Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning. After 5 hours of burning, a candle has a height of 26 centimeters. After 24 hours of burning, its height is 14.6 centimeters. What is the height of the candle after 18 hours?

Answer:

3rd option

Step-by-step explanation:

The equation of a vertical line parallel to the y- axis is

x = c

where c is the value of the x- coordinates the line passes through

The only equation in this form is option 3

3x - 2 = 0 , as

3x = 2 and

x = [tex]\frac{2}{3}[/tex] ← equation of vertical line

[tex]\text{Given that,}\\\\ab = 8 ~ \text{and}~ a^2 +b^2 = 35\\\\\text{Now,}\\\\(a-b)^2 = a^2 +b^2 -2ab\\\\\implies (a-b)^2 =35 - 2 (8) \\\\\implies (a-b)^2 = 19\\\\\implies a-b = \pm\sqrt{19}\\\\\text{Case 1:}\\\\(a-b)^3 = (a-b)^2(a-b)\\\\\implies (a-b)^3 = 19 \left(\sqrt{19}\right)\\\\\text{Case 2:}\\\\(a-b)^3 = (a-b)^2(a-b)\\\\\implies (a-b)^3 = -19 \left(\sqrt{19}\right)[/tex]

Answer: Hence, by ASA ( Angle side Angle) Rule of congruency two triangles;

Angle ADE = CDF Hence proved.

Step-by-step explanation:Diagram of two triangles are given such that side ED = FD and <AED = < CFD = 90

To Find: TO prove <ADE = <CDF

Solution; In figure ; we can see that <EDA and <FDC are vertically opposite angles and hence are equal.

=> <EDA = <FDC |Vertically opposite angles

<DEA = <CFD = 90 |Given

Also, ED = FD |Given

Hence, by ASA (Angle Side Angle)

Rule of congruency two triangles; <ADE = <CDF

Hence Proved.

Answer:

9x-5y=2======>9x-5y=2===>(+)7y=-28=>y=-4=>(1)3x-4(-4)=10=>x+16=20=>x=4

3x-4y=10(1)=>(×-3)-9x+12y=-30=>(+)

Answer:

(x+1)x(x+7)x(3x-4)

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

positive numbers are always bigger than negative numbers

Answer:

0.04444444444

Step-by-step explanation:

[tex]\\ \rm\rightarrowtail 4/9-4/10[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{40-36}{90}[/tex]

[tex]\\ \rm\rightarrowtail 4/90[/tex]

[tex]\\ \rm\rightarrowtail 2/45[/tex]

Answer:

Step-by-step explanation:

Each half of a hanger divides the total weight in half. The right-most vertical has a total weight of 80/16 = 5. It consists of a square and a diamond, and we know the square is 1 more than the diamond. That means 2 diamonds weigh 5 -1 = 4. A diamond weighs 2, and a square weighs 3. The other half of that balance is a circle, which weighs 5.

The total of a square and oval is 10, so the oval is 10 -3 = 7. The two trapezoids weigh 20, so each is 10.

The second vertical from the left is a circle and diamond which will weigh 5+2 = 7. That makes the sum of a pentagon and rectangle also be 7. The 7+7 = 14 below the square on the left branch makes the total of that branch be 14+3 = 17, which is also the sum of the triangle and hexagon.

The weight below the rectangle at top left is 17+17 = 34, and the weight of that entire branch is 40. Thus the rectangle is 40-34 = 6, which makes the pentagon 7-6 = 1.

We require the sum of the triangle and hexagon be 17, with the triangle being the smaller value, and both being 9 or less (the trapezoid is the only figure weighing more than 9). Hence the triangle is 8 and the hexagon is 9.

The weights are summarized in the answer section, above.

Answer:

130⁰

Step-by-step explanation:

Let,

<Q = x

<R = y

So,

In ∆PQR

2x + 2y + 80 = 180(Sum of all angle in a triangle is 180⁰)

2(x + y) = 180 - 80

2(x + y) = 100

x + y = 100/2

x + y = 50

Now,

In ∆QOR

x + y + QOR = 180(Sum of all angle in a triangle is 180⁰)

50 + QOR = 180

QOR = 180 - 50

QOR = 130⁰

[tex]\dfrac 17 x^2 + 1 = \dfrac 37 x\\\\\implies x^2 +7 =3x~~~;[\text{Multiply both sides by 7}]\\\\\implies x^2 -3x +7 =0\\\\\text{Apply quadratic formula}~ x = \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}.\\\\\text{In this case ,}~ a =1, b= -3 , c =7\\\\x = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4(1)(7}}{2(1)}\\\\\implies x= \dfrac{3 \pm \sqrt{-19}}{2}\\\\\implies x =\dfrac{ 3 \pm i\sqrt{19}}2\\\\\\\text{Smaller value of x } =\dfrac{ 3 -i\sqrt{19}}2\\\\\text{Larger value of x } =\dfrac{ 3 +i\sqrt{19}}2[/tex]

Answer:

4% maybe

Step-by-step explanation:

Answer:

the answer to this problem is D: 180 + w-z

Answer:

... ................................

Step-by-step explanation:

in that case we can imagine a diagonal line DB that splits the quadrilateral into 2 right-angled triangles: ADB and CDB.

the area of the quadrilateral is then the sum of the areas of the 2 triangles.

the area of a right-angled triangle is

leg1 × leg2 / 2

with the legs being the sides that enclose the 90 degree angle.

so, for ADB we get

AD × AB / 2 = 3 × 11 / 2 = 33/2 = 16.5

for CDB we get

BC × CD / 2 = 7 × 9 / 2 = 63/2 = 31.5

so, in total for the area of the quadrilateral we get

16.5 + 31.5 = 48

Answer:

[tex]x=12[/tex]

Step-by-step explanation:

when solving and equation with a variable, you must work backwards and do the opposite of the equation

sooo… you must subtract 4 (opposite of +4 is -4)

[tex]16-4=2[/tex]

x=12

Answer:

12 easy

Step-by-step explanation:

4 +12 =16 it's easy

Step-by-step explanation:

Area of Semi Circle

The area of a semicircle is half of the area of the circle. As the area of a circle is πr2. So, the area of a semicircle is 1/2(πr2 ), where r is the radius.

Answer:

Step-by-step explanation:

It's a lot greater. If you take 0.4% of some number and the answer is 76, you better be starting with something that is very large. The formula will make the solution automatic.

Formula

Let the number be x

0.4% x = 76

0.4% = 0.4/100

0.4 / 100 * x = 76            Multiply both sides of the equation by 100

0.4x = 76*100                Combine the right.

0.4x = 7600                  Divide by 0.4

x = 7600/0.4

x = 19000                       Which is quite a bit larger than 76

Answer:

greater than 76

Step-by-step explanation:

hope it will help goodbye

Answer:

11m + 4n

Step-by-step explanation:

when two numbers with the same variable are added together or subtracted the result is just the numbers added or subtracted. So you can add 6m and 5m to get 11m. and you can subtract 3n from 7n to get 4n

11m + 4n

Answer:

Yes, 2 or more acute angles can be in a right angle based on the degree.

Step-by-step explanation:

A right angle is 90 degrees so any acute angle would be less than 90 degrees which means that there can be multiple acute angles based on the degrees. There can be 2 or more acute angles based on degrees that lead up to 90 degrees in total.

Answer: 2/5

Step-by-step explanation: hope it helps

The range would be needed to label the subjects correctly is 000-210.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

Given that a researcher is comparing the effectiveness of three devices.

There are 210 people who snore participating in the experiment

The researcher will randomly place the participants into three equally sized treatment groups suitable for comparison.

We need to find the range which would be needed to label the subjects correctly.

210 people are participating in experiment

We need to label subjects from 001 to 210

Since there is no value in using 000 to indicate someone.

Hence, 000–210 is the range would be needed to label the subjects correctly.

To learn more on Statistics click:

https://brainly.com/question/29093686

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Answer:

7 3/8 hours

Step-by-step explanation:

5 + 2 = 7

2/8 + 1/8 = 3/8

Therefore, 7 + 3/8 =

7 3/8 hours

Answer:

1. The Pythagorean Theorem, a2+b2=c2, a 2 + b 2 = c 2 , is used to find the length of any side of a right triangle.

2. In a right triangle, one of the angles has a value of 90 degrees.

3. The longest side of a right triangle is called the hypotenuse, and it is the side that is opposite the 90 degree angle.

Step-by-step explanation:

Answer:

[tex] \sqrt{8} [/tex]

Step-by-step explanation:

an

irrational number can only be written in the form with never ending,non-repeatinng digits after the decimal comma

Answer:

2x-1=5x

-1=3x

1.A. we take away 2x from both sides

2.A they are the same sine they both have the same solution of -1/3

Hope This Helps!!!

Answer:

Rewrite one side by combining like terms                                                                       A yes the equations are equivalent meaning they have the same solution

Step-by-step explanation:

Hope this helped

Answer:

$31.68

Step-by-step explanation:

1.4 x 9.15 = $12.81

0.8 x 10.75 = $8.60

2.6 x 3.95 = $10.27

12.81 + 8.60 + 10.27 = $31.68

Answer:

5

Step-by-step explanation:

[tex]1\frac{7}{8}\div\frac{3}{8}[/tex]

[tex]=\frac{15}{8}\div \frac{3}{8}[/tex]

[tex]=\frac{15\times \:8}{8\times \:3}[/tex]

[tex]=\frac{15}{3}[/tex]

[tex]=5[/tex]

The quotient is 5.

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\textsf{Given that:}\\[/tex]

[tex] \sf1 \dfrac{7}{8} \div \dfrac{3}{8} \\ [/tex]

[tex] \sf \longmapsto \: \dfrac{7 \times 8}{8} \div \frac{3}{8} \\ [/tex]

[tex] \sf \longmapsto \: \dfrac{15}{8} \div \dfrac{3}{8} \\ [/tex]

[tex] \sf \longmapsto \: \dfrac{ \dfrac{15}{8} }{ \dfrac{3}{8} } \\ [/tex]

[tex] \sf \longmapsto \: \dfrac{ \dfrac{15}{8} \times \frac{8}{3} }{ \dfrac{ \cancel \green3}{ \cancel \red8} \times \frac{ \cancel \red8}{ \cancel \green3} } \\ [/tex]

[tex]\sf \longmapsto \dfrac{ \dfrac{15}{8} \times \frac{8}{3} }{1} \\ [/tex]

[tex]\sf \longmapsto \: \dfrac{15}{ \cancel \red8} \times \dfrac{ \cancel \red8}{3} \\ [/tex]

[tex]\sf \longmapsto \: \dfrac{15}{3} \\ [/tex]

[tex]\sf\longmapsto \:\dfrac{15÷3}{3÷3}\\[/tex]

[tex]\sf\longmapsto \:\dfrac{5}{1}\\[/tex]

[tex]\sf\longmapsto \:\boxed{5} \: Answer.\\[/tex]

also read similar questions: Multiply. Write your answer as a fraction in simplest form...

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Answer:

x-490=t

Step-by-step explanation:

Marlee has x money

She deposited $60 meaning adding $60 to the bank

So x+60

THen Marlee need to withdraw $550 from her bank to rent

So the equation is now

x+60-550

60-550 is -490

Thus:

x-490

(I will represent (t) as the money she has left for the equation)

Thus the equation is

x-490=t

Hope this helps!

Answer:

An improper fraction

Step-by-step explanation:

In improper fraction is when the numerator (top number) is greater than or equal to the denominator (bottom number)