suppose a 95% confidence interval was made to estimate the monthly cost of internet service instead of a 90% confidence interval. how would the interval change?

Answers

Answer 1

The 95% confidence interval will be more extensive than the 90% confidence interval

In measurements, the probability that a population boundary will fall between a bunch of values for a specific level of the time is alluded to as a certainty stretch. Investigators every now and again utilize certainty goes that incorporate 95% or the vast majority of expected perceptions. Thus, it could be presumed that there is a 95% probability that the genuine worth falls inside that reach assuming that a point gauge of 10.00 with a 95% certainty time frame - 10.50 is determined utilizing a factual model.

The degree of conviction or vulnerability in a testing cycle is estimated by certainty spans.

Also, they are utilized in relapse examination and speculation testing.

To decide measurable importance, analysts often join certainty spans with p-values.

95% or almost 100% certainty levels are most often utilized in their development.

Related Questions

Draw the graph of each circle given its equation below.

Answers

Step 1:

First, write the general equation of a circle

[tex]\begin{gathered} (x-a)^a+(y-b)^2=r^2 \\ r\text{ is the radius} \\ (a,\text{ b) is the center} \end{gathered}[/tex]

Step 2:

Question 1

[tex]\begin{gathered} x^2+y^2\text{ = 121} \\ x^2+y^2=11^2 \\ \text{radius r = 11} \\ \text{center = (0 , 0)} \end{gathered}[/tex]

Question 2

[tex]\begin{gathered} (x-2)^2+y^2\text{ = 64} \\ (x-2)^2+y^2=8^2 \\ \text{Center = (2, 0)} \\ r\text{ = 8} \end{gathered}[/tex]

Question 3

[tex]\begin{gathered} (x\text{ + }\frac{3}{2})^2\text{ + (y + }\frac{5}{8})^2\text{ = 36} \\ (x\text{ + }\frac{3}{2})^2\text{ + (y + }\frac{5}{8})^2\text{ = }6^2 \\ \text{Center = (-}\frac{3}{2}\text{ , -}\frac{5}{8}) \\ r\text{ = 6} \end{gathered}[/tex]

Question 4

[tex]\begin{gathered} (x-1)^2+(y+7)^2\text{ = 9} \\ (x-1)^2+(y+7)^2\text{ = }3^2 \\ \text{Center = (1, -7)} \\ r\text{ = 3} \end{gathered}[/tex]

Question 5

[tex]\begin{gathered} (x+8)^2+(y-3)^2\text{ = 7} \\ (x+8)^2+(y-3)^2\text{ = (}\sqrt[]{7})^2 \\ \text{Center = (-8, 3)} \\ \text{radius r = }\sqrt[]{7} \end{gathered}[/tex]

Simplify to create an equivalent expression 10+4(−8q−4)

Answers

Answer:

-32q-6

Step-by-step explanation:

Please look at the attachment! Hope this helps! ~~

Answer : -0.3125 + q + 0.5

1) Distribute

10 - 32q - 16

2) Divide all terms by -32

-0.3125 + q + 0.5

rearrange the following so g is the main subject:
f+4(g-h)=x

Answers

Answer:

g=x-f+4h/4

Step-by-step explanation:

change of subject of formula

f+4(g-h)=x

f+4g-4h=x

4g-4h=x-f

4g=x-f+4h

g=x-f+4h/4

rate as brainliest

Eric orders 3 large cheese pizzas. There is a $2 delivery fee for each pizza. He pays a total of $42. Which equation can be used to find the price, r, of each pizza?

Answers

we have that he paid 4 dollars due the delivery. So each pizza costs

[tex]\frac{38}{2}=19[/tex]

so the equation to find the price r is

[tex]r=\frac{42-4}{2}[/tex]

x = -4z - 19
y= 5x + z - 4
-5y - z = 25

Answers

Answer:

x = 1, y = -4, z = -5

Step-by-step explanation:

Solve the following system:

{x = -4 z - 19 | (equation 1)

{y = z + 5 x - 4 | (equation 2)

{-z - 5 y = 25 | (equation 3)

Express the system in standard form:

{x + 0 y + 4 z = -19 | (equation 1)

{-(5 x) + y - z = -4 | (equation 2)

{0 x - 5 y - z = 25 | (equation 3)

Swap equation 1 with equation 2: