Sally used a ruler to draw the segment ab she then opened her compass to the length of ab and drew a circle keeping thw compass open to the same length she marked off equal parts along the circle as shown in the following figure using some or all of the points of intersection and point a which of the following regular polygons could she construct

Answer:

Step-by-step explanation:

The student made $100 in week 8.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Amount earned from the first week to 6 weeks.

110, 100, 90, 110, 100, 90

We see that,

Every 3 weeks the amount gets repeated.

So,

7th week = 110

8th week = 100

Thus,

The amount earned in week 8 is $100.

Learn more about expressions here:

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Answer:

i think it's 1.8.

Step-by-step explanation:

why? bc if u add 6/20 + 1.5 = 1.8

i think it's 1.8, im not sure, hopefully it's correct!!

Answer:

1.8

Step-by-step explanation:

you just simplify -6/20 into a decimal and you get .3 then you add it to 1.5.

Answer:

Ignore the decimal points then multiply the numbers that remain. Count the number of decimal places in all of the numbers of the question combined. Place the decimal point so that there are the same number of decimal places in the answer and the question.

Step-by-step explanation:

Answer:

decrease in value: 20,160

current value: 203,840

Step-by-step explanation:

that is the 9% value decrease of the house

When diving fractions, use KFC:

K eep the first fraction the same

F lip the second fraction upside down

C hange the divide sign to a multiply

After, just work it out multiplying the denominators and the numerators together getting your answer

Hope this helped you, have a good day bro cya)

Answer:

[tex]8\sqrt{2}[/tex]

Step-by-step explanation:

To find the length of an isosceles triangle, you know that the angles of the triangle are 45-45-90, so let's use that triangle theorem.

Therefore, the length of the hypotenuse (BD) is [tex]x\sqrt{2}[/tex], and x is equal to 8 (length of BC).

[tex]x\sqrt{2}[/tex]

x=8

Therefore, [tex]8\sqrt{2}[/tex] would be the length of side BD.

Answer:

oh snap i have this question too sorry cant help :(

Step-by-step explanation:

but i can provide with advice bc is the side down and bd is across us this to your advantage

Answer:

seven

Step-by-step explanation:

Lol thxx for the points

Pls give brainliest! Also, plz sub to kgirl633 on yt.

Answer:

y=5/4x -7

Step-by-step explanation:

Hope this helps!

Answer:

100⁰

Step-by-step explanation:

Let,

First angle = x

Second angle = x + 40

Third angle = 5x

=> x + x + 40 + 5x = 180

=> 7x + 40 = 180

=> 7x = 180 - 40

=> 7x = 140

=> x = 140/7

=> x = 20

Largest angle = 5x = 5(20) = 100⁰

[tex]\huge{\purple{\underline{\underline{\bf{\pink{ANSWER:-}}}}}}[/tex]

[tex]:\implies\bf{x + x + 40 + 5x = 180} \\ \\ :\implies\bf{7x + 40 = 180} \\ \\ :\implies\bf{7x = 180 - 40} \\ \\ :\implies\bf{7x = 140} \\ \\ :\implies\bf{x = \frac{140}{7} } \\ \\ :\implies\bf{x = 20}[/tex]

The largest angle above is 5x thus,

[tex]:\implies\bf{5x} \\ \\ :\implies\bf{5 \times 20} \\ \\ :\implies\bf{100^°}[/tex]

Answer:

Makes the lungs able to fill more

Answer:

  P = -16(x -28)² +1024

Step-by-step explanation:

The equation can be written in vertex form as ...

  P = -a(x -h)² +k

where (h, k) is the vertex, and 'a' is a scale factor. We are given the vertex (h, k) = (28, 1024) and another point (x, P) = (10, -4160). Using these points, we can find the value of 'a'.

  -4160 = -a(10 -28)² +1024

  -5184 = -324a . . . . simplilfy

  a = 5184/324 = 16 . . . . divide by the coefficient of 'a'

A suitable quadratic relation is ...

  P = -16(x -28)² +1024

Answer:

C

Step-by-step explanation:

This means that there is another leg of an isosceles triangle that is also 5 inches.

a^2 + b^2 = c^2

a = 5

b = 5

c = ?

c^2 = 5^2 + 5^2                 Combine

c^2 = 25 + 25

c^2 = 50                            Take the square root of both sides.

sqrt(c^2) = sqrt(50^2)

c = sqrt(5 * 5 * 2)                Take out 1 of two factors under the root sign.

c = 5 * sqrt(2)                      The 2 is left over because there is only 1 of them

sqrt(2) = 1.4142

c = 5 * 1.4142

c = 7.07 = 7.1

Answer:

Step-by-step explanation:

assuming the equation is x^2 + (y - 1)^2 = 3

Answer:

x = 80 degrees

Step-by-step explanation:

Draw a line through DG and name the intersection of that line and line AB as K.

By the same side interior angle theorem, GKC is 40 degrees.

By the sum of interior angles of triangle theorem, CGK is 180-70=110 degrees.

By supplementary angle theorem, x = 80 degrees.

Recall that for two vector x and y making an angle θ with each,

x • y = ||x|| ||y|| cos(θ)

If we replace y with x, we see that

x • x = ||x|| ||x|| cos(0) = ||x||²   ⇒   ||x|| = √(x • x)

Using the last identity, the magnitude of w is

||w|| = √(w • w)

but since w = u + v, we have

w • w = (u + v) • (u + v)

The dot product distributes over sums and is commutative, so

w • w = (u • u) + (u • v) + (v • u) + (v • v)

… = ||u||² + 2 (u • v) + ||v||²

… = ||u||² + 2 ||u|| ||v|| cos(θ) + ||v||²

If u has a direction of 45° with the positive x-axis, v has a direction of 150°, then the angle between u and v is |45° - 150°| = 105°. So,

||w|| = √(||u||² + 2 ||u|| ||v|| cos(150°) + ||v||²)

… = √(10² + 2 • 10 • 13 cos(150°) + 13²)

… ≈ 14.2

Using the parallelogram rule for vector addition (see attached sketch), the sum of the angle between w and u and 45° is equal to the direction of w.

If φ is the angle between w and u, then

w • u = ||w|| ||u|| cos(φ)

… = 14.2 • 10 • cos(φ)

but we also have

w • u = (u + v) • u

… = (u • u) + (v • u)

… = ||u||² + ||u|| ||v|| cos(105°)

… = 10² + 10 • 13 • cos(105°)

… ≈ 66.4

Then

14.2 • 10 • cos(φ) ≈ 66.4

cos(φ) ≈ 0.467

φ ≈ 62.1°

and so the direction of w is 62.1° + 45° ≈ 107.1°.

Answer:

y = 0.4 x

Step-by-step explanation:

Answer:

Which of the following graphs is described by the function given below?

y = 2x2 + 6x + 3

-A. Graph A

The function y = 2x^2 + 6x + 3 is a quadratic function that has a vertex of (-1.5,-1.5)

The equation of the function is given as:

y = 2x^2 + 6x + 3

Differentiate

y' = 4x + 6

Set to 0

4x + 6 = 0

This gives

4x = -6

Divide by 4

x = -1.5

Substitute x = -1.5 in y = 2x^2 + 6x + 3

y = 2(-1.5)^2 + 6(-1.5) + 3

Evaluate

y = -1.5

This means that the function y = 2x^2 + 6x + 3 has a vertex of (-1.5,-1.5)

See attachment for the graph of y = 2x^2 + 6x + 3

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Answer:

The answer is to the problem is 18.

[tex] \large \bigstar \frak{ } \large\underline{\sf{Solution-}}[/tex]

Consider, LHS

[tex]\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}[/tex]

We know,

[tex]\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} 

\\ \\ \text{So, using this identity, we get}

\\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}[/tex]

We know,

[tex]\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\ [/tex]

So, using this identity, we get

[tex]\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}[/tex]

can be rewritten as

[tex]\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}[/tex]

[tex]\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}[/tex]

[tex]\rule{190pt}{2pt}[/tex]

Answer:

40% of airline A's flights were on time

Step-by-step explanation:

0.4=40% .the top row indicates that it was airline A. the left column indicates that it was on time.

Answer:

B

Step-by-step explanation:

happy holidays

Answer:

Let x be the number of dimes and y the number of quarters

x +y = 100

a dime is $0.10 and a quarter is $0.25

0.1x + 0.25y = 21.40 multiply by 100 to remove the decimals

10x + 25y = 2140, From the first equation y = 100 - x and plug it in to the second equation.

10x + 25(100 -x) = 2140

10x + 2500 - 25x =2140

2500 - 15x = 2140

360 = 15x x = 24 and y = 76

There are 24 dimes and 76 quarters

Answer:

76 Quarters = $19.00

24 Dimes = $2.40

$19.00 + $2.40 = $21.40

Step-by-step explanation:

Yaga

Answer:

[tex]\sqrt{18a}[/tex]

Step-by-step explanation:

To insert the factor, you must first find its squared value, in this case, 3's squared number is 9 so.....[tex]3=\sqrt{9}[/tex]

Now with square roots, they multiply like any other number

so you end up with[tex]\sqrt{9}*\sqrt{2a} \\\sqrt{9*2a}\\\\\sqrt{18a} <------ ANSWER[/tex]

Please leave a thanks!!!

Answer:

4 chairs

Step-by-step explanation:

Start with 2/3 can of paint: (2/3)

He used 1/6 of the can to paint each chair: (divided by 1/6)

Now use the 'keep, change, flip' method to get the expression: (2/3x6/1)

Then simplify your answer: (12/3)

Lastly simplify again: (4)

Thus, he painted 4 chairs.

Answer:

The number generator is not fair. In most of the experiments, considerably less than 60% of the selected marbles are green.

Step-by-step explanation:

Run a significant number of times, a fair distribution should be a bell curve  centered on the 6 for 60%

Answer:

the answer is 64%

Step-by-step explanation:

80/125 = 64

Answer:

2/7÷3/4=2/7×4/3=8/21

[tex] \rm \ \blue{ \overbrace{ \underbrace{ \tt \color{hotpink} \: \: \: \: \: \: \: \: \: \: answer \: \: \: \: \: \: \: \: \: }}}[/tex]

[tex]\large \color{pink} \frac{8}{21} [/tex]

Step-by-step explanation:

[tex] \huge \color{brown} \frac{2}{7} \div \frac{3}{4} [/tex]

[tex] \large \color{hotpink} \frac{2}{7} \div \frac{4}{3} [/tex]

[tex] \huge \color{darkblue} \frac{8}{21} [/tex]