leads to a = 4We can conclude :
[tex]\qquad \tt \rightarrow \:solution \: (a) = \{ 0,4\}[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
[tex] \quad \quad \quad \quad\huge \tt \pink ❆ AnSweR \pink ❆[/tex]
[tex]\quad\quad \tt-a^2+4a= 0[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex] \quad\quad\tt⇢-1(a^2 - 4a) = 0[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\quad\quad\tt⇢-1(a-4)a = 0[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\quad\quad\tt⇢a-4=0[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\quad\quad\tt⇢a = 0[/tex]
-----------------------------------------------------------
[tex] \boxed{ \tt \blue{a = 0}}[/tex]
[tex]\boxed{ \tt\blue{a = 4}}[/tex]