Star Spectra Gizmo Unusual stars Observe the spectra of...
Star Spectra Gizmo Unusual stars
Observe the spectra of stars 5- 10. Identify the elements in each spectrum, and try to classify each star. If you notice unusual features in these spectra, describe them
Match : Write the number of the star or object that matches each description. Then use this information to help you identify the elements and reclassify the stars in the table above.
____ High atmospheric pressures in a star cause spectral lines to be broadened, or "smeared out." Giant stars , which have relatively low atmospheric pressures, are characterized by narrow spectral lines.
____ If a star is moving away from an observer, spectral lines are redshifted , or shifted toward the red end of the spectrum. An approaching star is blueshifted
____A star orbited by a large planet will move in a small circle. This will cause its spectrum to be slightly redshifted part of the time and blueshift ed at other times.
____Binary stars are pairs of stars that orbit one another. Their presence is indicated by two spectra that shift in opposite directions.
____ Cepheid variable stars change their brightness in a regular cycle. Gas pressure builds up, causing the stars to expand quickly. When the pressure is released, the star contracts, and the intensity of some spectral lines may decrease.
____A nebula is an enormous cloud of gas and dust in which stars are born. Most nebulae produce an emission spectrum which is characterized by bright lines of color against a dark background. The bright lines in an emission spectrum correspond to the dark lines in an absorption spectrum.

The maximum speed around a level curve is 30. 0 km/h. What is the maximum speed around a curve with twice the radius is 42.4 km/h.

Meaning of the maximum speed curve:

You might travel at a maximum speed of around 1.4 times as fast on a curve with a radius of 60 meters (twice as much), according to the equation, which also states that your maximum speed is proportional to the square root of the curve's radius.

According to that,

30 km/hr is the maximum speed.

New radius equals 2 r

In all scenarios, the centripetal force will be the same.

Calculating the new top speed around a curve is necessary.

Using the centripetal force formula:

[tex]\frac{mv^{2} }{r} = \frac{mv^{2}}{r}[/tex]

Fill out the formula with the value

[tex]\frac{v^{2} }{2r} = \frac{30^{2} }{2r}[/tex]

[tex]v= 30\sqrt{2} \ Km/h[/tex]

The maximum speed around a curve is therefore 42.4 km/h.

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A diffraction pattern involving parallel rays is called (c) Fraunhofer diffraction.

Because of the far-field location of observation and the increasingly planar nature of the outgoing diffracted waves passing through the aperture, Fraunhofer diffraction is a type of wave diffraction that takes place when field waves are passed through an aperture or slit. This only results in a change in the size of the observed aperture image.

The parallel rays approximation can be used to view it at distances beyond the near-field distance of Fresnel diffraction, which modifies the size and form of the observed aperture image. This only happens when the Fresnel number at these distances.

Fraunhofer diffraction, which is typically explained through the use of observational experiments utilizing lenses to intentionally diffract light, is based on the notion that a wave is split into many outgoing waves when passing through an aperture, slit, or hole. When waves pass through, they are split into two diffracted waves that move at right angles to one another and the remaining incoming wave. These waves are frequently used in observational techniques by placing a screen in their path so that the image-pattern observed can be seen.

Fraunhofer's diffraction equation:

= (See Diffraction - Single-slit diffraction):

= I (θ) = I 0 (sin (d π λ sin θ) d π λ sin θ) 2

where,

d is the slit width, λ is the wavelength, and θ is the observed angle.

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Answer:

[tex]60^{\circ}[/tex] (assuming that air resistance is negligible.)

Explanation:

Let [tex]g[/tex] denote the gravitational field strength. If air resistance on the projectile is negligible:

Let [tex]\theta[/tex] denote the angle at which the projectile is launched. Let [tex]v[/tex] denote the initial velocity of the projectile:

Also because air resistance is negligible, vertical velocity of the projectile will be [tex]v_{y} = (-u_{y}) = (-v\, \sin(\theta))[/tex] right before the projectile lands. In other words, while the projectile was in the air, the change in vertical velocity would be [tex](-v\, \sin(\theta)) - (v\, \sin(\theta)) = (-2\, v\, \sin(\theta))[/tex].

Divide the change in velocity by acceleration to find the duration of the flight:

[tex]\begin{aligned}t &= \frac{v_{y} - u_{y}}{a_{y}} \\ &= \frac{(-v\, \sin(\theta)) - (v\, \sin(\theta))}{(-g)} \\ &= \frac{(-2\, v\, \sin(\theta))}{(-g)} \\ &= \frac{2\, v\, \sin(\theta)}{g}\end{aligned}[/tex].

Range measures the horizontal distance that this projectile has travelled. At a constant horizontal velocity of [tex]u_{x} = v\, \cos(\theta)[/tex], this projectile would travel a distance of:

[tex]\begin{aligned}(\text{range}) &= u_{x}\, t \\ &= (v\, \cos(\theta))\left(\frac{2\, v\, \sin(\theta)}{g}\right) \\ &= \frac{2\, v^{2}\, \sin(\theta)\, \cos(\theta)}{g}\end{aligned}[/tex].

Apply the double angle identity [tex]2\, \sin(\theta) \, \cos(\theta) = \sin(2\, \theta)[/tex] to further simplify this expression:

[tex]\begin{aligned}(\text{range}) &= \cdots \\ &= \frac{2\, v^{2}\, \sin(\theta)\, \cos(\theta)}{g} \\ &= \frac{v^{2}\, (2\, \sin(\theta)\, \cos(\theta))}{g} \\ &= \frac{v^{2}\, \sin(2\, \theta)}{g}\end{aligned}[/tex].

Note that in this question, [tex]v^{2}[/tex] and [tex]g[/tex] are both constant. Hence, for another angle of elevation [tex]\hat{\theta}[/tex], the range of the projectile will be the same as long as [tex]\sin(2\, \hat{\theta}) = \sin(2\, \theta)[/tex].

[tex]\sin(2\, \hat{\theta}) = \sin(2\, (30^{\circ}))[/tex].

Since [tex]0^{\circ} \le \hat{\theta} \le 90^{\circ}[/tex], [tex]0^{\circ} \le 2\, \hat{\theta} \le 180^{\circ}[/tex]:

[tex]\sin(2\, \hat{\theta}) = \sin(180^{\circ} - 2\, \hat{\theta}) = \sin(2\, (90^{\circ} - \hat{\theta}))[/tex].

Therefore, [tex]\hat{\theta} = 90^{\circ} - \theta = 90^{\circ} - 30^{\circ} = 60^{\circ}[/tex] will ensure that [tex]\sin(2\, \hat{\theta}) = \sin(2\, \theta)[/tex]. Launching the projectile at [tex]60^{\circ}[/tex] will reach the same range.

[tex]\begin{aligned}(\text{new range}) &= \frac{v^{2}\, \sin(2\, (60^{\circ}))}{g} \\ &= \frac{v^{2}\, \sin(2\, (30^{\circ}))}{g} = (\text{original range})\end{aligned}[/tex].

An experimental tool known as an air track enables the investigation of motion with the least amount of frictional disturbance. It is made out of a track with several tiny holes through which air is constantly blown.

A scientific tool called an air track is used to investigate motion in a low-friction setting. Its name is derived from the way it is built: air is pumped through a hollow track with tiny holes spaced out along the track to allow specially designed air track cars to float along with little resistance.

It will be required to level the air-track as carefully as possible in order to examine motion with constant velocity.

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The subscript 2 in [tex]Br_2[/tex] indicates that two atoms of bromine are joined together.

[tex]Br_2[/tex], which is a bromine compound, is formed by the combination of two bromine atoms.

At normal temperature and pressure, the original colour of Bromine ([tex]Br_2[/tex]) is a red-brown liquid.

When there is a subscript "2," it signifies that a molecule is made up of two Bromine atoms.

We never use subscripts of "1" while writing the chemical formula, since they are only used when more than one atom is being represented.

When referring to a diatomic molecule, we use the element's symbol and add the subscript "2" to denote the bond between two of that element's atoms.

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The propagated percent error in the time constant of a circuit is ±10% using these two circuit elements in series with a d. c. power supply.

The discrepancy between the measured and actual values might be used to define an error.

The fourth band of a resistor color code is gold means ± 5% tolerance in measurement of resistor.

The fourth letter on a capacitor's code is j means ± 5% tolerance in measurement of capacitor.

Now,  the time constant of a RC circuit = CR.

Hence, the propagated percent error in the time constant of a circuit using these resistor and capacitor =  ± 5%  + (± 5%)

= ±10%.

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Its consequences, either rewarding the desired behavior or punishing the undesired behavior. It is based on the idea that behavior is a function of its consequences. modified by the association of a stimulus with a previously neutral stimulus. It is based on the idea that behavior is a function of its antecedents.

Operant conditioning is a type of learning in which an individual's behavior is modified by its consequences. It is based on the idea that behavior is a function of its consequences, either rewarding the desired behavior or punishing the undesired behavior in order to shape behavior. Classical conditioning is a type of learning in which an individual's behavior is modified by the association of a previously neutral stimulus with a particular stimulus. It is based on the idea that behavior is a function of its antecedents. In operant conditioning, the response is voluntary, while in classical conditioning, the response is involuntary. Operant conditioning focuses on how behavior is strengthened or weakened in response to reinforcement or punishment, while classical conditioning focuses on how behavior is acquired through association.

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The primary global sources for carbon dioxide emissions are electricity and heating (31%) as well as farming (11%), transportation (15%), forestry (6%) and manufacturing (12%).

These sources can be found primarily in three different contexts: industrial processes, natural gas processing, and fuel combustion activities.By far, burning fossil fuels causes carbon to oxidize, which is what causes the biggest CO2 emissions.

The combustion of fossil fuels including gas, coal, and oil, deforestation, and volcanic eruptions are a few examples of carbon sources.

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Robot Mass stays the same. Anywhere in the universe, an object has the same mass as it has on Earth. Gravity affects an object's weight. The identical object weighs less on the moon than it does on Earth because there is less gravity there.

The mass and size of the moon also impact its gravitational pull. The moon won't draw things toward itself with the same force as the Earth because it has a lot less mass than the latter.

Therefore, This implies that even if robot mass remains the same, you would weigh less if you traveled to the moon.

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Inductance is 42.0 mh, capacitance is c, and resistance is r in the part h a l - r - c series circuit. The angular frequency of oscillation without the resistor is 624 rad/s. The angular frequency with the resistor is 208 rad/s.

The difference between frequency and angular frequency (measured in radians per second) is twofold (measured in cycles per second, commonly known as Hz). Instead of the letter f, the sign stands in for frequency. a sphere with an axis around which it spins. The points farther from the axis are fulfilling and moving more quickly = v / r.

inductance (L) = 42 mH

                = 42 × 10⁻³ H

Angular frequency (ω) = 620 rad/sec

without the resistor, the angular frequency of oscillation is,

ω = 1/ √LC

or,  1/√LC = 620 rad/sec

or, 1/LC =  (620)²

or, C = 1 / (620)²× (42 × 10⁻³)

or, C = 6.19 × 10⁻⁵ F

With resistor, ω = 208 rad/sec

or, ω = R/L

or, R = ωL

or, R = (42 × 10⁻³) × (208)

or, R = 8.736 Ω.

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Question:

An L-R-C series circuit has inductance 42.0 mH, capacitance C, and resistance R. Without the resistor, the angular frequency of oscillation is 624 rad/s. With the resistor, the angular frequency is 208 rad/s.

Find the value of C.

Find the value of R.

Answer:

S = 1/2 g t^2        time for stone to fall distance S

S = V0 (t - 2) * 1/2 g (t -2)^2     time for stone to fall distance S with an initial speed of 30 m/s, 2 seconds later

1/2 g t^2 = V0 t - 2 V0 + 1/2 g t^2 - 2 g t + 2 g     equating distance fallen

t = 3.88 sec

Check:

S = 1/2 * 9.8 * 3.88^2 = 73.8 m

S = 30 * 1.88 + 1/2 * 9.8 * 1.88^2 = 73.7 m

The total number of subjects or observations in the sample is denoted by the letter "n."

The collection of all natural numbers is known as N. Positive, non-zero whole numbers make up the natural numbers. N = 1 , 2 , 3 , 4 , .

The letter "n" represents the word "number." By changing the term number's value, we can create a sequence utilizing the nth term ( n ). Following the sequence's formula, we would substitute 10 for "n" to obtain the 10th term; similarly, we would substitute 50 for "n" to discover the 50th term.

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They are: radio waves, microwaves, ir, visible, ultraviolet, x-rays, and gamma rays.

The following list of the seven electromagnetic waves is organized by decreasing wavelength & increasing frequency and energy:X-rays, gamma rays, UV rays, visible light, radio waves, microwaves, and infrared waves.

Typically, electromagnetic radiation is divided in radio wave, microwave, ir, visible light, ultraviolet, X-rays, and gamma rays categories based on its wavelength.

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The dispersion of white light into its various colors is referred to as dispersion. Due to the medium's refraction property, each wavelength moves through the medium at a different pace, producing this property.

Dispersion is the name for the process through which visible light separates into its individual colors.

We have seen that when white light is transmitted through a glass prism, it is scattered into the spectrum of colors that make up white light. Therefore, we can observe that the phenomena of light separating into its individual hues is called dispersion of light.

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Your electric utility company sends you a monthly bill informing you of the number of kilowatt- hours you have used that month therefore the utility is charging you for energy.

This is referred to as a type of service such as light, power etc which are  provided by a public utility.

Electricity utility send us a monthly bill of the number of unit consumed by our appliance per month and the amount you owe is derived by multiplying your utility's rate per kWh by the total kWhs you used that month. It is also how much energy is used over a certain time period which is therefore the reason why energy was chosen as the correct choice.

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An existing, correctly designated source document that has been extracted, rephrased, restated, and/or generated in a new form for inclusion in another document counts as a second permitted source for derivative classification.

the OCA rollover Classification Authority at Origin a person appointed in writing to classify material in the first instance by the President, the Vice-President, agency heads, or other president-designated officials.

The classification authority block, or CAB, indicates who has power over and how long the classification determination will last. It identifies the person who classified the document, what it was generated from, what it was downgraded to (if applicable), and the date it was declassified.

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As per the given statement  the s2 term in the acceleration (5 m/s2) and the s term in the time (7 s) cancel leaving you with 35 m/s (velocity).

Velocity is the rate of change of speed per unit time. It also determines the direction of the movement of object or moving body. hence, it is called as directional speed.

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Answer:

Explanation:

To find the increase in total internal energy, we first need to find the kinetic energy of the sledgehammer before it hits the spike. We can use the formula:

KE = (1/2) * m * v^2

where KE is the kinetic energy, m is the mass, and v is the velocity.

Plugging in the values, we get:

KE = (1/2) * 2.50 kg * (65 m/s)^2

KE = (1/2) * 2.50 kg * 4225 m^2/s^2

KE = 5212.5 J

Next, we need to find the amount of energy that is converted to internal energy. Since one third of the kinetic energy is converted to internal energy, we can multiply the kinetic energy by 1/3 to find this value:

E = 1/3 * 5212.5 J

E = 1737.5 J

Finally, we need to find the total internal energy increase by adding the energy converted to internal energy to the initial internal energy of the hammer and spike. Since the initial internal energy is zero, the total internal energy increase is simply the energy converted to internal energy:

Total internal energy increase = 1737.5 J

Therefore, the total internal energy increases by 1737.5 J when the sledgehammer hits the spike.

The length of the minute hand of a wall clock is not relevant to finding the distance traveled by the end of the pointer in a given amount of time. The only important factors are the length of the hour hand and the amount of time that has passed.

If the length of the hour hand is X cm, then the distance traveled by the end of the pointer in 2 hours can be calculated as follows:

Distance traveled = (X * π * 2) cm

Here, π is the mathematical constant approximately equal to 3.14. The factor of 2 in the formula represents the number of hours that have passed. Therefore, to find the distance traveled in 2 hours, you would need to know the length of the hour hand and substitute it for X in the formula above.

According to the law of conservation of mass, the total mass of reactants and products in a chemical reaction is equal.

In a chemical process, the total mass of the reactants will be much smaller than the total mass of the products. A. Sodium metal and chlorine gas combine to generate sodium chloride in the chemical reaction shown below. will be 100 grammes exactly.

Chlorine gas and sodium metal combine to form sodium chloride (table salt) The mass of sodium chloride generated when the reaction is finished will be exactly 100 grammes if the combined mass of the reactants is 50 grammes.

A sodium cation (Na+) and a chloride anion are created when a sodium atom transfers an electron to a chlorine atom.

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If we are going to invent a new device that people can use instead of a microwave oven to warm up leftovers, the type of electromagnetic wave that would be most useful to investigate would probably be infrared waves.

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field.

Since electromagnetic waves are of different energy range and different electromagnetic waves are used for different works.

Higher energy range electromagnetic waves cannot be used to expose for human because they can cause damage to them. So, we can not use them for warming purpose as they are dangerous. So X rays and Gamma rays can not be used

And least energy waves can also not be used. So, radio waves which are least energy cannot be used for the purpose of warming.

So correct answer for the replacement of microwaves is infrared waves because they have sufficient energy that can be used to warm up.

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An engine can be cool down by the below steps

Knowing how to cool an overheated engine is a significant expertise for any authorized driver. Having the option to analyze and fix your own issues can get you back out and about rapidly, forestall exorbitant mechanical issues, and assist you with realizing when to look for proficient assistance.

Steps which I can take to cool down an overheated engine of car:

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You may get approximate numerical values for each of a polynomial equation's roots with NSolve. NSolve can be used to solve groups of concurrent equations. Mathematica's numerical mathematics (Mathematica Tutorial)

Equation, "Variable = initial value," NSolve identifies numerically all possible answers to the given equation for the provided unknown variable and its initial value.

To solve an equation or group of equations algebraically, use the function solve. Although it is sometimes preferable to have a numerical solution, it is not always possible to solve an equation algebraically. In either scenario, a group of equations or an individual equation can be solved numerically using NSolve.

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A suspension scaffold that uses a two point swing stage anchorage is preferably accessed from the ground or from a rooftop, and then either raised or lowered to its working location.

A two point adjustable suspension scaffold is sometimes referred to as a swing-stage scaffold and it is considered as the most common type of suspended scaffold.

Additionally, a two point adjustable suspension scaffold is designed and developed to be hung by cables (ropes) that are connected to stirrups at each end of the swing-stage scaffold platform, in order to enable the access of high-rise constructions and buildings.

According to the occupational safety and health administration (OSHA), a two point adjustable suspension scaffold can be accessed through the use of a ladder. However, the most preferred method of access is from the ground or from a rooftop, and then the scaffold should be either raised or lowered to its working location.

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Scope 3  Purchased goods and services, capital goods, fuel- and power activities, transportation and distribution, waste produced throughout operations, business trips, employee commuting, leased assets, processing of sold goods, use of sold goods, end-of-life treatment of sold goods, franchises, and investments are just a few of the three emission categories.

twenty groups Although not all businesses would fit into every category, the GHG Protocol defines 15 classifications for scope 3 emission. Upstream and downstream of a organization's operations are both considered sources of emissions within Scope 3.

Explained: emission types 1, 2, and 3.The primary GHG Protocol business standard divides a firm's greenhouse gas emissions into three categories. While reporting for scopes 1 and 2 is required, monitoring for scope 3 is optional and more difficult.

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Answer:

Below

Explanation:

F = m * a

8.2 N = 11.5 kg  * a

a = .71 m/s^2

The ripe fruits is around the same size as the colored part of the thumb are grape and cherry. Hence, option (C) is correct.

Fruit is a blooming plant's fleshy or dry, fully developed ovary that contains a seed or seeds. As a result, apricots, bananas, and grapes are all considered to be fruits as well as bean pods, maize grains, tomatoes, cucumbers, and (in their shells) acorns and almonds. However, the term is typically only used to describe matured ovaries that are delicious and either pulpy or succulent.

A developed ovary and its related elements constitute a fruit in terms of botany. It often contains seeds that have grown from the encased ovule after fertilization, though parthenocarpy, or growth without fertilization, is also known.

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A-36 steel is used to construct the w10x15 cantilevered beam, which is put under the indicated loading.

Moment of inertia for w10×15 is equal to 68.9in4 and Young's modulus for A–36 steel is equal to 29e3 ksi. Thus Slope at B can be given as,

θB = P₂x³/ (2EI) + P₁l³/ (2EI)

θB = (5 × 6³ + 9 × 12³)/ (2 × 29 × 10³ × 68.9)

θB = 0.0042rad

Therefore , displacement at B can be written as,

yB = P₂x³(3l - x)/ (6EI) + P₁l³(3l - l)/ (6EI)

yB = ( 5 × 6³ × (3 × 12 - 6) + 9 × 12³ × 2 × 12)/ (6 × 29 × 10³ × 68.9)

yB = 0.034ft

The given question is incomplete,

The W10×15 cantilevered beam is made of A-36 steel and is subjected to the loading shown. Suppose that w = 2.7 kip/ft .E = 29 (103) ksi and I = 68.9 in4. (Figure 1) Determine the slope of the beam B, measured counterclockwise from the positive x axis. Determine the displacement of the beam at B.

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A downward force is applied by the ladybug to the wall in order to advance up the wall, and a vertical force is applied by the wall to the ladybug.

The definition of force is the power or fuel applied to an item during any positive exercise or movement. A pressure or pull that results from two objects interacting is called a force. External force doesn't actually exist until two objects interact.

Forces are important because they produce changes to motion, as we learned in a prior lesson. Isaac Newton actually cites this in his first law. This inertia concept describes the phases of stillness and motion that occur in the absence of an external, opposing force.

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The cutoff frequency formula is 1 / (2 * pi * R * C).

What do you mean by cutoff frequency of a device?

The cutoff frequency of a device or system is the frequency at which its response starts to fall off sharply. It is the frequency above which the device or system does not pass or amplify signals effectively.

The cutoff frequency of a device or system can be calculated using the following formula:

cutoff frequency = 1 / (2 * pi * R * C)

where R is the resistance of the device or system, and C is the capacitance of the device or system.

The cutoff frequency is often used to describe the performance of electronic filters, such as low-pass filters, high-pass filters, and band-pass filters. It is also used to describe the performance of other types of systems, such as microphones and speakers.

Therefore, the cutoff frequency is formula is  1 / (2 * pi * R * C).

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