Solve 100x²+81=0 using square roots

Answers

Answer 1
the answer should be x=9i/10
Answer 2

Answer:

10

Step-by-step explanation:

The principal, real, root of:

100−−−√2

=10

All roots:

10

−10

100 is a perfect square


Related Questions


Find the equation of the line for the following
Find the equation of the line for the following: -) passing through (3, 2) with slope 4. 8) passing through (4, -2) and (5,6). - passing through (3,-1) and parallel to the line 6x +2y +4.

Answers

a) The equation of the line passing through the point (3, 2) with slope 4 is y - 2 = 4(x - 3).

b. The equation of the line passing through (4, -2) and (5,6) is y + 2 = 8(x - 4).

c) The slope of the line 6x +2y +4 is -3.

a. To derive the equation, we use the point-slope form of a linear equation: y - y₁ = m(x - x₁), where (x₁, y₁) represents the given point and m represents the slope.

Substituting the given values into the equation, we have:

y - 2 = 4(x - 3)

This equation can be further simplified if required.

b) The equation of the line passing through the points (4, -2) and (5, 6) can be found using the slope-intercept form, y = mx + b.

First, we calculate the slope (m) using the formula: m = (y₂ - y₁) / (x₂ - x₁).

m = (6 - (-2)) / (5 - 4) = 8.

Next, we substitute one of the given points and the calculated slope into the slope-intercept form:

y - y₁ = m(x - x₁).

y - (-2) = 8(x - 4).

Simplifying the equation:

y + 2 = 8(x - 4).

c) To find the equation of the line passing through the point (3, -1) and parallel to the line 6x + 2y + 4 = 0, we first need to determine the slope of the given line.

Rearranging the equation 6x + 2y + 4 = 0, we have:

2y = -6x - 4,

y = -3x - 2.

The given line has a slope of -3.

Since parallel lines have the same slope, the line we are looking for will also have a slope of -3. Using the point-slope form with the given point (3, -1), the equation becomes:

y - (-1) = -3(x - 3).

Simplifying:

y + 1 = -3(x - 3).

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Which of the following polynomials is reducible over Q 4x3³ + x - 2 5x³ + 9x² - 3 This option 3x³ - 6x² + x - 2 This option 08 O This option None of choices This option Activ 74°F Sun

Answers

None of the options are reducible polynomial

How to determine the reducible polynomial

From the question, we have the following parameters that can be used in our computation:

The list of options

The variable Q means rational numbers

So, we can use the rational root theorem to test the options

So, we have

(a) 4x³ + x - 2

Roots = ±(1, 2/1, 2, 4)

Roots = ±(1, 1/4, 2, 1, 1/2)

(b) 3x³ - 6x² + x - 2

Roots = ±(1, 2/1 ,3)

Roots = ±(1, 1/3, 2, 2/3)

(c) 5x³ + 9x² - 3

Roots = ±(1, 3/1 ,5)

Roots = ±(1, 1/5, 3, 3/5)

See that all the roots have rational numbers

And we cannot determine the actual roots of the polynomial.

Hence, none of the options are reducible polynomial


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Plzzz help me!!!!!!!!

Answers

w(2-3)+8w
=2w-3w+8w
=-w+8w
=7w.
Hope it will help you!

There are 60 apples and then add 59 apples two times . How many apples and there altogether

Answers

Answer:

Step-by-step explanation:

59 apples two times = 59 x 2 = 118 apples

Total apples = 118 + 60 = 178 apples

due soon! Please help :)

Answers

Answer:

Dining Hall = 24 square meters

Kitchen = 48 square meters

Together = 72 square meters

write 3^3 in expanded form and evaluate. can someone help me??

Answers

Answer:

27.

Step-by-step explanation:

3^3 = 3 * 3 * 3

= 9 * 3

= 27.

Answer:

IMAO YOU GAVE UP, PSY

Step-by-step explanation:

If the point (x,y) is in Quadrant IV, which of the following must be true?
x<0 and y>0
x>0 and y<0

Answers

The statement x > 0 and y < 0 must be true for any point (x, y) located in Quadrant IV.

If the point (x, y) is in Quadrant IV, it means that the x-coordinate is positive and the y-coordinate is negative. In Quadrant IV, the x-values are positive, as they are to the right of the y-axis, and the y-values are negative, as they are below the x-axis.

Therefore, the correct statement is:

x > 0 and y < 0.

In Quadrant IV, the x-values are greater than 0, indicating a positive x-coordinate, and the y-values are less than 0, indicating a negative y-coordinate. This is because in Quadrant IV, the x-axis is to the right of the y-axis, and the y-axis is below the x-axis.

Hence, the statement x > 0 and y < 0 must be true for any point (x, y) located in Quadrant IV.

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dentify all the steps necessary for graphing parametric equations? select all answers that apply. select one or more: a. draw arrows on the curve to show the direction the curve follows b. plot the points c. create a table d. solve the equations for t and plot that point e. connect the points with a dashed line f. connect the points with a smooth curve g. combine both equations into one equation in terms of t h. setup your coordinate plane with t on the horizontal axis

Answers

The steps necessary for graphing parametric equations include creating a table, solving the equations for t and plotting those points, connecting the points with a smooth curve, and setting up the coordinate plane with t on the horizontal axis (c, d, f, h).

Create a table: Choose a range of values for t and calculate the corresponding values for x and y using the parametric equations. List these values in a table.

Solve the equations for t and plot those points: Solve the parametric equations separately for t to obtain the x and y coordinates. Plot these points on the coordinate plane.

Connect the points with a smooth curve: Once all the points are plotted, connect them with a smooth curve. This curve represents the graph of the parametric equations.

Set up the coordinate plane with t on the horizontal axis: Label the horizontal axis as t and the vertical axis as either x or y. This allows you to visualize how the x and y values change with respect to the parameter t.

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The mean diastolic blood pressure of 144 individuals is 61 mmHg with a standard deviation of 10 mmHg Construct a 95% confidence interval for p. Select one: O a. (61.25, 62.63) O b. (-59.37, 60.59) O c. (59.37, 62.63) O d. (143.85, 145.56) O e. (-143.85, 145.56) Determine the success rate of the student from the following course list Course Score of student Standard Mean, deviation, Physics Mathematics 60 58 55 49 11 16 Select one: a. PHYS>MATH O b. PHYS=MATH = O c. NONE C. O d. MATH>PHYS

Answers

The the success rate of the student is PHYS>MATH. Therefore, the correct answer is Option A.

We can calculate the success rate of the student by calculating the z-score of each of the courses. The z-score is calculated as (x-μ)/σ, where x is the individual score, μ is the mean of the data, and σ is the standard deviation of the data.

For Physics, we have x=60, μ=49, and σ=11. So the z-score is (60-49)/11=1.09.

For Mathematics, we have x=58, μ=55, and σ=16. So the z-score is (58-55)/16=0.19.

Since the z-score of Physics is greater than the z-score of Mathematics, the student's success rate in Physics is greater than the student's success rate in Mathematics.

Therefore, the correct answer is Option A.

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i really need help so can you plz help meeee

Answers

Answer:

5/11 is 0.4555555555555555555555555

so basically the first option out of the two.

U do know you can just calculate this with the calculator right?

Adan took a test at school and completed it in an hour and a half. The test had two sections. If he took 45 minutes to complete the first Section, how much time did he use to finish the second section?

Answers

Answer:

45 minutes

Step-by-step explanation:

1 1/2 hours = 90 minutes

90 - 45 = 45

85 minutes is the correct answer

Actual sales for January through April are shown below.

Month Actual Sales (Yt)

January 18

February 25

March 34

April 40

May -

​Use exponential smoothing with α = .3 to calculate smoothed values and forecast sales for May from the above data. Assume the forecast for the initial period (January) is 18. Show all the forecasts from February through April along with the answer.

Answers

The forecasted sales for February through April are as follows:

February: 19.5, March: 25.65, April: 30.755. The forecasted sales for May is approximately 35.928.

Exponential smoothing is a time series forecasting method that assigns weights to past observations, with the weights decreasing exponentially as the observations get older. The smoothed value for a particular period is a weighted average of the previous smoothed value and the actual value for that period.

To calculate the smoothed values and forecast sales using exponential smoothing with α = 0.3, we start with the initial forecast for January, which is given as 18. Then, for February, we use the formula:

Smoothed value (February) = α * Actual sales (February) + (1 - α) * Smoothed value (January)

= 0.3 * 25 + 0.7 * 18 = 19.5

Similarly, for March:

Smoothed value (March) = α * Actual sales (March) + (1 - α) * Smoothed value (February)

= 0.3 * 34 + 0.7 * 19.5 = 25.65

And for April:

Smoothed value (April) = α * Actual sales (April) + (1 - α) * Smoothed value (March)

= 0.3 * 40 + 0.7 * 25.65 = 30.755

Finally, for the forecasted sales in May:

Forecasted sales (May) = Smoothed value (April) = 30.755

Therefore, the forecasted sales for May, using exponential smoothing with α = 0.3, is approximately 35.928.

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A person pushes a car with a force of 50 pounds. The car moves 5 feet into his garage. How much work was done?

Answers

Answer:

10

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

plllllzzz helppppppp

Answers

Answer:

5. B

6. A

7. C

Step-by-step explanation:

Answer:

5.) b. 12 - 2x

6.) a. 8x

7.) c. 5d + 3c = 66

Step-by-step explanation:

uhm, I don't really have proof, i've just been doing this for a long time, you're just gonna have to trust me on this one

4a=32



Fill in the blank:



a=___

Answers

Answer:

a = 8

Step-by-step explanation:

Divide both sides by 4.

a = 32 ÷ 4

a = 8

The first term of a geometric sequence is 8 and the fourth term is 216. What is the sum of the first 12 terms of the corresponding series? A. 2,125,760 B. 6,377,288 C. 236,192 D. 708,584

Answers

Answer:

2,125,760

Step-by-step explanation:

The first term (a) is 8

The fourth term is 216

Hence the sum of the first 12 term can be calculated as follows

= 8-8(3)^12/1-3

= 8-24^12/-2

= 2,125,760

The sum of first 12 terms is 2,125,760

Sum of the first 12 term  =  2,125,760

For geometric sequence,

aₙ = arⁿ⁻¹

where

a = first term

r = common ratio

n = number of terms

Therefore,

a = 8

a₄ = 216

let's find the common ratio

216 = 8 × r⁴⁻¹

216 = 8 × r³

r³ = 216 / 8

r³ = 27

r = [tex]\sqrt[3]{27}[/tex]

r = 3

Let's find sum of the first 12 terms.

Sₙ = a (rⁿ - 1) / r - 1

S₁₂ = 8(3¹² - 1) / 3 - 1

S₁₂ = 8(531440) / 2

S₁₂ = 4251520 / 2

S₁₂ = 2,125,760

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Suppose you have two similar trapezoids with a scale factor of 4. If the angle measures of trapezoid ABCD are 70,110,110,70, what is the answer?

Answers

Answer: 140,  220,  220,  140

Step-by-step explanation:

All you have to do is double the numbers.

please help me with this one!!

Answers

Answer:

V = 960 cm^3

Step-by-step explanation:

Volume of a rectangular prism = L * W * H

V = 12 * 8 * 10

V = 960 cm^3

Answer:

d. 960 cm^3

Step-by-step explanation:

The formula for volume is length x width x height. To solve you have to multiply 12 by 8 by 10 to get 960

An adult pass is 3 times as much as a child's pass. What is the cost of the adults pass? Write an expression for the situation

Answers

Answer:

however much the Child's pass is x 3 = Adult Pass cost

Step-by-step explanation:

In a survey of 100 men and 120 women, it was found that 40 of the men had group A blood. If sex and blood type are assumed to be independent variables, what is the expected number of women in the survey who have group A blood?

Answers

The expected number of women in the survey who have group A blood is 48.

To calculate the expected number, we assume that sex and blood type are independent variables. This means that the proportion of women with group A blood would be the same as the proportion of men with group A blood.

Out of 100 men surveyed, 40 had group A blood. This corresponds to a proportion of 40/100 = 0.4.

Since sex and blood type are assumed to be independent, we can assume that the proportion of women with group A blood is also 0.4.

To find the expected number of women with group A blood, we multiply the proportion by the total number of women surveyed:

Expected number of women with group A blood = Proportion of women with group A blood * Total number of women surveyed

Expected number of women with group A blood = 0.4 * 120 = 48

Therefore, the expected number of women in the survey who have group A blood is 48.

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the path of a projectile launched from a 16-ft-tall tower is modeled by the equation y = −16t2 64t 16. which is the correct graph of the equation?

Answers

The graph is a downward-opening parabola opening downward with its vertex at (2,0). Therefore, the correct option is C.

The equation y = -16t^2 + 64t + 16 represents the path of a projectile launched from a 16-ft-tall tower. To determine the correct graph, we can analyze the equation. The coefficient of t^2 (-16) is negative, indicating a downward-opening parabola. The coefficient of t (64) determines the horizontal shift of the graph, and in this case, t = 4 represents the maximum height of the projectile. The constant term (16) represents the initial height of the tower.

Considering these factors, we find that the correct graph of the equation is option C. It depicts a downward-opening parabola with its vertex at (2,0). The parabola starts at an initial height of 16 ft (the tower's height) and descends symmetrically from its vertex.

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1. What number is 20% of 40?

Answers

Answer:

8

Step-by-step explanation:

0.20 x 40 = 8

Therefore, 20% of 40 is 8

answer: 8

solving:
20x40
————
100

Graph y = -x^2 – 2. Identify the vertex of the graph. Tell whether it is a minimum or maximum.

Answers

Answer:

Maximum, and (0, -2)

Step-by-step explanation:

Peter makes 15 dollars an hour and he spends 25 dollars a day on transportation and food. Write an expression to describe his spendings and earnings in a day, where h is the number of hours that Peter works that day

Answers

15h - 25 dollars is an expression to describe his spendings and earnings in a day.

What is algebraic Expression?

Any mathematical statement that includes numbers, variables, and an arithmetic operation between them is known as an expression or algebraic expression. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.

Peter makes 15 dollars an hour, so if he works for h hours, he earns:

15h dollars

Peter spends 25 dollars a day on transportation and food, so his total spending can be expressed as:

25 dollars

Therefore, his total earnings minus his total spending can be expressed as:

15h - 25 dollars

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As a preliminary helper result, show by induction that for events E1, E2,..., EM, M P(E, or E2 or ... ог Ем) < Р(Еm). m=1

Answers

By applying the principle of inclusion-exclusion, we can show that for any events E1, E2,..., EM, the inequality P(E1 or E2 or ... or EM) < P(EM) holds. This result holds true for any integer M ≥ 1.

To prove the statement by induction, we will assume that for M = 1, the inequality holds true. Then we will show that if the statement holds for M, it also holds for M + 1.

Base case (M = 1):

For M = 1, we have P(E1) ≤ P(E1), which is true.

Inductive step:

Assuming that the inequality holds for M, we need to show that it holds for M + 1. That is, we need to prove P(E1 or E2 or ... or EM or EM+1) < P(EM+1).

Using the principle of inclusion-exclusion, we can express the probability of the union of events as follows: P(E1 or E2 or ... or EM or EM+1) = P(E1 or E2 or ... or EM) + P(EM+1) - P((E1 or E2 or ... or EM) and EM+1). Since events E1, E2, ..., EM, and EM+1 are mutually exclusive, the last term on the right-hand side becomes zero: P(E1 or E2 or ... or EM or EM+1) = P(E1 or E2 or ... or EM) + P(EM+1)

Since we assumed that P(E1 or E2 or ... or EM) < P(EM), we can rewrite the inequality as: P(E1 or E2 or ... or EM or EM+1) < P(EM) + P(EM+1)

Now we need to show that P(EM) + P(EM+1) < P(EM+1) for the inequality to hold. Simplifying the expression, we have: P(EM) + P(EM+1) < P(EM+1)

Since P(EM+1) is a probability and is always non-negative, this inequality holds true. Therefore, by the principle of mathematical induction, we have shown that for any integer M ≥ 1, the inequality P(E1 or E2 or ... or EM) < P(EM) holds.

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(- x * y) ^ 2 - 8x ^ - 7 * y ^ - 2

I need help fast!!!
What is the answer??

Answers

Answer:

answer is \/

Step-by-step explanation:

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

i'm really stuck on this part. once i figure out how i'll mark brainliest (however you spell it).

Answers

just the first one 11 ........

A method of assigning probabilities based upon personal judgment is referred to as the:
a. subjective method b. classical method c, Crelative frequency method
d, . non-probabilistic method.

Answers

A method of assigning probabilities based upon personal judgment is referred to as the subjective method. The correct answer is a.

The subjective method of assigning probabilities is based on personal judgment or subjective beliefs about the likelihood of events occurring. It involves incorporating individual knowledge, experience, and intuition to estimate the probabilities of different outcomes.

Unlike the classical method, which assigns probabilities based on equally likely outcomes, or the relative frequency method, which uses observed frequencies to determine probabilities, the subjective method relies on individual opinions and subjective assessments of probabilities.

In the subjective method, probabilities are not determined through mathematical calculations or empirical data. Instead, they are based on an individual's expertise, opinions, and subjective reasoning.

This method is commonly used in situations where objective data or historical information is limited or unavailable, such as in decision-making under uncertainty or when dealing with complex and uncertain scenarios.

The correct answer is a.

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According to a recent survey, the probability that the driver in a fatal vehicle accident is female (event F) is 0.2868. The probability that the driver is 24 years old or less (event A) is 0.1828. The probability that the driver is female and is 24 years old or less is 0.0576.

(a) Find the probability of FUA
(b) Find the probability of F'UA.

Answers

a. Using intersection of events probability of FUA is 0.0165

b. Using complement rule, the probability of F'UA is 0.9835

What is the probability of FUA?

To find the probabilities, we can use the given information and apply the appropriate probability rules.

(a) FUA represents the event that the driver is female, 24 years old or less, and is involved in a fatal vehicle accident.

We can calculate this probability using the formula: P(FUA) = P(F ∩ A), where ∩ denotes the intersection of events.

P(FUA) = P(F) * P(A|F)

Given information:

P(F) = 0.2868 (probability that the driver is female)

P(A) = 0.1828 (probability that the driver is 24 years old or less)

P(A|F) = 0.0576 (probability that the driver is 24 years old or less given that the driver is female)

P(FUA) = 0.2868 * 0.0576 ≈ 0.0165

Therefore, the probability of FUA is approximately 0.0165.

(b) F'UA represents the event that the driver is not female, 24 years old or less, and is involved in a fatal vehicle accident.

We can calculate this probability using the complement rule: P(F'UA) = 1 - P(FUA).

P(F'UA) = 1 - P(FUA) ≈ 1 - 0.0165 ≈ 0.9835

Therefore, the probability of F'UA is approximately 0.9835.

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Social Networking sites A recent survey of 10 social networking sites has a mean of 12.67 million visitors for a specific month. The standard deviation was 4 million. Find the 99% confidence interval of the true mean. Assume the variable is normally distributed. Round your answers to at least two decimal places.
______million <μ< _____million

Answers

The 99% confidence interval of the true mean is given as follows:

8.56 million < μ < 16.78 million.

What is a t-distribution confidence interval?

The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the equation presented as follows:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

The variables of the equation are listed as follows:

[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 99% confidence interval, with 10 - 1 = 9 df, is t = 3.2498.

The parameter values for this problem are given as follows:

[tex]\overline{x} = 12.67, s = 4, n = 10[/tex]

The lower bound of the interval is then given as follows:

[tex]12.67 - 3.2498 \times \frac{4}{\sqrt{10}} = 8.56[/tex]

The upper bound of the interval is then given as follows:

[tex]12.67 + 3.2498 \times \frac{4}{\sqrt{10}} = 16.78[/tex]

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