Starting from rest, a ball of mass 2 kg is accelerated at 4 m/s^2 for 3 s. What is the final kinetic energy (in J) of the ball after 3 s?

Answers

Answer 1

Answer:

144 joules

Explanation:

v=initial velocity+(acceleration × time)

v=0+(4×3)

v=12m/s

k.e =0.5 × mass × velocity^2

=0.5 × 2 × 12^2

=1 × 144

=144 joules


Related Questions

xác định quỹ của chất điểm chuyển động với phương trình chuyển động sau đây

Answers

Answer:

pls English

Explanation:

plsss,ಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠ

The gravitational field strength on earth is 10n/kg. find the weight of an object of mass 25kg​

Answers

Answer:

250N

Explanation:

weight = Mass(in kg) × Gravitational field strength

25 × 10 = 250N

Answer:

250 N

Explanation:

Refer the attachment for explanation.

You throw a ball upward with an initial speed of 3.0 m/s from an initial height of 1.5 m. After you throw the ball, its acceleration is 9.81 m/s downward. Taking upward to be the positive direction, write the position-time equation for the ball's motion​

Answers

Answer: An object undergoing a constant acceleration can have its motions be described by the kinematic equations. These equations relate the position of the particle, its velocity, acceleration, and time.

Explanation:

Answer:

vf^2=vo^2+2ay(y1-y0)

Explanation:

An object if mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.​

Answers

Hi there!

On the object, we know that there are two forces working on the object:

-Force due to gravity (Mg)

-Force due to air resistance

Let the positive direction of the force be downwards (direction of the acceleration)

We can write the summation of forces as:

∑F = Mg - Fa

Plug in values. Let g ≈ 10 m/s²

∑F = 30(10) - 50 = 250N

Find the acceleration using the formula:

∑F = m · a

∑F/m = a

Plug in values:

250/30 = 8.33 m/s²

What happens if the incident beam is perpendicular to the surface (at an angle of 90 degrees)?

Answers

If the ray is perpendicular to the surface, then the incident ray, the reflected ray and the transmitted (refracted) ray all lie along the same line (i.e they are collinear). If the ray is not perpendicular to the surface, then the ray appears to be bent at the surface.

Can air make shadows?

Answers

Answer:

Yes, air can indeed make shadows. A shadow occurs when an object in a light beam prevents some of the light from continuing on in the forward direction. When the light beam hits a wall or the ground, a darker shape is visible where less light is hitting the surface. Refraction is responsible.

Explanation:

Here is a clip of an example of air making a shadow

https://www.seeker.com/stories/air-shadows/

The pressure of liquid varies as per it's depth.

Answers

Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.

Explanation:

momentum is conserved it can be transferred but not lost. true or false​

Answers

Answer: False

explanation: because Total momentum is conserved only if the collision can be considered isolated from the influence of net external forces

The U.S. uses a household voltage of 110 V. However, electric stoves and dryers are wired with
220 V lines. Which would cause less damage --plugging a 110 V-rated curling iron into a 220 V
outlet, or a German-made 220 V-rated curling iron into a 110 V outlet? Explain. (Note: 110 and
220 V outlets are made in different shapes so that appliances cannot be accidentally
interchanged.)

Answers

Answer:

In the United States and neighboring countries, however, household outlets run at 110 or 120 volts. This can pose a serious problem for travelers. Connecting a 220-volt appliance to a 110-volt outlet can damage or destroy the appliance

I NEED HELP PLZZZZZZ

Answers

Mostly GPE and a little KE since the ball is high up (GPE) and it's also moving (KE) but not as much as it had when you first threw it

Reflect on your new experiences, what made you uncomfortable and what encouraged you. Did you learn anything new about yourself on the trip? Traveling can help you improve. Think about your journey and if it helped you grow in any way.​

Answers

Answer:

keke

Explanation:

If a ball is kicked horizontally off of a building at 8.0 m/s, what is the horizontal velocity (vx) after 3
seconds?

Answers

The characteristics of the projectile launch allows to find the result for the velocity on the x axis is:

In the horizontal axis there is no acceleration and therefore the speed must be kept constant. The horizontal speed is  vₓ = 8.0 m / s

In projectile launching we have an application of kinematics to motion in two dimensions near the surface of the Earth.

In this case, on the vertical axis we have an acceleration directed towards the center of the planet and called the gravity acceleration.

In the horizontal axis or x axis there is not acceleration, except in special cases that we tone is how much the resistance of the air.

Consequently in the horizontal axis there is no acceleration and therefore the speed must be kept constant, the result for the horizontal speed is:

           vₓ = 8.0 m / s

Learn more here: brainly.com/question/17228361

Agents of socialization?

Answers

Answer:

agents of socialization are:-

family

peers

school

mass media

Agents of socialization include the family, religion, peer groups, economic systems, legal systems, panel systems, language and the media

is this kinetic energy ---> elastic potential energy OR elastic potential energy ---> kinetic energy ??​

Answers

Answer:

it is potential energy ---- kinetic energy

Weight refers to the pull of _________ on an object.

Question 2 options:

mass


gravity


volume

Answers

Answer: Weight refers to the force of gravity acting upon an object.

(Answer B)

the answer is b gravity

100k points pls solve asap or no points

Answers

Answer:

Explanation:

You have given us a very weird question. Things do not mesh

If the mass is 500 kg and sits 25 m above the lowest spot on the track, the potential energy is

PE  = mgh = 500(9.8)(25) = 122500 Joules,

not the reported 61250 Joules

So either the Joules is incorrect or the mass is supposed to be 250 kg.

In either case, in the absence of friction, the potential energy will convert to kinetic energy.

½mv² = mgh

     v = √2gh

which does not involve the use of either Joules or kilograms.

Maximum velocity when starting from rest is

v = √(2(9.8)25) = √490 = 22.135943...

v = 22 m/s

SI units are used for scientific works. Why? ​

Answers

Answer:

SI units are used for scientific works to bring uniformity in measurements all over the world.

CEK- 9. If the speed of sound at 0° C is vo, the velocity at 273° C will be (a) 2 vo (b) 0.5 vo b (c) (d) 0.7 vo 1.4 vo​

Answers

Answer:

D

Explanation:

273 * 0.6=163.8

vo≈331

A box of mass 20kg rests on a flat horizontal floor. if the density of air is negligible. Draw a diagram showing forces acting on the box​

Answers

Hey
There are only two forces acting on the box!!!
Here it is, hope it helps!

Your new motorcycle weighs 2580 N.
The acceleration of gravity is 9.8 m/s2.
What is its mass?
Answer in units of kg.

Answers

Answer:

answer to your question is 263.26kg

Explanation:

m=f÷a ,m=2580÷9.8=263.26kg

PLEASE HELP
A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land

Answers

Answer:

Explanation:

It is hard to imaging that wind resistance is not a factor for such a low mass ball, but we must make that assumption on the first estimate.

s = s₀ + v₀t + ½at²

vertical analysis with floor level as origin

0 = 1.2 + 5t + ½(-9.8)t²

0 = 1.2 + 5t - 4.9t²

quadratic formula positive answer

t = (-5 - √(5² - 4(-4.9)(1.2))) / (2(-4.9))

t = 1.22 s is the flight time

horizontal analysis with launcher as origin

s = 0 + 12(1.22) + ½(0)1.22²

s = 14.6517... 15 m

A 0.038-kg bullet enters a 3.2-kg watermelon and embeds itself in the melon. The melon is immediately set into motion with a speed of 3.82 m/s. The bullet remains lodged inside the melon. What was the entry speed of the bullet (m/s)?

Answers

Hi there!

This is an example of a perfectly inelastic collection, so:

mb = mass of bullet

vb = velocity of bullet

mw = mass of watermelon

v = velocity final

mbvb = (mb + mw)v

Rearrange to solve for the velocity of the bullet:

vb = (mb + mw)v/mb

Plug in values:

vb = (0.038 + 3.2)(3.82)/(0.038) = 325.504 m/s

the electric field at point 4.00 cm from the axis, measured radially outward from the midpoint of the shell.

Answers

the answer is 825.7 m/s.

A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel itself sharply upward. Its acceleration steadily decreases as it leaves the water because less of its body and fewer of its fins are in contact with the water.

With what speed does the fish leave the water?
What height above the water does it reach?

Answers

Answer:

Explanation:

Velocity will be equal to the area under the curve of the acceleration-time plot.

v = ½(45)(0.075) = 1.6875

v = 1.7 m/s

h = (0² - 1.6875²) / (2(-9.8)) =  0.145288...

h = 15 cm

Questions

Q1. In this lab the centripetal force is provided by
a) the person’s hand
b) the tube
c) the hanging weight
d) the spinning motion

Q2. If the mass of the stopper were doubled but other things remained the same, the hanging mass would need to be
a) doubled
b) halved
c) tripled
d) quadrupled

Q3. If the velocity of the stopper were doubled, but other things remained the same, the hanging mass would need to be
a) doubled
b) halved
c) tripled
d) quadrupled

Answers

Answer:

just doing your module wag asa brainly ok malaki kna

If a car accelerates from rest at a constant of rate of 5.5m/s^2 north, how long will it take for the car to reach a velocity of 28 m/s north?

Answers

Answer:

Explanation:

vo= 0

a=5.5m/s^2

v= 28 m/s

t=?

v=vo+at

at=v-vo

t=(v-vo)/a

t=28/5.5

t=5.09 seconds

A 10 g dime and a 200 g gold coin are dropped from the Empire State Building in

New York at the same time.; if there is no air resistance which hits the ground first?

A.They both hit the ground at the same time

B.Which hits first depends on the weather & temperature of the air.

C.The 200 g gold coin hits the ground first

D.The 10 g dime hits the ground first

Answers

Answer:

Explanation:

The both hit the ground at the same time. There is no air resistance and that includes the factors brought up in B.

C and D are both eliminated. If you dropped an 800 kg honda Fit it would hit the ground at the same time as the two coins. When you look at the formulas used to derive time, they look like

d = vi * t + 1/2 a* t^2

vi = 0

the distance to fell is the same for all three masses.

a is the same for all 3 masses.

So when you solve for t, there is no mention of the mass of the object falling. Therefore t is dependent only on the height.

Which of the following is not an aspect of instincts?

Answers

There’s nothing there dude? What

Which of the following types of energy would cause one piece
of metal to be attracted to another?
a heat
b nuclear
c light
d magnetic

Answers

Magnetic is the best and only answer

Consider three properties of the net force on an object: a magnitude, direction, and angle with respect to the objects path. For the following situation select the choice that indicates wether these quantities are constant or changing during the course of the motion.

1. The magnitude and the angle of the net force with respect to path are constant, but the direction is changing

2. The direction and the angle of the net force with respect to path are constant, but the magnitude is changing.

3. The magnitude and direction of the net force are changing, but the angle of the net force with respect to path is constant.

4. The magnitude, direction, and angle with respect to path for the net force are constant.

5. The magnitude and direction of the net force are constant, but the angle of the net force with respect to path is changing.

Answers

Answer:

Explanation:

yeah i dont know i need the answer too

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