Students in a physical science class are measuring the velocity of a model car. Their data is shown in the table.
Based on the data table, what would the acceleration be at 3. 5 seconds?
Answers
Based on the data table, the acceleration of this model car at 3. 5 seconds is equal to: D. 10 m/s/s.
How to determine the acceleration at 3.5 seconds?By critically observing the data provided in the data table, we can logically deduce that there exist a proportional relationship between the velocity of this model car (in m/s) and the time taken (in seconds).
Mathematically, a proportional relationship can be represented with the following mathematical expression:
v = kt
Where:
v represents the velocity of this model car (in m/s).t represents the time.k represents the constant of proportionality.Next, we would determine the constant of proportionality (k) as follows:
Constant of proportionality (k) = v/t
Constant of proportionality (k) = 10/1
Constant of proportionality (k) = 10.
For the velocity at time, t = 3.5 seconds, we have the following:
Velocity, v = kt
Velocity, v = 10 × 3.5
Velocity, v = 35 m/s.
Mathematically, the acceleration of a physical object can be calculated by using this formula:
Acceleration = change in velocity/change in time
Substituting the given parameters into the formula, we have;
Acceleration = (35 - 15)/(3.5 - 1.5)
Acceleration = 20/2.0
Acceleration = 10 m/s/s.
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Answer:
10 m/s
Explanation:
Related Questions
12. Define aerobic capacity. How does it relate to cardiorespiratory endurance?
Answers
There are nine books in a stack, each with a weight of 6n. The coefficient of friction between all the books is 0. 1 as is the coefficient between the table and the bottom book. What horizontal push must i just exceed on the next to bottom book to start sliding the top eight books off the bottom one?.
Answers
The top five books must be pushed off the bottom one with 5 N of horizontal force.
The word "force" has a specific meaning in science. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. Each of the six books weighs five pounds, therefore we need to slide five of them.
them, where 55 = 25N
The following formula can then be used to get the friction force.
F = N μ
where F is the frictional force, N is the force, and is the static friction coefficient
F= (25 N) (0.2) (0.2)
F= 5 N
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from the top of a tall building, you drop two table tennis balls, one filled with air and the other with water. both experience air resistance as they fall. which ball reaches terminal velocity first? do both hit the ground at the same time?
Answers
The air-filled table tennis ball is the first to reach the terminal velocity.
No, the water-filled table tennis ball will be the first to hit the ground.
What is meant by terminal velocity?The maximum velocity attained by an object as it falls through a fluid is known as terminal velocity.
It demonstrates that the terminal velocity of a body is directly related to the object's weight for the same radius.
The lighter air filter table tennis is the first to attain terminal velocity. Because its mass is lighter for the same shape and size, the friction force of upward resistance equals the downward force of mg sooner. To hit If the terminal velocity of the water-filled table tennis ball is greater and it strikes the ground first, the force of gravity on the ball increases.
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if it took 2.17 ms for the bullet to change speed from 439 m/s to the final speed after impact, then what was the magnitude of the average force (in n) exerted by the block on the bullet during this time?
Answers
The magnitude of the average force exerted by the block on the bullet during that time is 202,304.147m N (m stands for bullet mass)
We got some values here,
v = 439 m/s
t = 2.17 ms = 2.17 × [tex]10^{-3}[/tex] s
First, we should find the acceleration of the car. We assume that final speed of bullet after impact is 0 m/s, so here we go
a = v/t
a = [tex]v_{1}[/tex] - [tex]v_{0}[/tex] / [tex]t_{1}[/tex] - [tex]t_{0}[/tex]
a = 0 - 439 / 2.17 × [tex]10^{-3}[/tex] - 0
a = -439 / 2.17 × [tex]10^{-3}[/tex]
a = -439,000 / 2.17
a = -202,304.147 m/[tex]s^{2}[/tex]
What actually happens when the result is negative is not the acceleration after the bullet hits the target, but the deceleration.
Now we got the amount of deceleration. We can found the force by the formula of: F = m.a but in the question there is no mass value of the bullet. So, we can answer this question by this way (we can ignore negative values)
F = m.a
F = m × 202,304.147 m/[tex]s^{2}[/tex]
F = 202,304.147m N
What is acceleration?Acceleration (a) is the change of velocity (Δv) over the change of time (Δt), and here is the formula, a = Δv/Δt. This formula allows you to measure how quick velocity changes in meters per second squared (m/s. Acceleration is also a vector quantity, so it includes both magnitude and direction.
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1. describe the sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length). begin with the aortic valve and compare others to it. this is a subjective description.
Answers
The sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length) is mentioned below
1. First heart sound
Heard dull. Described as LUB.At the beginning of the ventricular systole Frequency: 30-80 cpsVaries from 0.09 to 0.16 second.2. Second Heart sound
Sharp, described as DUBAt the end of ventricular systole Duration 0.11 secFrequency- 150 to 200 cps.Due to closure of semilunar valves.3. Third heart sound
Heard often. Weak and rumbling in nature. Frequency below 40 cpsDuration 0.04secHeart as lub-dub-ta4. Fourth heart sound
Weak and rumbling. When atria contracts Frequency- 20cpsTherefore, the sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length) is mentioned above
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A wooden block resting on a table is given a push. Which of the following describe the motion of the block a moment after the push
Continues at a constant speed for a while, then slows down
O Slows down gradually to a stop
Accelerates at a positive, constant rate
O Moves at a constant speed
Answers
Acceleration will be constant while speed will not. The third option describes the motion.
What is Force ?Force can simply be defined as a pull or push. It is the product of mass and velocity and it is measured in Newton.
If a wooden block resting on a table is given a push, the block of mass m will accelerate with acceleration a and stop due to friction
One of the following options that describe the motion of the block a moment after the push is the third option. That is, accelerates at a positive, constant rate.
Since the block will be accelerating, the speed of the block can never be constant.
Therefore, accelerates at a positive, constant rate is the option that describe the motion of the block a moment after the push.
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400 turn circular coil with a radius of 0.3 m is rotated through a quarter turn in 0.417 ms (this corresponds to 60 revolutions per second). suppose the plane of the loop was initially perpendicular to a uniform magnetic field. if the average induced voltage is 10 kv, what is the magnitude of the magnetic field?
Answers
Bohr atomic model can not predict spectra for multielectron atom.
What is Bohr atomic model?
The Bohr model postulates that the electrons are orbit the nucleus at fixed energy if levels. Orbits further from to the nucleus to exist at highest energy levels.
Sol-
Bohr’s theory was unable to explained the followings observations :
i) Bohr’s model could not explain the spectra of atoms containing more than one of electron.
ii) It never not explain the Zeeman effect.
In presence of the magnetic of field, each of spectral line gets split up to into fine lines, the phenomenon is known as Zeeman effect.
iii) It could not explain the to Stark effect.
In presence of the electric of field, each spectral line gets split up into fine lines, the phenomenon is known as as the Stark effect.
iv) The main objection to the Bohr’s model was raised by Heisenberg’s uncertainty principle.
According to the Heisenberg’s uncertainty principle, it is impossible to determine the simultaneously the exact position and the momentum of a small moving particle like an electron.
But, according to Bohr’s model electron moves in well-defined orbits around the nucleus, and hence its position, as well as momentum, can be determined simultaneously, which is against the of uncertainty principle.
So, electron moves in well-defined orbits around to the nucleus is impossible.
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Help, fast!
If you have an 18 Ohm light bulb connected to a 9.0 V cell, what is the current in the circuit?
Answers
Answer:
Explanation:
Given:
R = 18 Ohm
U = 9.0 V
__________
I - ?
Ohm's law:
I = U / R
I = 9.0 / 18 = 0.5 A
an satellite is said to be in geosynchronous orbit if the period of its orbit is equal to the period of rotation of the star or planet. for a satellite in geosynchronous orbit around the neutron star, what is its distance from the surface of the star?
Answers
Such an orbit places a satellite at a height of around 35,786 km (22,236 mi) above mean sea level. At relation to the surface of the Earth, it remains in the same place.
A prograde, low-inclination orbit with a period of 23 hours, 56 minutes, and 4 seconds is known as a geosynchronous orbit (GEO). Even if it may seem to move north and south, a spacecraft in geosynchronous orbit appears to stay above Earth at a constant longitude.
what is geosynchronous orbit?
The word "geosynchronous" describes the satellite's orbital period, which allows it to be in phase with the rotation of the Earth ("geo-"). In addition to the criteria for orbital time, the satellite must also be situated in an orbit that places it close to the equatorial in order to qualify as geostationary.
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Such an orbit places a satellite at a height of around 35,786 km (22,236 mi) above mean sea level. At relation to the surface of the Earth, it remains in the same place.
What is geosynchronous orbit?
The word "geosynchronous" describes the satellite's orbital period, which allows it to be in phase with the rotation of the Earth ("geo-"). In addition to the criteria for orbital time, the satellite must also be situated in an orbit that places it close to the equatorial in order to qualify as geostationary.
A prograde, low-inclination orbit with a period of 23 hours, 56 minutes, and 4 seconds is known as a geosynchronous orbit (GEO). Even if it may seem to move north and south, a spacecraft in geosynchronous orbit appears to stay above Earth at a constant longitude.
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A volumetric pipette has an uncertainty of 0. 01cm3. What are the lowest and highest possible volumes for a measurement of 0. 20cm3.
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In a volumetric pipette which has an uncertainty of 0. 01 cm³, for a measurement of 0. 20cm3, the lowest possible value is 0.195 cm³
and highest possible value is 0.205 cm³.
Measurement uncertainty = 0.01 cm³
Error = uncertainty value/2 = 0.01/2 = 0.005 cm³
The formula to calculate the possible values for a volumetric pipette with uncertainty0.01 cm³ is give below.
Possible values = measured value ± Error.
Lowest possible value = 0.20 - 0.005
= 0.195 cm³
Highest Possible Value = 0.20 + 0.005
= 0.205 cm³
Thus, for a volumetric pipette, the lowest possible value is 0.195 cm³ and highest possible value is 0.205 cm³.
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What happens to form the brown spots on a tlc plate when you place the developed tlc plate in an iodine chamber?.
Answers
Iodine sublimates and reacts with the compounds on the produced TLC plate when it is placed in the chamber and covered, producing yellow-brown spots.
Iodine interacts with many different chemical molecules to produce colorful complexes, which causes coloration. About half of the possible chemicals will work with this stain. For every step see attached file.
Because complexation is reversible and the original chemical will eventually remain on the TLC plate when the iodine has evaporated, this procedure is regarded as "semi-destructive." It is potentially feasible to utilize a different visualization method on the TLC plate after the coloring fades, though it's likely the compound may already have evaporated by then.
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at one instant, the two conductors in a long household extension cord carry equal 5.00-a currents in opposite directions. the two wires are 3.00 mm apart. find the magnetic field 35.0 cm away from the middle of the straight cord, in the plane of the two wires.
Answers
The magnetic field 35.0 cm away from the middle of the straight cord, in the plane of the two wires is 1.96 T j
What is meant by magnetic field?A magnetic field is a vector field that explains the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force that is perpendicular to both its own velocity and the magnetic field.
The magnetic field is a technique used to describe how magnetic force is distributed in the space surrounding and within something magnetic in nature.
Given,
A long household extension cord's two conductors carry equal 5.00-a currents in opposite directions at the same time.
And also given that the two wires are 3.00 mm apart.
Let B₁ be inside the plane and B₂ be outside the plane.
It is required to calculate the magnetic field at point A
The directions of the magnetic field at A can be calculated using Right hand rule.
[tex]B_{net}[/tex] = B₂ -B₁
[tex]B_{net}[/tex]=μ₀I/2Π(0.35-(3×10⁻³)/5) - μ₀I/2Π(0.35+(3×10⁻³)/5)
[tex]B_{net}[/tex]= 1.96×10⁻⁹ TJ
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How did you find the speed of the ball at the bottom of the ramp?
Answers
The speed of the ball at the bottom of the ramp is obtained by taking the square root of 2 times gravity times height of the ramp (v = √2gh).
What is the speed of the ball at the bottom of the ramp?The speed of the ball at the bottom of the ramp is calculated by applying the principle of conservation of energy as shown below.
According to principle of conservation of energy;
kinetic energy of the ball at bottom of the ramp = potential energy of the ball at the maximum height of the ramp
K.E(bottom) = P.E(top)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
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how much work does tension do on the laptop as it moves 2.0 mm ? express your answer with the appropriate units.
Answers
The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J
W = F d cos θ
W = Work done
F = Force
d = Displacement
θ = Angle between force and displacement vector
F = 14 N
d = 2 mm = 0.002 m
θ = 0
W = 14 * 0.002 * 1
W = 0.028 J
Work done is the change in energy of an object. So if an object moves a certain distance, work is done on the object. If the force and displacement are perpendicular to each other there is no work done on the object.
Therefore, the work done by tension on the laptop is 0.028 J
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an object is rolling without slipping. what percentage of its total kinetic energy is its translational kinetic energy if the object is (a) a uniform sphere, (b) a uniform cylinder, or (c) a hoop?
Answers
When the object is a sphere of Radius R and mass M the 60% of its total kinetic energy is its translational kinetic energy.
What is a kinetic energy?
The kinetic energy of an object is termed as the energy it posses because of its motion.
What is translational kinetic energy?The translational kinetic energy is the energy required to move or accelerate the object from its position of rest.It is described as the effort required to move a mass-determined body from rest to the indicated velocity.
The moment of inertia of the object will be⇒I =2/3MR2
Sphere is rolling without slip ,v=Rω (v= speed of centre of mass and ω is angular speed)
Translational KE =1/2Mv2
Rotational KE = 1/2Iω2=1/2(2/3MR2)x(V/R)2=1/3Mv2
Total KE= 1/2Mv2 +1/3Mv2 =5/6 Mv2
Now % of Translational Energy= 1/2Mv2 ÷ 5/6 Mv2 x100 = 60%
Hence, when the object is a sphere of Radius R and mass M the 60% of its total kinetic energy is its translational kinetic energy.
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30. An applied force of 60 N is used to accelerate a 50 N object to the right across a frictional surface. The object
encounters a 20 N of friction. Determine the coefficient of friction
a. 0.4
b. 2.5
c. 0.83
d. 3
Mu'
Answers
Coefficient of friction is calculated to be 0.4. Therefore, a) will be the correct answer .
What do you mean by frictional force ?Frictional force is that force which is generated by two surfaces that contact and slide against each other. Factors affecting the frictional force are the surface texture and the amount of force impelling them together.
The frictional force is said to be a contact force as frictional force occur when two surfaces come in contact with each other.
Given applied force = 60 N
weight of object = 50N; friction force = 20N
As we know that, Coefficient of friction = force of friction/normal force
= 20/50
Coefficient of friction = 0.4
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a compound microscope has objective and eyepiece focal lengths of 6.0 mm and 1.6 cm , respectively. if the lenses are 8.6 cm apart, what is the magnification of the instrument?
Answers
To learn about the focal length and magnification to solve this problem.
What is focal length?
The focal length of a narrow lens in air is measured from the lens's center to its primary foci, also known as focal points. The focal length of a converging lens, such as a convex lens, is positive and determines how far a collimated light beam must travel to focus on a single point.
What is magnification?
The size of a picture in relation to the size of the item that created it is known as magnification in optics. The term "linear" magnification—also referred to as "lateral" or "transverse" magnification—describes the ratio of image length to object length as measured in planes perpendicular to the optical axis.
Given U₀ = 3cm, f₀= 2.5cm, v₀=mage distance for objective lens
1/f₀= 1/v₀- 1/u₀
1/v₀=1/f₀+1/u₀=1/2.5-1/3
v₀= 3*2.5/3-2.5= 15cm
Object distance for eye piece =20−15=5cm
Given Ue= -5cm, Fe= 6cm, Ve = image formed by eye piece
1/Ve= 1/Fe +1/ Ue= 1/6-1/5
Ve=-30cm
magnification m = -L/F₀*25/Fe
where L is the length of the microscope
here L= 20 cm
m= -20/25*25/6= -33.33
Therefore, the focal length is 15cm and the magnification is 33.33 cm.
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A 10-kg mass and a 2.0-kg mass are connected by a light string over a massless, frictionless pulley. If g = 9.8 m/s2 , what is the acceleration of the system when released
Answers
For a frictionless pulley with mass connected by a light string, the acceleration for the system when released is equal to 6.5m/s²
How is the acceleration for a frictionless pulley calculated?Using the formula a = (m₂ - m₁)g/(m₁ + m₂)
Where a = acceleration, m = mass and g = gravity
m₁ = 2kg
m₂ = 10kg
g = 9.8m/s²
Applying to the formula, a = (m₂ - m₁)g/(m₁ + m₂) to find the acceleration of a frictionless pulley when released;
a = (10 - 2)(9.8)/(2 + 10)
a = 8(9.8)/12
a = 6.5m/s²
Therefore the system's acceleration 6.5m/s²
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bumper cars a and b undergo a collision during which the momentum of the combined system is conserved. which equation(s) correctly states the principle of conservation of momentum? check all that apply.
Answers
Equation A. P A i + P B i = P A f + P B f and D.ΔPA + ΔPB=0. correctly states the principle of conservation of momentum.
Momentum is the product of the mass and pace of an object. it's miles a vector quantity, owning a magnitude and a route. If m is an item's mass and v is its velocity, then the object's momentum is p.
Momentum is manufactured from the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both value and path. Isaac Newton's 2d regulation of motion states that the time price of trade of momentum is the same as the pressure performed at the particle. See Newton's legal guidelines of movement.
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Disclaimer:- your question is incomplete, please see below for the comlete question.
Bumper cars a and b undergo a collision during which the momentum of the combined system is conserved. which equation(s) correctly states the principle of conservation of momentum? check all that apply.
A. P A i + P B i = P A f + P B f
B. P A i + P A f = P B i + P B f
C. ΔPA = ΔPB
D. ΔPA + ΔPB=0
2. A ball is projected with a velocity of 50m/s at an angle of 53° to the horizontal
Calculate:
A. The time of flight of the ball.
B. The range and
C.The maximum height
Answers
The time of flight is 0.4 sec, The range is 1.6 m and maximum height is 3.2 meter.
Calculation:-
The initial vertical speed is u = 5m/s×sin53° = 4m/s
Time of flight = u/g
= 4/10
= 0.4 second
so if the final vertical velocity is v at a height h then v² = u² −2gh will give us v = [tex]\sqrt{16-20*0.45} = \sqrt{7} m/s[/tex]
The horizontal velocity remains constant and is given as Vx = 5m/s Cos53° = 3m/s
so the speed at the said instant will be V = [tex]\sqrt{v_{x} ^{2} +v^{2} } = \sqrt{9+7} = 4m/s[/tex]
Range = horizontal velocity× 0.4 second
= 4 × 0.4
= 1.6 m
Height = UT- 1/2at²
= 1.6 - 0.4 × 10 × 0.16
= 3.2 m
The horizontal velocity of the projectile is constant. There is the vertical acceleration due to gravity. Its value is 9.8 m/s/s, and the projectile's vertical velocity changes at 9.8 m/s per second. The horizontal movement of the projectile is independent of vertical movement. Horizontal acceleration is always zero because nothing accelerates the projectile horizontally.
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A double-slit experiment yields an interference pattern due to the path length difference from light traveling through one slit versus the other. Why does a single slit show a diffraction pattern?.
Answers
Light bends around the obstacles like the waves and this bend cause the diffraction pattern. single slit shows a diffraction pattern because of the path length difference from waves originating at different parts of the slit.
The double-slit experiment demonstrates that mild and remember can show traits of each classically described wave and debris; moreover, it presents the fundamentally probabilistic nature of quantum.
Mechanical phenomena. young's authentic double-slit experiments have been in fact the primary to illustrate the phenomenon of interference. when he shone mildly via two slender slits and determined the sample created on the display screen, the younger did not locate brilliant regions similar to the slits, however as an alternative noticed vivid and darkish fringes.
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A 53 kg person is being dragged in their sleeping bag to the lake by a 476 N force at an angle of 40 degrees. If the coefficient of friction between the sleeping bag and the ground is 0.37:
a.) What is the force of gravity acting on the person?
b.) What is the normal force acting on the person? (Use net force in y-direction)
c.) What is the force of friction acting on the person?
d.) What is the acceleration of the person in the sleeping bag?
Answers
(a) The force of gravity acting on the person is 519.4 N.
(b) The normal force acting on the person is 519.4 N.
(c) The force of friction acting on the person is 192.18 N.
(d) The acceleration of the person in the sleeping bag is 3.25 m/s².
What is the force of gravity acting on the person?
The force of gravity acting on the person is calculated as follows;
W = mg
where;
m is the mass of the persong is acceleration due to gravityW = 53 kg x 9.8 m/s²
W = 519.4 N
The normal force acting on the person is calculated as follows;
Fn = W
where;
Fn is the normal force on the person acting upwardsW is the weight of the person acting downwardsFn = 519.4 N
The force of friction acting on the person is calculated as follows;
Ff = μFn
where;
μ is coefficient of frictionFn is normal forceFf = 0.37 x 519.4 N = 192.18 N
The net force on the person is calculated as follows;
F(net) = F cosθ - Ff
where;
F cosθ is the force applied along the horizontalFf is force of frictionF(net) = 476 x cos(40) - 192.18
F(net) = 172.46 N
The acceleration of the person in the sleeping bag is calculated as follows;
a = F(net) / m
a = (172.46) / (53)
a = 3.25 m/s²
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During a game of tug-of-war, two students are pulling on a rope. One student pulls to the left with a force of 35 N, while another student pulls to the right with a force of 35 N. What is the net force being applied to the rope, and in which direction will the rope move?
35 N; the rope will move to the right
70 N; the rope will stay stationary
17.5 N; the rope will move up
0 N; the rope will stay stationary
Answers
Answer: 0N; the rope will remain stationary
Explanation: Connexus
Net force applied on the rope is 0 N and the rope will stay stationary.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given that:
One student pulls to the left with a force of 35 N.
Another student pulls to the right with a force of 35 N.
Hence, these forces act in opposite direction.
Net force applied on it = 35 N - 35 N = 0 N.
So, the net force of zero newton being applied to the rope, and the rope remains stationary.
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if the sun had been born with a smaller, lower-mass companion star, would that star be a red dwarf today or would it already be dead?it would still be a red dwarf today regardless of how much less mass than the sun it has, since its lifetime would be inherently longer than the sun'sit would be a red dwarf today only if it had much less mass than the sun (for example, a star with 20% msun)it would be dead by today only if if it had a little less mass than the sun (for example, a star with 90% msun)it would be dead today only if it had much less mass than the sun (for example, a star with 20% msun)it would be a red dwarf today only if it had a little less mass than the sun (for example, a star with 90% msun)
Answers
If the Sun had been born with a smaller, lower-mass companion star, would that star be a red dwarf today or would it already be dead, it would still be a red dwarf today regardless of how much less mass than the Sun it has, since its lifetime would be inherently longer than the Sun's.
Stars sparkle and shine—they appear to have an incandescence of their own even when they are bathed in the spotlight—so it stands to reason that they are stars. However, they are "stars" in a much more specific sense because they are a product of the long-standing Western cultural tendency to equate humanity with the heavenly.
Not all celebrities live alone. About half of all stars in our galaxy, the Milky Way, have a companion and journey through space in a binary system.
Now, the long-lost partner of the Sun could be found anywhere in the Milky Way. According to a team of Harvard astronomers, our solar system was once a binary system because the Sun formerly had a companion star.
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if a 69.87 kg person ate 181 calories worth of sugar (about the calories in a typical energy drink and they converted all of that energy to heat immediately, what would be the change in temperature of that person?
Answers
If a 69.87 kg person ate 181 calories worth of sugar and they converted all of that energy to heat immediately, the change in temperature of that person is 3.609 ºC.
What is calorie?
Energy is quantified by calories. One calorie is equal to the amount of a heat energy needed to raise one gram of water's temperature by one degree Celsius.In reality, the term "calorie" refers to a kilocalorie, or one thousand actual calories.To heat one kilogram of water by one degree Celsius, one nutritional calorie is required.Through combustion in a bomb calorimeter, the number of calories in various food servings is calculated.To calculate the change in temperature resulted from the intake of food calories or energy generated in Joules we use the formula,
Energy(Joules) = mass of the body (g) x specific heat of the body(J/gºC.) x change in temperature (ºC)
Let us assume that the average specific heat of the person's body is 3.00 J/gºC.
Using the above formula we find the change in temperature as-
181 x 1000 cal/ 1cal x 4.18 J/1 cal = 69.87 x 1000 x 3.00 J/gºC. x ΔT
ΔT = 181 x 1000 x 4.18/ 69.87 x 1000 x 3
= 3.609
Hence, the change in temperature of that person is 3.609 ºC.
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A 20 gram bullet traveling at 250m/s strikes a block of wood that weighs 2kg. With what velocity will the block and bullet move after the collision?.
Answers
The conservation of momentum can be used to determine the final velocity. The block and bullet system's velocity after the collision will be 2.5 m/s.
For example, a circular path's direction is always perpendicular to a line from the point to the circle's center. A point always moves in a direction that is tangent to its path (a radius). Using the momentum principle,
Where,
= bullet weight, 20 g, or 0.2 kilogram
250 m/s is the bullet's speed before colliding.
= block weight = 2 kg
= velocity following impact =?
Fill out the formula with the values,
Therefore, the block and bullet system's velocity following the collision will be 2.5 m/s.
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kinetic energy depends on both the mass of an object and on its speed. using the ratio k1k2 to see how changing one or both of these parameters changes the kinetic energy. match each case with the correct value of k1k2.
Answers
The effect on K₁/K₂ on changing the quantities are :
a)If the mass of 1 is double the mass of 2, and the speeds are the same, then ratio is 2 times
b)If the speed of 1 is double the speed of 2, and the masses are the same, then ratio becomes 4 times.
c)If The mass of 2 is double the mass of 1, and the speeds are the same, then ratio becomes half.
d)If The speed of 2 is double the speed of 1, and the masses are same, then ratio becomes 1/4 times.
e)If The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1,then ratio becomes half.
We know that kinetic energy of any body is given by (1/2)mv² where m is the mass of the body and v is the velocity of the body.
Hence, the ratio of K₁/K₂ is changing on changing one or both of these parameters
a) when mass of first body is doubled then K₁ becomes 2 times of initial kinetic energy, then ratio will become twice of the initial value.
b)when speed of first object is doubled then kinetic energy of first object will becomes 4 times of initial energy ,therefore the ratio becomes 4 times of initial ratio.
c) If The mass of 2 is double the mass of 1, and the speeds are the same then in that kinetic energy of 2nd object will become twice of initial kinetic energy, therefore ratio will become half.
d) If The speed of 2 is double the speed of 1, and the masses are same then ratio becomes 1/4 times of initial ratio.
e) If The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1, then in that case ratio becomes half of initial ratio,
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(Complete question) is:
Kinetic energy depends on both the mass of an object and on its speed. Ki the kinetic energy. Using the ratio K₁/K₂ to see how changing one or both of these parameters changes the kinetic energy. Match each case with the correct value of ratio K₁/K₂. 1) The mass of 1 is double the mass of 2, and the speeds are the same.2) The speed of 1 is double the speed of 2, and the masses are the same. 3) The mass of 2 is double the mass of 1, and the speeds are the same. 4) The speed of 2 is double the speed of 1, and the masses are the same. 5) The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1.
a system gains 612 kj of heat, resulting in a change in internal energy of the system equal to 246 kj. how much work is done?
Answers
The total work done if a system gains 612 KJ of heat, resulting in internal energy of the system equals to 246 KJ would be -366 KJ
What is the internal energy of the system?
Internal energy can be defined as the property that defines the energy of a substance in the absence of effects due to capillarity, external electric and magnetic fields
In the above case
Let Change in internal energy ΔU = 246 kJ
Let Heat gained by the system (q) = 612 kJ
Using the First law of thermodynamics
ΔU = q + w
Where:
ΔU represent change in internal energy
q represents heat added to the system
and w is work done.
Let plug in the formula
246 kJ = 612 kJ + w
w = 246 kJ - 612 kJ
w= - 366 kJ
Here the negative sign means that work is done by the system.
Therefore, The total work done if a system gains 612 KJ of heat, resulting in internal energy of the system equals to 246 KJ would be -366 KJ
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3. What group of elements found on the periodic table are NOT used when determining the number of
valence electrons a group has?
Answers
Answer: Transition metals
Explanation:
Why does a shaved camel standing in the sun require more water than an unshorn camel?.
Answers
The shaved camel has more evaporation than unshorn camel so it needs more water.
In order to lower the bog, the sweat, or more specifically its evaporation, cools the air around the body.
why does camels produce little sweat and urine?
A camel can easily withstand extreme temperatures.
Most of a camel's fat is deposited in its humps, unlike many other mammals, allowing for improved thermoregulatory. It is easier for them to release heat from their bodies in warmer climates. Camels seldom ever perspire. They are far better able to withstand the heat than we are.
During the day, their body temperature fluctuates, rising with the greater outside warmth and falling at midnight when it is colder. Although it may seem odd that camels have fur when they live in such desert areas, their hairs really act as insulation to keep them cool.
Therefore, The shaved camel has more evaporation than unshorn camel so it needs more water.
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The shaved camel has more evaporation than unshorn camel so it needs more water. In order to lower the bog, the sweat, or more specifically its evaporation, cools the air around the body.
Why does camels produce little sweat and urine?
A camel can easily withstand extreme temperatures. Most of a camel's fat is deposited in its humps, unlike many other mammals, allowing for improved thermoregulatory. It is easier for them to release heat from their bodies in warmer climates. Camels seldom ever perspire. They are far better able to withstand the heat than we are.
During the day, their body temperature fluctuates, rising with the greater outside warmth and falling at midnight when it is colder. Although it may seem odd that camels have fur when they live in such desert areas, their hairs really act as insulation to keep them cool.
Therefore, the shaved camel has more evaporation than unshorn camel so it needs more water.
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