State if the two triangles are congruent. If they are, prove by using a two column proof!!!

Answer:

169

Step-by-step explanation:

x²+26x=23

=> to complete the square, the equation should be : x²+26x + (26/2)² = 23 + (26/2)²

<=> x² +26x + 13² = 23 + 13²

<=> x² +26x +169 = 23 + 169

<=> (x+13)² = 192

so, (x+13)² is the square form , and 169 must be added to complete the square

For 2ab to complete in (a+b)² formula

a=1

So 169 must be added

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Answer:

  -50%

Step-by-step explanation:

Suppose the fraction is f = p/q before any changes.

Decreasing the numerator by 60% multiplies it by (1 -0.60) = 0.4.

Decreasing the denominator by 20% multiplies it by (1 -0.20) = 0.8.

Then the new fraction is ...

  f' = p(0.4)/(q(0.8)) = (p/q)(0.4/0.8) = f(0.5) = f(1 -0.50) = f(1 +(-50%))

The increase in the value of the fraction is -50%.

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The graph shown with your problem statement does not pass the vertical line test, so is not the graph of a function. (A vertical line intersects the graph in more than one place.) This graph can be rejected immediately.

I find it convenient to look at the domain statements (x≤1 and x>1). This tells you that you can separately evaluate the graph to the left of x=1 and to the right of x=1. Each of those portions of the graph must match the corresponding expression.

Here, it looks sufficient to identify the slope of the line in each domain. (We don't know what graphs you're selecting from, so we don't know what you will need to look at to differentiate the correct one from the rest.)

For x < 1, the coefficient of x is 3, so the line will have a steep upward slope.

For x > 1, the coefficient of x is -2, so the line will have a slightly less steep downward slope.

The value of z(1) is 3(1)-2=1, so (1, 1) is at the top end of the line forming the left side of the graph. The limit as x approaches 1 from the right is -2(1)+3=1. This means the two lines meet at the point (1, 1) and the graph has a generally ∧ shape. The attachment shows the graph you're looking for.

Answer:

The average of rate was of 0.4314 cm/day, which means that on average, during this interval, the plant grew by 0.4314 cm each day.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function f(x), from x = a to x = b, is given by:

[tex]A = \frac{f(b)-f(a)}{b-a}[/tex]

In this question:

[tex]f(x) = 12(1.03)^n[/tex]

From n = 3 to n = 10

[tex]a = 3, b = 10[/tex]

[tex]f(b) = f(10) = 12(1.03)^{10} = 16.13[/tex]

[tex]f(a) = f(3) = 12(1.03)^{3} = 13.11[/tex]

Average rate of change:

[tex]A = \frac{f(b)-f(a)}{b-a} = \frac{16.13-13.11}{10-3} = 0.4314[/tex]

The average of rate was of 0.4314 cm/day, which means that on average, during this interval, the plant grew by 0.4314 cm each day.

Step-by-step explanation:

We need to find a midpoint. A midpoint splits the two end coordinates to meet at a point.

Use midpoint formula

[tex] \frac{ - 2 + 10}{2} = 4[/tex]

[tex] \frac{ - 11 + 1}{2} = - 5[/tex]

So the coordinates will be at

(4,-5)

Answer:

Step-by-step explanation:

same side interior angles also mean co interior angle

heree,

1.angle 4 and 6 are same side interior angle

2.angle 3 and 5 are also same side interior angle.

Co-interior angles or same side interior angles  lie between two lines and on the same side of a transversal. In each diagram the two marked angles are called co-interior angles. If the two lines are parallel, then co-interior angles add to give 180o and so are supplementary.

Step-by-step explanation:

i) Angle 4 and 6

ii) Angle 3 and 5

Given:

The figure of a quadrilateral ABCD.

To find:

The perimeter of the quadrilateral ABCD.

Solution:

In an isosceles triangle, the two sides and base angles are congruent.

In triangle ABD,

[tex]\angle DAB\cong \angle ABD[/tex]               [Given]

[tex]\Delta ABD[/tex] is an isosceles triangle      [Base angle property]

[tex]AD=BD[/tex]                   [By definition of isosceles triangles]    

[tex]8=BD[/tex]                   ...(i)

In triangle BCD,

[tex]\angle BCD\cong \angle CDB\cong \angle CBD[/tex]        [Given]

All interior angles of the triangle BCD are congruent, so the triangle BCD is an equilateral triangle and all sides of the triangle area equal.

[tex]BC=CD=BD[/tex]

[tex]BC=CD=8[/tex]      [Using (i)]               ...(ii)

Now, the perimeter of quadrilateral ABCD is:

[tex]Perimeter=AB+BC+CD+AD[/tex]

[tex]Perimeter=11+8+8+8[/tex]

[tex]Perimeter=35[/tex]

Therefore, the perimeter of the quadrilateral ABCD is 35 units.

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Answer:

  (A)  6

Step-by-step explanation:

Divisors of 6 are ...

 1, 2, 3, 6

The sum of all but the last is 1+2+3 = 6.

Then  <<<6>>> = <<6>> = <6> = 6.

_____

Additional comment

Among integers less than 200, only 6 and 28 are solutions to <n> = n.

Answer:

y = -3x-2

Step-by-step explanation:

3y = -9x-6. y = (-9x-6)/3. y = (-9x/3)+(-6/3). y = -3x-2

Answer:

entonces no habria oxigeno

Step-by-step explanation:

Answer:

17x + 2 = 16x+6

17x-16x= 6-2

x=4

Answer:

5.21212121

Step-by-step explanation:

The first thing to keep in mind is that a line is equal to 180. The first thing you sould start off by doing is write 17x+2+16x+6. Then to make it easier combine the like terms. Both combine 17x + 16x to get 33x, and 6 and 2 to get 8. Now the problem should be 33x + 8 = 180. Next we will take away 8 from both sides. This should eliminate 8 for us and give us 33x=180 as our next problem. Finally you will do the opposite of multiplying which is diving. 33 divided by itself gives us 0. So we will divide 172 by 33 to get 5.21212121.

YOU MAY PLUG THIS NUMBER BACK IN TO CHECK YOUR ANSWER.

Answer:

f(x)=2x³+4x²+5

Step-by-step explanation:

1) the rule of the even function is: f(-x)=f(x)

the rule of the odd function is: f(-x)=-f(x);

2) the function f(x)=2x³+4x²+5 is neither even or odd according to the rules above:

f(-x)= -2x³+4x²+5= -(2x³-4x²-5).

Answer:

4

Step-by-step explanation:

21 - 4 × ❒ = 5

-4x = 5 - 21

-4x = 16 (divide both sides)

x = 4

Answer:

hi, it's b because a+b is 180°

Answer:

you first use the coefficients of the letters to times each equation.

Then you either subtract or divide to eliminate the first letter and it coeeffient.

then whatever you get you will divide it with the one with no letter.

then you substitute the answer for the letter in any of the equation.

then you solve it.

I hope this is helpful.

Answer:

The answer is in the picture.

15cm²

Answer:

ok so we know the amount we know the interest amount but we do know know the period of time so the equation would look like this

28000(0.4)T=I

T=Time

I=interest

Answer:

The answer is D-27.00 because you are rounding off to the nearest 100 I hope this helps you

Answer:

C. 26.75

Step-by-step explanation:

26.745 is rounded to 26.75

Answer:

40%

Step-by-step explanation:

Because you want to know the total percent the price increased so you add the amounts. 30% plus 10% makes 40%

Answer:

x = 20

Step-by-step explanation:

90° - 76° = 14°

[tex](x-6)=14[/tex]

[tex](x+6)=+6[/tex]         Add 6 to both sides

   x      =   20

Hence, x = 20

Answer: X=20

Right angles are 90 degrees and 90-76=14... X-6=14... add 6 to 14 and get 20. X=20. Don't quote me on it I haven't done this stuff in a year.

12? im not sure

i think u need to multiply 6 and 2 to get your answer.

Answer:

The correct answer is:304

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

100/5=20

Answer:

[tex]3 \sqrt{2} [/tex]

Step-by-step explanation:

Given

[tex] \frac{ \sin(60) \sec(60) \cot(30) }{ \cos( 45) ) } [/tex]

Using the unit circle, we know that

[tex] \sin(60) = \frac{ \sqrt{3} }{2} [/tex]

[tex] \cos(45) = \frac{ \sqrt{2} }{2} [/tex]

We can find sec and cot by using reciprocal identies.

[tex] \sec(x) = \frac{1}{ \cos(x) } [/tex]

[tex] \cos(60) = \frac{1}{2} [/tex]

So

[tex] \sec(60) = 2[/tex]

[tex] cot(x) = \frac{1}{ \tan(x) } [/tex]

[tex] \tan(30) = \frac{1}{ \sqrt{3} } [/tex]

so

[tex] \cot(30) = \sqrt{3} [/tex]

Plug in the values.

[tex] \frac{ \frac{ \sqrt{3} }{2} \times 2 \times \sqrt{3} }{ \frac{ \sqrt{2} }{2} } [/tex]

[tex] \frac{ \frac{ \sqrt{3} }{2} \times \frac{ \sqrt{12} }{1} }{ \frac{ \sqrt{2} }{2} } [/tex]

[tex] \frac{3}{ \frac{ \sqrt{2} }{2} } [/tex]

[tex]3 \sqrt{2} [/tex]

Answer:

[tex]g(t) = 0[/tex]

Step-by-step explanation:

Given

[tex]d = 1000m[/tex]

[tex]f(t) \to[/tex] Tortoise

[tex]g(t) \to[/tex] Hare

Required

Time needed by the Hare to complete the race

The function [tex]g(t)[/tex] implies that the Hare is t seconds from completing the race.

When g(t) = 0, it means that the Hare has completed the race

So, to calculate the time needed by the Hare;

We simply equate g(t) to 0, then solve for t

Answer:

56 degrees

Step-by-step explanation:

We know, the sum of the three angles of any triangle is equal to 180 degrees.

63 + 61 = 124

Now, 180 - 124 = 56 degrees

Hope this will help. Please give me brainliest.

Answer:

hygu

Step-by-step explanation:

yg9k

Answer:

The joint probability of the two events is one.

Step-by-step explanation:

Complementary events:

If two events are complimentary, these three following things are true:

They are dependent.

The intersection of them is zero.

The joint probability of the two events is one.

The last one is the correct choice.

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Answer:

  4) 95.7 m

Step-by-step explanation:

The angle at the cliff base between Alan and Keith is ...

  B = 180° -29° -48° = 103°

The law of sines will tell you the distance KB from Keith to the cliff base is

  KB/sin(A) = KA/sin(B)

  KB = KA×sin(A)/sin(B) = (70 m)sin(29°)/sin(103°) ≈ 34.82935 m

The height of the cliff is found from the tangent relation ...

  Tan = Opposite/Adjacent

  tan(70°) = height/(34.83 m)

  height = (34.83 m)tan(70°) = 95.693 m

The height of the cliff is about 95.7 m.

_____

Additional comment

These problems can usually be resolved into two 2-D problems. Here, we can work out the distance we need from Keith to the cliff by considering only the ground plan of the site. Then we can work out the height of the cliff only considering the vertical plane containing Keith and the base of the cliff.

The attachment shows the ground plan triangle KAB.