Solve the inequality.

IQR = Q3-Q1 = 53 - 36 = 17

your answer would be 147°

solution:

since ∠x and ∠y are supplementary angles. they must add up to 180°

so ∠+∠y=180°

     ∠x=180°-∠y

     = 180°- 33°

=147

Answer:

2≤7

Step-by-step explanation:

-7+9≤-2+9

2≤7

Answer:

it is the there'd one

if this is wrong sorry

The “Volume” in finance means total shares traded during a certain time frame option (B) is correct.

To make a profit, share traders buy and sell the stock of companies listed on the stock exchange.

The number of shares traded in a certain stock, index, or other investment during a given period of time is known as volume.

Thus, the “Volume” in finance means total shares traded during a certain time frame.

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Answer:

[tex]17\sqrt{7z}[/tex]

Step-by-step explanation:

[tex]7\sqrt{28z}+\sqrt{63z}\\ = 14\sqrt{7z}+3\sqrt{7z} \\= 17\sqrt{7z}[/tex]

Answer:

should be 872 in^2

Step-by-step explanation:

Answer:

Area = 872

Step-by-step explanation:

Formula for the surface area of a rectangular prism is

Plug in

Answer:

x=13.69

Step-by-step explanation:

154/30=5.13

33*5.13

plugin

13.69

The similarities and differences in a non-fiction text look at how the subject or events are portrayed.

Comparing non-fiction texts can focus on the similarities between the texts - things they have in common. You can also contrast texts and focus on their differences - things that set the texts apart from each other. You could compare and contrast the following:

Form – What types of text (letter, news report, etc) are they?

Purpose – What job (persuading, informing, advertising) is each text doing?

Audience – Who is the intended reader of the text?

Subject matter – What are the texts about?

Language choices – What kinds of words, images or rhetorical devices are being used?

Structure – How is the text ordered?

Tone – What is the overall tone or mood of the writing?

Non-fiction texts are all around us, and comparing them can help you become more aware of how language is being used in society. Comparing non-fiction texts can often prompt you to notice things that you might not have considered about a text in isolation.

Hence the similarities and differences in a non-fiction text look at how the subject or events are portrayed.

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The final matrix will be as follows   [tex]\rm D-C=\left[\begin{array}{ccc}12&-2&3\\3&1&-2\\\end{array}\right][/tex]

A matrix is a rectangular array or table of numbers, symbols, or expressions arranged in rows and columns in mathematics.

The calculation of the given matrix is as follows:-

[tex]\rm D-C= \left[\begin{array}{ccc}13&2&-5\\6&-4&0\\\end{array}\right] - \left[\begin{array}{ccc}1&4&-8\\3&-5&2\\\end{array}\right] \\[/tex]

[tex]\rm D-C= \left[\begin{array}{ccc}(13-1)&(2-4)&(-5+8)\\(6-3)&(-4+5)&(0-2)\\\end{array}\right][/tex]

[tex]\rm D-C=\left[\begin{array}{ccc}12&-2&3\\3&1&-2\\\end{array}\right][/tex]

Hence the final matrix will be as follows   [tex]\rm D-C=\left[\begin{array}{ccc}12&-2&3\\3&1&-2\\\end{array}\right][/tex]

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200

Step-by-step explanation:

1/5x -2/3y =30

Plug in 15 for y.

x-(15)= 30

2/3x of 2/3(15) is 10.

1/5x -10-30

Add 10 to each side.

1/5x = 40

Divide each side by 1/5.

(dividing by a fraction is the same as multiplying by its reciprocal...flip 1/5...*5)

x=200

The arrangement of items can be done with the use of permutation. The stacking of the number of books in the question can be done in 3,628,800 ways.

The arrangement of a given number of items can be done when definite numbers are to be considered at once by the use of permutation. A permutation is a mathematical method that can be used to determine the number of ways by which given items are to be arranged in a particular order.

Given that 10 books are to be stacked, the number of ways (n) that this can be done can be determined by:

n = 10!

  = 10 x 9 x 8 x7 x6 x5 x4 x3 x2x 1

n = 3,628,800

Therefore, the 10 books can be stacked in 3,628,800 ways.

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Check the picture below.

Make sure your calculator is in Degree mode.

g(-3) = 0.5 =

[tex] \frac{1}{2} [/tex]

[tex]\huge\mathfrak\colorbox{white}{}[/tex]

g(2) as defined = 2

[tex]\huge\mathfrak\colorbox{white}{}[/tex]

g(4)= 8-4 = 4

Given that :-

Prove that :-

Taking RHS :-

= sin 2B/(5 – cos 2B)] = [(2 tan B)/(1 + tan2B)]/ [5 – {(1 – tan2B)/(1 + tan2B)}]

= (2 tan B)/ [5(1 + tan2B) – 1 + tan2B]

= (2 tan B)/[5 + 5 tan2B – 1 + tan2B)

= (2 tan B)/(4 + 6 tan2B)

= (2 tan B)/[2(2 + 3 tan2B)]

= tan B/(2 + 3 tan B tan B)

Dividing the numerator and denominator by 2,

= [(1/2) tan B]/ [1 + (3/2) tan B tan B]

= [(3/2) tan B – tan B]/[1 + tan A tan B] {from (i)}

= (tan A – tan B)/(1 + tan A tan B)

= tan(A – B) = LHS

Answer:

As the two pack of ticket cost 17.24. Mean that the unit or the price of one pack will be half of it which is

8.62

Step-by-step explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

Answer:

the circumference of the circle is 50.24

Answer:

9

Step-by-step explanation:

Answer:

x = 30º

Step-by-step explanation:

Let's call the midpoint of OP, R.

The triangle of OQR would be an equilateral triangle since OQ = OR as they are both radii and is OQR and ORQ are 60º, ROQ is also 60º, making the triangle equilateral. Because tangents meet a circle at 90º, the angle RQP would be 30º and since angles on a straight line add to 180º, the angle QRP would be 180-ORQ which is 120º. Now we know the 2 angles in triangle of QRP so we can work out the final angle since angles in a triangle add to 180º. So:

180 - 120 - 30 = 30º.

x = 30º

This would also prove that QR and RP are the same since base angles in an isosceles triangle are equal.

Answer:

3. (3, 6)
4. (3, 7)
5. (3, 36)

Step-by-step explanation:

These are slope functions, so there's is no definite answer for x as it tells you to solve when x is 3. So put simply lets do that. Knowing that x is now 3, we can solve for all the functions. This will give you y, which is f(x) which just tells you the equations represents a function or slope on a graph. All these equations create lines. Solving for question 3, 3 + 3 is 6, so f(x) = 6, and the answer is (3, 6). For 4, you do 3 x 3 - 2, which is 9 - 2 = 7. So (3, 7). So on and so forth.

Answer:

number 1

Step-by-step explanation:

The car that travels for 7 hours and 50 minutes at an average speed of 130 km/h covered a distance of 1017.9 km.

The car travels for 7 hours and 50minutes at an average speed  of 130 km/h.

Therefore,

speed = distance / time

speed = 130 km/h

time = 7 hours 50minutes = 7 + 0.833333 = 7.83 hours

Therefore,

130 = distance / 7.83

cross multiply

distance = 7.83 × 130

distance = 1017.9 km

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The area of the face of a nickel 353.14 [tex]mm^{2}[/tex] (nearest hundredth)

The area of a circle is the amount of space enclosed within the boundary of a circle. The region within the boundary of the circle is the area occupied by the circle.

As the surface of nickel is in shape of 2-D circle.

radius of circle = [tex]\frac{21.21}{2}[/tex] = 10.605 mm

Area of circle= [tex]\pi r^{2}[/tex]

                      = 3.14* 21.21*21.21

                      = 353.143 [tex]mm^{2}[/tex]

                      = 353.14 [tex]mm^{2}[/tex] (nearest hundredth)

Thus, the area of the face of a nickel 353.14 [tex]mm^{2}[/tex] (nearest hundredth)

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Step-by-step explanation:

I'm not sure if I got the correct answer since English is not my first language

Answer:

120

Step-by-step explanation:

120 copies sold yesterday

Answer: 8,982,596 cm

Step-by-step explanation:

Rectangular Prism Volume = Height * Length * Width/base

238 cm * 113 cm * 334 cm = 8,982,596 cm

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[tex]\diamond\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]

          What is the slope-intercept form of 3x-2y=-16?

[tex]\diamond\large\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}[/tex]

✥ First, we need to subtract 3x on both sides, which results in

-2y=-16-3x

Or

-2y=-3x-16

[tex]\bigstar[/tex] Now, divide by -2 on both sides:-

[tex]\bold{(-2y):-2=(-3x-16):-2}[/tex]

On simplification,

[tex]\bold{y=\dfrac{3}{2} x+8}[/tex]

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Answer:

Angle ACD = 54° ( Angle standing on same arc at the circumference are equal )