Solve the system of equations 6x+3y=9 and -9x−2y=9 by combining the equations.

Answer:

x = 34 degrees

Step-by-step explanation:

Corresponding Angles Theorem: If 2 parallel lines are cut by a transversal, their corresponding angles are congruent.

Angle RNM = 78 degrees

Triangle RMN = 180 degrees

180 = 78 + 2x + x

102 = 3x

x = 34

Answer:

x = - 3 ± [tex]\sqrt{2}[/tex]

Step-by-step explanation:

x² + 6x + 7 = 0 ( subtract 7 from both sides )

x² + 6x = - 7

using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = - 7 + 9

(x + 3)² = 2 ( take square root of both sides )

x + 3 = ± [tex]\sqrt{2}[/tex] ( subtract 3 from both sides )

x = - 3 ± [tex]\sqrt{2}[/tex]

The interval around the mean that contains 95% of the airfare is (250.2,524.2).

Normal Distribution is bell shaped and symmetrical in nature.

We use standard normal to find probabilities of normal distribution

Normal distributions have key characteristics that are easy to spot in graphs: The mean, median and mode are exactly the same. The distribution is symmetric about the mean—half the values fall below the mean and half above the mean. Diagram below shows standard normal figure.

In a normal distribution, 95% of the values fall between mean±2*sd

Give:  mean=387.20

          sd=68.50

So the interval around the mean that contains 95% of the airfare is (250.2,524.2).

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[tex]\frac{FI}{IG}=\frac{14}{28}=\frac{1}{2}\\\\\frac{FE}{EH}=\frac{12}{26}=\frac{6}{13}[/tex]

So, IE is not parallel to GH.

Answer:

b. x=2, -3

Step-by-step explanation:

So I'm assuming the two equations are: [tex]y=4-x^2[/tex] and [tex]x-y=2[/tex]

Since it's asking to solve to solve for x. Then we need to solve for y in one of the equations, so that's it's defined using x, then substitute that into the other equation, that way the only variable left is going to be the x variable.

So since y is already solved for in the first equation. I'll plug that into the second equation.

Original equation:

[tex]x-y=2[/tex]

Substitute 4-x^2 in as y

[tex]x-(4-x^2)=2[/tex]

Distribute the negative sign

[tex]x-4+x^2=2[/tex]

Organize it so it's in order by degree

[tex]x^2+x-4=2[/tex]

Subtract 2 from both sides

[tex]x^2+x-6=0[/tex]

So now we have a quadratic equation and we're trying to find the zeroes. You can use the quadratic equation, but since the only options are integers, we can easily factor this equation. So you need to look for factors of -6, which add up to 1. I like to think about it as find two numbers with a difference of 1, and then figure out which is going to be positive and which is going to be negative after. So knowing this you can easily see 3 and 2 have a difference of 1. Since the 1 is positive, that means the 3 has to be positive and the 2 has to be negative

Use the factors: 3 and -2 to rewrite the equation:

[tex](x+3)(x-2)[/tex]

Now set each factor equal to 0

x+3 = 0

x=-3

x-2=0

x=2

this gives you the two solutions: -3, and 2

Maribel leaves school at 3:10 to walk home, spent 20 minutes shopping and spent 30 minutes walking

An equation is an expression that shows the relationship between two or more variables and numbers.

Let us assume that Maribel reaches home at 4:00, hence:

Time spent walking = 4:00 - (3:10 + 20 minutes) = 4:00 - 3:30 = 30 minutes

Maribel leaves school at 3:10 to walk home, spent 20 minutes shopping and spent 30 minutes walking

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Possible values of x is -4 or -16

[tex]{x}^2[/tex] + 20x +100 = 36

[tex]\\{x}^2[/tex] + 20x + 100-36 = 0

[tex]\\{x}^2[/tex] + 20x + 64 = 0

Using middle term split

In this method splitting of middle term in to two factors, In Quadratic Factorization using Splitting of Middle Term which is x term is the sum of two factors and product equal to last term.

[tex]{x}^2[/tex] + 4x + 16x + 64 = 0

x(x+4) + 16(x+4) = 0

taking common (x+4)

(x+4)(x+16) = 0

Either

x+4 = 0

⇒ x = -4

or (x+16) = 0

⇒ x = -16

Thus possible values of x is -4 or -16

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Answer: A

Step-by-step explanation:

Answer:

18.75

Step-by-step explanation:

[tex]Area=\pi r^{2} \\Area=3(\frac{5}{2} )^{2} \\Area=18.75[/tex]

The range of the function across the domain is {18, 2, -6}

The function is given as:

f(x) = -2x + 12

The domain is given as:

{-3, 5, 9}

So, we have:

f(-3) = -2*-3 + 12 = 18

f(5) = -2*5 + 12 = 2

f(9) = -2*9 + 12 = -6

Hence, the range of the function across the domain is {18, 2, -6}

The function is

f(x) = 3x - 11

To calculate f(4), we have:

f(4) = 3 * 4 - 11

Evaluate

f(4) = 1

Hence, the value of f(4) is 1

The function of the graph is given as:

w(x)

To calculate w(2), we check the corresponding point on the graph where x = 2

From the graph, we have:

w(2) = 5

Hence, the value of w(2) is 5

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Answer:

1.  f(4) = 1

2.  range: {18, 2, -6}

3.  w(2) = 5

Step-by-step explanation:

Question 1

[tex]\textsf{Given}: \quad f(x)=3x-11[/tex]

To find f(4) substitute x = 4 into the given function:

[tex]\begin{aligned}\implies f(4) & = 3(4)-11\\& = 12-11\\& = 1\end{aligned}[/tex]

Question 2

Domain: set of all possible input values (x-values)

Range: set of all possible output values (y-values)

[tex]\textsf{Given}: \quad b(x)=-2x+12[/tex]

To find the range of the given function for the domain {-3, 5, 9} simply input these values of x into the function:

[tex]\implies b(-3)=-2(-3)+12=18[/tex]

[tex]\implies b(5)=-2(5)+12=2[/tex]

[tex]\implies b(9)=-2(9)+12=-6[/tex]

Therefore, the range of the given function is {18, 2, -6}.

Question 3

Given:  The graph of function w(x)

To find w(2) simply find the y-value of the point on the graph where x = 2:

Therefore, w(2) = 5

The amount of bbd received for the given currency exchange rate is 6050  bbd.

The value of one country's currency in relation to the currencies of other countries or economic zones is known as the currency exchange rate.

The majority of currency exchange rates are free-floating and fluctuate according to market supply and demand.

There may be restrictions on some currency exchange rates since they are fixed to the value of other currencies.

According to the question,

Currency exchange rate: $1.00=5.50bbd

So, $1100=1100*5.50 bbd

               =6050 bbd

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Answer:

A. 19

Step-by-step explanation:

Slove this expression using the order of operation PEMDAS.

12 + 2x -5

Replace x with 6

12 + 2(6) - 5

12 + 12 - 5

24 -5

19

Therefore the answer is the first option A.19 .

The function is C(F) = (F-32) * 5/9
This means the function C, is using variable F to get the output.
C is Celsius, F is Fahrenheit, so the answer is "the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius"

Answer:

a

Step-by-step explanation:

The probability that he will use both bus and the train among bus, cab, train is 0.11.

Given There are 3 choices to people each among bus, cab, train for his trip home.

Probability is the likeliness of happening an event among all the events possible. The value of probability lies between 0 and 1. The formula to calculate probability is as under:

Probability= number of things/ total things.

The value of probability cannot be negative.

Number of buses=3

Number of cab=3

Number of train=3

Probability that he will go through train and bus is 3/9*3/9

=9/81

=1/9

=0.11

Hence the probability that he will travel with bus and train is 0.11.

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Question is incomplete as it includes:

What is the probability that he will use both train and bus?

Answer:

60 for both

Step-by-step explanation:

Since these angles are parallel, they are equal to each other :

6x = 5x + 10

Subtracting 5x from both sides gives us :

x = 10

Substituting this value back into both angles gives us

6x = 60

5x+10 = 60

The probability that the operator is busy is 33.33% if the call rate is 2 per minute and average time to handle is 10 seconds.

Given rate of calls 2 per minute and average time to handle a call is 10 seconds.

We have to find the probability that the operator is busy.

Probability is the chance of happening an event among all the events possible. The value of probability lies between 0 and 1.

Probability= number of items/ total items

If rate is 2 per minute then the customers handled in 1 hour=2*60=120

The average time to handle a call=10 seconds.

Therefore customers to be handled in 1 hour=360 (10*6*60)

Probability that the operator is busy is as under:

Probability=λ/μ

=120/360

=1/3

=1/3*100

=33.33%

Hence the probability that the operator is busy is 33.33%.

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Answer:

I don't know the answer

Step-by-step explanation:

it's hard solve it for me

Answer:

let why is equal to FX b and function with an independent variable X and dependent variable y if a function of f provide a way to successfully produced the single value using for the prepos a value of x then the chosen X value is called belong to domain f

Answer: $233

Step-by-step explanation:

- A flat fee is an amount that is charged or paid that doesn’t account for hourly use or work

- Then, you must pay by the hour for use

- So you would use the equation:

(22 • 9) + 35

- 22 is the maximum hours and 9 is the hourly rate

- 35 is your flat fee

- So, (22 • 9) + 35 = $233

hope this helps :)

Answer:

$233

Step-by-step explanation:

We can make up a linear equation. We already know that it costs $35 to rent a small auger.

Every hour there is a extra fee of 9$.

So, 9 can be the slope, while 35 can be the x intercept.

y=9x+35

x=22; maximum hours

y=9(22)+35

y=198+35

y=$233

Here is a more simple way

multiply 22 hours with 9 dollars, =$198

then add the 35 dollars; 198+35=$233

Answer:

n = 8 or n = −6

Explanation:

First, isolate the absolute value:

5 − |n − 1| = −2

7 − |n − 1| = 0

7 = |n − 1|

Then, split this into two equations, since the result of the absolute value could be positive or negative:

7 = n − 1                           7 = −(n − 1)

8 = n                                7 = −n + 1

                                       n = −6

Answer:

[tex]\{-6\} \cup \{8\}[/tex]

Step-by-step explanation:

[tex]5 - |n - 1| = -2; \\ -|n - 1| = -2 - 5 \\ -|n - 1| = -7 \\ |n - 1| = 7 \\ \left \ [ {{n - 1 = 7} \atop {n - 1 = -7}} \right. \Leftrightarrow \left \ [ {{n = 7 + 1} \atop {n = -7 + 1}} \right. \Leftrightarrow \left \ [ {{n = 8} \atop {n = -6}} \right.[/tex]

Answer:

2/3

Step-by-step explanation:

that the ratio of that number

The missing step in the given solution to the inequality -x-3 < 13 + 3x is - 4x - 3 < 13

Incorrect steps:

- x - 3 < 13 + 3x

-4x < 16

X > -4

Correct steps:

- x- 3 < 13 + 3x

-x - 3x - 3 < 13

- 4x - 3 < 13

- 4x < 13 + 3

- 4x < 16

x < 16/-4

x > -4

Therefore, the missing step in the given solution to the inequality -x-3 < 13 + 3x is - 4x - 3 < 13

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The possible solutions using the Sine Law are given as follows:

Triangle A:
B = 50.26°

C = 79.74°

Triangle B:

B = 62.79°

C = 70.21°

The sine law asserts that the ratio of a triangle's side length to the sine of the opposing angle is the same for all three sides. The sine rule is another name for it.

Triangle A

Given the sine law:
a/SinA = b/SinB

Hence

Sin B = (b/a) SinA

Sin B = 15/10 (Sin 50)

Sn B = (15/10) * 0.766

Sin B = 1.5 * 0.766

B = Sin⁻1 (1.14)

B = 50.26°

Hence, C =

180 - B - A

= 180 - 50.26 - 50

C = 79.74°

Solution B

Given the sine law:

a/SinA = b/SinB

Hence

Sin B = (b/a) SinA

Sin B = 2/1.6 (Sin 47)

Sn B = 1.25 * 0.73

Sin B = 0.9125

B = Sin⁻1 (0.9125)

B = 62.79°

Hence,

C = 180 - 62.79 - 47

C = 70.21°

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The amount Cindy should increase for each dimension of the scaled model will be 12 meters.

The scale factor is defined as the proportion of the new image's size to that of the previous image. decision-making.

Given that:-

The scale model will be solved as follows:-

Present volume = 2 x 4 x 6 = 48 cubic meters

Let the lengths be increased by x meters now the new volume will be:-

( 2 + x ) ( 4 + x ) ( 6 + x ) = 48 x 84

( x² + 6x + 8 ) ( 6 + x ) = 48 x 84

( x³ + 44x + 12x² - 3984 ) = 0

By solving the cubic equation we will get the value of x = 12 meters.

Therefore the amount Cindy should increase for each dimension of the scaled model will be 12 meters.

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Answer:

Step-by-step explanation:

its A i just did it lol

The value of a is  0.10.

The value of b is 20.78.

The value of c is 0.02.

When two variables have inverse variation, the two variables move in opposite directions. If one variable increases, the other decreases.

p = 8.31 / V

V = 8.31 / p

a = 8.31 / 83.1 = 0.10

b = 8.31 / 0.4 = 20.78

c = 8.31 / 415.5 = 0.02

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Answer:

a= 0.1

b=20.775

c=0.10

Step-by-step explanation:

edge 2023

The number of those who attended the picnic was 8.

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = [tex]ax^{2} + bx + c[/tex] = 0 where a, b, c, ∈ R and a ≠ 0.

Such questions are best examples of quadratic equations where  the unknown is simply assumed to be a variable which when substituted according to the conditions yield a quadratic equation which can easily be solved.

Let x represent the whole population.

Total Spending = Rs. 96

Thus, each individual's contribution is equal to 96/x.

Four people did not show up causing

others to contribute Rs. 4 extra.

So the given condition can be written as

96/(x-4) – 96/x = 4

=>96x – 96(x-4) = 4x(x-4)

=> 96x -96x + 384 = 4x2 – 16x

=> 4x2 – 16x – 384 = 0

=> x2 – 4x – 96 = 0

=> (x – 12)(x + 8) = 0

=> x = 12 or x = -8 (neglect)

So x = 12

x-4 = 8  ( because  four of them did not turn up)

∴ The number of those who attended the picnic was 8.

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Answer: 36

Step-by-step explanation:

[tex]\overline{AB} \cong \overline{BC}[/tex] (Triangle ABC is isosceles)

[tex]m\angle CAB=m\angle CBA=30^{\circ}[/tex] (base angles of an isosceles triangle are congruent)

[tex]\angle MCB=90^{\circ}[/tex] (In triangle CMB, angles in a triangle add to 180 degrees)

[tex]\angle ACM=30^{\circ}[/tex] (triangle sum theorem)

[tex]MB=24[/tex] (30-60-90 triangle CMB)

[tex]AB=12[/tex] (sides opposite congruent angles in a triangle are congruent)

[tex]AB=36[/tex] (segment addition postulate)

The slope of the perpendicular line passes through C in GeoGebra.

GeoGebra is the software for the mathematical question for all levels of academics.

GeoGebra brings many mathematical problem solutions like geometry, algebra, spreadsheets, graphing, statistics, and calculus in one search engine.

Display the slope of and the slope of the perpendicular line passing through C.

Hence, the slope of the perpendicular line passes through C in GeoGebra.

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Answer:

See below

Step-by-step explanation:

x^2 +2x -8   =   (x-2)(x+4)

x^2 + 6x  - 16 = (x + 8)(x-2)        now you can cancel the ( x-2 ) to get

(x+4) / (x+ 8)