The reason for more risk and sensitivity to swings in the capital cycle with real estate is that there is increased leverage in real estate, illiquidity, the changes in terms of local markets, as well as the need for a helping hand from expert.
What is risk in real estate?Risk is said to be anything that makes the projected or actual returns on a property or portfolio volatile in the context of commercial real estate investing.
Therefore, note that most shrewd investors not only evaluate their profits but also they do carry out cash flow estimates as well as efficiently manage any form of risk.
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consider a solid stainless steel wire with a thermal con- ductivity of 14 w/m⋅k. the wire has a diameter of 1 mm, has a resistivity of 45 × 10−8ω⋅m, and carries a current of 120 a. (a) determine the rate of heat generated within the wire (w/m3 ), and (b) calculate the maximum temperature rise in the wire.
The heat generated within the wire is 1.05 x 10¹⁰ W/m³ with a maximum temperature of 589.5 K.
Heat is the energy that has a correlation with the resistivity of the material. Resistivity depends on the resistance and wire dimension where the resistance of the material can be written as
R = ρ.L/A
where R is resistance, ρ is resistivity, L is the length of the wire and A is surface area.
The given parameters from this question are
σ = 14 W/m.K
ρ = 45 x 10¯⁸ Ωm
I = 120 A
d = 1 mm
r = 0.5 mm = 5 x 10¯⁴ m
Calculate the surface area
A = πr²
A = π(5 x 10¯⁴)²
A = 7.86 x 10¯⁷ m²
In 1 m³, the length of wire should be
V = A . L
1 = 7.86 x 10¯⁷ . L
L = 1272727.273 m
Find the resistance of wire per m³
R/V = ρ.L/A
R/V = 45 x 10¯⁸ . 1272727.273 / 7.86 x 10¯⁷
R/V = 728925.62 Ω/m³
Find the heat generated per m³ by using power
P/V = I² . R
P/V = 120² . 728925.62
P/V = 1.05 x 10¹⁰ W/m³
Find the heat generated per m by using power
P/L = P/V
P/L = P/V . A
P/L = 1.05 x 10¹⁰ . 7.86 x 10¯⁷
P/L = 8253 W/m
Find the maximum temperature
T = (P/L) / σ
T = 8253 / 14
T = 589.5 K
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Refrigerant-134a enters the evaporator coils placed at the back of the freezer section of a household refrigerator at 100 kPa with a quality of 20 percent and leaves at 100 kPa and −26°C. If the compressor consumes 600 W of power and the COP of the refrigerator is 1.2, determine: 3.1 the mass flow rate of the refrigerant and 3.2 the rate of heat rejected to the kitchen air.
The calculate value of Mass flow rate = 0.00414 kg/s while the rejected heat is 1.32 Kw
How to find the mass flow rate
We have to use the properties of the enthalpies from the pressure table
At p4 = 100 kpa
hf = 17.28 kj / kg
hfg = 217.16 kj / kg
enthalpy at the state 1
= 17.28 + 2*217.16
= 60.712 kj / kg
T1 = - 26 degrees celsius
enthalpy of vapor = 234.44 kj / kg
a. The mass flow rate
Ql = 1.2 x 600
= 720 watts
convert to Kw
= 0.72 KW
We have to find the mass flow rate
This is given as the formula
Ql / h1 - h4
we would have
0.72 / 2344 - 60.712
Mass flow rate = 0.00414 kg/s
b. We have to find the rejection of the heat through the use of the number 1 law of thermodynamics
Qh = Ql + W
= 0.72 + 0.6
= 1.32 Kw
Hence the mass flow rate is 0.00414 and the rejected heat rate is 1.32 kW
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the hydraulic conductivity of a sand is 0.56 cm/s. the viscosity of water at 250c is 0.0911x10-4 g.s/cm2, determine the absolute permeability of the soil (in cm2)
The absolute permeability of the soil is 5.1016*10^{-6} cm^{2}
The absolute permeability of the soil is calculate using the formula:
Absolute permeability=(Hydraulic conductivity*Viscosity of water)/Density of water
Hydraulic conductivity=0.56
Density of water=1
Viscosity of water=[tex]0.0911*10^{-4}[/tex]
We are now finding absolute permeability:
Absolute permeability=(0.56*0.0911^-4)/1
Absolute permeability=[tex]5.1016*10^{-6} cm^{2}[/tex]
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explain two possible factors that make first and second generation computer consuming more power
Answer: the type of battery, refrigerator.
Explanation: The battery since the first and second generation ones overheat more and do not have too much electricity, causing it to turn off faster than the current ones.
The refrigerator that is the little avaniquito that is inside the computer with the function of refrigerating and refreshing the battery and the components avoiding overheating and making the batteries last longer.
Locate the center of gravity of the composite volume for r = 0.5 m, �d=0.04 m, L=4.5 m and γ = 14 kN/m and γ=77kN/m.
The center of gravity that has been calculated in the question that we have here is given as 0.1594
How to solve for the center of gravityWe have the following data to answer the questions with
r = 0.5 m,
d=0.04 m,
L=4.5 m
γ = 14 kN/m
γ=77kN/m.
v1 = 4/3πr³
= 4 / 3 * π * 0.5³
= 0.5236
v2 = π / 4 d² L
= π / 4 * 0.04² * 4.5
= 0.7857 * 0.0016 * 4.5
= 0.005857 m³
y1v1 = 14 x 0.5236
= 7.3304 kN
y2v2 = 77 x 0.005857
= 0.45098
center of gravity
= 7.3304 x 0+ 0.45098 (0.5 + 4.5/2) ÷ 7.3304 + 0.45098
= 1.2402 / 7.78138
= 0.1594
What is center of gravity?This is the term that is used to represent the point in physics that is the point that refers tp where the average location of objects would have to appear. It can simply be referred to as the point of balance of all objects where their masses are said to be located.
The calculated center of gravity is given as 0.1594
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How can I derive the Navier-Stokes Equation in the y direction?
Answer:
Let's flip the equations about the equal sign so what we have in the first equation is the sum of forces in the x-direction is equal to the mass times the acceleration.
The large piston in a hydraulic lift has a radius of 8 inches. what force must be applied to the small piston with a radius of 2 inches in order to raise an electric bicycle with weight 300 lbs? what is the pressure exerted on the large piston? on the small piston? is this system reasonable? why or why not?
The pressure exerted on hydraulic system is 1.49 lbs/in² and the force needed to raise the load is 18.75 lbs.
We need to know about pressure to solve the hydraulic system. Pressure is a unit that describes how much force is applied on a surface area. It can be determined as
P = F / A
where P is pressure, F is force and A is area.
In hydraulic lift piston, the pressure of both pistons will same
P1 = P2
From the question above, we know that
r1 = 8 in
r2 = 2 in
F1 = 300 lbs
Calculate the pressure exerted on the large piston
P1 = F1/A1
P1 = 300 / (πr1²)
P1 = 300/ (π. 8²)
P1 = 1.49 lbs/in²
Calculate the force needed
P1 = P2
1.49 = F2 / (πr1²)
1.49 = F2 / (π2²)
F2 = 18.75 lbs
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for the post of prob. 2., determine the maximum centric force that can be applied if the allowable normal stress is 20 ksi in the steel and 2.4 ksi in the concrete. problem 2. the 4.5-ft concrete post is reinforced with six steel bars, each with a 1-in. diameter. knowing that es 29 × 106 psi and ec 4.2 × 106 psi, determine the normal stresses in the steel and in the concrete when a 350-kip axial centric force p
When an object is subjected to a force such that the force's direction of action passes via the object's center of gravity or a fixed axis of rotation.
Only linear motion is caused by central force. In the straight section of the tracks, it is a force that affects a bobsleigh54. Eccentric force is an outside force57 whose vector line does not pass through the body's center of gravity. Eccentric force alters both rotary and linear motion. Torque, often known as a moment of force, is the turning result of an eccentric force. The product of the force's magnitude and the angle between its direction and the rotational axis determines the torque about any given point.
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a 100-mm nozzle is bolted with 6 bolts to the flange of a 300-mm-diameter horizontal pipeline and discharges water into the atmosphere. calculate the tension load on each bolt when the gage pressure in the pipe is 600 kpa. neglect vertical forces
The ratio of the force being applied divided by the unit area that causes the material to extend or stretch.
The opposite of compression, which tends to shorten a material, is tensile load, which tends to lengthen a material. Tensile stress is another name for tensile load. One of the main categories or types of load cells frequently seen in the weighing business is a tension load cell. Other varieties include single-point, compression, and beam, for instance. As their name implies, tension load cells are typically employed to measure tension or pulling force. A force that stretches anything is tension. A force that squeezes things together is called compression. Only materials that can withstand forces are helpful.
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you are required to design a circuit that given inputs a, b, and i, tests if bit i of a and b, are equal. as a specific case (i.e., for this question) we are dealing with 4-bit inputs a and b and therefore i is an integer between 0 and 3, i.e., a
Class A IP addresses have a default mask of 255.0.0.0 (or /8 in CIDR), and their ranges are 1.0.0.0 to 127.255.255.255. Accordingly, Class A addressing may support a maximum of 128 (27) networks with a total of 16,777,214 (224-2) useable addresses per network.
510 host IP addresses are available, which is 512 minus 2. This would surely work for a network of 20 users today and 300 hosts in the future. With that knowledge, we can conclude that the network's most effective subnet mask is 255.255.254.0. Number of total subnets: The value 248 (11111000) of the subnet mask 255.255.255.248 shows that 5 bits are utilized to identify the network.
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determine the compressive stress in a 6 inch diameter by 9 inch concrete column used as a test specimen when the deformation under load is 0.0012 inches.
The compressive stress of the test specimen is 2.22k x 10¯⁵ N/inch².
We need to know about compressive stress to solve this problem. The compressive stress to solve this problem. The compressive stress is the force applied per unit area. It can be written as
σ = k . x / A
where σ is compressive stress, F is force and A is surface, k is the force constant as (N/inch) and x is displacement.
From the question above, we know that
A = 6 . 9 = 54 inch²
x = 0.0012 inch
By substituting the given parameters, we get
σ = k . x / A
σ = k . 0.0012 / 54
σ = 2.22k x 10¯⁵ N/inch²
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All of the following statements are true except: group of answer choices installing the cross with the zerk fitting backwards will make it difficult, if not impossible, to lube the u-joint after the driveshaft is installed on the vehicle. universal joint lubricant is nlgi #5, with an extreme pressure (ep) additive. sometimes, universal joint cups are held in place with plastic material that is injected into a hole in the yoke. usually galling will be found on a trunnion 180 degrees to brinelling.
This failure is usually caused by someone who does not install the U-joint in the correct orientation in the drive shaft. The front U-joint of a drive shaft must be installed so the driving torque compresses the U-joint lube fitting.
The U-joint that connects the differential and drive shaft. It may even enable two drive shafts to connect to one another in some situations when the drive shaft is connected to the transmission. Drive shafts can be moved up and down with the suspension while they are in motion thanks to universal joints, which enable power to be transferred even when the drive shaft is not in a straight line between the transmission and drive wheels. U-joints or universal joints are located at the ends of the drive shaft of rear-wheel-drive automobiles. Normally, the drive shaft has two u-joints that need to be replaced. A double-cardan joint, which consists of two u-joints, can be found on some driveshafts' front. When letting off and pressing the accelerator, in particular, a poor u-joint might make your car jolt or make a loud noise while you're driving. At certain speeds, vibration from the center or back of the car can also be caused by a damaged u-joint.
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QUESTION 7
An indemnity clause in a contract may allow the subcontractor hold harmless the contractor in a construction case.
O True
False
Answer:
True
Explanation:
Ture, the indemnity protects.
Answer: The correct choice is True
What are some trouble shooting tips for web searching include items that help refine searches. A minimum of 5 items must be highlighted.
(computer science)
There is a lot of information on the Internet today, with billions of web pages available. Search engines make it easy to discover this information. Let's go through the fundamentals of utilizing a search engine, as well as some troubleshooting tips for getting better search results.
What are troubleshooting tips for getting better results?1. Keywords - Create a list of keywords that characterize your topic; these will serve as your search phrases.
Be as detailed as possible, for example, Germans Shepherds instead of Dogs.For instance, what proportion of Irans' electricity is generated by wind power?Key terms here might include wind, power, Iran, and electricity.
2. Use quotation marks around specific terms, such as "wind power," to find online sites that include that phrase. There will be fewer sites than if we searched individually for wind and power.
3. Boolean searching: To refine your search, use + and -.
"wind energy" +Iran"wind energy" AND "Iran"
To include all terms, use + or AND.
"wind power" + "jobs in Iran" "wind energy" AND "Iran" NOT WORK
To eliminate terms you don't want, use - or NOT.
It is to be noted that one must not use a space between the + and - signs and the search phrase, for example, -jobs rather than -jobs.
4. Advanced search function
To limit your search by date, country, amount, language, or other criteria, click the Advanced Search option at the bottom of the Search engine's start or results page.
5. Internet Explorer History
It's convenient to discover web pages you've already utilized or discarded.
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Heat air rises, cools then falls. Air near heat is replaced by cooler air and the cycle repeats
a solid round bar with diameter of 2 in has a groove cut to a diameter of 1.8 in, with a radius of 0.1 in. the bar is not rotating. the bar is loaded with a repeated bending load that causes the bending moment at the groove to fluctuate between 0 and 25 000 lbf in. the bar is hot-rolled aisi 1095, but the groove has been machined. a fully corrected endurance limit is
The groove has been machined a fully corrected endurance limit is = 1.792. Simply maintain all stress amplitudes below the fatigue limit if you wish to design for unlimited life, as was previously suggested.
Life will continue to exist indefinitely as long as even the highest stress amplitude is below the exhaustion limit. The "infinite life" zone for ferrous materials is bounded by a "endurance limit." The endurance limit of a material is a specified stress level below which fatigue damage from stress cycles will not be accumulated.
Given that D=2.1, d(diameter)=1.892, and r=0.17
The material's maximum endurance is 60 kpsi.
Using the Goodman relation, nf equals 0.833.
Safety factor yielding equation: ny= Sy/max= 66/36.828 ny= 1.792
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