Someone please tell me the answer with working please!! I

Someone Please Tell Me The Answer With Working Please!! I

Answers

Answer 1
by investigating the graph, we can see that at x=20, y=8. therefore, the spring will stretch 8 cm.

Related Questions

How do we obtain data about the properties of exoplanets and objects in our solar system?

Answers

Answer:

Doppler effect to analyze the motion and properties of the star and planet.

Explanation:

The radial velocity method invovles watching the spectral lines of a star as a planet orbits around the star. Because of the planets gravitational pull on the star, will wobble. This causes Doppler shifts in the spectral lines, allowing astronomers to infer the presence of the planets.

does an object in motion stay in motion

Answers

Yes, an abject in motion stay in motion.

A stretched spring attached to two fixed points is compressed on one end and released, as shown. The resulting wave travels back and forth between the two fixed ends of the spring until it comes to a stop. This is an example of _____ .


a Transverse wave
b
longitudinal wave
c
surface wave
d
electromagnetic wave

Answers

Answer:

B. Longitudinal wave

Explanation:

It's the only option that makes sense. Hope this helped :)

1. A large ocean liner floating in the sea has a volume of
375 000 m² and displaces 50 000 m² of sea water. Determine the
density and mass of the ship. Explain why, despite being made
of metal, the ship is able to float.​

Answers

Answer:

Density of the ship :133.33 kg/m³

Mass of the ship :50,000,000 kg

Ships are able to float on water because they displace a volume that equals  their own weight

Explanation:

The formula for density is ;

Density = Mass/Volume

But the mass of  displaced fluid is give by the formula;

m=ρV where ρ is density of the fluid and V is volume of water displaced

Volume of liner= 375000 m³

Volume displaced = 50000 m³

The volume of the water displaced is equal to mass of the liner

I m³ = 1000 kg

50000 m³ = 50000*1000 =50,000,000 kg

50,000,000 kg ----------mass of the ship

So if ;

m= 50,000,000 kg

v= 375000 m³

ρ = m/V

ρ = 50,000,000/375000

ρ = 50,000,000/375000

ρ =133.33 kg/m³

Ships are able to float on water because they displace a volume that equals  their own weight. Additionally, the air contained in the spaces of the ship inside is much less dense than density of water aiding in the floating process.

If you can run at a speed of 30 miles per hour and run a distance of 15
miles, how long did it take you to run that distance?

Answers

Answer:

30 mins

Explanation:

speee=distance/time

300m/h=15m/time

time=15miles/300miles/hous=1/2 hours=30 mins

Answer:

30 minutes.

Explanation:

If it takes you an hour to run 30 miles but you only need to run 15 miles then you split that hour in half, which results in half an hour or 30 minutes.

Can someone help me in this please any one good in science.

Answers

Let's calculate the equivalent resistances on both circuits.

On Diagram A we have a series connection of the resistors. The equivalent resistance will be the sum of all resistances:

[tex]R_{eq}=1+1+1\\\\\boxed{R_{eq}=3\Omega}[/tex]

On diagram B we have a parallel connection of the resistors. The reciprocal of the equivalent resistance will be the sum of the reciprocals of all the resistances:

[tex]\frac{1}{R_{eq}} = \frac{1}{1} +\frac{1}{1} +\frac{1}{1} \\\frac{1}{R_{eq}}=3\\\\\boxed{R_{eq}=\frac{1}{3}}[/tex]

Therefore, the larger resistance occurs on diagram A.

For the current, recall

[tex]V=IR[/tex]

Where [tex]I[/tex] stands for current [tex]R[/tex] is the resistance and [tex]V[/tex] is the voltage. Rearranging the equation we have

[tex]I = \frac{V}{R}[/tex]

We can see that the larger the resistance, the smaller the current gets. So the larger current must happen in the diagram with smaller resistance. Therefore, the larger current occurs on diagram B.

Glad to help, wish you great studies ;)

Mark brainliest if you deem the answer worthy

Who else got stuck on a question and is NOT ready for test return at 2? its 1:58 AAAAAAA​

Answers

Good luckkkk hope you do well

INEGRATED SCIENCE-8th grade science
report cards due dec.18
Please Help ASSSAAAAPPPP! PLEASEEEEEEE

Answers

Answer:

I do drink bottled water but not to often, I live about 2.8 miles away from its water source and if i did'nt drink bottled water and I had to found out how my drinking water is treated I would go ask the people that are taking care of the water.

Explanation:

hope this helps

which option lists materials in order by their ability to allow the flow of electrons, from most easily to least easily?
A. Conductor, semiconductor, insulator
B. Semiconductor, insulator, conductor
C. Insulator, semiconductor, conductor
D. Semiconductor, conductor, insulator ​

Help me pls!

Answers

Answer: Conductor, semiconductor, insulator

Explanation:

Just did the quiz

The correct option is option A.

The descending order in which electrons flow easily is:

Conductor, semiconductor, insulator

Conductivity and flow of electrons:

The correct order for materials by their ability to allow the flow of electrons, from most easily to least easily is Conductor, semiconductor, insulator.

Conductors are generally metals, they have plenty of free electrons due to which the electron flow is easy. Also, the conduction band and valance band in a conductor overlap, so they can conduct at room temperature.

In the case of semiconductors, the band gap between the conduction band and valance band is almost 1eV, so a little energy is enough to make the flow of electrons possible

Whereas, in insulators, the band gap is quite high and electrons can not jump from the conduction band to the valence band due to which the flow of electrons is not possible.

Learn more about band gap:

https://brainly.com/question/14124478?referrer=searchResults

100 points if u help me and get it right this needs to be done in 3 min hurry to get ur 100 points

Calculate the kinetic energy of a 50 kg cart moving at a speed of 6.9 m/s.

Answers

Answer:

35

Explanation:

c7z ya boiiiiiiiiiiiiiiiiii

2.45kJ.
(I think it is)

If you increase the frequency what happens to the distance between the waves (wavelength)?



The size of the waves stays the same


the distance increases (longer wavelength)


There is no way to tell.


the distance decreases (shorter wavelength)

Answers

Answer:

C)the distance decreases Shorter wavelength

Step by step Explanation:

How much Tension force is required to pull a 1500 kg car (it is being towed) forward with an acceleration of 3 m/s^2 if the friction force on the towed car's tires is pulling backward with a force of 2500 N?

Answers

If the pull is done horizontally, then the net force on the car is

F = T - f = (1500 kg) (3 m/s²)

where T is the magnitude of the tension in the towing cable, and f is the friction which points in the opposite direction. Then

T = f + (1500 kg) (3 m/s²)

T = 2500 N + 4500 N

T = 7000 N

4. A Ferrari travels 350km in 2 hours. What was it's
s speed?

Answers

175km per hour
That’s the speed it was going.

A river flows due east at 1.50 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant velocity of 10.0 m/s due north relative to the water. If the river is 325 m wide, how far downstream is the boat when it reaches the north shore?

Answers

Answer:

Explanation:

Given that the velocity of the river is 1.50m/s due east.

The velocity of the boat with respect to the river is 10.0 m/s due north .

The width of the river is 325 m.

Note that the velocity of the boat will help in crossing the river.

Hence, speed = distance/time

Speed = 10.0 m/s

Distance = 325 m

Time = ?

10 = 325/time

Time = 325/10

Time = 32.5s

Hence in 32.5s the horizontal distance traveled by boat will be

= 1.50m/s × 32.5s

= 48.75m

The sixth grade teachers are planning a field trip. They want to divide the 192 students evenly on the four buses. How many students will ride each bus?

Answers

Answer:

48 students will ride on each bus.

Explanation:

192 students divided by 4 busses comes out to 48 students per bus.

Basically: 192/4=48

A box is being pulled across a horizontal surface by a 20 N force to the right.
a. If the box moves at a constant velocity, what do you know about the forces acting on the object?
b. If the box moves at a constant velocity, how much force opposes the motion of the box?
c. If the box experiences a force of 15 N to the left, along with the 20 N force acting to the right, what is the net force on the box?

Answers

A) If the box moves at a constant velocity, what we know about the forces acting on the object is; the sum of the forces acting on the object must be zero.

B) If the box moves at a constant velocity, the force that opposes the motion of the box is; Frictional Force of -20 N

C) If the box experiences a force of 15 N to the left, along with the 20 N force acting to the right, the net force on the box is; F_net = 5 N

We are told that a box is being pulled across a horizontal surface by a 20N force to the right.

A) Newton's first law of motion states that an object will remain at rest or continue in motion unless an external force acts on it. This means that any object/body moving with constant velocity will have no net external force acting on it. Thus, the sum of the forces acting on the object must be zero.

B) Since we are told that the box is moving at a constant velocity and that the sum of all forces must be zero. Then the force that will oppose the applied force of 20N to the right will be an equal but opposite force .

        In this case the opposing force will have to be the frictional force which will be -20 N to balance out the applied force.

C) We are told that a force of 15 N is acting to the left along with the 20 N force.

Thus, the net force will be;

F_net = 20 - 15

F_net = 5 N

Read more at; https://brainly.com/question/20712983

A 55 kg boy running at 2.0 m/s jumps onto a 2.0 kg skateboard. Calculate the final velocity of the boy and the skateboard.​

Answers

Answer:

The final velocity of the boy and the skateboard is 1.93 m/s.    

Explanation:

We can find the final velocity of the boy and the skateboard by conservation of linear momentum:

[tex] P_{1} = P_{2} [/tex]

[tex] m_{b}v_{i_{b}} + m_{s}v_{i_{s}} = m_{b}v_{f_{b}} + m_{s}v_{f_{s}} [/tex]  (1)

Where:

[tex]m_{b}[/tex]: is the boy's mass = 55 kg

[tex]m_{s}[/tex]: is the skateboard's mass = 2.0 kg

[tex]v_{i_{b}}[/tex]: is the initial speed of the boy = 2.0 m/s

[tex]v_{i_{s}}[/tex]: is the initial speed of the skateboard = 0

[tex]v_{f_{b}}[/tex]: is the final speed of the boy =?

[tex]v_{f_{s}}[/tex]: is the final speed of the skateboard =?

Since the boy and the skateboard will have the same final velocity by entering the above values into equation (1) we have:

[tex] 55 kg*2.0 m/s + 0 = v_{f}(55 kg + 2.0 kg) [/tex]

[tex] v_{f} = 1.93 m/s [/tex]

Therefore, the final velocity of the boy and the skateboard is 1.93 m/s.    

I hope it helps you!                                

The final velocity of the boy and the skateboard is 1.93m/s

According to the law of conservation of momentum, the momentum of the bodies before the collision is equal to the momentum of the bodies after the collision.

Mathematically, [tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]

[tex]m_1 \ and \ m_2[/tex] are the masses of the object

[tex]u_1 \ and \ u_2[/tex] are the velocities of the object

v is the final velocity

Given the following parameters

m₁ = 55kg

u₁ = 2.0m/s

m₂ = 2.0kg

u₂ = 0m/s

Required

Final velocity "v"

Substitute the given parameters into the formula to have:

[tex]55(2)+2(0)=(55+2)v\\110=57v\\v=\frac{110}{57}\\v= 1.93m/s[/tex]

Hence the final velocity of the boy and the skateboard is 1.93m/s

Learn more here: https://brainly.com/question/22257327

Students are asked to design an experiment about Newton’s 2nd Law. One student decides to roll a marble down a ramp into a pile of sand to measure the force impact.
Which variable should she manipulate to best exemplify the relationship explained by this law?

A.She should use a heavier marble, because the marbles will roll at the same rate of acceleration but more mass will produce a larger impact force.


B.She should increase the slope of the ramp by propping it up to higher height, because a steeper ramp will cause a greater rate of acceleration and a larger impact force.


C.She should use a heavier marble, because a bigger marble will accelerate more quickly down the ramp and cause a greater impact force.


D.She should decrease the slope of the ramp, because a ramp with a smaller slope will allow the ball more time to build up speed and cause a greater impact force.

Answers

Answer:

A

Explanation:

Trust me I just took it !

A car decelerates uniformly from 54 m/s to 38 m/s in 8.0 seconds. How far does it travel dunng this time?

Answers

Answer:

368m

Explanation:

dx=vt

54+38/2=46

46*8=368m

Integrated Science- 8th grade science
Please Help ASAP!
Its almost the end of semester And I need to fix my grade for science so PLEASE help!
its almost report cards time!

Answers

Answer:

A. a rigorously tested explanation

Explanation:

B. and D. are out - theories are not opinionated, they are factualC. is out - not all theories are mathematicalA. is the best choice

Answer:

The answer is option letter B

true or false? drag forces decrease when the density of a fluid increases

Answers

Answer:

Drag increases with the density of the fluid (ρ). More density means more mass, which means more inertia, which means more resistance to getting out of the way. The two quantities are directly proportional.

What is power??????????

Answers

D.) The energy needed to create work.

PLEASE HELP ME IM TIMED

Answers

Answer:

the answer is the core

Explanation:

the core is composed of iron and nickel

As we know, the moon is a satellite of our earth, what is the
theoretical period of the moon? The average radius of the
moon's orbit is 3.84 108 m and the mass of the earth is 5.97 x
1024 kg (in hours, G = 6.67 x 10-9 N (m/kg) 3).

Answers

Answer:c

Explanation:c

This question involves the concepts of the time period, orbital radius, and gravitational constant.

The theoretical period of the moon is "658 hr".

The theoretical time period of the moon around the earth can be found using the following formula:

[tex]\frac{T^2}{R^3}=\frac{4\pi^2}{GM}[/tex]

where,

T = Time Period of Moon = ?

R = Orbital Radius = 3.84 x 10⁸ m

G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of Earth = 5.97 x 10²⁴ kg

Therefore,

[tex]\frac{T^2}{(3.84\ x\ 10^8\ m)^3}=\frac{4\pi^2}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}\\\\T^2=(9.91\ x\ 10^{-14}\ s^2/m^3)(56.62\ x\ 10^{24}\ m^3)\\\\T=\sqrt{561.34\ x\ 10^{10}\ s^2}[/tex]

T = 2.37 x 10⁶ s[tex](\frac{1\ h}{3600\ s})[/tex]

T = 658 hr

Learn more about the orbital time period here:

https://brainly.com/question/14494804?referrer=searchResults

The attached picture shows the derivation of the formula for orbital speed.

Please help

Answers

Answer; 1 wavelength has a longer wavelength and lower frequency, 2 wavelength has a high frequency and short wavelength

What is thermodynamics?
the movement of energy
the classification of energy
the way energy changes
the movement of heat

Answers

Answer:

The movement of energy

Explanation:

Answer:

the movement of energy

Kayla is measuring how long it takes a ball to roll down a hill. The ball has a
starting velocity of 2.6 m/s. The ball rolls down the hill for 5.5 seconds, and
when it reaches the bottom, it has a velocity of 8.0 m/s. How far did the ball
roll during this time frame?

A) 44 meters

B) 14 meters

C) 29 meters

D) 58 meters

Answers

The answer would be A. 44 meters

How much power is used if a force of 35 newtons is used to push a box a distance of 10 meters in 5 seconds?w=350j

Answers

The answer your looking for is 70watts

Answer:

How much power is used if 350J of work is done when pushing a box for 5 seconds.

Explanation:

the answer is 70watts

A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ?

Answers

Answer:

Explanation:

The force of static friction acting on the box is the frictional force;

Frictional force Ff = Wsin theta (force acting along the ramp)

W is the gravitational force known as the weight

Ff = 112.1sin42°

Ff = 112.1(0.6691)

Ff = 75.00N

Hence he force of static friction acting on the box  if box has a gravitational force of 112.1 N id 75.00N

Answer:

75N i did test

Explanation:

how do you know the pole on the left is the south pole and the pole on the right is the north pole?

Answers

Answer:

Left is deciamled to the right [tex]x_{123}[/tex]

Explanation:

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