Solve. Suppose that 1,000 students took a math examination wherein the maximum score that they can obtain is 100. Their average score is 70 with a standard of the deviation of 5. How many of the students obtained a score from 70 to 95?

Answers

Answer 1

Answer:

prolly like 689

Step-by-step explanation:

Answer 2

As per the given data, approximately 499 of the 1,000 students obtained a score from 70 to 95.

What is z-score?

A standardized score is an example of a z-score. A z-score is a measure of how far a data point is from the mean in a distribution.

To solve this problem, we need to calculate the number of students who obtained a score from 70 to 95.

First, we need to calculate the z-scores for these two scores using the formula:

z = (score - mean) / standard deviation

For a score of 70:

z = (70 - 70) / 5 = 0

For a score of 95:

z = (95 - 70) / 5 = 5

Next, we need to find the area under the standard normal distribution curve between these two z-scores using a standard normal distribution table or calculator.

The area between z = 0 and z = 5 is approximately 0.499, or 49.9%.

Finally, we can calculate the number of students who obtained a score from 70 to 95 by multiplying this proportion by the total number of students:

Number of students = proportion x total number of students

Number of students = 0.499 x 1000

Number of students ≈ 499

Therefore, approximately 499 of the 1,000 students obtained a score from 70 to 95.

For more details regarding standard deviation, visit:

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Part D

What do the measures of angles BDA and BEA and the fact that AD and AE are radii of circle A tell us about BD and BE



Font Sizes

Answers

Answer:

BD and BE are tangents to the circle

Step-by-step explanation:

Given

See attachment

Required

What does BD and BE represent?

From the attachment, we have:

[tex]\angle BDA = 90^\circ[/tex]

[tex]\angle BEA = 90^\circ[/tex]

[tex]Radii = AD\ and\ AE[/tex]

The measure of angles between a tangent and the radius of a circle is always [tex]90^\circ\\[/tex]

So, because [tex]\angle BDA = 90^\circ[/tex] and AD is a radius, then BD is a tangent to circle.

Similarly,; [tex]\angle BEA = 90^\circ[/tex] and AE being a radius implies that BE is a tangent to circle.

The radius of the a circle is:

is a line segment with its endpoints on the circle.

is a line segment from the center of a circle to a point on the circle

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Step-by-step explanation:

The radius of the a circle is:

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So, (b) part is the correct answer.

Hope it helps :) [tex].[/tex]

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2. Quotient

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