Answer:
$14000
Step-by-step explanation:
= (3500 x 0.8 x 5) / 100
= $14000
I hope my answer helps you.
Two random number generators each generate a number from 1 to 10. What is the probability that both number generators generated the number 5
Hello,
The probability that both number generators generate the number 5 is (1/10) * (1/10) = 1/100 = 0.01 or 1%.
This is because the probability of an event occurring is the product of the probabilities of each event occurring independently. In this case, the probability of the first generator generating the number 5 is 1/10 and the probability of the second generator generating the number 5 is also 1/10, so the probability of both events occurring is (1/10) * (1/10) = 1/100.
----
Which sequence explains a geometric method of determining
● Plot 2 + 2i. Scale by 2. Rotate 45° clockwise.
4
Plot 3-17i. Scale by ✓2.Rotate 45° clockwise.
O Plot 2 + 2i. Scale by 2√2. Rotate 45° clockwise.
Plot 3-17i. Scale by 2√2. Rotate 45° clockwise.
3-171 ?
2 + 2i
Answer:
Second option (Plot 3-17i. Scale by ✓2/4 .Rotate 45° clockwise.)
Step-by-step explanation:
Given below in the picture.
I hope my answer helps you.
a random sample of adults was surveyed about their exercise habits. of the 100 surveyed, 56 stated they exercise regularly. which of the following is the 95% confidence interval for p, the proportion of all adults who exercise regularly? find the z-table here. (0.50, 0.62) (0.48, 0.64) (0.46, 0.66) (0.43, 0.69)
The 95% confidence interval for p, the proportion of all adults who exercise regularly is (0.46, 0.66).
What is a confidence interval?
An estimated range for an unknown parameter is known as a confidence interval. The 95% confidence level is the most popular, however other levels, such as 90% or 99%, are occasionally used when computing confidence intervals.
Here, we have
Given
Sample size(n) = 100
x = 56
Sample proportion (p) = x/n = 56/100 = 0.56
Here, c = 95%, a = 0.95
1-a = 0.05, a/2 = 0.025
Z(a/2) = 1.96
95% confidence interval for p is:
= p-Z(a/2)√{p(1-p)}/n, p+Z(a/2)√{p(1-p)}/n
= 0.56- 1.96√{0.56(1-0.56)}/100, 0.56+1.96√{0.56(1-0.56)}/100
= 0.56 - 0.0972, 0.56+0.0972
= 0.4628, 0.6572
= (0.46, 0.66)
Hence, the 95% confidence interval for p, the proportion of all adults who exercise regularly is (0.46, 0.66).
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Work out m and c for the line: y = 3-4x
Answer:
m = -4 ; c = 3
Step-by-step explanation:
m is the number that multiplies x
c is the number without letters
A phone company charge a base fee of $12 per month plus additional charge per minute. The monthly phone cost can be represented by the following equation where is the additional charge per minute and is the number of minutes used. Rearrange the equation to solve for the number of minutes, m.
C=12+a•m
m=(C-12)/a
According to question
C=12+a*m
⇒C-12=a*m
⇒(C-12)/a=m
∴Equation to solve for the number of minutes , m = (C-12)/a
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A college admissions officer for an MBA program has determined that historically
applicants have undergraduate grade point averages that are normally distributed with
standard deviation 0.45. From a random sample of 25 applications from the current year,
the sample mean grade point average is 2.90.
Required: Find the confidence interval foe the population mean at the 5% significance level.
(10marks)
B. An educational study was designed to investigate the effectiveness of a reading program
of elementary age children. Each child was given a pre-test and post-test. Higher posttest scores would indicate reading improvement. From a very large population, a random
sample of scores for the pre-test and post-test are as follows:
The confidence interval for the population mean at significance level is
2.724<μ<30.76 .
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Population standard deviation: σ = 0.45
Sample size: n = 25
Sample Mean: x= 2.90
Х=2.90 represent the sample mean for the sample
μ population mean (variable of interest)
σ = 0.45 represent the population standard deviation
n=25 represent the sample size
We have the following distribution for the random variable:
X≈N(μ,σ =0.45)
And by the central theorem we know that the distribution for the sample mean is given by:
X≈N( μ, [tex]\frac{σ}{\sqrt{n} }[/tex])
Since the Confidence is 0.95 or 95%, the value of [tex]\alpha =0.05[/tex] and[tex]\frac{\alpha }{2} =0.025[/tex], and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)" and we see that
Z₁ =±1.96
Now we have everything in order to replace into formula:
[tex]2.90-1.96\frac{0.45}{\sqrt{25} }=2.724[/tex]
[tex]2.90+1.96\frac{0.45}{\sqrt{25} }=3.076[/tex]
So on this case the 95% confidence interval would be given by (2.724:3.076) .
At a significance level, the population mean's confidence interval is 2.724–30.76.
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researchers hoped to determine whether time spent watching television is associated with cardiovascular fitness. subjects were asked how many hours per day they watch television and were classified as physically fit if they scored in the excellent or very good category on a step test. the data obtained is as follows:
A hypothesis Test will be used to check the association the researchers were interested in exist or not. Chi-square test statistic will be used for testing the relationship between gender and participation in the last election.
The hypothesis test we shall use here is -
Chi-square test for independence
Reason - this type of hypothesis test is used to test whether there is a significant association between two categorical variables.
The two variables in this question are hours spent watching TV and cardiovascular fitness.
2.) Test statistic here is
Chi-square test statistic
Reason - here also to test the association we should use the chi-square test for
and thus the test statistic would be Chi-square.
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pls help asap I will give many points just help me on this
Answer:1=t
2=flase
3=flase
4=flase
5=true
6=true
7flase
8=true
Step-by-step explanation:i spelt false wrong lol
Surwatullah is starting university in 3 years and would like to have $4000 when he starts. He has $3000 to invest now, and his bank pays 5% compounded quarterly. Will he have enough?
Answer:
Answer found by the following formula/e: CI = A – P
for a study cvaluating the difference among three treatments with a separate sample of n-10 for cach treatment,the kruska-walis test statistic would have df -
for a study cvaluating the difference among three treatments with a separate sample of n-10 for cach treatment,the kruska-walis test statistic would have df - 2(3-1)=2
The Kruskal-Wallis test statistic has a degrees of freedom (df) equal to the number of groups minus one. In this case, there are three groups, so the df is 2 (3-1).The Kruskal-Wallis test statistic is a non-parametric test used to compare the means of a set of independent samples. In this case, we have three separate samples of n-10 for each treatment. To calculate the Kruskal-Wallis test statistic, we need to first calculate the sum of the ranks for each sample and then subtract the expected sum of ranks for each sample. The df for the Kruskal-Wallis test statistic is equal to the number of groups minus one. In this case, there are three groups, so the df is 2 (3-1). Finally, the Kruskal-Wallis test statistic is calculated by dividing the calculated sum of ranks by the expected sum of ranks and multiplying by the df. This will give us the Kruskal-Wallis test statistic for the data set.
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If the probability that a person will die in the next year is
probability that the person will not die in the next year?
OA. 99%
B. 99548
C. 0.00452
OD. 0.99548
452
100,000
what is the
SUBMIT
The probability that the person will not die will be D. 0.99548
How to illustrate the probability?Probability is the occurence of likely events. It is the area of mathematics that deals with numerical estimates of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1. In this case, 0 denotes the impossibility of the event and 1 represents certainty.
Since the probability that the person will die is 814/1000000, the probability that the person will not die will be:
= 1 - 452/100000
= 99548/100000
= 0.99548
The correct option is D.
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If the probability that a person will die in the next year is 452/100000, the probability that the person will not die in the next year?
A. 99%
B. 0.99548
C. 0.00452
D. 0.99548
Mackenzie's car used 4 gallons to travel 108 miles. How many gallons of gas would she need to travel 162 miles?
The gallons of gas that she would need to travel 162 miles will be 4374 gallons.
How to illustrate the ratio?Ratio demonstrates how many times one number can fit into another number. Ratios contrast two numbers by ordinarily dividing them. A/B will be the formula if one is comparing one data point (A) to another data point (B).
Since Mackenzie's car used 4 gallons to travel 108 miles. The rate will be:
= 108 / 4
= 27 miles per gallon
The gallons of gas that she would need to travel 162 miles will be:
= 162 × 27
= 4374 gallons.
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In each case below find an equation for the line with the given information about the linear equation and
give the slope of each line.
a) Vertical line through point (2, -65)
b) Horizontal line through point (-2, 4)
a) The equation of a vertical line is x = k, where k is the x-coordinate of the point where the line intersects the y-axis. In this case, the point where the line intersects the y-axis is (2, -65), so the equation of the line is x = 2. The slope of a vertical line is undefined, since it has no slope.
b) The equation of a horizontal line is y = k, where k is the y-coordinate of the point where the line intersects the x-axis. In this case, the point where the line intersects the x-axis is (-2, 4), so the equation of the line is y = 4. The slope of a horizontal line is 0, since it has no slope.
Assume that the distributions for the following scenarios are normal. Use the normal standard table to find the following probabilities. Round z-scores to the nearest hundredth.
1. The average score on a math test is 75 with a standard deviation of 8. What is the probability that a randomly selected test has a score of 90 or higher?
2. The life of a gas grill is 3.5 years with a standard deviation 0.35 years. What is the probability that the grill will last less than 3 years?
3. Ambulance response times average 7.5 minutes with a standard deviation of 2.5. What is the probability that an ambulance will respond within 6 to 8 minutes.
Answer:
1. To find the probability that a randomly selected test has a score of 90 or higher, we need to find the z-score corresponding to a score of 90 and then use the standard normal table to find the probability that a score is greater than or equal to this value. To find the z-score, we can use the formula:
z = (x - mean) / standard deviation
where x is the score we are interested in, mean is the average score, and standard deviation is the standard deviation of the distribution. Plugging in the values from the problem, we get:
z = (90 - 75) / 8 = 1.875
Rounding this value to the nearest hundredth, we get z = 1.88. Looking up this value in the standard normal table, we find that the probability that a score is greater than or equal to 1.88 is 0.9637. Therefore, the probability that a randomly selected test has a score of 90 or higher is 0.9637.
2. To find the probability that the grill will last less than 3 years, we need to find the z-score corresponding to a life of 3 years and then use the standard normal table to find the probability that a life is less than this value. To find the z-score, we can use the formula:
z = (x - mean) / standard deviation
where x is the value we are interested in, mean is the average value, and standard deviation is the standard deviation of the distribution. Plugging in the values from the problem, we get:
z = (3 - 3.5) / 0.35 = -1.43
Rounding this value to the nearest hundredth, we get z = -1.43. Looking up this value in the standard normal table, we find that the probability that a life is less than -1.43 is 0.0747. Therefore, the probability that the grill will last less than 3 years is 0.0747.
3. To find the probability that the ambulance will respond within 6 to 8 minutes, we need to find the z-scores corresponding to a response time of 6 and 8 minutes, respectively, and then use the standard normal table to find the probability that a response time is between these two values. To find the z-score, we can use the formula:
z = (x - mean) / standard deviation
where x is the value we are interested in, mean is the average value, and standard deviation is the standard deviation of the distribution. Plugging in the values from the problem, we get:
z1 = (6 - 7.5) / 2.5 = -0.6
z2 = (8 - 7.5) / 2.5 = 0.2
Rounding these values to the nearest hundredth, we get z1 = -0.6 and z2 = 0.2. Looking up these values in the standard normal table, we find that the probability that a response time is less than -0.6 is 0.2743 and the probability that a response time is less than 0.2 is 0.5398. Therefore, the probability that a response time is between -0.6 and 0.2 is 0.5398 - 0.2743 = 0.2655. Therefore, the probability that the ambulance will respond within 6 to 8 minutes is 0.2655.
1. The probability that a randomly selected test has a score of 90 or higher is 0.0301.
2. The probability that the grill will last less than 3 years is 0.0764.
3. The probability that an ambulance will respond within 6 to 8 minutes is 0.1465.
How to determine the required probabilities?In Mathematics and Statistics, the z-score of a given sample size or data set can be calculated by using the following formula:
Z-score, z = (x - μ)/σ
Where:
σ represents the standard deviation.x represents the sample score.μ represents the mean score.Part 1.
By substituting the given parameters, we have the following:
Z-score, z = (90 - 75)/8
Z-score, z = 1.88
Based on the standardized normal distribution table, the required probability is given by:
P(Z ≥ 1.88) = 1 - P(x < Z)
P(Z ≥ 1.88) = 1 - 0.9699
Probability = 0.0301.
Part 2.
By substituting the given parameters, we have the following:
Z-score, z = (3 - 3.5)/0.35
Z-score, z = -1.43
Based on the standardized normal distribution table, the required probability is given by:
P(Z < -1.43) = 1 - P(x > Z)
P(Z < -1.43) = 1 - 0.9236
Probability = 0.0764.
Part 3.
At 6 minutes, we have:
Z-score, z = (6 - 7.5)/2.5
Z-score, z = -0.6
At 8 minutes, we have:
Z-score, z = (8 - 7.5)/2.5
Z-score, z = 0.2
Based on the standardized normal distribution table, the required probability is given by:
P(6 < x < 8) = P(-0.6 < z < 0.2)
P(-0.6 < z < 0.2) = P(z < 0.2) - P(z < -0.6)
P(-0.6 < z < 0.2) = 0.42074 - 0.27425
P(-0.6 < z < 0.2) = 0.1465.
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What is the last blank?
A square-based pyramid has a total of five faces. Four of the faces are triangles and one of the faces is a square. The surface area of a square-based pyramid is the total area of all its sides.
hope this helps!! :D
consider the set of students enrolled in a college and the set of faculty members at that college. suppose we define a one to one correspondence between the two sets by saying that a student corresponds to a faculty member if the student is currently enrolled in a course taught by that faculty member. is this correspondence a function? briefly discuss. a simple yes or no needs reasoning so please answer thoughtfully.
We state that a student correlates to a faculty member if somehow the student gets currently enrolled in some kind of a course taught by such faculty member in order to define a one to one relationship between the two sets. The correspondence a function.
Define the term one-to-one relation in function?The symbol for an ordered pair is (INPUT, OUTPUT): The relation denotes the connection between the input and output.
A function, on the other hand, is a relation that yields one Outcome for each input Data.A is a relationship that states that there should only be one outputs for each input. Alternatively, we could say that a function is a special sort of relation (a collection of ordered pairs) that adheres to the rule that every X-value should only be connected with one y-value.A function f: A → B is one-to-one if there is only one instance of a ∈ A with f(a) = b for each instance of b B. It is onto if it has least one a A with f(a) = b for each b B. If it is simultaneously one-to-one and onto, it is a one-to-one correlation or bijection.For the stated question-
We state that a student correlates to a faculty member if somehow the student gets currently enrolled in some kind of a course taught by such faculty member in order to define a one to one relationship between the two sets.
One student is related to one facility.
Thus, correspondence given forms a function.
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Which function has the same graph as f(x) = 0.3|x|?
Answer:
D
Step-by-step explanation:
b/c
A B and C are not true
Answer:
D
Step-by-step explanation:
We can visualize this by ignoring the constant of 0.3 and remembering the |x| graph.
It has a -x slope when x < 0, and a +x slope when x > 0
The only answer that has a negative slope when x is less than 0 and a positive slope when x is greater than 0 is D.
What is the result of 6+
3/8?
1/8
1/4
16
48
Answer:
C) 16------------------------------
Simplify:
6 ÷ 3/8 = Given6 × 8/3 = Flip the fraction2 × 8 = Cancel the denominator 16 AnswerAnswer:
[tex] \sf \red{c) \: 16} \: is \: the \: answer.[/tex]
Step-by-step explanation:
Given problem,
[tex] \sf →6 + \frac{3}{8} [/tex]
Changing error in problem,
[tex] \sf →6 \div \frac{3}{8} [/tex]
Let's solve the problem,
[tex] \sf →6 \div \frac{3}{8} [/tex]
[tex] \sf →6 \times \frac{8}{3} [/tex]
[tex] \sf → \frac{(6 \times 8)}{3} [/tex]
[tex] \sf → \frac{48}{3} [/tex]
[tex] \sf \: →16 \:[/tex]
Hence, the answer is 16.
y = x^4 , y = 2 − |x|
Answer:
no solution
y=x^3
y= 2-1 x 1
Step-by-step explanation:
1. Computer Depot is a large store that sells and repairs computers. A random sample of 110 computer repair jobs took technicians an average of = 93.2 minutes per computer. Assume that is known to be 16.9 minutes.
(a) Find a 99% confidence interval for the population mean time for computer repairs.
(b) Write a brief explanation of the meaning of the confidence interval in the context of this problem.
Confidence interval for the population mean time σ for computer repairs is [98.05 , 89.850].
What is confidence interval?
A confidence interval, in statistics, refers to the chance that a population parameter can fall between a collection of values for an exact proportion of times.
Main body:
According to question:
N = 110
X bar = 93.9 minutes
σ = 16.9 minutes
value for 99% confidence interval = 2.576
C.I. = x bar ± z*s/√n
C.I. = 93.9 ± 2.576 *16.9 /√110
C.I. = 93.9 ± 4.150
C.I. = [98.05 , 89.850]
Hence , confidence interval for the population mean time σ for computer repairs is [98.05 , 89.850].
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Element X is a radioactive isotope such that every 71 years, its mass decreases by half.
Given that the initial mass of a sample of Element X is 30 grams, write a function
showing the mass of the sample remaining after t years, where the annual decay rate
can be found from a constant in the function. Round all coefficients in the function to
four decimal places. Also, determine the percentage rate of decay per year, to the
nearest hundredth of a percent.
1) The function that shows the decay is N(t) = 30e^-rt.
2) The percentage rate of decay is 0.98 %.
What is the function?We know that an element is said to be radioactive if the element can be able to decay spontaneously. The implication of this is that the amount of the element that in the system would continue to be reduced and new daughter nuclei are formed.
We have that;
If the initial mass of the radioactive isotope X has been give to us in the question as 30 g then it follows that we can write the function as;
N(t) = 30e^-rt
N(t) =Mass of the element at time t
r = rate of decay
t = time taken
Since half of the element X would remain after 71 years, we have;
15 = 30e^ -71r
15/30 = e^ -71r
0.5 = e^ -71r
ln 0.5 = -71r
r = ln 0.5/-71
r = 0.0098 or 0.98 %
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I don’t know why I’m finding this so hard but I’ve tried so many attempts
Check the picture below.
none of the answer choices is correct. the sample consisted of all veterinarians who treat horses with nsaids. the sample consisted of all veterinarians on the list and therefore equaled the target population. the sample consisted of all veterinarians who returned the questionnaire.
equaled the target population. the sample consisted of all veterinarians who returned the questionnaire is None of the answer choices is correct.
The sample in this case consists of all veterinarians who treat horses with Non-Steroidal Anti-Inflammatory Drugs (NSAIDs). The target population for this study would be all veterinarians who treat horses with NSAIDs. Therefore, since the sample is made up of all veterinarians in the target population, the sample equals the target population. None of the answer choices provided is correct in this scenario.
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Solve the given problem related to population growth. During the first decade of this century, the population of a certain city grew exponentially. The population of the city was 145,210 in 2000 and 219,185 in 2010. Find the exponential growth function that models the population growth of the city. Use t = 0 to represent 2000, t - 10 to represent 2010, and so on. (Round k to five decimal places.) N(C) = Use your exponential growth function to predict the population of the city in 2016. Round to the nearest thousand.
The exponential growth function that models the population growth of the given city is P(t) = P(0) x e^rt and the population of the city in 2016 is 328,029.39.
The population of the city in 2000 (t=0) = 145,210
The population of the city in 2010 (t=10) = 219,185
Rate of growth for 10 years = ((219185 - 145210)/145210) x 100
Rate of growth for 10 years = 50.943%
Rate of growth per year = Rate of growth for 10 years/10
Rate of growth per year = (50.943/10)%
Rate of growth per year = 5.094%
According to the exponential growth function,
P(t) = P(0) x e^rt
Population in 2016 (t=16) is:
P(16) = 145210 x e^((5.094/100) x 16)
P(16) = 145210 x 2.259
P(16) = 328029.39
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A property is available for sale that could normally be financed with a fully amortizing $82,800 loan at a 10 percent rate with monthly payments over a 25-year term. Payments would be $752.40 per month. The builder is offering buyers a mortgage that reduces the payments by 50 percent for the first year and 25 percent for the second year. After the second year, regular monthly payments of $752.40 would be made for the remainder of the loan term.
Required:
a. How much would you expect the builder to have to give the bank to buy down the payments as indicated?
b. Would you recommend the property be purchased if it was selling for $5,000 more than similar properties that do not have the buydown available?
The builder must pay the bank $6005.66. for further details read below.
what is the mortgage?A mortgage is a type of loan used to purchase or maintain a home, land, or other types of real estate.
For the given problem We must determine the present value of all the relaxations granted to us over the first two years in order to determine how much the builder must pay the bank for this buydown payment. The output and Excel formulae are listed below.
Monthly payment 726.96
Monthly interest rate 10.%/12
Relaxation value in 1st year:
Amount reduced C2*50%
No. of months 12
present value PV(C3,C7, -C6)
Relaxation value in 2nd year:
The amount reduced C2*25%
No. of months 12
present value PV(C3,C12, -c11)
Present value today C13/(1+ C 3)^12
Present value of buy option C14 + C8
Therefore, the buydown option's current value is $6005.66. In order to provide this option to the customers, the builder must pay the bank $6005.66.
b. It is advised to take advantage of this option since the benefit the house buyer would get, or its current value exceeds the additional cost. Benefits to the purchaser of this option include. The benefit to the buyer equals the Present Value of the BuyDown Option - Additional Payment
Buyer benefit is equal to 6005.66 - 5000, or 1005.66$.
So, if a buyer received this option, he would profit $1005.66. It is thus advised to purchase real estate using this buydown option.
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A city has 4 voting districts. Records from previous years show what proportion of residents live in each district. A political analyst wondered if those proportions still held true, so they took a random sample of 120 residents. Here are their results along with a chi-square goodness-of-fit test:District A B C DHypothesized 0.39 0.27 0.15 0.19 Observed 58 22 12 28 Expected 46.80 32.40 18.00 22.80 Components 2.68 3.34 2.001.19 x² = 9.20, DF = 3 P-value = 0.027 Which voting district contributed the most to the test statistic?
Answer: The voting district that contributed the most to the test statistic is District B.
Step-by-step explanation:
How do you calculate the contribution of each voting district to the test statistic?
The contribution of each voting district to the test statistic is calculated by taking the difference between the observed and expected values for that district, squaring it, and then dividing it by the expected value. In this case, the contribution for District A is (58-46.80)^2/46.80 = 2.68, the contribution for District B is (22-32.40)^2/32.40 = 3.34, the contribution for District C is (12-18)^2/18 = 2.00, and the contribution for District D is (28-22.80)^2/22.80 = 1.19. Therefore, District B contributed the most to the test statistic.
The chi-square goodness-of-fit test compares observed and expected values to determine if they are significantly different from each other. The test statistic is calculated by summing the squared differences between the observed and expected values, divided by the expected values. The larger the difference between the observed and expected values, the larger the contribution to the test statistic. In this case, District B had the largest difference between the observed and expected values, therefore it had the greatest impact on the overall test statistic.
District B contributed the most to the test statistic because it had the highest value in the "Components" column. The formula for the chi-square goodness-of-fit test is (Observed - Expected)^2 / Expected, and the resulting value for District B is 3.34, which is the highest of the four districts. Therefore, District B had the biggest deviation from the hypothesized proportions.
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Answer: Voting district B contributed the most to the test statistic.
Step-by-step explanation:
How do you determine each voting district's contribution to the test statistic?
By subtracting the observed value from the predicted value for each voting district, square rooting the result, and then dividing the result by the expected value, the contribution of each voting district to the test statistic is determined. In this instance, the contributions for Districts A, B, C, and D are as follows:
District A's contribution is (58-46.80)²/46.80 = 2.68; District B's contribution is (22-32.40)²/32.40 = 3.34; District C's contribution is (12-18)²/18 = 2.00; and District D's contribution is (28-22.80)²/22.80 = 1.19. As a result, District B was most responsible for the test statistic.
In order to assess if actual and expected values differ significantly from one another, the chi-square goodness-of-fit test compares observed and expected values. The test statistic is determined by multiplying the expected values by the total of the squared discrepancies between the actual and predicted values. The contribution to the test statistic increases as the gap between observed and predicted values widens. In this instance, District B's largest disparity between actual and predicted values had the biggest effect on the test statistic as a whole.
Due to having the highest value in the "Components" column, District B had the greatest impact on the test statistic. (Observed - Expected)² / Expected is the formula for the chi-square goodness-of-fit test, and the result for District B, which is the highest of the four districts, is 3.34.
District B therefore, showed the greatest departure from the predicted proportions.
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Belinda is thinking about buying a house for $286,000. The table below shows the projected value of two different houses for three years: Number of years 1 2 3 House 1 (value in dollars) 294,580 303,417.40 312,519.92 House 2 (value in dollars) 295,000 304,000 313,000 Part A: What type of function, linear or exponential, can be used to describe the value of each of the houses after a fixed number of years? Explain your answer. (2 points) Part B: Write one function for each house to describe the value of the house f(x), in dollars, after x years. (4 points)
a) The type of function that can be used to describe the value of each house is:
House 1: Exponential function.House 2: Linear function.b) The functions that define the value of each house are given as follows:
House 1: H1(x) = 294580(1.03)^x.House 2: H2(x) = 295,000 + 9,000x.What are the functions?For House 1, the change each year is a percentage, as follows:
312519.92/303417.30 = 303417.30/294580 = 1.03.
Hence, considering the initial value of $294,580, the exponential function is defined as follows:
H1(x) = 294580(1.03)^x.
For House 2, the change each year is a fixed amount, as follows:
313,000 - 304,000 = 304,000 - 295,000 = 9,000.
Hence, considering the initial value of 295,000, the linear function is defined as follows:
H2(x) = 295,000 + 9,000x.
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Write 28 as a product of its prime factors, write factors in order from smallest to largest
Answer:
2 × 2 × 7
Step-by-step explanation:
start dividing by the lowest prime and work up until 1 is reached
28 ÷ 2 = 14
14 ÷ 2 = 7
7 ÷ 7 = 1
then
28 = 2 × 2 × 7 = 2² × 7
0.1 recurring as a fraction
Answer:
1/9
Step-by-step explanation:
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Use Taylor's Theorem to obtain an upper bound for the error of the approximation. Then calculate the exact value of the error. Round your answers to three significant figures.)
cos(0.3)=1−(0.3)22!+(0.3)44!
R4≤ .
R4=.
Answer:
Step-by-step explanation:
According to Tylor theorem,
f(x)=f(a)+f′(a)/1!×(x−a)+f′′(a)/2!×(x−a)2+......+fn(a)/n!×(x−a)n
Tylor series for cosx is
1 - x^2/2! + x^4/4! + x^6/6! + ……
cos (0.3) = 1 - 〖(0.3)〗^2/2! + 〖(0.3)〗^4/4!
The R4 valur is fourth derivative of cosx
f’(x) = -sinx
f’’ (x) = -cosx
f’’’ (x) = sinx
f’’’’ (x) = cosx
Here, a = 0, n = 3, x = 0.3
max l f^4l = cos (0.3)
= 0.9999
lR_4 (x)l ≤ |0.3-0|^(4+1)/4! × 0.9999
≤ 0.00015186
= 1.51786 × 10^(-4)
R_n (x) = cos (0.3) – (1 - 〖(0.3)〗^2/2!-(0.3)^4/4!)
= 0.0446
The error of approximation R_4 (x) ≤ 1.2 × 10^(-2) and exact value of error R_4 = 0.0446