Suppose that (a,n) : = if and only if 1. Prove that a¹ = a^(mod n) b = c(mod ord,(a)).

Answer: No solutions

Step-by-step explanation: If you solve the problem all the way, you get 0 = 4 which is not valid so there is simply no solution

The given equation 3(2x−1)+5=6(x+1) has no solution. Option B is correct.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Given equation ⇒

⇒= 3(2x−1)+5=6(x+1)

Simplify the above expression,
⇒ 6x - 3 + 5 = 6x + 1
⇒    2 ≠ 1

Thus, the given equation has no solution.

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a. In the picture we can see that the scatterplot is given for the data in the given table.

b. It is not linear as we can see from scatterplot.

c. The correlation between y and x is 0.

d. when r = 0 there is no relationship between x and y.

Given that,

The data is given in the table.

We know that,

a. We have to make a scatterplot of y versus x.

In the picture we can see that the scatterplot is given for the data in the given table.

b. We have to describe the relationship between y and x.

When x increases y increases upto certain point after that y start to decrease but x is increases only

Therefore, it is not linear as we can see from scatterplot.

c. We have to find the correlation between y and x.

The formula for the correlation coefficient is

r = [tex]\frac{n\times \sum XY-\sum X \times\sum Y}{\sqrt{[n\sum X^2 - (\sum X)^2][n\sum Y^2 - (\sum Y)^2]} }[/tex]

Now we find summation of all X, Y and XY, [tex]X^2[/tex] and [tex]Y^2[/tex]

X          Y           XY            [tex]X^2[/tex]            [tex]Y^2[/tex]

25        10         250         625          100

35        30        1050        1225         900

45        50        2250       2025        2500

55        30        1650        3025        900

65        10          650        4225        100

Now, ∑X = 225

∑Y = 130

∑XY = 5850

∑[tex]X^2[/tex] = 11125

∑[tex]Y^2[/tex] = 4500

Now, Substitute the values in the formula

r = [tex]\frac{5\times 5850-225 \times130}{\sqrt{[5\times 11125 - (225)^2][5\times 4500 - (130)^2]} }[/tex]

r = 0

Therefore, The correlation between y and x is 0.

d. We have to find what important point about correlation does this exercise illustrate.

Therefore, when r = 0 there is no relationship between x and y.

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YOUR ANSWER IS ANGLE BAC

Answer:

A

Step-by-step explanation:

the y intercept (where x is 0) should be -3 because of y<3x-3

Answer:

D). irrational numbers between 10 and 30

Answer:

34.55556%

Step-by-step explanation:

Answer:

33.94 cms of ribbon

Step-by-step explanation:

Because you need two diagonals to form the x, therefore the amount  of ribbon needed is the sum of the distance of both diagonals.

When crossing the diagonal, a rectangular angle is formed, where the diagonal would be the hypotenuse, we know that the distance of the hypotenuse can be calculated by means of the legs, which we know its value (12):

d ^ 2 = a ^ 2 + b ^ 2

a = b = 12

d ^ 2 = 12 ^ 2 + 12 ^ 2

d ^ 2 = 288

d = 288 ^ (1/2)

d = 16.97

16.97 cm is what it measures, a diagonal, therefore tape is needed:

16.97 * 2 = 33.94

A total of 33.94 cms of ribbon is needed

Answer from jmonterrozar

Answer:

huh?

Step-by-step explanation:

did you forget a pic?

Answer:

whatdo u need help with love?

Step-by-step explanation:

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{(\dfrac{4}{9})^2}[/tex]

[tex]\mathsf{= \dfrac{4}{9}\times\dfrac{4}{9}}[/tex]

[tex]\mathsf{= \dfrac{4^2}{9^2}}[/tex]

[tex]\mathsf{\dfrac{4\times4}{9\times9}}[/tex]

[tex]\mathsf{4 \times 4 = \bold{16}\leftarrow \underline{Numerator}}[/tex]

[tex]\mathsf{9\times9 = \bf 81}\leftarrow\mathsf{\underline{Denominator}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \boxed{{\bf \dfrac{16}{81}}}}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

I believe the answer to be 5 and 4

The exterior angles of the given triangle are angles 4 and 5

A triangle is a polygon with three sides, angles and vertices.

Given that, a triangle, with angles, 1, 2, 3, 4, 5 we need to find the exterior angles,

An exterior angle of a polygon is the angle that lies outsides of the polygon,

Here, we can see, that only two angles 4 and 5 lies outsides of the triangles

Therefore, the exterior angles are 4 and 5

Hence, the exterior angles of the given triangle are angles 4 and 5

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Using the standard deviation, mean, and z-score, the 7% of items with the shortest lifespan will last less than approximately 1.59 years.

To find the number of years that the 7% of items with the shortest lifespan will last, we need to determine the z-score corresponding to the 7th percentile of the normal distribution.

Step 1: Convert the given percentile to a z-score using the standard normal distribution table or a statistical calculator. The 7th percentile corresponds to a z-score of approximately -1.405.

Step 2: Use the formula for z-score to find the corresponding value in terms of years:

x = μ + z * σ

where x is the value we are looking for, μ is the mean, z is the z-score, and σ is the standard deviation.

Plugging in the values:

x = 4.4 + (-1.405) * 1.2

x = 1.59 years

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Answer:

B

Step-by-step explanation:

A will equal the sine inverse (arc sine or sin^-1 ) of 0.3571. Using a calculator, sin^-1(0.3751) = 22.03 degrees (B)

slope is 3

y-intercept is 0,-5

Answer:

52 cubic units

Step-by-step explanation:

got it right on edg

Answer:

37h 900

Step-by-step explanation:

Answer:

3

5

(

−

2

)

Step-by-step explanation:

Simplify then multiple the numbers

Answer:

A=2, B=10, C=-18

The answer is the first one.

Step-by-step explanation:

[tex]5x^{2} -3x^{2} +x+9x-18=0[/tex]

[tex]2x^{2} +10x-18=0[/tex]

Formula: [tex]f(x)=ax^{2} +bx+c[/tex]

General solution of the second order differential equation:

-6Ae^(-3x) / x + 9Bxe^(-3x) * ln(x) - Be^(-3x) / x^2

To find the general solution of the given second-order differential equation: y" + 6y' + 9y = e^(-3x) * ln(x)

We will use the method of undetermined coefficients to find a particular solution and then combine it with the complementary solution to obtain the general solution.

Step 1: Finding the particular solution

Since e^(-3x) * ln(x) is a product of exponential and logarithmic functions, we assume a particular solution in the form of:

yp = (A + Bx) * e^(-3x) * ln(x)

where A and B are constants to be determined.

Step 2: Find the first and second derivatives of yp.

yp' = (Ae^(-3x) * ln(x) - 3(A + Bx)e^(-3x) * ln(x) + (A + Bx) * e^(-3x) / x

yp" = (Ae^(-3x) * ln(x) - 3(A + Bx)e^(-3x) * ln(x) + (A + Bx) * e^(-3x) / x)'

yp" = (-9(A + Bx)e^(-3x) * ln(x) + 3(A + Bx)e^(-3x) * ln(x) - 3(A + Bx)e^(-3x) / x + (A + Bx) * (-e^(-3x) / x^2 + e^(-3x) / x))

Simplifying, we have:

yp" = -9(A + Bx)e^(-3x) * ln(x) - 6(A + Bx)e^(-3x) / x + (A + Bx) * (-e^(-3x) / x^2 + e^(-3x) / x)

Step 3: Substitute yp, yp', and yp" into the original differential equation to find the values of A and B.

yp" + 6yp' + 9yp = e^(-3x) * ln(x)

Substituting the expressions we found for yp and its derivatives:

(-9(A + Bx)e^(-3x) * ln(x) - 6(A + Bx)e^(-3x) / x + (A + Bx) * (-e^(-3x) / x^2 + e^(-3x) / x))

6((Ae^(-3x) * ln(x) - 3(A + Bx)e^(-3x) * ln(x) + (A + Bx) * e^(-3x) / x))

9((A + Bx) * e^(-3x) * ln(x))

= e^(-3x) * ln(x)

Expanding and simplifying, we get:

-9Ae^(-3x) * ln(x) + 3Bxe^(-3x) * ln(x) - 6Ae^(-3x) / x + 6Bxe^(-3x) / x + Ae^(-3x) / x - Be^(-3x) / x^2 + Be^(-3x) / x + 9Ae^(-3x) * ln(x) + 9Bxe^(-3x) * ln(x)

= e^(-3x) * ln(x)

Combining like terms, we have:

-6Ae^(-3x) / x + 9Bxe^(-3x) * ln(x) - Be^(-3x) / x^2

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Answer:

[tex]2x^{3} +10[/tex]

Step-by-step explanation:

[tex]x*2x*x+10=2x^{3} +10[/tex]

Answer:

128 fluid ounces

Step-by-step explanation:

We were told that:

During the experiment was poured from a beaker after the water was poured 1/4 gallon of water was left in the beaker

Hence, this means that the total gallon of water in the beaker is 1 gallon

Convert 1 gallon to fluid ounces

1 gallon =128 fluid ounces

Therefore, the total number of fluid ounces of water in the beaker before the water was poured by the 12 students is 128 fluid ounces.

Answer:

12 mph

Step-by-step explanation:

Given that:

Total distance traveled = 78 miles

Time taken, t = 6 hours

Average speed for first 30 miles = 15 mph

Time taken = distance / speed

Time taken = 30 / 15

Time taken = 2 hours

Average speed for last 48 miles = x

Time taken to travel last 48 miles = (6 - 2) = 4 hours

Average speed for last 48 miles :

Distance traveled / time taken

48 miles / 4 hours

= 12 mph

Answer:

Step-by-step explanation:

Answer:

(A) B h(x)= -2x-5.5

(B) The y intercept is (0,-5.5)

(C) The rate of change is -2

(D) The x intercept is (-2.75,0)

To solve the equation y - 4.5 = 12.2 we have to add 4.5 on both sides of the equation.

Two or more expressions with an Equal sign is called as Equation.

The given equation is y - 4.5 = 12.2

y minus four point five equal to twelve point two.

In the equation y is the variable and minus is the operator in the equation.

To solve the equation we have to isolate the variable y.

To isolate the variable y we have to add 4.5 on both sides of the equation

y-4.5+4.5=12.2+4.5

y=16.7

Hence, to solve the equation y - 4.5 = 12.2 we have to add 4.5 on both sides of the equation.

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Answer:

72

Step-by-step explanation:

Multiply all the numbers, and you get the answer

The approximate area under the curve from x = 2 to x = 5, using a left endpoint approximation with 3 subdivisions, is 13.5 square units.

To approximate the area under the curve, we divide the interval from x = 2 to x = 5 into three equal subdivisions, each with a width of (5 - 2) / 3 = 1. The left endpoint approximation involves using the leftmost point of each subdivision to approximate the height of the curve.

In this case, we evaluate the function at x = 2, x = 3, and x = 4, and use these values as the heights of the rectangles. The width of each rectangle is 1, so the areas of the rectangles are calculated as follows:

Rectangle 1: Height = f(2) = 2, Area = 1 * 2 = 2 square units.

Rectangle 2: Height = f(3) = 4, Area = 1 * 4 = 4 square units.

Rectangle 3: Height = f(4) = 7, Area = 1 * 7 = 7 square units.

Finally, we add up the areas of the three rectangles to obtain the approximate area under the curve: 2 + 4 + 7 = 13 square units. Therefore, the approximate area under the curve from x = 2 to x = 5 using a left endpoint approximation with 3 subdivisions is 13.5 square units.

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Answer:

12

Step-by-step explanation:

b-4x

Plug in 4 as b and -2 as x

= (4)-4(-2)

Multiply 4 and 2

= 4-(-8)

Two negatives make a positive

= 4+8

= 12

I hope this helps!

(a) The probability that X is less than 3, P(X < 3), is 0.

(b) The mean of X, denoted as E(X), is 71/24, which is approximately 2.9583 when rounded off to four decimal places.

(c) Given Y = e^X, the mean of Y, denoted as E(Y), is approximately 15.75 when rounded off to two decimal places.

(a) It is required to compute P(X<3). Since the range for which f(x) is not equal to 0, is the interval from 2 to 4 for f(x), the probability that X is less than 3 is 0.

Similarly, for X > 4, P(X > 4) = 0.

P(2 ≤ X ≤ 4) = ∫f(x)dx from 2 to 4= ∫ (x/24 - 7/3) dx from 2 to 4= [x^2/(2 × 24) - 7x/3] from 2 to 4= 1/4 - 28/3 + 8/(2 × 24) + 14/3= 71/24= 2.9583(rounded off to four decimal places)

(b) The mean of X can be computed as follows:

E(X) = ∫xf(x)dx from -∞ to ∞= ∫ (x/24 - 7/3) dx from 2 to 4= [x^2/(2 × 24) - 7x/3] from 2 to 4= 1/4 - 28/3 + 8/(2 × 24) + 14/3= 71/24= 2.9583(rounded off to four decimal places)

(c) Y = e^X

The mean of Y can be computed as follows:

E(Y) = E(e^X)= ∫ e^x f(x) dx from -∞ to ∞= ∫ e^x (x/24 - 7/3) dx from 2 to 4= [e^x (x - 31)/(24)] from 2 to 4= (e^4/6 - 31e^4/24 - e^2/6 + 31e^2/24) ≈ 15.75(rounded off to two decimal places).

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The solution to the differential equation (D^2 + 4)y = 6 sin(2x) + 3x^2 is y = (3/4)x^2 + A sin(2x) + B cos(2x).

To solve the given differential equation (D^2 + 4)y = 6 sin(2x) + 3x^2, where D represents the derivative operator, we can use the method of undetermined coefficients.

y = y_h + y_p

y = A sin(2x) + B cos(2x) + (3/4)x^2

Here, A and B are arbitrary constants that can be determined by applying initial or boundary conditions, if given.

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