Based on the mole ratio of the balanced equation of the reactions;
Gretchen did the experiment incorrectlyGretchen did not measure the accurate mass of aluminum required to produce 19 g of aluminum fluorideGretchen needs to react 6.1 g of Al in excess fluorine in order to produce 19 g of AlF₃What mass of iron(III) oxide is produced from reacting 41 g of Fe with excess oxygen?The equation of the reaction is given below:
4 Fe + 3 O₂ → 2 Fe₂O₃Based on the reaction, mole ratio of Fe and Fe₂O₃ is 2 : 1
Moles of Fe reacted = 41/56 moles
Mass of Fe₂O₃ produced = 41/56 * 1/2 * 160 = 58.6 g
What mass of aluminum fluoride is produced from reacting 5 g of aluminum with excess fluorine?The equation of the reaction is given below:
2 Al + 3 F₂ → 2 AlF₃Based on the reaction, mole ratio of Al and AlF₃ is 1 : 1
Moles of Al reacted = 5/27 moles
Mass of AlF₃ produced = 5/27 * 84 = 15.5 g
This is less than the required mass of AlF₃
Moles of AlF₃ in 19 g = 19/84 = 0.2262 moles
Mass of Al required = 0.2262 * 27 = 6.1 g
Based on the results above;
Gretchen did the experiment incorrectlyGretchen did not measure the accurate mass of aluminum required to produce 19 g of aluminum fluorideGretchen need to react 6.1 g of Al in excess fluorine in order to produce 19 g of AlF₃In conclusion, the mole ratio of the reactions obtained from the equation are required to know the accurate masses of reactants required.
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What are the magnetic quantum numbers possible for a 6s subshell and for a 4f subshell? Drag the correct numbers into each of the columns.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
6s Subshell 4f Subshell
For the 6s subshell, the magnetic quantum number is zero while for the 4f subshell we have -3, -2, -1, 0, 1, 2, 3.
What is the magnetic quantum number?The magnetic quantum number takes on values between 0 to (n - l). It gives the orientations of the sublevels. The four types of quantum numbers are;
Principal quantum numberAzimuthal quantum numberMagnetic quantum numberSpin quantum numberFor the 6s subshell, the magnetic quantum number is zero while for the 4f subshell we have -3, -2, -1, 0, 1, 2, 3.
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Hi, I am trying to calculate the dosage of mg i should be taking per night. I am 135 pounds 5’7.
I choose the lower limit 0.024 mg/kg/day
1 pound = 0.453592 kg
135 pounds = 61.235 kg
dosage/day = 0.024 x 61.235 = 1.47 mg
Answer:
See below
Explanation:
I will use the approximate AVERAGE
of the dosage range ~ .20 mg/kg/week
135 pounds = 61.23 kg
Now , for SEVEN days/week dosing:
61.23 kg * .20 mg/kg-wk / 7 days/week = 1.75 mg/day
if the rate of infusion
why bonding of water molecule called a pure
Answer:
A molecule of water has two hydrogen atoms. Both of these atoms can form a hydrogen bond with oxygen atoms of different water molecules. Every water molecule can be hydrogen bonded with up to three other water molecules
ssssssssssssssssssssssssssssss
Answer:
s
Explanation:
PLEASE HELP!!!
What is the correct net ionic reaction for Pb(NO3)2(aq) +2NaI(aq) → PbI2(s) + 2NaNO3(aq)?
The net ionic equation of the reaction is:
Pb²⁺aq) + 2 I(aq) → PbI2(s) What is a net ionic ionic equation?A net ionic equation is an equation which shows only the ions that are involved in the formation of a product in the reaction as well as the product of the reaction alone. Spectator ions are omitted.
The net ionic equation of the reaction is given below:
Pb²⁺aq) + 2 I(aq) → PbI2(s)
In conclusion, a net ionic equation does not show spectator ions.
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Answer: B
Explanation:
Behavior can best be defined as
A.
the response of an organism to its environment.
B.
the physical characteristics of a species.
C.
a sudden change in an organism's habitat.
D.
the geographic range of a species.
Polysaccharides are healthier for the body than mono- or disacxharides are. What choices could you make to increase your consumption of polysaccharides and decrease your consumption of mono- and disaccharides?
Polysaccharides are healthier for the body than mono- or disaccharides are as glucagon is a type of polysaccharide found in animal tissues and is usually found in small amounts in meat from poultry and diet.
What do you need for both monosaccharides and polysaccharides?The Importance of Monosaccharides and Polysaccharides Both are essential as the primary food and dietary energy sources for all living organisms. Cell-wall polysaccharides make up the fibers that humans eat, and monosaccharides add sweetness to food.
Glycogen – This is a type of polysaccharide found in animal tissues and is usually found in small amounts in meat from poultry and diet. Most of the glycogen is stored in the liver, not in the muscles unless you eat a lot of liver and meat, so I said it was a small amount. In general, you may not be consuming too much glycogen. Starch (amylose and amylopectin) – It is found primarily in plants and is composed of two structurally distinct polysaccharides called amylose and amylopectin. Amylose is a linear polysaccharide, but amylopectin has many branched chains. Fiber-This is primarily cellulose, also a linear polysaccharide, a major structural component of plant cell walls. Humans cannot digest this carbohydrate because they lack the digestive enzymes needed to digest it.Read more about carbohydrates:
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When 5ml of 30% H2O2 is decomposed into water and oxygen, how many grams of oxygen and how many grams of water are left?
The mas of the products are given below:
mass of oxygen produced = 0.7056 g of oxygenmass of water produced = 0.794 g of hydrogenHow many moles are there in 5 ml of 30% of hydrogen peroxide?The moles of hydrogen peroxide in 5 ml of 30% of hydrogen peroxide is calculated using the formula:
Moles = concentration * volume
Molarity of 30% of hydrogen peroxide = 8.82 mol/L
Moles = 8.82 * 5/1000 = 0.0441 moles
The equation of the the decomposition of hydrogen peroxide is given as:
2 H₂O₂ -----> 2 H₂O + O₂
Based on the mole ratio;
mass of oxygen produced = 0.0441/2 * 32 g = 0.7056 g of oxygen
mass of water produced = 0.0441 * 18 g = 0.794 g of hydrogen
Therefore, the mass of the products of the decomposition of hydrogen peroxide is determined from the mole ratio of the reaction.
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How many grams of N2o are formed if 0.46 mole of NH4No3 is used in the reaction
20.24 grams of [tex]N_2O[/tex] is formed if 0.46 mole of [tex]NH_4NO_3[/tex] is used in the reaction.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Balanced equation:
[tex]NH_4NO_3[/tex] → [tex]N_2O + 2H_2O[/tex].
1 mole [tex]NH_4NO_3[/tex] gives 1 mole of [tex]N_2O.[/tex]
0.46 mole of [tex]NH_4NO_3[/tex] gives [tex]\frac{ 1 mole}{ 1 mole}[/tex] x 0.46 mole [tex]N_2O[/tex].
0.46 mole [tex]N_2O[/tex] =[tex]\frac{mass}{44.013 g/mol}[/tex]
Mass= 0.46 x 44.013
Mass=20.24gram.
Hence, 20.24 grams of [tex]N_2O[/tex] is formed if 0.46 mole of [tex]NH_4NO_3[/tex] is used in the reaction.
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Based on the electron configuration of the two
atoms, predict the ratio of metal cationic (+) atom
to nonmetal anionic (-) atom in the compound.
1s²2s²2p63s²
1s²2s²2p63s²3p4
A. 1:1-
C. 2:1
Magnesium
Sulfur
B. 1:2
D. 3:1
Based on the electron configuration of the two atoms predict the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound hence the ratio is 1:1.
What does the octet rule say?The Octet Rule states that the atoms of the elements bond to each other in an attempt to complete their valence shell (the last shell of the electrosphere).
Basically, they obey the octet rule which states that the capacity of atoms (e.g. here Magnesium and Sulfur) to prefer to have 8 (eight) electrons (e-) in their respective valence shells. In this case, Magnesium is Mg (+2) and Sulfur is (-2) hence the ratio is 1:1.
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What volume of carbon dioxide in liters could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas (C5H12)?
C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g)
(OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g")
Do not type units with your answer
589L volume of carbon dioxide in litres could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas ([tex]C_5H_{12}[/tex])
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
[tex]C_5H_{12}(g) + 8 O_2(g)[/tex] --->[tex]5 CO_2(g) + 6 H_2O(g)[/tex]
To find the volume, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
P = pressure (atm)
V = volume (L)
n = number of moles
R = constant (0.0821 L*atm/mol*K)
T = temperature (K)
To find the volume of water vapour, you need to (1) convert grams C₅H₁₂ to moles C₅H₁₂ (via molar mass), then (2) convert moles C₅H₁₂ to moles H₂O (via mole-to-mole ratio from reaction coefficients), then (3) calculate volume H₂O (via Ideal Gas Law). The final answer should have 3 sig figs.
Molar Mass (C₅H₁₂) =72.151 g/mol
1 C₅H₁₂ (g) + 8 O₂ (g) -----> 5 CO₂ (g) + 6 H₂O (g)
228.85 g C₅H₁₂ 1 mole 6 moles H₂O
----------------------- x ---------------- x ----------------------- = 19.03 moles H₂O
72.151 g 1 mole C₅H₁₂
Moles of H₂O= 19.03
P =0.96 atm
R = 0.0821 L x atm/mol x K
V = ?
T = 362 K
n = 19.03 moles
PV = nRT
(0.96 atm)V = ( 19.03 moles)(0.0821 Latm/molK)(362K)
(0.96 atm)V = 565.575406
V = 589L
Hence, 589L volume of carbon dioxide in litres could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas ([tex]C_5H_{12}[/tex]).
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Alpha Decay
1. If an atom of Uranium-238 decays via alpha emission, what would be its daughter product? (You will need a periodic table.)
2. If an atom of Thorium -228 decayed via beta emission, what would be the daughter isotope?
Thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
What are the products of Uranium-238 and Thorium -228?If an atom of Uranium-238 decays via alpha emission, a nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234 while If an atom of Thorium -228 decayed via beta emission, the daughter isotope is protactinium 234.
So we can conclude that thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
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10. Suppose that 20.0 mL of 5.00 x 10-3 M aqueous sodium hydroxide (NaOH) is required to neutralize 10.0
mL of an aqueous solution of hydrochloric acid (HCI). Using the balanced chemical equation below,
find the molarity of the HCI solution?
NaOH (aq) + HCI (aq) → H₂O (1) + NaCl (aq)
A. 1.00 x 103 M HCI
B. 1.00 x 102 M HCI
C. 5.00 x 103 M HCI
D. 5.00 x 10-2 MHCI
Explanation:
B. 1.00 x 10^-2 M HCI
The question is asking us to find the molarity/concentration of the acid (HCl).
We have been provided with;
20.0 mL of 5.0 x 10^-³ M NaOH10.0 mL of HClWe know that molarity (M) of a solution is contained in 1 L or 1000 mL or 1000 cm³.
This means that;
5.0 x 10^-³ moles is contained in 1000 mL.
is contained in 1000 mL.X mol is contained in 20.0 mL
[tex]x \: mol \: = \frac{20 \times 5.0 \times {10}^{ - 3} }{1000} \\ = 0.0001 \: mol[/tex]
= 0.0001 moles
These 0.0001 moles is contained in 10 mL of HCl.
To find the molarity of the acid;
0.0001 moles is contained in 10 mL
x mol is contained in 1000 mL
[tex]x \: mol \: = \frac{0.0001 \times 1000}{10} \\ = 0.01 \: mol[/tex]
= 0.01 M
Therefore the Concentration of the acid (HCl) is 0.01 M or 1.0 x 10^-2 M
Write the formula for methionine (red = O , gray = C , blue = N , yellow = S , ivory = H ).
Express your answer as a molecular formula. Enter the elements in the order: C , H , N , O , S .
Answer:
The molecular formula of methionine is C₅H₁₁NO₂S
What is the electron configuration for magnesium (Mg)?
The Periodic Table
O A. 1s²2s22p²3s6
OB. 3s 3p 304
O C. 1s²2s22p3s²
O D. 1s22s23s23p6
Magnesium has atomic no 12
Electronic configuration given by
1s²2s²2p⁶3s²Or
[Ne]3s²[tex]1s^22s^22p^63s^2[/tex] is the electron configuration for magnesium. Therefore, the correct option is option C.
The positioning of electrons within an atom is referred to as electron configuration. The distribution of electrons in each of their corresponding energy levels or orbitals is described in great detail. The notation known as the Aufbau principle is frequently used to represent the electron configuration of an atom. This theory states that electrons fill an atom's orbitals starting at the lowest energy level and moving up the energy scale. The energy level diagram, which can also be represented by a periodic table, serves as the foundation for this sequential filling. A maximum of two electrons can be held in the main level, the initial energy level, which is closest to the nucleus. [tex]1s^22s^22p^63s^2[/tex] is the electron configuration for magnesium.
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2. Calculate the pl of the following amino acids(use their Pka values) a. Arginine b. Glutamic acid of water an c. Asparagine d. Tyrosine
pl (25*C)
Arginine -----> 10.76
Glutamic -----> 3.08
Asparagine -----> 5.43
Tyrosine -----> 5.63
☆...hope this helps...☆
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What is technology ?
Answer:
Technology is the application of scientific knowledge for practical purposes especially in industry.
Calculate the mass of water produced by metabolism 84.0 g of glucose
The amount of water that will be produced is 50.36 grams
Stoichiometric problemsThe metabolism of glucose is represented by the following equation:
[tex]C_6H_1_2O_6(s)+6O_2(g)--- > 6CO_2(g)+6H_2O(g)[/tex]
The mole ratio of glucose metabolized to the water produced is 1:6.
Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles
Equivalent mole of water = 0.4662 x 6 = 2.7975 moles
Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams
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(ii) CH₂=C - CHCH3 Br,give the IUPAC name of the compound
Answer:
propene
Explanation:
According to the rules,the name of hydrocarbon:root word+suffix=prop+ene=propene
Place the stages of a high-mass star's life cycle in the correct order, from a star's birth to its death.
supergiant
neutron star
protostar
nebula
supernova
Whether a living or non-living object, everyone has a particular life cycle. It starts right from the birth and ends upon the death of that object. Just like others, stars also have their own life cycle and that has different stages.
Nebula ⇒ Protostar ⇒ Supergiant ⇒ Supernova ⇒ Neutron Star
What is the life cycle of a high-mass star?In the initial stage, a star is in the form of a nebula. At this stage, it is a huge cloud of gas and dust. The changes occur in the star and the final size totally depends upon the size of that star.
In a massive star, the fuel is used very quickly because of its life span of a few hundred thousand years. The second stage is the Protostar.
The next stage is the Supergiant. At this stage, the nuclear reactions that occur because of the hydrogen will gradually run out and the star will enter the final phase of its life span. The bigger star will have more massiveness.
Following this, the star will enter the next stage, i.e., supernova, and after that, neutron star. In a supernova, the star will have a very energetic and violent end. In the last stage, when the dust particles clear, a neutron star will be visible.
For better understanding, an image is attached at the end.
Thus, the life cycle of a high-mass star is arranged from its birth to its death.
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The stages of a high-mass star's life cycle in the correct order, from a star's birth to its death are-
Nebula
Protostar
Supergiant
Supernova
Neutron star
The life cycle of a high-mass star begins with a nebula, a cloud of gas and dust in space. As gravity pulls the nebula together, it forms a protostar—a young, hot, and dense object. The protostar continues to gather mass and becomes a main-sequence star, burning hydrogen in its core.
Once the hydrogen is exhausted, the star expands into a supergiant and starts fusing helium into heavier elements. Eventually, it undergoes a supernova explosion, releasing an enormous amount of energy and leaving behind a dense core known as a neutron star. This process showcases the incredible transformations that high-mass stars undergo throughout their life cycle.
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Calculate the relative rate of diffusion of 1H2 (molar mass 2.0 g/mol) compared with 2H2 (molar mass 4.0 g/ mol) and the relative rate of diffusion of O2 (molar mass 32 g/mol) compared with O3 (molar mass 48 g/mol).
The ratio of diffusion rates of ¹H₂ to ²H₂ is 1.4 while the ratio of diffusion rates of O₂ to O₃ is 1.2.
What is Graham's law?Graham’s law states can be described as the rate of diffusion of a gas is inversely proportional to the square root of its molecular weight of the gas.
According to this Law, molecules with lower molecular mass will diffuse faster than those with higher molecular mass molecules at constant pressure and temperature.
The mathematical formula is utilized to compare the rates of diffusion of two different gases at pressures and temperatures.
[tex]{\displaystyle \frac{R_1}{R_2} =\sqrt{\frac{M_2}{M_1} }[/tex]
Where M₁ and M₂ represent the molar mass of gas 1 and gas 2.
Given, the molar mass of ¹H₂ = 2.0 g/mol
The molar mass of to ²H₂ = 4.0 g/mol
The ratio of the rate of diffusion of ¹H₂ to ²H₂:
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =\sqrt{ \frac{M_{^2H_2}}{M_{^1H_2}} }[/tex]
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =\sqrt{ \frac{4}{2} }[/tex]
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =1.4[/tex]
Given, the molar mass of O₂ = 32.0 g/mol
The molar mass of to O₃ = 48.0 g/mol
The ratio of the rate of diffusion of O₂ to O₃:
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =\sqrt{ \frac{M_{O_3}}{M_{O_2}} }[/tex]
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =\sqrt{ \frac{48}{32} }[/tex]
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =1.2[/tex]
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if 185 g of wax c22h44 burns how many litres of oxygen gas were used up assume the conditions in the lab are 101kpa and 25 degree celcius
13.73 L of oxygen gas were used up if 185 g of wax [tex]C_{22}H_{44}[/tex] burns.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide
the given mass by the number of moles to get molar mass.
Given data:
P= 101kpa =0.996792 atm
V= ?
R=[tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=25 +273 =298 K
Moles =?
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{185 g }{308.6}[/tex]
Moles =0.56
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]0.56= \frac{0.996792\;atm\; X \; V }{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]
13.73 L =V
13.73 L of oxygen gas were used up if 185 g of wax [tex]C_{22}H_{44}[/tex] burns.
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A mineral sample has a mass of 75 g. When the sample is dropped
into a graduated cylinder with a volume of 20mL, the volume of the
graduated cylinder rises to 40 mL. What is the density of the
sample?
Answer:
3.75 g/mL
Explanation:
Density can be calculated using the following formula:
Density = mass (g) / volume (mL)
You have been given the mass of the mineral sample (75 g). To find the volume, you need to determine the amount of space that the sample takes up when it is placed in the water. This can be done by subtracting the initial water volume from the final water volume.
Volume = Final - Initial
Volume = 40 mL - 20 mL
Volume = 20 mL
Now, you can calculate the density of the mineral sample.
Density = mass / volume
Density = 75 g / 20 mL
Density = 3.75 g/mL
Answer:
Explanation:
Givens
The volume is the tricky part of this question. You are using the graduated cylinder to measure volume. The rise in the reading of the graduated cylinder = the volume of the sample.
Volume = 40 mL - 20 mL = 20 mL
Mass = 75 grams
Formula
Density = mass / volume
Solution
Density = 75 / 20 = 3.75
Answer
Density = 3.75
Anna stated that ionic compounds have high melting points and low boiling points. She said that this demonstrates that ionic compounds have strong bonds because a lot of energy is needed to break the electrical forces that hold the bonds together.
Which statement best describes Anna’s error?
Strong electrical forces will make ionic compounds have high boiling points.
Strong electrical forces will make ionic compounds have weak bonds.
A low amount of energy is needed to break the bonds in ionic compounds.
Gravitational forces hold the bonds together in ionic compounds.
The statement which best describes Anna’s error is: A. strong electrical forces will make ionic compounds have high boiling points.
The type of chemical bonds.In Chemistry, there are different types of chemical bonds and these include the following:
Metallic bondsHydrogen bondsCovalent bondsIonic bondsAn ionic bond is typically characterized by electrostatic attraction that is formed between oppositely charged ions or atoms of chemical elements with different electronegativities.
In conclusion, Anna was wrong to posit that strong electrical forces makes all ionic compounds to have high boiling points.
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Answer:
✔Strong electrical forces will make ionic compounds have high boiling points.
❌Strong electrical forces will make ionic compounds have weak bonds.
❌A low amount of energy is needed to break the bonds in ionic compounds.
❌Gravitational forces hold the bonds together in ionic compounds.
Explanation:
a radioactive nuclide that is used for geological dating has an atomic number of 19 and mass 40. what is the symbol of this nuclide?
The symbol of the radioactive nuclide, given the data is ⁴⁰₁₉K
Data obtained from the questionAtomic number = 19Mass number = 40Symbol of nuclide =?How to determine the nuclideFrom the question given above, the atomic number of the nuclide is 19.
Comparing the atomic number (i.e 19) of the nuclide with those in the periodic table, the nuclide is potassium with a symbol of K
How to determine the symbol of the nuclideAtomic number (Z) = 19Mass number (A) = 40Name of nuclide = Potassium (K)Symbol of nuclide =?The symbol of a nuclide is given as ᴬ₂X
Where
A is the mass number Z is the atomic numberX is the symbol of the elementThus,
ᴬ₂X => ⁴⁰₁₉K
Therefore, the symbol of the nuclide is ⁴⁰₁₉K
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determine the number of moles of H in each sample
C. The number of moles of H in 0.109 mole of N₂H₄ is 0.436 mole
D. The number of moles of H in 34 moles of C₁₀H₂₂ is 748 moles
C. How to determine the number of mole of H in 0.109 mole of N₂H₄1 mole of N₂H₄ contains 4 moles of H
Therefore,
0.109 mole of N₂H₄ will contain = 0.109 × 4 = 0.436 mole of H
D. How to determine the number of mole of H in 34 mole of C₁₀H₂₂1 mole of C₁₀H₂₂ contains 22 moles of H
Therefore,
34 mole of C₁₀H₂₂ will contain = 34 × 22 = 748 mole of H
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How many moles of KF would need to be added to 2500 ml of water to make 1.2 M solution?
The number of moles of KF needed to prepare the solution is 3 moles
What is molarity?Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
How to determine the mole of KF Volume = 2500 mL = 2500 / 1000 = 2.5 L Molarity = 1.2 MMole of KF =?Molarity = mole / Volume
1.2 = mole of KF / 2.5
Cross multiply
Mole of KF = 1.2 × 2.5
Mole of KF = 3 moles
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According to the article, puberty indicates the beginning of adolescence. How does nutrition influence the start of adolescence?
Answer:
adolescence begins according to your dietExplanation unhealthy diet brings about early or late commence of adolescence especially in girls
A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section be? *
Each section would be 230 centimeters or 2.30 meters long.
Sectional divisionThe original wood pole is 12 meters long.
12 meters = 12 x 100 = 1200 centimeters
It is to be cut into 5 equal sections: 1200/5 = 240 centimeters
But each cut wastes 10 cm of the pole.
240 - 10 = 230 centimeters.
Thus, each section would be 230 centimeters or 2.30 meters long.
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