Answer:
Hypothesis, Prediction, Experiment, Analyze Data, and Draw a Conclusion.
Explanation:
How many millimeters are there in 5.12 x 10^5
kilometers? (1000 millimeters = 1 meter, 1000
meters - 1 kilometer) (Use 3 sig figs in your answer.)
Answer:
5.12x10¹¹ millimeters
Explanation:
Milli is a prefix used in science and engineering to decribe the number as the exponent x10⁻³. In the prefix kilo, the number is at the exponent x10³.
5.12x10⁵ kilometers are:
5.12x10⁵ kilometers * (1000m / 1km) = 5.12x10⁸ meters
5.12x10² meters * (1m / 1000millimeters) = 5.12x10¹¹ millimeters
Which part of the scientific cycle does the graph directly represent?
Experiments
Explanations
Questions
Facts
Answer:
Experiments
hope this helps:)
Answer:
experiments
Explanation:
...
A student lists three temperature measurements: 100°F, 100°C, and 100 K. Of the three measurements, 100 K is the highest temperature.a. Trueb. False
Answer:
The answer is False.
Explanation:
To find which is the highest temperature we need to convert the °C and °F units to °C:
[tex] T_{1} = 100 K [/tex]
[tex] T_{2} = 100 ^{\circ} C + 273 = 373 K [/tex]
[tex] T_{3} = \frac{5}{9}*(100 ^{\circ} F - 32) = 37.78 ^{\circ} C [/tex]
[tex] T_{3} = 37.78 ^{\circ} C + 273 = 310.78 K [/tex]
Therefore, the answer is False, since the highest temperature is 100 °C.
I hope it helps you!
Answer:
The answer is False, or ¨F¨.
A student in a chemistry class mixes together two chemicals and observes bubbling and the beaker getting hotter. There was also a dark blue precipitate settling down to the bottom of the beaker. Did a new substance form during the investigation?
Explanation:
Obviously there's an exothermic reaction going on, which suggests a neutralisation reaction. A dark blue precipitate is formed, which could be a copper salt. So a new substance formed.
There is undoubtedly an exothermic reaction occurring, which denotes a neutralization reaction. A dark blue precipitate that could be a copper salt forms. Thus, a new material developed.
Why does the pace of a reaction increase as temperature rises?The average kinetic energy of the molecules rises as the reactants heat up. This indicates that more molecules are traveling more quickly and colliding more forcefully. The pace of the reaction rises as more molecules collide with one another with sufficient energy to cause a reaction.
Usually, a reaction's rate increases as temperature rises. As a result, a higher percentage of molecules will possess the minimal amount of energy required for a successful collision.
Endothermic reactions occur when two substances interact and the temperature of the resulting mixture drops.
learn more about exothermic reaction refer
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Water is being pumped out of a reservoir at a rate of 2.54 liters per 15.0 seconds. If the reservoir contains 1.0500 x 106 gallons of water, how many hours will it take to empty it?
Answer:
It will take 6,519.44 hours to empty the reservoir.
Explanation:
First of all, you should know that 1 gallon = 3.785 L
So, you can apply the following rule of three to know the amount of water in liters in the reservoir: if 1 gallon is 3.785 liters, 1.0500 * 10⁶ gallons of water, how many liters are they?
[tex]amount=\frac{1.0500*10^{6} gallons*3.785 liters}{1 gallon}[/tex]
amount= 3,974,250 liters
Knowing that water is pumped out of a reservoir at a rate of 2.54 liters every 15.0 seconds, you now want to pump 3,974,250 liters of water out of the reservoir. For that you apply the following rule of three: if 2.54 liters are pumped out every 15 seconds, how long does 3,974,250 liters take to be pumped out?
[tex]time=\frac{3,974,250 liters*15 seconds}{2.54 liters}[/tex]
time= 23,469,980.32 seconds
With 1 hour 60 minutes and 1 minute equal to 60 seconds, then 1 hour represents 3,600 seconds. So you apply the following rule of three: if 3,600 seconds is 1 hour, 23,469,980.32 seconds, how many hours are they?
[tex]time=\frac{23,469,980.32 seconds*1 hour}{3600 seconds}[/tex]
time=6,519.44 hours
It will take 6,519.44 hours to empty the reservoir.
All atoms of the same element have the same
Explanation:
proton ..............