Find the mean of this data set: 2, 5, 5
Answer:
Mean = 4
Step-by-step explanation:
[tex]Mean = \frac{\sum x}{n} = \frac{2 + 5+ 5}{3} = \frac{12}{3} = 4[/tex]
Answer:
4
Step-by-step explanation:
Mean is average, so you would add every number up, then divide by the numbers you have, So 2+5+5 divided by 3 would be 4
List these from least to greatest π2, 12, √80
Answer:
π2,√80,12
Step-by-step explanation:
π2= 6.28
√80= about 8
12=12
Hope I could help!
Find the volume of a pyramid with a square base, where the perimeter of the base is
9.9 cm and the height of the pyramid is 8.6 cm. Round your answer to the nearest
tenth of a cubic centimeter.
The volume of a pyramid with a square base is 17.6 cubic centimeter.
Given the following data;
Perimeter of base = 9.9 cmHeight of pyramid = 8.6 cmTo find the volume of a pyramid with a square base;
Mathematically, the volume of a pyramid with a square base is given by the formula;
[tex]V = A(\frac{h}{3})[/tex]
Where;
V is the volume of a pyramid with a square baseA is the area of the square base.h is the height of the pyramid.First of all, we would determine the length of sides of the square base from its perimeter;
[tex]Perimeter \ of \ square = 4s\\\\9.9 = 4s\\\\s = \frac{9.9}{4}[/tex]
s = 2.475 cm
Next, we would determine the area of the square;
[tex]Area \ of \ a\ square = s^{2} \\\\Area \ of \ a\ square = 2.475^{2}[/tex]
Area of a square = 6.126 cm
Now, we would use the above value to find the volume of a pyramid with a square base.
Substituting the values into the formula, we have;
[tex]V = 6.126*(\frac{8.6}{3})\\\\V = 6.126*2.867[/tex]
Volume, V = 17.6 cubic centimeter
Therefore, the volume of a pyramid with a square base is 17.6 cubic centimeter
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z2+4z-165=(z-11)(z+-15)
Answer: look at the picture
Step-by-step explanation: Hope this help :D
hey! i’ll give brainliest please help
Answer:
The second option, external conflict w/other citizens who don't want the Cinema.
Step-by-step explanation:
Using the figure show, find the missing values. Round each value. Every time I put this up people get it wrong
Answer:
I'm sorry, I can help you with only this one :( ∠F = 44°
Step-by-step explanation:
∠F = 180° - (46° + 90°) = 44°
Ken recorded the weights (in pounds) of 78 boxes. He created a box plot of his data. What is the interquartile range of Ken’s data?
A) 8
B) 10
C) 17
D) 48
The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.
What is the interquartile range of a data?The interquartile range(IQR) = third quartile(Q3) - first quartile(Q1)
The third quartile of in the box plot given is : 56 pounds
The third quartile of the data as represented in the box plot given :
39 pounds
The interquartile range(IQR) of ken's data = 56 - 39
= 17 pounds
Hence, The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.
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An online music store offers 2 downloads for $7.50. Another online music store offers 12 downloads for $20.20 which store offers the better deal
Answer:
the second store has the better deal.
Step-by-step explanation:
12 ÷ 2 = 6
7.5 × 6 = 45
20.2 < 45
What is the perimeter of the triangle? Show your work.
Y
12
9
Answer:
36
Step-by-step explanation:
So to find the last angle first. The formula is a power 2+b power 2=c power 2
So 9 power 2 is 81 and 12 power 2 is 144
144+81=225
the square root of 225 is 15. So x is 15
No we just have to do 9+12+15=36.
36 is the perimeter
3
Select the correct answer.
Which data set has the greatest spread for the middle 50% of its data?
O A. {18, 13, 22, 17, 21, 24}
OB.
{17, 19, 22, 26, 17, 14}
Ос.
{13, 17, 12, 21, 18, 20}
D.
{18, 21, 16, 22, 24, 15)
Reset
Next
Answer:
D
Step-by-step explanation:
please reply within 10 minutes
Answer:
H
Step-by-step explanation:
For F - Median For Class 1 is 52.5 Median for Class 2 is 75 ( False )
For G - Range for class 2 is 75 Range for class 1 is 45.9 ( False )
For H - IQR for class 1 is 30.45 IQR for class 2 is 60 ( True )
For J - Minimum for Class 2 is 30 Minimum for Class 1 is 30 ( False )
Work out the size of the angle marked X.
Give your answer correct to 1 decimal place.
Answer:
41.8°
Step-by-step explanation:
We solve using the Trigonometric function of Sine
Hypotenuse = 15cm
x = θ
Opposite = 10cm
sin θ = Opposite/Hypotenuse
sin θ = 10/15
θ = arc sin ( 10/15)
θ = 41.810314896°
θ = Approximately to 1 decimal place = 41.8°
Therefore, x = θ = 41.8°
hey! i’ll give brainliest pls help.
Answer:
Life forms change over time
Step-by-step explanation:
Identify the following solid figure.
hexagonal prism
pentagonal prism
rectangular prism
triangular prism
QUICK PLEASE!!
The Answer is A. Hexagonal prism
God bless u! ❤️
The base is a hexagon
The top is also hexagon
The sides are rectangle
Hence the polygon is hexagonal prism
What is the total surface area of the square pyramid below?
A square pyramid. The square base has side lengths of 6 meters. The triangular sides have a height of 8 meters.
132 m2
144 m2
160 m2
228 m2
Answer:
144 m2
Step-by-step explanation:
The bisectors of the perpendicularity of the vectors
The spinner shown has congruent sections. The spinner is spun 63 times. What is a reasonable prediction for the number of times the spinner will land on a section that is shaded red?
Answer:
36 times
Step-by-step explanation:
Given
[tex]Red = 4[/tex]
[tex]Total = 7[/tex]
[tex]n = 63[/tex]
See attachment
Required
Predicted number of times to land on red
First, we calculate the probability of landing on red
[tex]Pr = \frac{Red}{Total}[/tex]
[tex]Pr = \frac{4}{7}[/tex]
The predicted number of red is the =n calculated as:
[tex]Red = Pr * n[/tex]
[tex]Red = \frac{4}{7}*63[/tex]
[tex]Red = 4 * 9[/tex]
[tex]Red = 36[/tex]
Please help me after this one I have one more
Answer:
3 2/21
Step-by-step explanation:
used a calculator
5. A construction area has 6 cylindrical posts protecting the
equipment. They are filled with sand to reinforce them. If each
cylinder is 4 feet tall and has a diameter of 1 foot, how much sand
was needed to fill the cylinders?
Record your answer and fill in the bubbles on your answer. (If it’s wrong or random you will be reported)
document. Be sure to use the correct place value.
Answer: what’s the answer ?
Step-by-step explanation:
If each cylinder is 4 feet tall and has a diameter of 1 foot then the amount of sand needed to fill the cylinders is 19 cubic feet.
Given that there are 6 cylindrical posts protecting the equipment
To find tge amount of sand needed for cylinders,
We need to find the volume of each cylinder.
The cylinder is 4 feet tall and has a diameter of 1 foot,
Height is 4 feet
Diameter is 1 foot and radius is 1/2 feet.
Volume of cylinder = πr²h
=3.14×(1/4)(4)
=3.142 cubic feet.
As there are six cylinders.
Multiply 6 with 3.142
Amount of sand needed = 6×3.142
= 18.852 cubic feet.
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I need answers asap.
You roll a 6-sided die.
What is P(divisor of 63)? Choose the closest answer.
Answer:
the divisors of 63 are
Step-by-step explanation:
1,3,7,9,21,63
Answer:
Fraction Form: 2/6 or 1/3
or Decimal Form: .333
or Percent Form: 33.333?%
Step-by-step explanation:
The divisors of 63 that are 1-6 is 1 and 3
So there are TWO numbers out of SIX.
We would turn that into the fraction 2/6 and then simplify (optional) it to 1/3.
Then we use 2/6 to convert it to multiple forms if needed.
Angel saved $100 a week for a year. She spent 40%
of her savings on a new bed. How much did she
spend on the bed?
Answer:
40 because 40 percent of 100 is 40. You can just multiply the number by the percentage $100x40%
Whoever solves it correctly will get 32 points
Simplify the expression and write any restrictions.
Answer:
Numerator :
[tex]8x^2 - 10x + 3 = 8x^2 -6x -4x + 3[/tex]
[tex]= 2x(4x -3)-1(4x -3) \\= (2x-1)(4x-3)[/tex]
Denominator :
[tex]6x^2 + 3x -3 = 6x^2 +6x -3x - 3[/tex]
[tex]=6x(x+1)-3(x+1)\\=(6x-3)(x+1)\\=3(2x-1)(x+1)[/tex]
[tex]\frac{8x^2-10x+3}{6x^2+3x -3} = \frac{(2x-1)(4x-3)}{3(2x-1)(x+1)} = \frac{(4x-3)}{3(x+1)}[/tex]
Can some help with this Math question .?
No linksss
Answer:
I think ir is 2 -2
Step-by-step explanation:
hope it helps
△JKL has vertices at J(−2, 4), K(1, 6), and L(4, 4). Determine whether △JKL is a right triangle. Explain. please with full calculations
Answer:
below
Step-by-step explanation:
basically find the line that connects JK and KL, and since its 2/3 and -2/3 which are not opposite reciprocals, the points dont form a right triangle
Liam puts 40$ in savings in March and 175% of this amount in savings in April. How much does Liam put in savings in April?
Answer:
$70
Step-by-step explanation:
You want 175% of $40.
175% as a decimal = 1.75
1.75 times 40 = 70
Therefore Liam put $70 in savings in April
Answer:
70
Step-by-step explanation:
Multiply 40$ by 175% :)
[tex]2h-3\ \textgreater \ 15[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\textsf{2h - 3 }\mathsf{>}\large\textsf{ 15}[/tex]
[tex]\large\text{ADD 3 to BOTH SIDES}[/tex]
[tex]\large\textsf{2h - 3 + 3 }>\large\textsf{ 15 + 3}[/tex]
[tex]\large\text{CANCEL out: \textsf{-3 + 3} because that gives you 0}[/tex]
[tex]\large\text{KEEP: \textsf{15 + 3} because it helps you solve for your h-value}[/tex]
[tex]\large\textsf{15 + 3 = \boxed{\large\textsf{\bf 18}}}[/tex]
[tex]\large\text{NEW EQUATION: \textsf{2h} }\mathsf{>}\large\textsf{ 18}[/tex]
[tex]\large\text{DIVIDE 2 to BOTH SIDES}[/tex]
[tex]\mathsf{\dfrac{2h}{2}>\dfrac{18}{2}}[/tex]
[tex]\large\text{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\text{ because it gives you 1}[/tex]
[tex]\large\text{KEEP: }\mathsf{\dfrac{18}{2}}\large\text{ because it gives you your h-value is being compared to}[/tex]
[tex]\large\text{NEW EQUATION: }\mathsf{h > \dfrac{18}{2}}[/tex]
[tex]\mathsf{\dfrac{18}{2}}[/tex]
[tex]\mathsf{= 18\div 2}[/tex]
[tex]=\boxed{\mathsf{\large\textsf {\bf 9}}}[/tex]
[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf h > 9}}}\huge\checkmark\\\\\boxed{\boxed{\rm \bf It\ it\ an\ O P E N E D\ circle\ shaded}}\\\boxed{\boxed{\rm \bf to\ the\ right\ starting\ at\ point\ 9}}\checkmark[/tex]
[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]
Let's solve![tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]
Add both sides by 3.[tex] \quad \quad \quad \quad\tt{2h - 3 + 3 > 15 + 3}[/tex]
[tex]\quad \quad \quad \quad\tt{2h \: \: \cancel{ \color{red}- 3 + 3} \: > 15 + 3}[/tex]
[tex]\quad \quad \quad \quad\tt{2h > 18}[/tex]
Divide it by 2.[tex]\quad \quad \quad \quad\tt{ \frac{2h}{2} > \frac{18}{2} }[/tex]
[tex]\quad \quad \quad \quad\tt{ \frac{ \cancel{ \color{red}2}h}{ \cancel{ \color{red}2}} > \frac{18}{2} }[/tex]
[tex]\quad \quad \quad \quad\tt{ h > \frac{18}{2} }[/tex]
[tex]\quad \quad \quad \quad\tt{ h > 9}[/tex]
Hence the answer is:[tex]\quad \quad \quad \quad \boxed{\tt { \color{green}h > 9}}[/tex]
________
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HELPPPPPPPPPPPP
ind the possibility that a random selected point within the circle falls in the red shaded area
Answer:
25cm
Step-by-step explanation:
one the possibility 36 - 11 =25 the answer is 25
I NEED HELP RIGHT NOW!!PLEASE!! π∆π ¶×¶
Find the RATIO and the EXACT VALUE of the given Cot A.
A right angled triangle with its side length is given. The sides of the triangle are 12ft , 13ft and 5ft. And we need to find out the value of cot A .
Here :-
Base = 12 ft .Perpendicular = 5ft. Hypotenuse = 13ft.We know :-
[tex]\tt\implies cot \theta = base / perpendicular [/tex]
Substitute the respective values :-
[tex]\tt\implies cot \theta = base / perpendicular\\\\\tt\implies\boxed{\red{\tt cot A = 12/5 }}[/tex]
Hence the required answer is 12/5.
A radio station broadcasts a signal over an area with a 120-mile diameter. The population density of the area is 100 people per square mile.
How many people are within receiving distance of the broadcast signal?
Use 3.14 for pi.
Answer:
1,130,400 people
Step-by-step explanation:
Find the area of the broadcasting area, using the circle area formula.
Since the diameter is 120 miles, the radius will be 60 miles.
Use the circle area formula, plug in 60 as r, and plug in 3.14 as pi:
A = [tex]\pi[/tex]r²
A = (3.14)(60²)
A = 11304
So, the area is 11304 square miles
To find how many people are in receiving distance, multiply this by 100, since there are 100 people per square mile.
11304(100)
= 1,130,400
So, 1,130,400 people are within receiving distance of the signal.
Answer:
1,130,400
Step-by-step explanation: