shows three ropes tied together in a knot. one of your friends pulls on a rope with 3.0 units of force and another pulls on a second rope with 5.0 units of force.

To determine the force constant (k) of a spring, we need to perform an experiment which requires a retort stand and clamp, a spiral spring, a meter rule and different weights.

Force constant of the spring or the spring constant can be defined as the stiffness of the spring.

The setup is arranged as shown in the image attached as Fg.1.

The natural length of the spring is first recorded. Different weights are added to the spring one after the other and the extension is recorded, each time when the different weights are added simultaneously

The weight is now plotted on the vertical axis and the extension is plotted on the horizontal axis. The slope of the graph is the force constant of the spring.

The graph is shown in the image attached as Fig.2

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The spring constant, k, in Hooke's Law has units of Newton per meter since it is a constant for the force applied per unit of length. The spring constant measures how strong and stiff the spring is. Hope this answers the question. Have a nice day.

The distance covered by the train is 225m.

Given,

u = 36km/hr = 10ms^(-1)

a = 5ms^(-2) ,t = 5sec

According to Newton's first law of motion:

v = u + (a × t)

v = 10 + (5 × 5) = 35ms^(-1)

According to Newton's third law of motion:

(v)²- (u)² = 2as

(35)² - (10)² ÷ (2 × 2.5) = s

s = 225m

The final velocity of the train is derived using Newton's first law of motion. Where, u = initial velocity, a = acceleration,v = final velocity, and t = time. The equations of motion define the behavior of the physical schema in order of motion.

Then find the distance covered by the train implementing the third equation of motion with velocity v, starting velocity u, constant velocity a, and displacement.

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The buoyant force  is same for both boxes. Steel box sinks because its density is higher than water and the density of wood is lower than water.

An object that is fully or partially submerged in a fluid will experience an upward push called the buoyant force. Another name for this upward thrust is up thrust. An object's propensity to float in a fluid is known as buoyancy. Any object submerged in a liquid or gas experiences an upward force known as the buoyant force when there is gravity present.

When an object is submerged in a static fluid, pressure differences acting on its opposing sides provide buoyancy. water density is less. After reading this article, you will be able to describe the buoyant force and the rationale behind why fluids push submerged things higher. Let's discuss the definition of buoyancy and its various manifestations.

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The equation used to calculate required fastener torque as a function of desired preload and bolt size is τ = K D [tex]F_{i}[/tex].

τ = K D [tex]F_{i}[/tex]

[tex]F_{i}[/tex] = σ[tex]_{t}[/tex] * A[tex]_{t}[/tex]

σ[tex]_{t}[/tex] = 0.9 * σ[tex]_{y}[/tex]

τ = Torque

K = Torque co-efficient

D = Nominal bolt diameter

[tex]F_{i}[/tex] = Desired preload

σ[tex]_{t}[/tex] = Tensile stress

A[tex]_{t}[/tex] = Tensile stress area

σ[tex]_{y}[/tex] = Ultimate yield strength

Therefore, the equation used to calculate required fastener torque as a function of desired preload and bolt size is τ = K D [tex]F_{i}[/tex].

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An object weighing 254.4 N and inclined at a 40° angle has a gravitational pull of 2380.5.

The formula of a Force is F=Mg.

Where M is the mass of an object, and g is the gravity.

[tex]F_{1}[/tex]=254.4× 10, Value of gravity ≈ 10.

  = 2544

Here F ≠ Mg, due to an angle of 40°.

∴ [tex]F_{ax}= mass. cos \alpha[/tex] .

 =  254.4× cos 40

As cos40 =0.766

=  254.4 ×  0.766

= 194.88

To find a Normal force, use the formula of  Gravitational pull.

[tex]F_{total} = F_{1}-F_{bx}[/tex] , here [tex]F_{bx} = M. sin\alpha[/tex] =163.5

= 2544-163.5

=2380.5

Hence Gravitational pull is 2380.5

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The change in momentum of the ball will be biggest in Case 1.

The change in momentum of the ball will be highest in the case 1, where the ball bounce back to it's half the initial height after the collision with the cement floor.

When the ball hits the cement floor, the time of contact between ball and the floor is the very very less. This is why the force imparted by the cement floor on the ball will be very high.

The impulse I imparted on the ball by floor is.

I = ∆F/∆t

As the force is very high and the time of contact is very less. The impulse will be very high. And as we know from the impulse momentum theorem. The impulse is equal to the change in momentum.

So the change in momentum will be biggest in case 1.

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Complete question - Identical balls are dropped from the same initial height and bounce back to half the initial height. In case 1 the ball bounces off a cement floor and in case 2 the ball bounces off a piece of stretchy rubber. In which case is the change in momentum of the ball between the instant just before the ball collides with the floor or rubber and the instant just after the ball leaves the floor or rubber the biggest?

Case 1

Case 2

Same in both

If energy is released in a chemical reaction, the order of reaction’s characteristics from start to finish are higher energy of reactants → transition state → lower energy of products

When two or more two molecules interact with each other and undergo certain chemical changes, a chemical reaction occurs. Chemical reaction results in changes in the chemical properties of the reactants.

There are two types of chemical reactions involving energy. If energy is absorbed during the reaction it is called as Endothermic reaction. If energy is released during the reaction it is called as Exothermic reaction.

Therefore, the order of reaction’s characteristics from start to finish are

Higher energy of reactants

         ↓

Transition state

         ↓

Lower energy of products

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Answer:

144 Newtons towards the nearest firefighter

Explanation:

The net force is 200 - 56 = 144N

Answer:

MA of a simple machine is 4. It means that load overcome is 4 times more than effort used in the machine. This machine can multiply force 4 times the effort used.

All forms of waves have a definite amplitude, and this amplitude is what determines how loud a sound wave is. In contrast to good surfing waves, which may have an amplitude of 10 feet or more, a wave on a calm ocean will often have a height of less than one foot.

Decreasing.

Determination of a wave's amplitude:

The amplitude of a sound wave determines how loud or loud it is. A louder sound has a bigger amplitude, and a softer sound has a smaller amplitude.

Higher pitch and sharper edges result from decreasing wavelength and increasing frequency. As a result, increasing the frequency makes sounds sharper while increasing the amplitude or intensity increases the volume.

A sound wave's amplitude measures the height of the wave. When a sound is made, the maximum displacement of the medium's vibrating particles from their mean position determines the amplitude of the sound wave.

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The height at which the stream of water strike the building is 12.9 m.

The time of motion of the stream of water is calculated as follows;

X = Vₓt

where;

Substitute the given parameters and solve for time of motion of the water,

t = X/Vₓ

t = (48 m) / (40 x cos24)

t = 1.31 seconds

The height reached by the stream of water is calculated as follows;

h = Vyt - ¹/₂gt²

where;

Substitute the given parameters and solve for the height reached by the stream of water

h  = (40 x sin24)(1.31)  -  ¹/₂(9.8)(1.31)²

h = 12.9 m

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Answer:

A

Explanation:

because both energy and temperature ️ increase both are related.

The boot and incline have 0.859 as their static and kinetic friction coefficients.

We start for the first angle where the given angle is 36.5 ° and the acceleration is zero.

The force equations would be given by:

F = m g sin θ

N = m g cos θ

Fr = μs N

Where μ is coefficient of friction (static)

If we make a sum of forces in the direction in which the block moves we will have the sin θ Component and that of the friction force, so

∑ F = 0

F - Fr = 0

F = Fr

mg sin θ = μ N

m g sin θ = μ m g cos θ

solving for the coefficient, then

μ = sin θ / cos θ = tan θ

substitute the value in the above equation, we get

μ = tan (36.5)

μ = 0.740

We apply the same consideration for the angle of 30.5°, then we know that

μk = tan θ

substitute the value of θ, in the above equation, we get

μk = tan (30.5)

μk = 0.859

Therefore, the value coefficients of static and kinetic friction between the boot and the incline is 0.859.

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a rubber boot is at rest on an inclined plane. when the angle of inclination of the plane is increased to 35.8°, the boot begins to slide.

How do you calculate force on an incline?

Inclined plane formulas for a cubic block

      Gravitational force: F g = m × g F_g = m \times g Fg=m×g, where m is the mass of object and g is the gravitational constant

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Answer:

18 m

Explanation:

Velocity = distance / time

v = d/t

d = vt

d = (6 m/s) (3  s)

d = 18 m

Hope that helps

A physical quantity which has only magnitude is called scalar quantity eg: speed and distance whereas physical quantities which have both magnitude and direction are called vector quantities eg: velocity and displacement.

The acceleration of this car is zero. Because Acceleration is the change of velocity with respect to time and since car maintains a constant velocity, there is no acceleration.

The rate at which a velocity changes over time in both direction and speed. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

Acceleration is the rate at which speed changes, while speed is the ratio of the distance in a time period. The metric process utilizes meters per second (m/s) as the unit of speed and meters per second squared (m/s²) as the measure of acceleration. Velocity is a scalar quantity, whereas speed is indeed a scalar quantity.

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Answer:

1.45 N

Explanation:

Newton's Second Law: F=ma

Convert 145 grams to kilograms

0.145kg*10m/s^2

1.45 N

The distance covered by Sam within the first 13 seconds is 96.75 m.

Given that the mass m of Sam is 80 kg and the force F is 170 N. The coefficient of friction is 0.1.

The net force is given below

Fₙ = F - F₁

Where Fₙ is the net force and F₁ is the friction force.

Fₙ = 170 - μmg

Fₙ = 170 - 0.1 x 80 x 9.8

Fₙ = 91.6

Fₙ = ma

91.6 = 80 x a

a = 91.6 / 80

a = 1.145 m/s²

For the first 13 seconds.

So, the distance covered by Sam with this acceleration is given .

s = ut + 1/2 at²

u is the initial velocity which will be zero and t is the time interval.

So,

s = 1/2 at²

s = 1/2 x 1.145 x 13²

s = 96.75 m

Hence, the distance covered by Sam within the first 13 seconds is 96.75 m.

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Without the natural greenhouse effect, heat from the Earth's surface would simply escape into space, resulting in an average temperature of about 20 °C.

Earth would be a frozen wasteland without greenhouse gases. By retaining some of the Earth's heat energy so that it doesn't all escape into space, greenhouse gases keep our planet habitable. The greenhouse effect is a label for this heat-trapping phenomenon. The climate control in your greenhouse needs to be improved because it can help with disease prevention, plant growth stimulation, quality improvement, and even energy savings. The preservation of our planet's habitable temperature depends on "greenhouse gases."

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Assuming that the night will remain clear, calm, and unsaturated, the predicted minimum temperature is 32°f. suddenly, the wind speed increases and remains gusty throughout the night. The minimum temperature will most likely be higher than predicted due to mixing.

As wind speed increases, it moves the air molecules at a greater frequency due to collisions, and hence, the overall kinetic energy of the molecules increases making them move at a higher speed.

When the night is calm and clear then the surface of earth will be cooler than usual as the air molecules move at normal speed. However, when the wind speed increases, it draws warmer air from the surrounding which is mixed downward on the earth's surface preventing the temperature from dropping. Therefore, on a such night, the temperature will be slightly warmer than usual.

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When plates of capacitor are slowly pulled to the half so, voltage of capacitor is now V/2.

The charge Q and voltage V between the capacitor plates are related to the energy U C U C stored in a capacitor because it is electrostatic potential energy. A charged capacitor stores energy in the electrical field that develops between its plates. The capacitor charges up, expanding the electrical field. Two parallel lines, either flat or curved, should be close but not touching in order for the capacitor symbol to accurately represent how the capacitor is constructed.

The capacity of a component or circuit to gather and hold energy in the form of an electrical charge is known as capacitance. Devices that store energy include capacitors, which come in a variety of sizes and shapes.

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Zero the dynamic sensor is important because of its sensitivity, resolution, range, zero drift and repeatability.

Dynamic applications describe cyclical, quick measuring processes like those frequently seen in presses. In dynamic applications, it's crucial to tare the zero point at regular intervals to prevent the measuring signal from wandering.

The input for automated zero point adjustments is provided by the strain transducers. The PLC can be used to start the zero point adjustment. The signal is reset (pulled to zero) and the zero point adjustment is performed if the input is pulled to 3 V.

The sensor is in measuring mode if the input is open. Instead of using "Active-Low-Levels," the reset logic is also possible with "Active-High-Levels".

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The work calls for a 10k Omega resistance value and a 1 nF capacitance value. Being aware of those output gives us a clear advantage. To get the frequency of unity gain, we can utilize the transfer function (2.34)

The output waveform will consist of positive and negative spikes of size Vsat, which is roughly 13V for a 15V op-amp power source, for a square wave input, let's say 1V peak and 1 KHz.

The differentiated output will be zero whenever the input is held constant at 1V.

For a perfect square wave, the input slope is infinite when it transitions between the t 1V levels.

As a result, the output is clipped to around 13V for a 15V op-amp power source.

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The question was incomplete. Check below the full question.

differentiator utilizes an ideal op amp, a 30 kω resistor, and a 0.03 μf capacitor. what is the frequency 0f in hz at which its input and output sine‐wave signals have equal magnitude? what is the output signal for a 1 v peak‐to‐peak sine‐wave input with frequency equal to 10f₀ ?

Answer: Density

Explanation:  

I remember learning it in 9th-grade physic class.

The radius of its circular orbit is calculated to be 1/B √(2qV/m)

If the field is vacuum, then the magnetic field is dominant factor determining the motion. As the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle then continues to follow curved path until it forms a complete circle. As the magnetic force is perpendicular to velocity, so that no work is done on the charged particle. The kinetic energy of the particle and speed remain constant. The direction of motion is usually affected but not the speed.

The speed of particle just before entering into magnetic field is v₀

qV = 1/2*m *v₀²

v₀= √(2qV/m)

Radius of the circular path is given by

 r= mv₀/qB

r=m/qB √(2qV/m)

=1/B √(2qV/m)

Radius of circular orbit = 1/B √(2qV/m)

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Answer

the answer is 6.25

Explanation:

Here, the mass of the stone (m) = 0.5 kg, velocity at which it is thrown (v) = 5 m/s, The kinetic energy of the stone (KE) =? We have, Kinetic energy of the stone (KE) = \ (\frac12mv^21) = \(\frac120.5\times5^2\) = 6.25 Joules Hence, the kinetic energy of the stone (KE) is 6.25 joules. Hope it will be helpful

The diagram shows the resulting wave when they cross at point X is the second one (b) because It is the triangle that is pointed upward on the rope's top side and appears to be a little larger than the others.

A wave is a disturbance that can go through a material without permanently moving the material's components. Transverse and longitudinal are known to be the two types.

In a transverse wave, the wave's direction of propagation is parallel to the direction in which the medium's particle vibrations are occurring. Examples include X-rays, light waves, as well as water waves. In contrast, in longitudinal waves, the direction of the particle vibration is said to be parallel to the path of the wave transmission.

Note that it is type of longitudinal wave is a wave in a rope where there is the motion of two wave pulses.

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THIS MODEL DOES NOT SHOW THE CORRECT SCALE FOR THE SUN