Solve this problem. 74-4^3+6= *

Answer:

28

Step-by-step explanation:

Hope this helps

Answer:

b + 2 = 6

Step-by-step explanation:

This may not be the right answer, but its what I think it is.

Answer:

[tex] \cos (u + v) = -\dfrac{56}{65} [/tex]

Good job!

Step-by-step explanation:

[tex] \cos (u + v) = \cos u \cos v - \sin u \sin v [/tex]

[tex] \sin u = -\dfrac{3}{5} [/tex]; u is in QIII.

That makes [tex] \cos u = -\dfrac{4}{5} [/tex]

[tex] \sin v = -\dfrac{12}{13} [/tex]; v is in QIV.

That makes [tex] \cos v = \dfrac{5}{13} [/tex]

[tex] \cos (u + v) = (-\dfrac{4}{5})(\dfrac{5}{13}) - (-\dfrac{3}{5})(-\dfrac{12}{13}) [/tex]

[tex] \cos (u + v) = -\dfrac{20}{65} - \dfrac{36}{65} [/tex]

[tex] \cos (u + v) = -\dfrac{56}{65} [/tex]

You are correct.

Answer:

Step-by-step explanation:

-0.8615

Answer:

i can't graph it but i'll give you the points to graph

Step-by-step explanation:

(-2, -5) (-1,-2) (0,1) (1,4) (2,7)

start at the point in bold

17/20 is the probability that their eyes are green or Hafzel.

It is a branch of mathematics that deals with the occurrence of a random event.

Given,

The number of students having Green eyes =6

The number of students having Blue eyes =3

The number of students having Hafzel eyes =11

The total number of students=11+3+6

=20

The probability that their eyes are green is 6/20

The probability that their eyes are Hafzel is 11/20

The probability that their eyes are green or  Hafzel

6/20 + 11/20

= 17/20

Hence,  17/20 is the probability that their eyes are green or Hafzel.

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Multiplying a matrix by a scalar is equivalent to multiplying each entry in the matrix by that scalar:

[tex]A=\begin{bmatrix}0&-3\\-5&5\end{bmatrix}\implies3A=\begin{bmatrix}0&-9\\-15&15\end{bmatrix}[/tex]

[tex]B=\begin{bmatrix}-2&-6\\2&5\end{bmatrix}\implies-6B=\begin{bmatrix}12&36\\-12&-30\end{bmatrix}[/tex]

Now combine them:

[tex]3A-6B=3A+(-6B)=\begin{bmatrix}0+12&-9+36\\-15+(-12)&15+(-30)\end{bmatrix}=\begin{bmatrix}12&27\\-27&-15\end{bmatrix}[/tex]

it should be 3 and 3 is the the right answer

The required middle number is 284 and the three consecutive numbers would be 283, 284, and 285 respectively.

A number system is defined as a way to represent numbers on the number line using a set of symbols and approaches. These symbols, which are known as digits, are numbered 0 through 9. Based on the basic value of its digits, different types of number systems exist.

Let the three consecutive numbers would be x, x + 1, x + 2 respectively

Given that the sum of three consecutive numbers is 852

⇒ x + x + 1 + x + 2 = 852

⇒ 3x + 3 = 852

⇒ 3x = 852 - 3

⇒ 3x = 849

⇒ x = 849/3

⇒ x = 283

So the three consecutive numbers would be 283, 284, and 285 respectively.

Therefore, the required middle number is 284.

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Answer:

37

Step-by-step explanation:

Sorry if this is wong I haven't done these in awhile, but this is how I got it.

f(X)=3x+7

f(10)=3(10) +7

f(10)=30 +7

f(10)=37

Answer:

f(10)=37

Step-by-step explanation:

f(x)=3x+7

(for f(10) we sub 10 for x)

f(10)=3×10+7

=30+7

=37

Answer:

X<1 or X>3/2

Step-by-step explanation:

Answer:

271 degrees

Step-by-step explanation:

143-(-128)=143+128=271 degrees

To see if these ratios make a proportion let us first change them into fractions

= 4:10 = 4/10 = 4 ÷ 2 / 10 ÷ 2 = 2/5

= 6:15 = 6/15 = 6 ÷ 3 / 15 ÷ 3 = 2/5

= Since both these ratios are getting simplified into a same fraction , they are proportional .

Therefore , 4 : 10 :: 6 : 15 ( 4 : 10 is proportional to 6 : 15 )

Answer:

I'll assume that x2 = x^2 and y2 = y^2 and the answer is sqrt{35}.

Step-by-step explanation:

This problem invovles completing the square, so if I square (x+y), I get

x^2+2xy+y^2, and since xy = 6, 2xy = 12, 23+12 = 35, and your answer is sqrt{35}.

Answer:

3

Step-by-step explanation:

he pattern is continued by adding 3 to the last number each time, like this: 1, 8, 27, 64, 125, 216, 343, 512, 729

Answer:

17.7

Step-by-step explanation:

The tenths place is the very first value after the decimal. The number 17.68694 rounds up to 17.7, because .68 is closer to .7 than it is to .6.

Answer:

486 inches is 13.5 yards and 162 inches is 4.5 yards please mark brainlist thank you

Answer:

4^2 + 5 = 21, 5^2 + 3 = 28, 7^2 + 3 = 52, 3^2 + 43 = 52, 7^2 + 19 = 68, 3^2 + 11 = 20, 1^2+19 = 20. I can't find a prime number and a perfect square that sums to 13.

Explanation:

these are primarily derived by finding the closest perfect square to a number and finding the difference to make the sum work, or finding the simplest prime number that will reduce the number which is a multiple of a perfect square.

If ∆LMC ≅ ∆BJK, then ∆CL ≅ ∆KB. so the correct option is D.

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We have been given that ∆LMC ≅ ∆BJK.

The image of the triangles are attached below;

The triangle are congruent to each other so,

∆LMC ≅ ∆BJK

∆LM ≅ ∆BJ

∆LC ≅ ∆BK

∆MC ≅ ∆JK

Thus, ∆LC ≅ ∆BK so the correct option is D.

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Answer:

Use this formula:

A^2 + B^2 = C^2

40 is the hypotenuse of the triangle:

A^2 + 25^2 = 40^2

A=31.2 meters (Approx)

Answer:

j = 12

Step-by-step explanation:

j + (-3) = 9

j = 12

Answer:

∠EBF = 51°

∠DBE = 17°

∠ABF = 141°

∠EBA = 90°

∠DBC = 107°

∠DBF = 68°

Step-by-step explanation:

Hope this helps

Answer:

1.

a. m<EBF = 90 - 39 = 51

b. m<EBA = 90

c. m<DBE = 90 - 73 = 17

d. m<DBC = 90 + 17 = 107

e. m<ABF = 90 + 51 = 141

f. m<DBF = 17 + 51 = 68

2.

<ABD, <DBE, <EBF, <FBC, <DBF

3.

<ABF, <DBC

4.

<ABE, <EBC

9514 1404 393

Answer:

  A: 66/21

  E: 22/7

Step-by-step explanation:

The offered choices reduce to 3 1/7 or to 3. The best approximations of those given are the ones that reduce to 3 1/7.

  A: 66/21 = 22/7 = 3 1/7

  B: 60/20 = 3

  C: 21/7 = 3

  D: 45/15 = 3

  E: 22/7 = 3 1/7

___

Comment on pi approximations

The ratio 22/7 differs from π by about 0.04%. A better approximation is 355/113, which differs from π by about 0.000008%. The approximation 3.14 differs from π by about 0.05%.

Answer: 600

Step-by-step explanation: 555

The five in the tens place is equal to 5

To round to the nearest tens place the number has to be 5 or more than 5

Answer:

List some of the given data:

1 L = 33.8 oz.

A) Which one has more volume?

In a six-pack, each can has 12 oz.

Then in total, this is:

6*12oz = 72oz.

In one liter we have 33.8 oz.

Then in two liters, we have two times that:

2L = 2*33.8 oz = 67.7 oz.

Then the sixpack has more volume.

B) Which one has more value?

Here we must divide the volume by the price:

Six-pack:

Volume  = 72 oz.

Price = $1.37

Ratio = 72oz/$1.37 = 52.55 oz/$.

2L bottle:

Volume = 67.7 oz

Price = $1.31

Ratio = 67.7oz/$1.31 = 51.68 oz/$.

You can see that the ratio is larger in the case of the six-pack, this means that you get more ounces for each dollar.

Answer:

B

Step-by-step explanation:

Answer:

Step-by-step explanation:

A coefficient is basically the number infront of a variable or term.

E.g. the coefficient in 7x is 7

The coefficient in 23y is 23

The coefficient in 43a is 43.

So for your question: 7a + 23b + 2c + 16,

The coefficients are 7, 23 and 2

Answer:

1) [tex]f'(t)=4t,\ g'(t)=3t^2+4[/tex]

2) [tex]p(t) =2t^5+8t^3[/tex]

[tex]p'(t)=10t^4+24t^2[/tex]

3) False

4)[tex]q(t) =\dfrac{1}{2}t+2t^{-1}[/tex]

[tex]q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]

5) False

Step-by-step explanation:

Given that:

[tex]f(t) = 2t^2[/tex] and [tex]g(t) = t^3 + 4t[/tex]

Formula:

[tex]1. \dfrac{d}{dx}x^n=nx^{n-1}[/tex]

[tex]2. \dfrac{d}{dx}C.f(x)=C.f'(x)\ \{\text{C is a constant}\}[/tex]

1) Using above formula:

[tex]f'(t)=2\times 2 t^{2-1}=4t[/tex]

[tex]g'(t)=3t^{3-1}+4\times 1 t^{1-1}=3t^2+4[/tex]

2) [tex]p(t) =2t^2(t^3+4t)[/tex]

Rewriting the formula by distributing the [tex]2t^2[/tex] term:

[tex]p(t) =2t^2.t^3+2t^2.4t=2t^5+8t^3[/tex]

[tex]p'(t) = 10t^4+24t^2[/tex]

3) By using answers of part (1):

[tex]f'(t).g'(t)=12t^3+16t[/tex]

[tex]p'(t) = 10t^4+24t^2[/tex]

Therefore it is False that [tex]p'(t) = f'(t).g'(t)[/tex]

4) [tex]q(t)=\dfrac{t^3+4t}{2t^2}[/tex]

Writing by distributing:

[tex]q(t)=\dfrac{t^3}{2t^2}+\dfrac{4t}{2t^2}\\\Rightarrow q(t) =\dfrac{t}{2}+\dfrac{2}{t}\\\Rightarrow q(t) =\dfrac{1}{2}t+2t^{-1}[/tex]

Using the formula:

[tex]q'(t)=\dfrac{1}{2}t^{1-1}+2\dfrac{-1}{t^2}\\\Rightarrow q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]

(5)By using answers in part (1):

[tex]\dfrac{g'(t)}{f'(t)}=\dfrac{3t^2+4}{4t}=\dfrac{3}{4}t+\dfrac{1}t[/tex]

[tex]q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]

Therefore, it is False that:

[tex]q'(t)=\dfrac{g'(t)}{f'(t)}[/tex]