Mass of the brown. dwarf., M₂ = 4.132 * 10²⁷ kg
Let M₁ = Mass of the main-sequence star
M₂ = Mass of the brown dwarf
v₁ = speed of the main-sequence star
v₂ = speed of the brown dwarf
The system's average distance apart r₁ = r₂ = 1 AU
The brown dwarf's orbital speed is 22 times that of a star in the main sequence.
Consequently, v2 = 22 v1.
Considering that the Sun is a main-sequence star
2 * 1030 kg is the main-sequence star's mass.
Centripetal force: F = Mv2/r
M1v12 = M2v22 M2/M1 = v12/v22 M2/M1 = (1/22) M1v12 = M2v22/r2 M2v22/r2
2 M2/M1 = 0.002066 M2 = 0.002066M1 M2 = 0.002066*2*1030 M2 = 4.132*1027 kg
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a vechile ravels at a constant speed of 6.0 meters per second round a horrizontal circular curve with a radius of 24 meters. the mass of the vechile is 4.4 x 10^3 kolgranms, an icy patch is location at p on the curve
17) The magnitude of the frictional force that keeps the vehicle on its circular path is C) 6.6 x 103 N
The magnitude of the frictional force that keeps the vehicle on its circular path can be found by using the equation For = mv2/r, where m is the mass of the vehicle, v is the velocity of the vehicle, and r is the radius of the curve. Plugging in the given values, we get Ffr = (4.4 x 103 kg)(6.0 m/s)2/24 m = 6.6 x 103 N.
18) The amount of work done on the object is D) 30 J.
Work is equal to the amount of force multiplied by the distance the object has moved. In this case, the force is 5 N and the distance moved is 3 m, so the work done on the object is 5 N x 3 m = 15 Nm = 15 J.
19) The crane does work at the rate of C) 5 x 104 watts
The rate at which work is done is equal to the total amount of work done divided by the total time it took to do the work. In this case, the total amount of work done is 200 N x 50 m = 10,000 Nm = 10,000 J, and the total time taken is 5 s. So the rate of work done is 10,000 J/5 s = 2,000 J/s = 2 kW = 5 x 104 watts.
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Complete question:
A vehicle travels at a constant speed of 6.0 meters per second around a horizontal circular curve with a radius of 24 meters. The mass of the vehicle is 4.4 × 103 kilograms. An icy patch is located at P on the curve.
17) What is the magnitude of the frictional force that keeps the vehicle on its circular path?
A) 6.5 × 104 N B) 1.1 × 103 N C) 6.6 × 103 N D) 4.3 × 104 N
18) A net force of 5.0 newtons moves an object a distance of 3.0 meters in. How much work is done on the object?
A) 10. J B) 15 J C) 1.0 J D) 30. J
19) A crane raises a 200‐newton weight to a height of 50 meters in 5 seconds. The crane does work at the rate of
A) 2 × 103 watts B) 8 × 10−1 watt C) 5 × 104 watts D) 2 × 101 watts
Two identical pendulums have the same period when measured in the factory. While one pendulum swings on earth, the other is taken on a spaceship traveling at 95% the speed of light. Assume that both pendulums operate under the influence of the same net force and swing through the same angle. When observed from earth, how many oscillations does the pendulum on the spaceship undergo compared to the pendulum on earth in a given time interval?
The spaceship's pendulum experiences fewer oscillations in a given time period than the pendulum on Earth.
Because of the effect of time dilation, a clock moving with respect to an observer appears to run more slowly than a clock that is at rest in the observer's frame. When observed from earth, the pendulum on the spaceship takes longer to complete one oscillation. Therefore, the clock associated with that pendulum will run slower (gives fewer oscillations as seen from the earth) than the clock associated with the pendulum on earth.
Oscillations is the process of any quantity or measure repeatedly varying its equilibrium value in time. Another definition of oscillation is the periodic variation of a substance between two values or around its core value.
An object's mechanical oscillations are referred to as vibrations. However, oscillations also happen in dynamic systems, or to be more precise, throughout all of science. Even our heartbeat generates vibrations. Oscillators, meanwhile, are described as having motion toward an equilibrium point.
To put it simply, oscillation motion is the word used to describe a mechanical system's item swinging from side to side.
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on integrated circuits the dc biasing of bjts is usually done using resistors and capacitors, since transistor current sources are too expensive. true or false
Due to the high cost of transistor ecurrent sourcs, resistors and capacitors are typically used to bias bjts in integrated circuits.
A semiconductor wafer on which hundreds or millions of small resistors, capacitors, diodes, and transistors are manufactured is known as an integrated circuit (IC), also known as a chip, microchip, or microelectronic circuit. Integrated circuits, which can be classified as analogue, digital, or a hybrid of the two, are extensively utilised in electronics design today. Amplifiers, video processors, computer memory, switches, and microprocessors are just a few applications for ICs.
On a silicon wafer, integrated circuits are made up of reduced versions of transistors, microprocessors, and diodes.
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Answer to this required:
(I just need some words for each answer, and I will form the full answer myself)
(thanks)
All the prompts indicated above are related to the qualities of light in Physics parlance.
1) When the left hand is lifted in front of the mirror, the picture depicts the right hand rising. This is due to the picture being reversed laterally. In the case of a flat mirror, it is produced.
2) Keep in mind that convex mirrors are commonly employed in shop security mirrors because the reflective surface bulges outwards toward the light source, resulting in a distorted picture but an increased range of view. This broad perspective is ideal for visually covering a large area.
3) A piece of paper appears white in the sunshine because it reflects all colors of light. When seen in red light, it appears red.
4) A rainbow is created by the interaction of sunlight and atmospheric circumstances. As light reaches a water droplet, it slows and bends as it transitions from air to denser water. The light bounces off the interior of the droplet, splitting it into wavelengths (or colors).
5) One effect of refraction is the bending of light as it passes through a medium with a different refractive index. For example, when light travels from air into water, it is bent, or refracted, causing objects to appear distorted or shifted. This is why objects underwater may appear closer or larger than they actually are.
6) The Newton disc, also known as the Disappearing Color Disc, is a well-known physics experiment in which a revolving disc with multiple colored parts becomes white when spun very quickly.
What are the qualities of light?Some of the qualities of light are as follows:
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Before quarks were proposed, this scientist proposed partons to analyze high-energy hadroncollisions. Using a formalism fully developed by this person, the quantum mechanical amplitude canbe found by integrating over all the possible paths with a weighting factor given by the classicalaction, the so-called path integral formulation.
Richard Feynman was the scientist who first suggested partons to study high-energy hadron collisions before quarks were suggested.
Quarks are what?The elementary particle known as the quark is a fundamental component of matter. Hadrons, which are composite particles made of these quarks and neutrons and protons, the building blocks of atomic nuclei, are the most stable of these hadrons.
How do hadrons work?A strong contact between two or more quarks holds together hadrons, which are composite subatomic particles. Simply put, hadrons are like molecules that the electric force holds together. Protons and neutrons combine to form hadrons, which are particles.
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microbursts are dangerous for commercial aircraft on takeoff or landing because of the associated:
Microbursts are dangerous for commercial aircraft on takeoff or landing because of the associated high wind gusts and turbulence.
Microbursts can create strong and sudden downdrafts that can cause a rapid decrease in airspeed and altitude, leading to a potential loss of lift and control. This can be especially dangerous during takeoff or landing when the aircraft is already at a low altitude and has limited ability to recover.
Microbursts are intense, short-lived downdrafts that can cause severe turbulence and strong winds in a localized area. They occur during thunderstorms and can last from a few seconds to a few minutes.
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Some electric-power companies use water to store energy. Water is pumped by reversible turbine pumps from a low to a high reservoir. To store the energy produced in 1 hour by a 120 MW electric-power plant, how many cubic meters of water will have to be pumped from the lower to the upper reservoir? Assume the upper reservoir is 470 m above the lower and we can neglect the small change in depths within each. Water has a mass of 1000 kg for every 1.0{m}^3.
The volume of water that will be pumped from the lower to the upper reservoir to generate the energy is 93,790.7 m³.
What is the volume of water needed to generate the power?The volume of water needed to generate the given power is calculated by applying the law of conservation of energy as shown below.
gravitational potential energy of water or work done by the water = energy generated
Mathematically, the equation is given as;
W = PV
where;
W is work done by the waterV is the volume of the waterP is the pressure of the waterW = (ρgh)V
where;
ρ is the density of waterg is acceleration due to gravityh is the height through which the water is pumped(ρgh)V = Pt
where;
P is the power generatedt is the time in which the power was generatedV = Pt / ρgh
The given parameters include;
P, power = 120 MW = 120 x 10⁶ Wt , time = 1 hour = 3600 sρ, density of water, = 1000 kg/m³g, acceleration due to gravity = 9.8 m/s²h, height of water, = 470 mThe volume of water needed to generate the energy is calculated as follows;
V = (120 x 10⁶ x 3600) / (1000 x 9.8 x 470)
V = 93,790.7 m³
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an ellipse is the locus of points in a plane such that the sum of the distances from any point in the locus to two points, called the foci, is a .
An ellipse is the location of all the points in a plane whose distances from two fixed points in the plane add up to a constant value. The foci, or singular focus, are the fixed points that are encircled by the curve.
what is an ellipse?In mathematics, an ellipse is the location of points in a plane so that their separation from a fixed point has a fixed ratio of "e" to their separation from a fixed line (less than 1). The conic section, which is the intersection of a cone with a plane that does not intersect the base of the cone, includes the ellipse. The fixed point is called the focus and is denoted by S, the constant ratio 'e' as the eccentricity, and the fixed line is called as directrix (d) of the ellipse.
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a 355 ml soda can is 6.2 cm in diameter and has a mass of 20 g. such a soda can half full of water is floating upright in water. What length of the can is above the water level?
The length of the can above the water level is 5.22 cm.
First determine the height of the can.
355cm3 = pi * r2 * l Volume of cylinder formula where l is length of can.
355=pi * (3.1)2 * l Where 3.1 is half of the diameter.
l = 11.76cm
Now determine the total mass of the can including the water inside.
Total mass = 20g + (355ml)/2 * 1g/ml = 177.5g, where 1g/ml is the density of water, therefore since we know half the can is full of water we take the volume of water inside, multiply it by the density and determine the mass of water. This, in addition to the weight of the can itself gives us the total mass of the floating object.
Total mass=197.5g
According to Archimedes' principle the mass of a floating object equals the mass of fluid displaced by the object.
197.5=mass of water displaced
197.5=density of water * volume of water
197.5= 1g/ml * (pi * (3.1)2 * l) where l is the length of can inside the water
6.54cm=l
So take total length of can and subtract the submerged length to retrieve the above water length.
11.76cm - 6.54cm = 5.22cm
5.22 cm of water level.
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What happens to length of metals as the temperature increases?
When a metal is heated, its atoms begin to vibrate more vigorously and move further apart from each other. This increases the distance between the atoms, which in turn causes the metal to expand and become longer.
The amount of expansion that a metal undergoes when heated depends on several factors, including the type of metal, the initial temperature of the metal, and the rate at which it is heated. In general, most metals will expand by a small amount when heated over a wide range of temperatures.
At very high temperatures, some metals may begin to undergo a phase change, such as melting or vaporization. This can cause the metal to undergo a significant change in length, depending on the amount of phase change that occurs.
Overall, the length of a metal will generally increase as the temperature increases, although the exact amount of expansion will depend on the specific conditions and the type of metal involved.
a uniform disk with mass 43.6 kg and radius 0.300 m is pivoted at its center about a horizontal, frictionless axle that is stationary. the disk is initially at rest, and then a constant force 29.0 n is applied tangent to the rim of the disk.
The magnitude v of the tangential velocity of a point on the rim of the disk after the disk has turned through 0.320 revolutions will be 1.266 m/s
Mass = m = 43.6 Kg.
radius = 0.300 m
F = 29 n
So, value of Torque to the rim of disc will be = Fr = 30*0.3 = 9 Nm.
So, the value of angular acceleration will be: [tex]$\alpha=\frac{\tau}{I}: I=$[/tex] moment of inert of dice
[tex]=\frac{M R^2}{2}\\$\alpha=\frac{29 \mathrm{~N} \times 0.3 \mathrm{~m}}{\frac{43.6 \times \mathrm{kg} \times(0.3 \mathrm{~m})^2}{2}}\\\\=\frac{29 \times 0.3 \times 2}{43.6 \times(0.3)^2} \mathrm{rad} / \mathrm{s}^2$\\\\=4.4342 \mathrm{rad} / \mathrm{s}^2$[/tex]
[tex]$\quad \Delta \theta=0.320 \mathrm{rev}=0.320 \times 215 \mathrm{rad}$[/tex]
An Angular velocity at that instant [tex]$=\omega_f > $[/tex]
[tex]$$\begin{aligned}& \omega_i=0 \\& \text { using } \omega_f^2=\omega_i^2+2 \alpha \Delta \theta \\& \omega_f^2=0+2 \times 4.4342 \times 0.320 \times 2 \pi \\& \omega_f=\sqrt{2 \times 4.4342 \times 0.320 \times 2\Pi} \mathrm{rad} / \mathrm{s} \\& \omega_f=4.22 \mathrm{rad} / \mathrm{s}\end{aligned}$$[/tex]
The tangential velocity of point on [tex]$n m=\omega_f r$[/tex]
[tex]$$\begin{aligned}& V=4.22 \times 0.3 \mathrm{~m} \\& V=1.266 \mathrm{~m} / \mathrm{s}\end{aligned}[/tex]
The complete question should be:
A uniform disk with mass 43.6 kg and radius 0.300 m is pivoted at its centre about a horizontal, frictionless axle that is stationary. the disk is initially at rest, and then a constant force 29.0 n is applied tangent to the rim of the disk. What is the magnitude v of the tangential velocity of a point on the rim of the disk after the disk has turned through 0.320 revolutions?
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If you traveled for 25hours with an average speed of 48miles/hours, the distance travel
If you traveled for 25 hours with an average speed of 48 miles/hour, the distance traveled is 25 * 48 = 1200 miles. This can be found by multiplying the number of hours traveled by the average speed to get the total distance traveled.
|_-_ I did an experiment _-_|
If I ask a, non legit question, it instantly get's flagged, if I ask a legit question, it doesn't get answered.
CAN SOME ONE EXPLANE??
Answer:
Explanation:
happens to me with some guy names venus he always flaggs me when i even answer a question its really dificult to even try to answer when someone is on your tail ever now and then
At the time of its discovery, 3C 273 was the most ____________________ object in the universe.
3C 273 was the most luminous object in the universe at the discovery time.
What are stars?An illuminated sphere of plasma that is held together by its gravity is a star.
The Sun is the star that is closest to Earth. Due to their enormous distance from Earth, many more stars are also visible at night to the unaided eye from Earth, appearing as a multiplicity of stationary light dots in the sky.
In the past, the brightest stars were assigned names and grouped into constellations and asterisms.
Star catalogs have been put out by astronomers that list the known stars and offer standardized stellar labels.
All stars outside of our galaxy, the Milky Way, and the majority of other stars in the universe are, nevertheless, invisible to the human eye from Earth.
Even the most powerful telescopes cannot see the majority of them from Earth.
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which of the following situations is an example of a negative feedback loop? group of answer choices a thermostat regulating the temperature of your home rolling a ball of snow down a hill the greenhouse effect a viral video on the internet
The greenhouse effect is one instance of a negative feedback loop among the examples presented. There are several instances of positive feedback loops.
Positive feedback loop: what is it?Positive feedback, also known as aggravating feedback or self-reinforcing feedback, is a phenomenon that takes place in a feedback loop that amplifies the impact of a little disruption. In other words, a perturbation's impacts on a system include an increase in the perturbation's size.
A negative feedback loop is what?When a system, process, or mechanism's output is fed back in a way that seeks to lessen oscillations in the output, whether brought on by changes in the input or other disturbances, this is known as negative feedback (or balancing feedback).
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under the influence of its drive force, a snowmobile is moving at a constant velocity along a horizontal patch of snow. when the drive force is shut off, the snowmobile coasts to a halt. the snowmobile and its rider have a mass of 136 kg. under the influence of a drive force of 205 n, it is moving at a constant velocity whose magnitude is 5.50 m/s. the drive force is then shut off.Find (a) the distance in which the snowmobilecoasts to a halt and (b) the time required to dos
There is no difference in the shape of 2p and 3p orbitals since the azimuthal quantum number, which defines the shape of the orbital, is the same for both.
The electron orbital energy levels are listed in the following order, from lowest to highest: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, and 7p. Because electrons all have the same charge, they try to stay as far apart as possible due to repulsion. We only need three hybrid orbitals, aka sp2, because the carbon has no lone pairs and is connected to three hydrogens. Don't forget to account for any lone pairings. Every solitary pair need its own hybrid orbital.
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what must the emf e of the battery be in order for a current of 2.00 a to flow through the 5.00 v battery, as shown?
The battery's emf has to be -108.75 volts for a 2a current to pass through a 5.00 v battery.
Kirchhoff's Voltage Law states that for any closed network, the voltage around a loop is equal to the total of all voltage drops in that loop and is equal to zero. The conservation of energy, or to put it another way, is the characteristic of Kirchhoff's law which states that the algebraic sum of each voltage in the loop must equal zero.
Do a series/parallel reduction first. Apply Kirchhoff's laws now to get the answer.
ΔV adefa =0 or − (20Ω) × (2A) × 5V − (20Ω) × I2
= 0 or I2
= −2.25A
I1 + I2 = 2A or I1 = 2A − ( −2.25A ) = 4.25A
ΔV adefa = 0 or (15Ω) × (4.25A) + ϵ − (20Ω) (−2.25A) = 0
ϵ = −108.75V; Reversing polarity is necessary.
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A boy swings a rubber ball attached to a string over his head in a horizontal, circular path. The piece of string is 0.735 m long and the ball
makes 159 complete turns each minute. What is the ball's centripetal acceleration?
Answer:
approximately 1.007 * 10^8 m/s^2
Explanation:
To find the ball's centripetal acceleration, we can use the formula a = v^2 / r, where a is the centripetal acceleration, v is the tangential velocity of the ball (the speed at which it moves around the circle), and r is the radius of the circle (the length of the piece of string).
First, we need to find the tangential velocity of the ball. The ball makes 159 complete turns each minute, which means it makes 159 * 2 * pi = 998.46 radians per minute. Since the ball is moving at a constant speed, the tangential velocity is equal to the angle it travels in radians per unit of time, so the tangential velocity of the ball is 998.46 radians per minute.
Next, we need to find the radius of the circle. The length of the piece of string is 0.735 m, and since the ball is swinging in a horizontal circle, the radius of the circle is equal to the length of the piece of string. Therefore, the radius of the circle is 0.735 m.
Now that we have the tangential velocity and the radius of the circle, we can plug these values into the formula to find the centripetal acceleration:
a = v^2 / r
= 998.46^2 / 0.735
= 1.007 * 10^8 m/s^2
Therefore, the ball's centripetal acceleration is approximately 1.007 * 10^8 m/s^2.
quasars may result from the very energetic merging of in condensing galaxies. quasars may result from the very energetic merging of in condensing galaxies. black holes suns stars dark matter
Quasars may result from the very energetic merging of dark matter in condensing galaxies.
Quasars may result from the very energetic merging of gas spiraling at high velocity in condensing galaxies.
What is a quasar?
A quasar forms can be regarded as one that the material that falls into the accretion disc which is seen in supermassive black hole at the center of a galaxy.
A massive object, like a galaxy cluster, is able to deform the space-time shape as a consequence of its own gravity, so the light that it is coming from a source that is behind it in the line of sight will be bend or distorts in a way that will be magnified, making small arcs around the cluster with the image of the background object.
Not only does the central engine of active galaxies and quasars require a black hole, Accretion disk of matter is also needed to provide the energy radiated. Dust, other stellar debris, and gas that has come near to a black hole but fallen into it yet forms a flattened band of spinning matter around the event horizon called the accretion disk (or disc).
Therefore, quasars may result from the very energetic merging of dark matter in condensing galaxies.
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Quasars may result from the very energetic merging of dark matter in condensing galaxies.
Quasars may result from the very energetic merging of gas spiraling at high velocity in condensing galaxies.
What is a Quasar?
A quasar forms can be regarded as one that the material that falls into the accretion disc which is seen in supermassive black hole at the center of a galaxy.
A massive object, like a galaxy cluster, is able to deform the space-time shape as a consequence of its own gravity, so the light that it is coming from a source that is behind it in the line of sight will be bend or distorts in a way that will be magnified, making small arcs around the cluster with the image of the background object.
Not only does the central engine of active galaxies and quasars require a black hole, Accretion disk of matter is also needed to provide the energy radiated. Dust, other stellar debris, and gas that has come near to a black hole but fallen into it yet forms a flattened band of spinning matter around the event horizon called the accretion disk (or disc).
Therefore, quasars may result from the very energetic merging of dark matter in condensing galaxies.
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a rope is attached to the top of a block. if the block hangs in the air, the tension on the rope is 300 n. when the block is fully submerged in a fluid of density 600 kg/m3 , the tension on the rope is 200 n.
The tension on the rope is 300 n. when the block is fully submerged in a fluid of density 600 kg/m3 ,The tension on the rope is 2940.
T = buoyancy force - weight of block = 600 x 9.8 - 300 x 9.8 = 2940
When two opposing pressures pull on a rope, string, or wire, the force communicated through the object is known as tension. The energy is pulled equally on the bodies at the ends by the tension force, which is applied over the entire length of the wire.
Each physical object that comes into contact with another applies force to that other. Names are given to these contact forces based on the types of objects. The term "tension" can be used to describe one of the forces acting on an object that is a rope, cable, or chain.
Since they effectively convey a force over a predetermined distance, cables and ropes can be utilized to apply forces (e.g. the rope length). Remember that since ropes cannot effectively push, tension acts as the pulling force.
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An object undergoes an acceleration as it travels along a straight,horizontal section of a track. Which of the following graphs could represent the motion of the object? Select two answers. Speed Position Position Time Squared Velocity
A distance-time graph can be used to see the distance traveled by an object when it moves in a straight line. A distance-time graph's line gradient corresponds to the object's speed. The gradient's magnitude determines how quickly an object is travelling.
Explain what an acceleration is.Acceleration is the rate at which velocity, both in terms of speed and direction, varies over time. Whenever something moves either quicker or slower in a horizontal path, it is referred to as pushed.
What prompts accelerating?An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.
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in fig. 11-37, a small, solid, uniform ball is to be shot from point p so that it rolls smoothly along a horizontal path, up along a ramp, and onto a plateau.then it leaves the plateau horizontally to land on a game board, at a horizontal distance d from the right edge of the plateau. the vertical heights are h1 ! 5.00 cm and h2 ! 1.60 cm. with what speed must the ball be shot at point p for it to land at d ! 6.00 cm?
The speed at which the ball must be shot at the point p for it to land at the distance 6 cm is 6.635 m/s.
Given that,
Height h₁ = 5 cm
Height h₂ = 1.6 cm
Distance d = 6 cm
We know, t = √(2 h₂/g) = √(2* 1.6)/9.8 = 0.57 s
We know that, distance is nothing but speed multiplied by time.
According to the above statement, expression can be written as d = V₁* t
V₁ = d/t = 6/0.57 = 10.52 m/s
Using work energy theorem, we have
mg(h₁ - h₂) = 1/2* m * V₁² - 1/2* m * V₂²
Eliminating 'm' on both sides, g(h₁ - h₂) = 1/2* V₁² - 1/2* V₂²
9.8 (5 - 1.6) = 1/2* 10.52² - 1/2* V₂²
33.32 = 1/2(10.52² - V₂²)
(10.52² - V₂²) = 66.64
V₂² = 44.03
V₂ = 6.635 m/s
Thus, the speed of the ball with which it should be shot is 6.635 m/s.
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taipei 101 (a 101-story building in taiwan) is sited in an area that is prone to earthquakes and typhoons, both of which can lead to dangerous oscillations of the building. to reduce the maximum amplitude, the building has a tuned mass damper, a 660,000 kg mass suspended from 42-m-long cables that oscillates at the same natural frequency as the building (figure 1). when the building sways, the pendulum swings, reaching an amplitude of 75 cm in strong winds or tremors. damping the motion of the mass reduces the maximum amplitude of oscillation of the building.
The period of oscillation of the building will be=13 s
During strong winds, the pendulum moves when it passes through the equilibrium position with a speed of = 0.36 m/s
(a)
Let us assume that the time period of oscillations of the building be [i 0]
So, the expression for time period will be: [tex]$$T=2 \pi \sqrt{\frac{l}{g}}$$[/tex]
Where, l is the length of the pendulum and g is the acceleration due to gravity.
So, the value of time period of oscillations will be:
[tex]T & =2 \pi \sqrt{\frac{(42 \mathrm{~m})}{\left(9.8 \mathrm{~m} / \mathrm{s}^2\right)}}[/tex] =13.0 seconds.
(b)
As we have, the relation between angular frequency and time period, which is [tex]$$\omega=\frac{2 \pi}{T}$$[/tex]
So, the value of the linear velocity of the pendulum will be
[tex]$$\begin{aligned}v & =A \omega \\& =A\left(\frac{2 \pi}{T}\right) \\& =\frac{2 \pi A}{T} \\& =\frac{2 \pi(0.75 \mathrm{~m})}{(13.0 \mathrm{~s})} \\& =0.36 \mathrm{~m} / \mathrm{s}\end{aligned}$$[/tex]
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The complete question should be:
Taipei 101 (a 101-story building in Taiwan) is sited in an area that is prone to earthquakes and typhoons, both of which can lead to dangerous oscillations of the building. To reduce the maximum amplitude, the building has a tuned mass damper, a 660,000 kg mass suspended from 42-m-long cables that oscillates at the same natural frequency as the building. When the building sways, the pendulum swings, reaching an amplitude of 75 cm in strong winds or tremors. Damping the motion of the mass reduces the maximum amplitude of oscillation of the building.
What is the period of oscillation of the building?
During strong winds, how fast is the pendulum moving when it passes through the equilibrium position?
A 10.0-kg microwave oven is pushed 8.00 m up the sloping surface of a loading ramp inclined at an angle of above the horizontal, by a constant force \vec{F} F with a magnitude 110 N and acting parallel to the ramp. The coefficient of kinetic friction between the oven and the ramp is 0.250. (a) What is the work done on the oven by the force ? (b) What is the work done on the oven by the friction force? (c) Compute the increase in potential energy for the oven. (d) Use your answers to parts (a), (b), and (c) to calculate the increase in the oven’s kinetic energy. (e) Use \Sigma \vec{\boldsymbol{F}}=m \vec{\boldsymbol{a}}Σ F =m a to calculate the acceleration of the oven. Assuming that the oven is initially at rest, use the acceleration to calculate the oven’s speed after traveling 8.00 m. From this, compute the increase in the oven’s kinetic energy, and compare it to the answer you got in part (d)
(a) Work done on the oven = 110J
(b) Work done by the friction force =250J
(c) Increase in PE =1000J
(d) Increase in KE = 640J
(e) Acceleration of the oven =14.9 m/s² And KE =74.5J
Given
g = 10
mass = 10kg
distance = 8 m
Magnitude of force = 110 N
Kinetic friction = 0.250 N
A
The work done on the oven by the force is given by
W = F.d
W = 110*14cos(0)
It is a Horizontal component
W = 110 J
B
Now to calculate the work done by the friction force
Frictional force = μ * N
Frictional force = 0.25*10*10
Frictional force = 25 N
Frictional work = frictional force . d
work(f) = 25 * 10cos(0)
Work(f) = 250 J
C
Increase in the Potential energy
PE = mgh
PE = 10*10*10cos(0)
PE = 1000 J
D
The increase in the oven's kinetic energy
PE₁ = KE₁ + W = PE₂ + KE₂
110 - 260 - 1000 = KE₂
KE₂ = 640J
E
The acceleration of the oven
Force - frictional force = ma
a = 110 -250/10 = 14 m/s²
Now to calculate KE we should know the velocity
V(f)² = v(i)² + 2ad
v(f)² = 2(14)(8) = 224
v(f) = 14.9 m/s
Now KE will be given as
(1/2)mv²
KE = (1/2)(10)(14.9)
KE = 74.5 J
Therefore, we got to know the work done, PE and KE just by the force applied.
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A pulse of electromagnetic radiation is propagating in the +y direction. You have two devices that can detect electric and magnetic fields. You place detector #1 at location < 0, -3, 0> m and detector #2 at location < 0, 3, 0> m.
(a) At time t = 0, detector #1 detects an electric field in the -x direction. At that instant, what is the direction of the magnetic field at the location of detector #1?
(b) At what time will detector #2 detect electric and magnetic fields?
a. At the time [tex]\rm \(t = 0\)[/tex], the magnetic field at the location of detector #1 is in the +z direction.
b. At [tex]\(t \approx 2 \times 10^{-8}\)[/tex] seconds, detector #2 will detect the electric and magnetic fields.
(a) To determine the direction of the magnetic field at the location of detector #1, we can use the right-hand rule, which relates the direction of the magnetic field [tex]\rm (\(B\))[/tex], the direction of the electric field [tex]\rm (\(E\))[/tex], and the direction of propagation [tex]\rm (\(+y\))[/tex].
Since the pulse of electromagnetic radiation is propagating in the +y direction and detector #1 detects an electric field in the -x direction, the magnetic field [tex]\rm (\(B\))[/tex] must be in the +z direction.
This is because electromagnetic waves are transverse waves, and the electric and magnetic fields are perpendicular to each other and the direction of propagation.
So, at time [tex]\rm \(t = 0\)[/tex], the magnetic field at the location of detector #1 is in the +z direction.
(b) To determine the time at which detector #2 will detect electric and magnetic fields, we need to consider the distance between the two detectors and the speed of propagation of the electromagnetic wave.
Let's assume that the speed of light [tex]\rm (\(c\))[/tex] is [tex]\rm \(3.00 \times 10^8\)[/tex] m/s.
The distance between the two detectors is [tex]\rm \(d = 6\)[/tex] m (distance between the y-coordinates of the detectors).
The time [tex]\rm (\(t\))[/tex] it takes for the electromagnetic wave to travel from detector #1 to detector #2 is given by:
[tex]\[ t = \frac{d}{c} \]\\\\\ t = \frac{6 \, \text{m}}{3.00 \times 10^8 \, \text{m/s}} \]\\\\\ t \approx 2 \times 10^{-8} \, \text{s} \][/tex]
So, in [tex]\rm \(t \approx 2 \times 10^{-8}\)[/tex] seconds, detector #2 will detect the electric and magnetic fields.
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Most of the spaceflight missions to the outer planets have been flyby missions, but two of them were orbiters. Which of these two spacecraft orbited giant planets? Check the correct two.
(Hint: An orbiter might do a flyby of one planet and then go on to orbit a differentplanet.)
Group of answer choices
Galileo
Ulysses
New Horizons
Voyager
Cassini
Pioneer
Galileo and Cassini are the two missions on outer planets that were orbiters. Galileo orbited Jupiter for eight years, while Cassini orbited Saturn for thirteen years.
A total of 9 spacecraft have been launched for missions on outer planets. Two of them are orbiters. Galileo was an American spacecraft to study Jupiter. It was delivered into Earth orbit on October 18, 1989, by Space Shuttle Atlantis,
Cassini was a space mission by NASA and ASI to study the planet Saturn. It was launched on Titan IVB/Centaur, and the date was October 15, 1997. Cassini was active for nearly 20 years which it spent orbiting Saturn for 13 years. It was the first spacecraft to enter Saturn orbit.
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what is the average power pavg supplied by the voltage source? express your answer in terms of any or all of the following quantities: v0 , c , l , and r .
The average power supplied by the voltage source is given by
Pavg = Irms * Vrms
Pavg = 1/2 I₀² R = I²rms * R
Pavg = 1/2 V₀²/R = V²rms /R
where, Pavg is average power
Irms is rms current
Vrms is rms voltage
I₀ is the peak value of alternating current
V₀ is the peak value of alternating voltage
Root mean square current of the alternating current represents the DC current that dissipates the same amount of power as the average power dissipated by the alternating current.
The RMS value of alternating current is given by the direct current which flows through a resistance.
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N А. В. S Current Current is moving through a copper ribbon in the direction shown. The ribbon is suspended between the poles of a magnet as indicated. When the voltage is measured between A and B, it is observed that A is at higher potential than B. Which of the following explains this observation? A The electrons in the ribbon behave like magnetic dipoles; thus, they align with the magnetic field of the magnet that deflects electrons in the ribbon toward point A. B The electrons in the ribbon behave like magnetic dipoles; thus, they align with the magnetic field of the magnet that deflects electrons in the ribbon toward point B. с Electrons moving through the magnetic field experience a magnetic force to the left that deflects electrons in the ribbon toward point A. D Electrons moving through the magnetic field experience a magnetic force to the right that deflects electrons in the ribbon toward point B. E The electric field in the ribbon is distorted by the magnetic field. This distortion creates an electric field component directed from point A to point B that deflects electrons in the ribbon toward point B.
The explanation for this observation is that the magnetic field distorts the electric field in the band. This distortion creates an electric field component directed from point A to point B which deflects the electrons in the bar toward point B.
The physical field that surrounds an electrically charged particle and exerts a force on all other charged particles in that field, either attracting or repelling them, is called the electric field (or E-field). It can also refer to the physical field system of charged particles.
The negatively charged electrons are directed to the positive electrode or (+) plate. Positively charged protons are directed to the negative electrode or plate (-).
Therefore, ferromagnetic materials bend the lines of magnetic force in space in a static field. The distortion effect on the static magnetic field is disturbed by the deformed material.
The complete questions:
Current is moving through a copper ribbon in the direction shown. The ribbon is suspended between the poles of a magnet as indicated. When the voltage is measured between A and B, it is observed that A is at higher potential than B. Which of the following explains this observation?
A) The electrons in the ribbon behave like magnetic dipoles, thus, they align with the magnetic field of the magnet that deflects electrons in the ribbon toward point A.
B) The electrons in the ribbon behave like magnetic dipoles, thus, they align with the magnetic field of the magnet that deflects electrons in the ribbon toward point B.
C) Electrons moving through the magnetic field experience a magnetic force to the left that deflects electrons in the ribbon toward point A
D) Electrons moving through the magnetic field experience a magnetic force to the right that deflects electrons in the ribbon toward point B
E) The electric field in the ribbon is distorted by the magnetic field. This distortion creates an electric field component directed from point A to point B that deflects electrons in the ribbon toward point B.
The true choice is E
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g determine the binding energy per nucleon for 56fe. compare to 62ni at 8.795 mev/nucleon. the atomic mass of 56fe is 55.9349375 u.
Binding energy for Fe is 8.52 MeV and for nickel is 554.3 MeV.
Binding energy : It is the minimum amount of energy required to disassemble or break down an atom's nucleus into the subatomic particles, which are protons and neutrons.
The average energy required to release a nucleon from a nucleus is called binding energy per nucleon.
Binding Energy , BE=Δmc2, where Δm is the mass defect
Here , Δm=Mass of nucleon- Mass of nucleus=26 [tex]m_{p[/tex] +30 [tex]m_{n[/tex] -m 56 Fe
Hence,
BE = (26 [tex]m_{p[/tex] +30 [tex]m_{n[/tex] -m 56 Fe) [tex]c^{2}[/tex]
where [tex]m_{n[/tex] = 1.00866 u
[tex]m_{p[/tex] = 1.00727 u
BE=[26×1.00727+30×1.00866−55.936]×931
=0.51282×931
=477.435 MeV
Binding energy per nucleon = 477.435/56 MeV
=8.52 MeV.
Now we will calculate binding energy for nickel
Then mass defect,
Δm=28m H +34m n − 28 34 m
Δm=28×1.008+34×1.0087−61.9237
Δm=0.5961u
Hence binding energy,
B.E.=Δm×931
B.E.=0.5961×930=554.3 MeV
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you are designing an elevator for a hospital. the force exerted on a passenger by the floor of the elevator is not to exceed 1.50 times the passenger's weight. the elevator accelerates upward with constant acceleration for a distance of 2.8 m and then starts to slow down. What is the maximum speed of the elevator?
The maximum speed of the elevator, the force exerted on a passenger by the floor of the elevator is not to exceed 1.50 times is 6m/s
ΣFy=may
n−mg=ma
n=1.5mg
a=0.60g=6ms^−2
v2=u2+2as=02+2×6×3
v=6m/s
The rate at which an object's distance traveled changes is measured by its speed. In terms of measurement, speed is a scalar, meaning it has magnitude but no direction. Speed is the rate at which an object moves over a given distance. a thing that travels at a high rate of speed and covers a lot of distance quickly. A slow-moving object, on the other hand, travels a comparatively short distance in the same amount of time when moving at a low speed. An object with zero speed is completely immobile.
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