Since Allura Red is red in color, why did we choose to use monitor the wavelength of 470 nm? does allura red transmit or absorb red light ?

Explanation:

(a) The car will leave tangentially to the road, so it will take path d.

(b) Sum of forces on the car in the vertical direction:

∑F = ma

N − mg = 0

N = mg

Sum of forces on the car in the centripetal direction:

∑F = ma

Nμ = m v²/r

mgμ = m v²/r

gμ = v²/r

v = √(grμ)

The maximum velocity is independent of mass, so adding sandbags will not work.

Answer:

R = 52.08 cm

Explanation:

given data

tangential velocity v = 21.3 m/s

radial acceleration aR = 871 m/s²

solution

we will get here length of her arm from the pivot point at her shoulder so

here we know aR = [tex]\frac{v^2}{R}[/tex]     ........................1      

so put here value and we get

871 = [tex]\frac{21.3^2}{R}[/tex]  

R = 0.5208840 m

R = 52.08 cm

Answer:

Explanation:

linear speed of ball v = 21.3 m /s

radial acceleration = 871 m /s²

radial acceleration = v² / R

where R is length of arm which acts as radius of circular path of the ball .

Putting the values

21.3² / R = 871

R = .52 m.

Answer:

mass of the block is 7.2Kg

Tension on string A = 72N

Tension on the string with an angle is =  108N

Explanation:

The Horizontal string will have the cos component of the force...

Hence, mg cos60 = 36

by keeping acceleration due to gravity = 10 m/s^2, we get,

m = 7.2Kg

The tension in String A = mg = 7.2*10 = 72N

since the whole string holding the block is pulled by another string with 36 N

the resultant force will be the tension of the string with an angle.

Hence, 72 +36 = 108 N

Please let me know whether I got this right or not...

Answer:

F = 1.6 N

Explanation:

Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:

F = ma

where,

F = Force Required to Move the Object Upward = ?

m = mass of object

a = upward acceleration = 2 m/s²

but, we know that weight of object is given as:

Weight = mg

8 N = m(9.8 m/s²)

m = 0.8 kg

using values in the equation:

F = (0.8 kg)(2 m/s²)

F = 1.6 N

Answer:

18*10^10 meters

Explanation:

V= d/t         10 mins = 600 seconds

3*10^8 = d/600s

(3*10^8)*(6*10^2) = d

d = 18*10^10 m

Answer:

plz give the question... floor the proper answer

Explanation:

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me and follow ma

Answer:

the full segment is:  30 units long

which coincides with answer C in your list

Explanation:

If M is the midpoint, then it divides the segment in two equal parts. Then, we can say that:

RM = MS (equality among the two parts of the divided segment)

replacing RM with "5 x" and MS with "x + 12", we get:

5 x = x + 12

solving for x:

5 x - x = 12

4 x = 12

then x = 3

With this info, we can calculate the length of each half of the segment and consequently its full length:

RM = 5 x = 5 (3) = 15

then the full segment is:  30 units long

Answer:

a) we can form a triangle in order to use the Pythagorean theorem = 3² + 1² = h²

h² = 9 + 1 = 10

h = √10

h = 3.1623 blocks

we must also find the angle at the initial point of the triangle (A):

tan⁻¹ (1/3) = 18.43°    

the position relative to her starting position is 90° - 18.43° = 71.57° north of east

b) total distance traveled = 6 + 3 + 7 = 16 blocks

Answer:

Resultant = 13km

Direction = 67.38° East of North

Explanation:

Given the following :

5km North ; 12km East

Resultant Displacement (r) :

r² = 5² + 12²

r² = 25 + 144

r² = 169

r = √169

r = 13

Direction:

Tangent = opposite / Adjacent

Tanθ = opposite / Adjacent

Opposite = 12 ; adjacent = 5

Tanθ = (12/5)

Tanθ = 2.4

θ = tan^-1(2.4)

θ = 67.38° east of north

Answer:

The wavelength of the wave is 1 m

Explanation:

Given;

mass of the string, m = 20 g = 0.02 kg

length of the string, L = 3.2 m

tension on the string, T = 2.5 N

the frequency of the wave, f = 20 Hz

The velocity of the wave is given by;

[tex]v = \sqrt\frac{T}{\mu} {}[/tex]

where;

μ is mass per unit length = 0.02 kg / 3.2 m

μ = 6.25 x 10⁻³ kg/m

[tex]v = \sqrt{\frac{T}{\mu} } \\\\v = \sqrt{\frac{2.5}{6.25*10^{-3}} } \\\\v = 20 \ m/s[/tex]

The wavelength of the wave is given by;

λ = v / f

λ = (20 m/s )/ (20 Hz)

λ = 1 m

Therefore, the wavelength of the wave is 1 m

Given:-

To Find: Speed of it.

We know,

v = s/t

where,

Putting the values,

v = (20 m)/(4 s)

→ v = 5 m/s (Ans.)

The speed of an object will be "5 m/s".

The given values are:

Distance,

Time,

As we know, the formula:

→ [tex]Distance (d)= Speed (v)\times Time (t)[/tex]

or,

→ [tex]Speed (v) = \frac{Distance (d)}{Time (t)}[/tex]

By putting the values, we get

→                [tex]= \frac{20}{4}[/tex]

→                [tex]= 5 \ m/s[/tex]

Thus the above answer is correct.

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Answer:

C

Explanation:

The 15N object has more mass than the 10N object.

A 15 N object has more mass than the 10 N object due to their weight differences.

Weight is defined as the force exerted by the earth on an object on the surface of earth. The direction of this force is directed towards the center of earth. Mathematically -

W = mg

Where -

m is the mass of body

g is the acceleration due to gravity

Weight can also be written as -

W = ρVg     [ρ is density and V is volume]

Given is a person who dropped two objects from the same height. One object weighs 15 N and the other weighs 10 N.

We can write -

Weight of Object 1 [W1] = 15 N

Weight of Object 2 [W2] = 10N

We know that -

W = m x g

We can write it as -

m = W/g

Therefore -

Mass of Object 1 [M1] = 15/9.8 = 1.53 Kg

Mass of Object 2 [M2] = 10/9.8 = 1.02 Kg

Clearly -

M1 > M2

So, the 15 N object has more mass than the 10 N object.

Therefore, a 15 N object has more mass than the 10 N object due to their weight differences.

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Explanation:

...................,..........

Newton's first law states that at rest the sum of the forces acting on a body is zero

The distance S to which the painter can climb is approximately 2.55 meters

The reason the above value for the distance is correct is as follows:

The given parameter are;

The mass of the painter, m₁ = 90 kg

Length of the ladder, l = 4 m

The mass of the ladder, m₂ = 15 kg

The coefficient pf static friction, μ = 0.25

Friction force, [tex]\mathbf{F_f}[/tex] = Normal reaction, N × μ

Normal reaction (flat surface), N = Weight of painter + Weight of ladder

N = m₁·g + m₂·g

Where;

g = The acceleration due to gravity, g = 9.81 m/s²

N = 90 kg × 9.81 m/s² + 15 kg × 9.81 m/s² = 1,030.05 N

∴ [tex]\mathbf{F_f}[/tex] = 1,030.05 N × 0.25 = 257.5125 N

Friction force, [tex]\mathbf{F_f}[/tex] = 257.5125 N (Horizontal force)

At equilibrium, the sum of the  horizontal forces = 0

∴ Fₓ + [tex]\mathbf{F_f}[/tex] = 0

Fₓ = [tex]-F_f[/tex] = -257.5125 N (Acting opposite to the direction of the friction force)

The height of the top of the ladder from the ground, h = √(4²-1.5²) = √(13.75)

Taking moment about point A gives;

Clockwise moment = Anticlockwise moment

Fₓ × h = m₁·g·s·cos(θ) + m₂·g·(l/2)·cos(θ)

Therefore;

Fₓ × √(13.75) m = 90 kg × 9.81 m/s² × s × (1.5/4) + 15 kg × 9.81 m  × 2 m × (1.5/4)

Fₓ × √(13.75) m = 331.0875 N × s + 110.3625 J

257.5125 N × √(13.75) m = 331.0875 N × s + 110.3625 J

s = (257.5125 N × √(13.75) m - 110.3625 J)/(331.0875 N) ≈ 2.55 m

The distance to which the 90 kg painter can climb without causing the 4 m ladder to slip at its lower end, A, distance S ≈ 2.55 meters

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Answer:

16.7m/s

Explanation:

Using v= u+ at

V = final velocity. U = initial velocity

So since the two movements are the same they will return with the same speed they went up

Then final velocity v= 0

So

0:= u +-9.8 x 1.7

U= 16.7m/s

Explanation:

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.2 m/s²

Find: v

The problem does not involve time.  Therefore, the required equation is:

v² = v₀² + 2aΔx

Plug in values and solve:

v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)

v = 4.47 m/s

The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity (which is 0 in this case as the car starts from rest)

a = acceleration

s = distance traveled

Plugging in the values into the equation:

v² = 0² + 2(0.2)(50)

v² = 0 + 20

v² = 20

Taking the square root of both sides:

v = √20

v = 4.47 m/s

Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

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Answer:

[tex]V_1=2mL[/tex]

Explanation:

Hello,

In this case, considering this as a dilution problem, the first step here is to consider that the moles of tetrodotoxin remains the same and just the volumes and concentrations are modified from the initial stock (1) and the required dilution (2):

[tex]V_1M_1=V_2M_2[/tex]

Whereas V is referred to volume and M to molar concentration, in this case in mM. In such a way, solving the V1 as the volume of the 3-mM solution we obtain:

[tex]V_1=\frac{V_2M_2}{M_1} \\\\V_1=\frac{6mL*1mM}{3mM} \\\\V_1=2mL[/tex]

It means you need 2 mL of the 3-mM solution.

Best regards.

Momentum = (mass) x (speed)

We don't know the mass of the bowling ball, but we know how much it weighs.  So if we knew the acceleration of gravity in the place where the ball is, we could calculate its mass.  The question doesn't tell us what planet the bowling ball is on.  So if we only use the information given in the question, there's no way to find the answer, and we're stuck here.

But I urgently need the points, so I'm going to go out on a limb here and make a big assumption:  I'll assume that the alley where this ball is rolling and bowling is located on planet Earth, where the acceleration  of gravity is around  9.8 m/s²  everywhere on the planet's surface.  NOW I can go ahead and answer the question that I just invented.

weight = m  g

Mass = (weight) / (g)

Mass = (78.0 N) / (9.8 m/s²)

Mass = 7.96 kilograms

Momentum = (mass) x (speed)

Momentum = (7.96 kg) x (8.00 m/s)

Momentum = 63.7 kg-m/s

Answer:

1. a = 9.8 m/s²

2. t = 4.28 s

3. Vf = 42 m/s

4. Vf = 28 m/s  

Explanation:

1.

Since, the body is under free fall motion. Therefore, the value of its acceleration shall be equal to the acceleration due to gravity.

a = 9.8 m/s²

2.

The time taken by the ball to reach the ground can be calculated by using second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 90 m

Vi = initial velocity = 0 m/s

t = time taken = ?

Therefore,

90 m = (0 m/s)t + (1/2)(9.8 m/s²)t²

t = √(18.36 s²)

t = 4.28 s

3.

In order to find final velocity we use first equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(4.28 s)

Vf = 42 m/s

4.

when the ball is at height of 50 m, it means it has covered:

h = 90 m - 50 m = 40 m

we use third equation of motion at this point:

2gh = Vf² - Vi²

(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²

Vf = √(784 m²/s²)

Vf = 28 m/s

Answer:

A. Dependent variable

Explanation:

In a graph showing how temperature of a material changes over time, temperature is taken on y-axis and time is taken on x-axis. It shows how temerature altered as the time changes.

In temperature-time graph, temperature is directly dependent on time. With the increase in time, temperature rises, falls or remains constant. It implies that temperature is dependent variable that depend on time.

Hence, the correct option is (A).

Answer:

c

Explanation:

Answer:

the answer is c i just did it

Explanation:

Answer:

Explanation:

Let the internal resistance be r .

Since in open circuit the volt is 1.55 V , this will be the source voltage .

Source voltage = 1.55

If external resistance be R .

1.55 / (R + r ) = .500

R + r = 3.1 ohm

So sum of internal resistance and external resistance will be 3.1 ohm.

Answer:

Open and globular

Explanation:

Answer:

240 meters

Explanation:

He is walking 2 meters per second, and there are 60 seconds per minute. There are 120 seconds in two minutes. So, 120 x 2 = 240. That's your answer!

Answer:

Explanation:

If a positive charge enters a magnetic field at 90 degrees the charge is deflected in a circular path by a force that acts perpendicular to it in line with Flemings right-hand rule

to derive the radius of the path of the charge we apply

F= mv^2/r=Bev

where

m= mass of the electronic charge

e=charge

B=magnetic field

v=average speed

r=radius

rearranging we have

r=mv^2/Bev

r=mv/Be

Answer:

towards the center of the circle

(which appears to be the last option in your list of possible answers)

Explanation:

The centripetal force points always towards the center of the circle described by the object moving.

The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.

The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.

Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.

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Answer:

A

Explanation:

Answer: a. Stall AOA increases, CL max increases.

Explanation:

Deploying slats or slots on an airfoil affect CL max and Stall AOA by increasing Stall AOA and also increasing CL max.

It should be noted that the coefficient of lift CL would rise through the use of slots due to increase in boundary later energy. The slots also leads to delay of stall by through increase in AOA.