Stephan can type 2700 words in 90 mins Jim can type 2450 in 70 mins gavin can type 1600 words in 40 mins who can type the fastest rate of words per minute

Answer:

7) 6170

8) 70000

9) 7310000

10) 0.000000054

11) 0.0067

12) 959

Answer:

A.

Step-by-step explanation:

Since it says greater than, that means that it cannot be B or D. And ≥ means greater than or equal to and they don't state that in the problem. So the answer would be A.

I HOPE THIS HELPED! :)

Step-by-step explanation:

5+5-3= 7

!!!!!!!!!!!!!!!!!

Answer:

answer is 7 please give a brainliest please

Step-by-step explanation:

Answer:

A. 3/8*2=6/8

Step-by-step explanation:

Think about a whole number as (whole number)/1

(2/1)

Then multiply

3/8*2/1=6/8

Hope that helps!

Answer:

Value of the test statistic for this problem = -3.74

Step-by-step explanation:

Here

the sample size n = 1263

and the x = 565

So, the p' -value = 565/1263 = 0.4473

As per the test statistics formula, z value will be evaluated

z = (0.4473-p)/sqrt {p(1-p)/n}

Let us say that p = 0.5

Substituting the given value in above equation, we get -

z = (0.4473-0.5)/sqrt {0.5(1-0.5)/1263}

z = -3.74

The test statistic of the question is; z = -3.74

We are given;

Sample size; n = 1263

Number of people that said yes; x = 565

Sample proportion is; p'= 565/1263 = 0.4473

Formula for the test statistic of proportion is;

z = (p' - p)/(√(p(1 - p)/n)

We will assume that population proportion p = 0.5. Thus;

z = (0.4473 - 0.5)/(√(0.5(1 - 0.5)/1263)

z = -3.74

Read more about test statistic at; https://brainly.com/question/4621112

Answer:

the answer would be 128cm³

Step-by-step explanation:

have a great rest of ur day

Answer:

96cm

Step-by-step explanation:

============================================================

Work Shown:

Apply the tangent ratio. Make sure your calculator is in degree mode.

tan(angle) = opposite/adjacent

tan(B) = CD/BC

tan(39) = x/30

30*tan(39) = x

x = 30*tan(39)

x = 24.2935209958502

x = 24.3

Answer:

The answer for this question is 42

9514 1404 393

Answer:

  (x +1)^2 +(y -3)^2 = 4

Step-by-step explanation:

The equation of a circle centered at (h, k) with radius r is ...

  (x -h)^2 +(y -k)^2 = r^2

The graphed circle is centered at (h, k) = (-1, 3), and has radius 2, so its equation is ...

  (x +1)^2 +(y -3)^2 = 4

Answer: x= 17 I hope that helps you understand it Goodbye!

Step-by-step explanation:  

7(x-2)=5(x+4) So the first step is to Distribute meaning Multiply so 7(x-2 ) that would give you -14 that where I got that from and I just did 5(x+4)= 20 and bring the x down

1. 7x-14=5x+20 So, I just do the opposite of subtracting which is adding so, I'm going to add 14 to both sides

2. 7x=5x+20+14 = 5x+34

3. 7x= 5x+34 So, I'm going to do the opposite of adding now which is subtracting meaning I'm just going to subtract 5x from both sides

4. 7x-5x=34 So then I do 7x-5x=2x

5. 2x= 34 so. I just Divide 2 from both sides x=34/2= 17

So, your answer would be x=17 and yes you got to put the variable for your answer to be right you can't just put 17 it got to be x= 17 and variable is just letters in the equation don't let it confused you but that would be your answer x=17 And can you make me Brainliest Please  

( - 1 )^5 = - 1

.....................

.....................

.....................

Answer:

the answer is -1 have a nice day

Answer:

5/27

Step-by-step explanation:

Answer:

1/18

Step-by-step explanation:

[tex]\frac{1}{9}[/tex]÷2

make 2 a fraction

[tex]\frac{1}{9}[/tex]÷[tex]\frac{2}{1}[/tex]

cross multiply

1*1

9*2

[tex]\frac{1*1}{9*2}[/tex]

[tex]\frac{1}{18}[/tex]

Answer:

Step-by-step explanation:

You always invert the second number in a division question and then multiply. This one is a little different. It has three levels. What do you do about that?

[tex]\frac{\frac{1}{9} }{\frac{2}{1} }[/tex]

Now you have a four level question which is handled the same way as all four level question.

Invert the bottom and multiply. Invert means turn upside down. So you turn the 2/1 upside down and you get 1/2

[tex]\frac{1}{9}*\frac{1}{2}[/tex]

What you get is 1/18 The green box with the question mark is a 1.

Answer:

divided both sides of the equation by 3

Step-by-step explanation:

x---- independent variable

f(x)--- dependent variable(can also be "y")

The dependent variable (fx) is the output or you can say... For every value of the independent variable (x)...There's a unique value for the dependent variable.

Ok... Lemme explain

Say you have an equation

f(x)=2x+1

let x be take value from all natural Numbers (1,2,3..….)

When x is 1

f(x) = f(1) = 2(1)+1

=3

when x is 2

f(x)=f(2) = 2(2)+1 =5.

So for every x value... There's a unique value for f(x).

You dig?

Now

let's proceed to your question.

We're already given tbe values of x and f(x)

What we now need to find is the equation that corresponds to the values being gotten

From the table

When x =1 ...….f(x)=8

When x=2 .........f(x) = 32

When x=3 ...........f(x)=128

Etc

Which equation from the options will give you these values of f(x)???

You're gonna have to test run it quickly by puttinh values of x and see if they'll give the corresponding value of f(x).

Fun right?

OK. From Observation....

OPTION A WILL DO THE JOB.

f(x)=2.4^t where "t" represents x in this case.

Input your values of x in this

You'll get the exact f(x) value

Eg

when x= 1... f(x)= 2.4¹ =8

x=2 ..….f(x) = 2. 4² = 2.16 = 32.

OPTION A IS OUR ANSWER.

HAVE A GREAT DAY BRO!

Answer:

The null hypothesis is [tex]H_0: \mu = X[/tex]

The alternate hypothesis is [tex]H_1: \mu \neq X[/tex]

Step-by-step explanation:

Mean of X in 1990, test if the mean duration has changed:

At the null hypothesis, we test if the mean duration is still X, that is:

[tex]H_0: \mu = X[/tex]

At the alternate hypothesis, we test if the mean duration has the changed, that is, if it is different of X. So

[tex]H_1: \mu \neq X[/tex]

Answer:

DIBF

Step-by-step explanation:

I'm pretty sure it's that

Answer:

I think A and B

Step-by-step explanation:

• A statistical question is a question that has more than one possible answer ( and can be answered by collecting data) where there will be variability in the data. for instance an example would be " How old are the students in this room?"

• However a non statical question has only one answer for instance "How old are you?"

both a and b dont have specific answers because it's not talking about a specific high school students or a specific soccer team. i would guess those are correct, but using the information from above you can also see what you think! hope this helps :)

Answer:

use a calculator

Step-by-step explanation:

hope this helps

Step-by-step explanation:

no sn as. kojsshsusishheidhsusjjsbsbshsbsjs7ehsjsnkosvsjsishshshsjdjjddyfygyvrcudjdhdudhsjsudhdjs

Answer:

D   540

Step-by-step explanation:

5.4 * 10²

5.4 * 100

540

Answer:

The probability is [tex]\frac{729}{100000}[/tex].

Step-by-step explanation:

probability of missing the bus = 1/10

Probability of catching the bus = 1 - 1/10 = 9 /10

So, the required probability is

[tex]\frac{9}{10}\times \frac {9}{10}\times \frac {1}{10}\times \frac {9}{10}\times \frac {1}{10}[/tex]

[tex]\frac{729}{100000}[/tex]

Answer:

I understand what you wrote as 18 + M = y. We don't know what M and y are. They are variables. When you add M to 18, it is equal to a value y.

I hope this makes sense. This is the foundation of algebraic thinking.

9514 1404 393

Answer:

  228 km

Step-by-step explanation:

Traveling 3 hours at 76 km/hour, the train covers a distance of ...

  distance = speed × time

  distance = (76 km/h)(3 h) = 76×3 km = 228 km

Answer:

Para un vaso de [tex]V = 25\pi\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 2.321\,cm[/tex] y [tex]h \approx 4.642\,cm[/tex].

Para un vaso de [tex]V = 1000\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 5.419\,cm[/tex] y [tex]h \approx 10.839\,cm[/tex].

Step-by-step explanation:

El vaso se puede modelar como un cilindro recto. El enunciado pregunta por las dimensiones del vaso tal que su área superficial ([tex]A_{s}[/tex]), en centímetros cuadrados, sea mínima para el volumen dado ([tex]V[/tex]), en centímetros cúbicos. Las ecuaciones de volumen y área superficial son, respectivamente:

[tex]V = \pi\cdot r^{2}\cdot h[/tex] (1)

[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r\cdot h[/tex] (2)

De (1):

[tex]h = \frac{V}{\pi\cdot r^{2}}[/tex]

En (2):

[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot \left(\frac{V}{\pi\cdot r} \right)[/tex]

[tex]A_{s} = 2\cdot \left(\pi\cdot r^{2}+V\cdot r^{-1} \right)[/tex]

Asumamos que [tex]V[/tex] es constante, la primera y segunda derivadas de la función son, respectivamente:

[tex]A'_{s} = 2\cdot (2\pi\cdot r -V\cdot r^{-2})[/tex]

[tex]A'_{s} = 4\pi\cdot r - 2\cdot V\cdot r^{-2}[/tex] (3)

[tex]A''_{s} = 4\pi + 4\cdot V \cdot r^{-3}[/tex] (4)

Si igualamos [tex]A'_{s}[/tex] a cero, entonces hallamos los siguientes puntos críticos:

[tex]4\pi\cdot r - 2\cdot V\cdot r^{-2} = 0[/tex]

[tex]4\pi\cdot r = 2\cdot V\cdot r^{-2}[/tex]

[tex]4\pi\cdot r^{3} = 2\cdot V[/tex]

[tex]r^{3} = \frac{V}{2\pi}[/tex]

[tex]r = \sqrt[3]{\frac{V}{2\pi} }[/tex] (5)

Ahora, si aplicamos este valor a (4), tenemos que:

[tex]A_{s}'' = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }[/tex]

[tex]A''_{s} = 4\pi + 8\pi[/tex]

[tex]A_{s}'' = 12\pi[/tex] (6)

De acuerdo con este resultado, el valor crítico está asociado al área superficial mínima. Ahora, la altura se calcula a partir de (5) y (1):

[tex]h = \frac{V}{\pi\cdot \left(\frac{V}{2\pi} \right)^{2/3} }[/tex]

[tex]h = \frac{2^{2/3}\cdot \pi^{2/3}\cdot V}{\pi\cdot V^{2/3}}[/tex]

[tex]h = \frac{2^{2/3}\cdot V^{1/3}}{\pi^{1/3}}[/tex]

Si [tex]V = 25\pi\,cm^{3}[/tex], entonces las dimensiones del vaso son:

[tex]r = \sqrt[3]{\frac{25\pi\,cm^{3}}{2\pi} }[/tex]

[tex]r \approx 2.321\,cm[/tex]

[tex]h = \frac{2^{2/3}\cdot (25\pi\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]

[tex]h \approx 4.642\,cm[/tex]

Un litro equivale a 1000 centímetros cúbicos, las dimensiones del vaso son:

[tex]r = \sqrt[3]{\frac{1000\,cm^{3}}{2\pi} }[/tex]

[tex]r \approx 5.419\,cm[/tex]

[tex]h = \frac{2^{2/3}\cdot (1000\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]

[tex]h \approx 10.839\,cm[/tex]