Rotation about a carbon-carbon double bond does not readily occur because: __________.1) the overlap of the p orbitals of the carbon-carbon π bond would be lost2) the double bond is much shorter and therefore more difficult to rotate3) the overlap of the sp2 orbitals of the carbon-carbon σ bond would be lost4) the double bond is much stronger and therefore more difficult to rotate

Answer:

manganese has greater ionization energy than Selenium

Answer:

E

Explanation:

Here in this question, what we will do is to select which of the pairs that do not correlate.

A. Enthalpy and heat content

This two terms are at par with each other. By definition, the enthalpy of a system simply is the total amount of heat content it has.

B. Endothermic reaction and +H

These two terms are at par with each other. An endothermic reaction is one in which heat is absorbed from the surroundings. It has a positive value for the heat content i.e the enthalpy is positive and thus H is positive.

C. Exothermic reaction and -H

An exothermic reaction is one in which heat is released to the environment. It usually has a negative value for the enthalpy and thus the value of H is negative.

D. High energy and High Stability

These two terms are not at par. When an entity has or is of high energy, it is usually unstable. An entity at a higher energy level will not be stable until it goes to a lower level of energy.

Thus higher energy level is associated with lesser stability while lower energy levels are associated with higher stability. The lesser the energy of an entity, the higher its stability.

This makes the option our answer.

Answer:

NH3 < NF3 < BCl3

Explanation:

The vapour pressure of a substance has something to do with the nature of intermolecular forces between its molecules. If the molecules of a substance are held together by strong intermolecular forces, the substance will display a low vapour pressure at a given temperature and vice versa.

Ammonia has the lowest vapour pressure because of strong intermolecular hydrogen bonds that hold its molecules together.

The trend for increasing vapor pressure will be:

NH₃<NF₃<BCl₃

We know that,

The stronger the intermolecular forces, the lower the vapor pressure, and the higher the boiling point.

Thus to solve this question we need to look the intermolecular attractions in the given molecules.

1. In ammonia molecule, since it is polar in nature. It exhibits, dipole-dipole interactions and also there is hydrogen bonding between nitrogen and hydrogen atoms. So these interactions are strongest  thus NH₃ will have lower value of vapor pressure.

2. Forces of attractions in NF₃ is also stronger in comparison to BCl₃ but weaker than NH₃ thus in terms of vapor pressure it will come after NH₃.

3. Lastly, in BCl₃ it is a non-polar molecule; it exhibits London forces which are the weakest thus it will have the higher value of vapor pressure.

Trend for intermolecular attraction:

ion-dipole>hydrogen bonding>dipole-dipole> London forces > Van der Waals forces

Therefore,

Increasing order of vapor pressure will be:

NH₃<NF₃<BCl₃

Learn more:

https://brainly.com/question/14220340

Answer:

scientists use the scientific method to collect measurable, empirical evidence in an experiment related to a hypothesis. The process of the scientific method involves making conjectures.

Answer:

pH=3.40

Explanation:

For this question, we can start with the general ionization reaction of a general acid:

[tex]HA~<->~A^-~+~H^+[/tex]

The acids can produce the hydronium ion ([tex]H^+[/tex]). If we can to calculate the pH we have to use the equation:

[tex]pH=-Log[H^+][/tex]

So, if we want to calculate the pH value we have to know the concentration of the hydronium ion. For this, we can check the percentage of ionization. If we have 0.2 % of ionization, we will have only  0.2 % of hydronium ions from the initial concentration. In other words, we can calculate the concentration of [tex]H^+[/tex], if we do the 0.2% of the initial concentration, so:

[tex]0.2~M*\frac{0.2}{100}~=~0.0004~M[/tex]

With the concentration we can calculate the pH:

[tex]pH=-Log[0.0004~M]~=~3.40[/tex]

The pH value is 3.40

I hope it helps!

Answer: Cl-35

Explanation:

Answer:

A particular kind of matter

Explanation:

Answer:

y = 35.06 %.

Explanation:

The reaction of fermentation is:

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂      (1)        

From the reaction (1) we have that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH, then the number of moles of C₂H₅OH is:

[tex]n = \frac{2 moles C_{2}H_{5}OH}{1 mol C_{6}H_{12}O_{6}}*1 mol C_{6}H_{12}O_{6} = 2 moles C_{2}H_{5}OH[/tex]

Now, we need to find the mass of C₂H₅OH:

[tex]m = n*M = 2 moles*46.07 g/mol = 92.14 g[/tex]  

Finally, the percent yield of C₂H₅OH is:

[tex] \% = \frac{32.3 g}{92.14 g}*100 = 35.06 \% [/tex]

Therefore, the percent yield of C₂H₅OH is 35.06 %.

I hope it helps you!

The percent yield of C2H5OH should be 35.06% also it have the 1.00 moles.

Since

The reaction of fermentation should be

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂      (1)        

Here  1 mol of C₆H₁₂O₆ generated 2 moles of C₂H₅OH, so the number of moles of C₂H₅OH should be

= 2 moles / 1mole * 1 mole

= 2 moles C₂H₅OH

So here the percent yield should be

= 32.3 / (2 * 4607)

= 32.3 / 92.14

= 35.06%

Hence, The percent yield of C2H5OH should be 35.06% also it have the 1.00 moles.

Learn more about moles here: https://brainly.com/question/19669595

Answer:

i dont have much detail, but im pretty sure it would be at a boil/vaporizing phase.

Answer:

72.45 mmol K⁺ and 36.225 mmol Cr₂O₇²⁻

Explanation:

It is possible to obtain millimoles of a substantce by the multiplication of molarity times milliliters of the solution.

In the solution that is 0.0750M K₂Cr₂O₇:

K⁺ = 0.0750M * 2 = 0.150M

Cr₂O₇²⁻ = 0.0750M

The millimoles of these ions are:

Millimoles K⁺:

483mL * 0.150M = 72.45 mmol K⁺

Millimoles Cr₂O₇²⁻:

483mL * 0.075M  = 36.225 mmol Cr₂O₇²⁻

Answer: As altitude increases, there is less air pushing down from above, which decreases the pressure.

Explanation:

Atmospheric pressure is the result of air particles being pulled to the surface of the Earth by gravity. As they are pulled, they will exert more pressure on the Earth and this is what atmospheric pressure is.

It makes sense therefore that as we move higher into the atmosphere, the atmospheric pressure will decrease because less air particles are exerting pressure as we go further off the ground.

Another way to look at it is that there is air in the earth's atmosphere and all that air has weight that is pushing down on us. As we go higher into the atmosphere, there'll be less air pushing down on us so the weight will be less.

Answer:

A as te altitude increases

Explanation:

Answer:

The value is [tex]U =1.3908 *10^{11} \ kg [/tex]

Explanation:

From the question we are told that

mass of carbon dioxide produced by one gallon of gasoline is [tex]m = 9.50 \ kg[/tex]

The number of cars is [tex]N = 40 \ million = 40 *10^{6} \ cars[/tex]

The distance covered by each car is [tex]d = 7930 \ mi[/tex]

The rate is [tex]R = 23.6 \ mi/ gallon[/tex]

Generally the amount of gasoline used by one car is mathematically represented as

[tex]G = \frac{d}{R}[/tex]

=> [tex]G = \frac{7930}{23.6}[/tex]

=> [tex]G = 366 \ gallons [/tex]

Generally the amount of gasoline used by N cars is

[tex]H = N * G[/tex]

=> [tex]H = 40*10^{6} * 366[/tex]

=> [tex]H = 1.464*10^{10} \ gallons [/tex]

Generally the annual production of carbon dioxide is mathematically represented as

[tex]U = m * H[/tex]

=> [tex]U =9.50 * 1.464*10^{10}[/tex]

=> [tex]U =1.3908 *10^{11} \ kg [/tex]