SLOPE-INTERCEPT FORM: PA
Xander has biked 2 miles so far this week and plans to bike an
average of 6 miles each day over the next several days. Xander
wrote the equation and created the graph to represent x, the number
of days and y, the total number of miles traveled on his bike.
a. Find the slope of the graph. Where do you see this value in
Xander's equation?
b. What value does the graph touch on the y-axis? Where do you
see this value in Xander's equation?

As per the concept of probability, there are 7776 different lottery numbers are possible.

Probability:

Probability means the concept that is based on the possible chances of something to happen.

Given,

Lottery numbers in a particular state consist of 5 digits. Each lottery cube that is drawn/rolled has six sides, numbered 1-6.

Here we need to find how many different lottery numbers are possible.

Through the given question we know that,

The number of digits in a lottery ticket = 5

Side in cube = 6

So, in each time they will roll the dice 5 times to get one number.

So, the possible options of that event are,

For the first time we have 6 options

Second time we got 6 options

Third time also we got six option

Fourth time = 6 options

Fifth time = 6 options.

Therefore, it can be written as,

=> 6 x 6 x 6 x 6 x 6

=> 6⁵

=> 7776.

Therefore, there are 7776 different lottery numbers are possible.

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The given expression is,

Opening the brackets and multiplying each term inside the bracket with 5, we get,

The simplified expression is 15k = 35 and the value of k is 2.33.

F is the correct answer (option A) that is, the relation is like many to one. So, it is a function.

Given mapping diagram that represents the relation.

We have to determine whether the relation is a function.

(-8, -6), (-5, 2), (-8, 1), (7, 3)

Here,

Domain = (-8, -5, 7)

Range = (-6, 2, 1, 3)

A function is a relation where each input has only one output.

Here,

F. The relation is like many to one. So, it is a function.

G. The relation is many to one. So, it is a function.

H. The relation is one to many. It is not a function.

G. The relation is one to many. It is not a function.

So, F is the correct answer (option A) that is, the relation is like many to one. So, it is a function.

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Answer:

a = 12.5 m/s2

Step-by-step explanation:

anwser 12.5

Answer:

-3/9 or -1/3

Step-by-step explanation:

:]

Answer:   -1/3

Step-by-step explanation- To subtract fractions, you first make the the denominators the same. The denominator is the bottom number. To make the denominator the same, you look for the lowest common denominator. Making the answer -1/3

Answer:

Step-by-step explanation:

9*(15/2)[2+14] = 9*15*16 = 2160.

Answer:

Step-by-step explanation:

[tex]\frac{150}{x} =tan72 \\x=150 cot~72=150 cot(90-18)=150 ~tan ~18 \approx 48.74 ~meteres[/tex]

We are given the following expression:

To simplify the expression, we will first use the distributive property on the parenthesis, like this:

Solving the operations:

Now we add like terms:

Solving the operations:

This is the most simplified form of the equation

With the help of Linear equation we can say that  Damion added 12 on both sides.

The given equation was,

If we will add 12 on both sides ,

Hence we can say that Damion added 12 to both sides.

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In an isosceles triangle, there are

2 legs (equal sides)

1 base

The 2 legs are the equal sides

The base is the third side

In the isosceles triangle ABC:

Since AB = BC, then

AB and BC are the legs of the triangle, then

AB and BC are called legs

The answer is d

The amount of bond amortization for each six month period is [tex]\$225[/tex].

In the given question,

Towson Corporation issued [tex]\$150,000[/tex] of [tex]7\%[/tex] ten year bonds at [tex]103[/tex] on the semi-annual interest date.

Towson uses the straight line method to amortize any bond premium or discount.

We have to find the amount of bond amortization for each six month period.

Cash issued [tex]=\$150,000[/tex]

Rate [tex]=7\%[/tex] ten year bond at [tex]103[/tex] n the semi-annual interest date.

So the cash proceed on issue of bond = Cash issued [tex]\times103[/tex] [tex]/100[/tex]

Cash proceed on issue of bond [tex]=\$150,000\times\frac{103}{100}[/tex]

Firstly simplifying ratio

After simplification of ratio

Cash proceed on issue of bond [tex]=\$150,000\times1.03[/tex]

Now simplifying after multiplication

Cash proceed on issue of bond [tex]=\$154,500[/tex]

Hence, the cash proceed on issue of bond is [tex]\$154,500[/tex].

Now we find the premium that issued in the bond.

Premium on issue of bond [tex]=\$154,500-\$150,000[/tex]

Simplifying

Premium on issue of bond [tex]=\$4,500[/tex]

Hence, the premium on issue of bond is [tex]\$4,500[/tex]

Now finding the amount of bond amortization for each six month period.

Bond Amortization = (Premium on issue of bond/10 years) * 1/2

Bond Amortization [tex]=(\frac{\$4500}{10})\times\frac{1}{2}[/tex]

Simplifying the ratio

Bond Amortization [tex]=\$450\times0.5[/tex]

Bond Amortization [tex]=\$225[/tex]

Hence, the amount of bond amortization for each six month period is [tex]\$225[/tex].

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Answer:

x=55

Step-by-step explanation:

2x+6+x+9=180

3x=165

x=55

:]

Given,

1)P(A) = 0.25

P(B) = 0.65

The value of P( A or B) is,

Hence, option d is correct.

2)P(A) = 0.45

P(B) = 0.35

The value of P( A or B) is,

Hence, option c is correct.

Given:

The initial investment is, P = $720.

The rate of interest is, r = 7.8% = 0.078.

The number of years of investment is, t = 6 years.

Explanation:

The general formula to find the compound interest is,

Here, n represents the number of times compounded in a year. It is given that the amount is compounded monthly, so the value of n = 12.

To find total amount after 6 years:

Now, substitute the given values in the general equation.

Thus, the total amount earned is $1147.95.

To fnd interest amount:

Now, the amount of interest can be calculated as,

Hence, the interest amount earned is $427.95 and the total amount earned is $1147.95.

Given:

Total number of cookies is, N = 36.

Number of friends is, n(f) = 8.

The objective is to find the number of cookies (c) will each of them get while sharing.

Consider the required number of cookies to each person as (c).

The value of c can be calculated as,

Hence, each of them will get 4 and a half cookies.

Answer:

A" (2, 12)

B" (8,8)

C" (6, 4)

Step-by-step explanation:

For each point P(x, y) of the image, the translations are as follows:

Translate P(x, y) by <2, 3> [tex]\longrightarrow[/tex] P'(x + 2, y + 3) [tex]\longrightarrow[/tex] P'(x', y')

Dilate P'(x', y') by 2 [tex]\longrightarrow[/tex] P'' (x'', y'') [tex]\longrightarrow[/tex] P(2x', 2y')

Point      [tex]\longrightarrow[/tex]           Translate <2, 3>                   [tex]\longrightarrow[/tex]       Dilate by 2

A(-1, 3)    [tex]\longrightarrow[/tex]         A'(-1 +2, 3 + 3) =>  A'(1, 6)       [tex]\longrightarrow[/tex]            A''(2, 12)

B(2, 1)     [tex]\longrightarrow[/tex]         B'(2 + 2, 1 + 3) =>  B'(4, 4)       [tex]\longrightarrow[/tex]           B"(8, 8)

C(1, -1)    [tex]\longrightarrow[/tex]          C'(1 + 2, -1 + 3) =>  C'(3, 2)     [tex]\longrightarrow[/tex]            C"(6, 4)

The value of x is equal to 10 and the exterior angle to angle d is equal to 141 degrees.

To solve this problem, we have to recall that the sum of angles in a triangle is equal to 180 degrees.

Applying that formula here;

[tex]m < d + m < e + m < f = 180^0\\(2x + 19) + (3x + 24) + 87 = 180\\x = 10[/tex]

But the exterior angle to angle D can be found assuming the angle lies on a straight line, then the sum of angle D and it's exterior angle would be equal to 180 degrees.

Let y = exterior angle

[tex]m < d + y = 180\\2x + 19 + y = 180\\x = 10\\2(10) + 19 + y = 180\\20 + 19 + y = 180\\39 + y = 180\\y = 141^0[/tex]

The value of the exterior angle to d is equal to 141 degrees.

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Answer: its C

Step-by-step explanation: i got it right

First, let's calculate the area of the triangle.

Now let's calculate the area of the semicircle.

The total area of the figure is:

24+25.12 ft2 = 49.12 ft2

we have that

TLy+TRy=20,290 ------> equation A

and

sin(24.3)=TLy/TL

TLy=TLsin(24.3) ------> equation B

sin(44.5)=TRy/TR

TRy=TRsin(44.5) ------> equation C

and

TLx=TRx

TLcos(24.3)=TRcos(44.5)

TL=TRcos(44.5)/cos(24.3) --------> equation D

substitute equation B and equation C in equation A

TLsin(24.3)+TRsin(44.5)=20,290 -------> equation E

substitute equation D in equation E

(TRcos(44.5)/cos(24.3))sin(24.3)+TRsin(44.5)=20,290

solve for TR

factor TR

TR[cos(44.5)/cos(24.3))sin(24.3)+sin(44.5)]=20,290

TR=19,835 pounds

Find TL

TL=(19,835)cos(44.5)/cos(24.3)

TL=

The formula for the margin of error is

The critical value for 95% confidence interval is 1.96

The standard error is

To know which of the list of options will yield approximately the desired margin of error, we will have to calculate the margin of error with the following values

For 110 trees, n= 110, standard dev. =16

For 144 trees, n=144, standard dev=16

For 43 trees, n=43 , standard dev.=16

For 87 trees, n= 87, standard dev=16

Hence, from the above calculations, the most prefered is the sample size of 110 trees (because the margin of error of 2.9988 is approximately 3 )

Answer is 110 trees

The given statement is false: vertical angle do not depend on the line being parallel. A pair of vertical angles are always congruent.

Vertical angle:

Vertical angle means that the angles opposite each other when two lines cross.

Given,

Here we have the diagram and we also know that angle 7 is congruent to angle 5.

Now we need to find the given statement is true or not.

Through the given diagram, we have identified that, the eight angles will together form four pairs of corresponding angles.

Angles 1 and 5 constitutes one of the pairs.

We know that all the corresponding angles are congruent.

All angles that have the same position with regards to the parallel lines and the transversal are corresponding pairs e.g. 3 + 7, 4 + 8 and 2 + 6.

Through that we know that basically, the vertical angles are always congruent, which means that they are equal. So, it is not necessary for them to be parallel.

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The technique of repeated addition involves combining equal groups.

4 x ( -3) = 12.

Repeated addition is the combining of equal groupings. It offers a basis for comprehending multiplication. For instance, 3 x 5 can be expressed as 5 + 5 + 5 to represent 3 groups of 5 counters.

We have been given that

4 x ( -3) = 12

By using repeated addition for multiplication

Add 4 three times or add 3 for times ..

In question negative 3 is given so we add negative 4 , three times

(-4) + (-4) + (-4)

-12.

Or

Add negative 3 , four times

(-3) + (-3 )+ (-3) + (-3)

-12.

Hence, we solved given multiplication by the using repeated addition method.

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The value of 6 to the negative 3rd power times 6 to the 2nd power times 6 to the 5th power times 6 is 6^5.

The exponent is the number of times that a number is multiplied by itself. It should be noted that the power is an expression which shows the multiplication for the same number. For example, in 6⁴ , 4 is the exponent and 6⁴ is called 6 raise to the power of 4.

Based on the information given, the numbers will be expressed as:

6^-3 × 6^2 × 6^5 × 6

= 6^5

It's important to note that they've the same base. Therefore, the powers will be added thus:

= -3 + 2 + 5 + 1

= 5

This gives 6^5. This illustrates the concept of exponents.

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Answer:

  (a) graph with line through (90, 60)

Step-by-step explanation:

You want a graph of the proportional relationship between sit-ups and seconds if a student can do 40 sit-ups in 60 seconds.

Seconds are plotted on the x-axis, and sit-ups are plotted on the y-axis The graph will match that shown in the attachment.

<95141404393>

This video from khan academy should clear up your confusion on scale factors.

https://www.khanacademy.org/math/7th-engage-ny/engage-7th-module-1/7th-module-1-topic-d/v/identifying-scale-factors

The safe load, L of a wooden a beam 3 in. wide 9 in. deep and 11 ft long of the same material support is 307.17

Analyzing the given conditions in the question, we get

The safe load, L is directly proportional to width (w) and square of depth (d²)

also,

L is inversely as length (l) i.e L = k/l

combining the above conditions, we get an equation as:

L = k(wd²/l)

now, for the first case we have been given

w = 8 in

d = 6 in

l = 10 ft

L = 1966 lbs

thus,

1966 lb = k ((8 × 6²)/10)

or

k = 68.26 lbs/(ft.in³)  

Now,

Using the calculated value of k to calculate the value of L in the second case  

in the second case, we have

w = 3 in

d =9 in

l = 11 ft

Final Safe load L' =  68.26 × (6 × 3²/12)

or

L' =307.17 lb

Therefore, The safe load, L of a wooden a beam 3 in. wide 9 in. deep and 11 ft long of the same material support is 307.17

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