The rate of turn can be increased and the radius of turn decreased by decreasing airspeed and shallowing the bank. Option C.
Turn radius depends on both airspeed and bank angle. The turning radius at any bank angle is directly proportional to the airspeed squared. Doubling the airspeed quadruples the turning radius, and trebling the airspeed quadruples the radius.
During a constant banked turn, increasing airspeed will decrease turn speed and increase turn radius. Airplanes fly fast, but the distance they fly is faster than their speed. As a result, it takes longer to complete a turn and slows down the turn.
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which of these correctly compares the masses of different objects in the universe?
In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.
Do stars have more mass than planets and less mass than galaxies?A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.
What is the proper ranking of the universe's elements, from smallest to largest?Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.
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the figure (figure 1) is a current-versus-potential-difference graph for a material. What is the material's resistance?
Resistance of material, R = 50 Ω
Ohm's law is one of the most fundamental and significant principles governing electrical circuits. Under the assumption that all physical parameters and temperatures stay constant, Ohm's law asserts that the voltage across a conductor is precisely proportional to the current flowing through it.
The German physicist Georg Ohm, who published a dissertation in 1827 describing measurements of applied voltage and current via basic electrical circuits with different lengths of wire, is credited with giving the rule its name.
Ohm's law, which modifies the connection between the voltage and the current by taking into account the resistance value, is crucial to understanding how electric circuits work.
As per the image attached below,
Using Ohm's Law,
V = I * R
At 100 v, current = 2 A
100 = 2 * R
R = 50 Ω
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The correct image of the questions is attached below:
a speeding driver sees a police officer, hits her brakes, and changes her speed from 41 mph to 18 mph in 2.7 seconds. what was her average acceleration (in m/s2) during this time?
Her average acceleration (in m/s2) during this time is 8.5 mph / sec².
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
V 1 = 41
V 2 = 18
time = 2.7 seconds
Acceleration = V2 - V1 / time
= 18 - 41 / 2.7
= 23 /2.7
= 8.5 mph / sec²
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. Movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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what aspect of the blackbody spectrum forced planck to propose energy quantization?
Black body spectrum forced planck to propose energy quantization Radiation occurs at a particular frequency that does not change.
Energy is the ability to perform work in physics. Different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc., can be assumed by it. Two further examples of how energy may be transferred from one body to another are heat and work. Energy is consistently distributed after being given in accordance with its kind. As a result, heat transfer can provide thermal energy while effort can produce mechanical energy. Motion is a property that all forms of energy have in common. When a body is moving, for instance, kinetic energy is present. Due to the device's integration of potential energy, a tensioned item, such a spring or bow, can move even when at rest.
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in a liquid with a density of 1000 kg/m3, longitudinal waves with a frequency of 145 hz are found to have a wavelength of 10.0 m. calculate the bulk modulus of the liquid.
The bulk modulus of the liquid is 0.25 × [tex]10^{10}[/tex]Pa
Given ρ = 1000kg/[tex]m^{3}[/tex],n = 145 HZ, λ = 10m
We have velocity of wave v = nλ
v = 145 × 10 = 1450m/s
The velocity of longitudinal wave in a liquid of density ρ is given by.
V = √K/ρ
K = bulk modulus of liquid
1450 = [tex]\sqrt{K/1000}[/tex]
K = 0.25 × [tex]10^{10}[/tex]Pa
A substance's bulk modulus (sometimes written as "displaystyle K" or "displaystyle B") indicates how resistant it is to compression. It is described as the proportion between an increase in pressure that is infinitesimally small and the ensuing proportional decrease in volume. [1]
Shear and Young's moduli both explain how the material responds (strains) to different types of stress. The former defines how the material responds to shear stress, while the latter describes how the material responds to normal (lengthwise stretching) stress. Only the bulk modulus of a fluid has any significance. The entire generalized Hooke's law must be used to fully describe the behavior of a complex anisotropic solid like wood or paper because the information contained in these three moduli is insufficient.
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. consider the 65.0-kg ice skater being pushed by two others shown below. (a) find the direction and magnitude of ftot, the total force exerted on her by the others, given that the magnitudes f1 and f2 are 26.4 n and 18.6 n, respectively. (b) what is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of ftot? (c) what is her acceleration assuming she is already moving in the direction of ftot? (remember that friction always acts in the direction opposite that of motion or attempted motion between surfaces in contact.)
For the purpose of determining the acceleration, we will employ Newton's second law. F (totally) = ma, a = F(totally) / m, a = 32.0 N / 65.0 kg = 0.492 m/s2. If she starts out motionless and skating on steel blades, her initial acceleration is about 0.492 m/s2.
By magnitude, what do you mean?"Distance or quantity" is the simplest definition of magnitude. It depicts the amount and direction that even a body travels in either an absolute or comparative perspective.
What is an illustration of magnitude?Size is referred to as magnitude. A automobile is traveling more quickly than a bike, for instance, when it comes to speed. In this case, the car is moving faster than the bike by a larger margin.
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in the circuit shown in the figure (figure 1), find the magnitude of current in the upper branch.
0.8 A of current is flown through the upper branch of the circuit shown below:
as shown in the figure the current through lower loop is [tex]I_1+I_2[/tex] and the current through the upper loop is [tex]I_2[/tex].
the kirchoff's loop eqns in lower loop is:
-4[tex]I_1[/tex] + 5 -[tex]I_1[/tex] - 10([tex]I_1+I_2[/tex]) = 0
=> 2[tex]I_1[/tex] +[tex]I_1[/tex] + 2[tex]I_2[/tex] = 1
=> 3[tex]I_1[/tex] + 2[tex]I_2[/tex] =1 ----- (i)
we have obtanied 1 equation
the kirchoff's loop eqns in upper loop is:
-3[tex]I_2[/tex] +10 -2[tex]I_2[/tex] + [tex]I_1[/tex] - 5 +4[tex]I_1[/tex] = 0
=> - 5 [tex]I_2[/tex] +10+ 5 [tex]I_1[/tex] -5 =0
=> [tex]I_2[/tex] - [tex]I_1[/tex] =1 -------(ii)
solving equation (i) and equation (ii) we get
[tex]I_1[/tex] = -0.2
here negative sign represents that the current direction is opposite to our assumption.
so [tex]I_2[/tex] = 1 + [tex]I_1[/tex]
=> [tex]I_2[/tex] = 0.8A
So the current through the upper branch is 0.8A
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Complete question:
in the circuit shown in the figure , find the magnitude of current in the upper branch.
what is the frequency of damped vibration for a single degree of freedom system with a spring of stiffness k n/m, a mass of m kg and a damping ratio of 0.1?
The frequency of damped vibration for a single degree of freedom system is Wd = 0.99[tex]\sqrt{\frac{k}{m} }[/tex]
Calculation :
Natural frequency (Wn)= [tex]\sqrt{\frac{k}{m} }[/tex]
Damped frequency (Wd) = Wn[tex]\sqrt{1-s^{2} }[/tex] (s = damping ratio)
= Wn[tex]\sqrt{1-0.1^{2} }[/tex]
= Wd = 0.99[tex]\sqrt{\frac{k}{m} }[/tex]
Frequency is the number of occurrences of a repeating event per unit time. For clarity, also called temporal frequency, which is different from angular frequency. Frequency is measured in hertz (Hz) and corresponds to one event per second. Duration is the reciprocal of frequency because duration is the time interval between events.
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What is the weight of a 72-kg astronaut on the Moon (g = 1.7 m/s2)?
W=117.36 N is the weight of a 72-kg astronaut on the Moon (g = 1.7 m/s2)
Equation
W=mg
W=72 kg *1.63 m/s²
W=117.36 N
Weight is force, and the Newton is its unit.
what is an astronaut?
An astronaut is a person who has been trained, outfitted, and sent into space by a human spaceflight programme to work as a commander or crew member on a spaceship. The word astronaut is derived from the Ancient Greek words v (astron), which means "star," and (nautes), which means "sailor." The phrase is occasionally used to refer to anyone who travels into space, including scientists, politicians, media, and tourists, despite the fact that it is typically designated for professional space travellers.
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what is the adjusted ampacity for each of six no. 4/0 thhn copper current-carrying conductors in a single conduit? (given: the ampacity of 4/0 thhn is 260a.)
The adjusted ampacity for each of the six No. 4/0 THHN copper current-carrying conductors in a single conduit is 220 amps.
This is because the ampacity of 4/0 THHN is 260 amps, but when more than three current-carrying conductors are in the same conduit, they must be derated. To derate, multiply the ampacity by the appropriate factor. In this case, the factor is 0.85, so 260 multiplied by 0.85 gives 220. Additionally, the National Electrical Code requires that the ampacity of the conductor must not be less than the rating of the overcurrent device which is protecting the circuit. In other words, the ampacity of the conductor must not be less than the rating of the fuse or circuit breaker protecting the circuit. This means that the ampacity of the conductors must be 220 amps or greater.
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What is the electric flux through the surface shown in the figure? Assume that E = 340N/C. Express your answer in newton meters squared per coulomb.
In this case, the electric field is 340 N/C, and the area vector is normal to the surface, so the dot product of the two is 0.
Electric flux is a measure of the amount of electric field that passes through a given area. It is measured in units of coulombs per meter squared (C/m2). Electric flux is important in electric circuits and fields, as it allows for the calculation of electric field strength, current, and other electrical properties. Electric flux is related to the concept of electric field lines, which represent the direction of the electric field at any point.
The electric flux through the surface shown in the figure is 0 N ⋅ m2/C. This is because the electric field is perpendicular to the surface and so no electric flux is passing through it. The electric flux is calculated as the dot product of the electric field and the area vector, and since the two are perpendicular, the result is 0.
Mathematically, electric flux is given by the formula Φ = E · A, where E is the electric field and A is the area vector.
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if you continue to exert this force once the crate starts to slip, what will its acceleration then be?
a) The maximum force that can be applied horizontally to the crate without moving it is 58.8 N.
b) The magnitude of the acceleration on the crate that starts to slip is 1.96 m/s².
The given problem is based on the concept of friction. If the crate is stationary and maximum horizontal force is applied, maximum static friction will act. If the crate starts sliding, kinetic friction will start to act. Newton's laws can be written in both cases. With the solution, we will get the maximum horizontal force in the first case and the acceleration in the second case.
a) A crate is not moving:
Because the crate is in balance
N = m.g
[tex]F_s[/tex] = Static
[tex]F_s[/tex] < F_max and F_max = μ[tex]_s[/tex]mg
In question:
μ[tex]_s[/tex] = 0.5, m = 12 kg, g = 9.8 m/s
F_max = μ[tex]_s[/tex]mg
F_max = 0.5 x 12 x 9.8
F_max = 58.8 N
b) Crate has started slipping:
F = F[tex]_s[/tex] - F[tex]_k[/tex]
m.a = μ[tex]_s[/tex]mg - μ[tex]_k[/tex]mg
a = g (μ[tex]_s[/tex] - μ[tex]_k[/tex])
a = 9.8 (0.5 - 0.3)
a = 1.96 m/s²
So, crate acceleration has started slipping is 1.96 m/s²
Complete question:
Suppose you have a 120-kg wooden crate resting on a wood floor (μ[tex]_k[/tex]
= 0.3, μ[tex]_s[/tex] = 0.5).
(a) what maximum force can you exert horizontally on the crate without moving it?
(b) if you continue to exert this force once the crate starts to slip, what will the magnitude of its acceleration then be?
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the heat capacity of manganese is 0.480 kj kg-1 k-1. how much energy is required to raise the temperature of 3.00 kg of manganese by 20.0 k?
The amount of energy required by 3 kilogram of Manganese to raise the temperature by 20 degree kelvin is 28.8 KJ.
The heat capacity of manganese is given to be 0.480 KJ/kg-K.
We have to raise the temperature of 3 kilogram of Manganese by 20 degree kelvins.
We know that the change in heat of the compound is given by the formula,
Q = MC∆T
Where Q is the heat/energy gained,
C is the heat capacity of Manganese,
∆T is the total change in temperature of Manganese.
Putting values in the above relation accordingly,
Q = 0.480 x 3 x 20
Q = 28.8 KJ.
So the energy required to raise the temperature of Manganese by 20 kelvin is 28.8 KJ.
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A pring of force contant 120N/m i acted upon by a contant force of 240N. Calculate the elatic potential energy tored in the pring
A spring of force constant 120N/m is acted upon by a constant force of 240N. The elastic potential energy stored in the spring is 240 Nm.
The elastic potential energy stored in a spring is given by the formula:
= U = 1/2 x k x x^2
Where U is the elasticity potential energy, k is the force constant of the spring, and x is the displacement of the spring from its equilibrium position. In this case, the force constant of the spring is 120 N/m, and the constant force acting on the spring is 240 N. To find the displacement of the spring, we can use the formula:
= F = k x x
Where F is the force applied to the spring, k is the force constant, and x is the displacement.
Solving for x, we get:
= x = F / k
= 240 N / 120 N/m
= 2 m
Substituting this value for x into the formula for elastic potential energy, we get:
= U = 1/2 x 120 N/m x 2 m^2
= 240 Nm
So the elastic potential energy stored in the spring is 240 Nm.
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if c(x) is a cost function, then c'(x) would be called the
The cost C is defined by the cost function as a function of the quantity x of things. As a result, C(x) is the price of x products. A linear cost function is one that has the formula C(x) = mx + b.
The quantity mx is referred to as the fixed cost, and the intercept b is referred to as the variable cost. The incremental cost per item is measured by the slope m, or marginal cost.
As a result, the relationship between the cost function and the profit function posits that a company cannot alter its profit without also altering its output and overall production costs. The cost function can also be used to calculate the average cost and the marginal cost of production in addition to calculating the overall production cost.
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rank in order, from largest to smallest, the angular velocities ω1, ω2, and ω3 of these points.
ω₁ = ω₂ = ω₃ Every particle rotates about the axis of rotation with a constant angular velocity (ω). The rank for velocity is v₃ > v₂ = v₁ because = r and r₁ = r₂<r₃.
A pseudovector used to express how quickly the angular location or orientation of an item changes over time is called an angular velocity or rotational velocity ( or ). (i.e. how quickly an object rotates or revolves relative to a point or axis). The pseudovector's direction is normal to the instantaneous plane of rotation or angular displacement, and its magnitude corresponds to the object's angular speed, or the rate at which it rotates or revolves. The right-hand rule is typically used to specify the direction of angular motion.
The angular velocity comes in two flavors.
Orbital angular velocity, also known as the temporal rate of change of an object's angular location with respect to an origin, is the rate at which a point object revolves about a fixed origin.In contrast to orbital angular velocity, spin angular velocity describes how quickly a rigid body rotates with regard to its center of rotation and is independent of the choice of origin.To know more about angular velocity
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a 29 kg child is coasting at 2.4 m/s over flat ground in a 5.0 kg wagon. the child drops a 1.4 kg ball from the side of the wagon. what is the final speed (in m/s) of the child and wago
The final speed of child and wagon is 2.503 m/s.
Given that, mass of the child is 29 kg
Mass of the wagon is 5 kg
Initial mass of the child and the wagon mi = 29 + 5 = 34 kg
It is said that the child dropped 1.4 kg ball from the wagon.
So, final mass mf = 29 + 5 - 1.4 = 32.6 kg
From the law of conservation of linear momentum, we know that
Initial momentum = Final momentum
mi * vi = mf * vf
where, vi is the initial velocity
vf is the final velocity
Making vf as subject, we have
vf = (mi * vi)/mf
Initial velocity is given as 2.4 m/s
Placing the values in the above equation, we have
vf = (mi * vi)/mf = (34 * 2.4)/32.6 = 2.503 m/s
Thus, the final speed of child and wagon is 2.503 m/s.
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Which of the following is not true about Magnetic field Lines? 1 point Are always north to side outside magnet Are always south to north inside the magnet Are always north to south inside the magnet Has tangential direction at curves
The statement that is not true about magnetic field line is that they are always from north to south inside the magnet.
When a bar magnet is observed closely in the presence of the small metal granules.
We can observe a pattern, the magnetic field lines are always from north to south outside the magnet.
But when we talk about inside the magnet the direction of the magnetic field lines are from South to North.
Magnetic lines forms a loop like shape outside the magnet the direction of which is given by a tangent drawn to the curve of the magnetic field line.
The direction of the magnetic field line is tangential at the curves.
So the only statement that is not true about the magnetic field lines are that they are from north to south inside the magnet.
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a trailer truck traveling east at 24m/s sounds a 950 hz horn. what is the wavelength of the sound heard by a stationary listner located est of the truck
The wavelength of the sound heard by a stationary listner located est of the truck is 0.332 m
F = fο (V/V - Vs) ,Doppler effect
= 950 (340 / 340 -24) = 1022.25 HZ
λ = V / F = 340 / 1022.25 = 0.332 m
Everything in sound is a vibration. The larynx (voice box) of a person, the string of a guitar, or the loudspeakers on your radio all need to vibrate in order to produce sound. When sound waves move away from their source, vibrating particles knock into other vibrating particles, which in turn causes those other particles to vibrate and knock into still more particles, and so on. Our eardrums vibrate in response to air vibrations, and these vibrations are then transformed into nerve signals and delivered to our brains, which enable us to perceive sound. Similar to this, microphones translate air vibrations into electrical signals after detecting them.
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an electron volt, ev, is a unit of energy. which is larger, a gev or a mev?
GeV is 1000 times larger than MeV .
"When an electron crosses a one volt potential, which is measured in electron volts, it gains energy" (eV). An electron volt, or ev, serves as the sign for energy. Electron volts, a measure of energy often used in atomic and nuclear physics, are the amount of energy that an electron (a charged particle carrying one unit of charge) acquires when the electric current at the electron increases by one volt.
Mega electron-volts, or MeVs, are a million times more potent than electron-volts. An electron has an energy of one eV.
When the giga-electron volt, or 109 eV, is initialised, energy is released in units of meV that are equivalent to 3108 ms 1 for every kilogramme of mass that is completely converted to energy.
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why is the uncertainity principle or the wave nature of particles not significant when looking at macroscopic objects
The uncertainty principle of the wave nature of particles does not matter as much when looking at macroscopic objects because, unlike microscopic objects, their location and velocity don't change when photons strike them.
The uncertainty principle states that an object's position and velocity can't be measured exactly at the same time. It applies commonly to particles that can only be observed using a microscope. That is because, for objects as small as them, when light strikes them, their location and velocity may get altered.
Macroscopic object, on the other hand, does not get any significant alteration by photons. While they may be altered, the amount is very minuscule that it has hardly any consequence, making the uncertainty principle insignificant for macroscopic objects.
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What is the condition necessary for free fall
Answer:
The free fall is a motion that happens when we let something fall from certain height, this motion only happens when the object falls because of its own weight without any initial force or initial velocity, because then we would be talking about a vertical motion.
The free fall is a uniformly accelerated motion that only moves in the vertical axis (“y” axis), with the condition that the initial velocity will always have to be equals to 0 and the acceleration will be the value of the gravity in the place of the motion (9.8m/s). When a free fall motion happens in perfect conditions (this means that there is no air or any other factor that affects the trajectory of the object) the object only moves vertically.
When an object is in free fall, it will star with a 0m/s velocity, but while time passes, the velocity of the object will increase progressively until it impacts the floor or any object that is in its trajectory, this is why, the higher the initial height is, the stronger the impact will be against the floor.
Free Fall Conditions
The trajectory of an object in free fall could be affected by the air masses, an atmospheric phenomenon also known as aerodynamic resistant. In theory an object in free fall only moves vertically, but because of the air masses the trajectory of the object could change, both vertically and horizontally, how much will the air masses affects the object will depend on the weight of the object, if the object is heavier, then the air masses will not affect the object that much.
The condition depends on the property of the material under free fall. For example, if the body has a certain mass as well as charged, it causes a deflection due to Earth's magnetic field. Also the Coriolis effect due to Earth's rotation (when dropped from space to earth) comes into play when the object falls from a much higher altitude.
calculate the energy required to lift an elevator and its occupants with a mass of 1000 kg through a vertical distance of 5 m. group of answer choices 49000 j 5000 j 11000 j 2500 j
The energy required to lift an elevator and its occupants with a mass of 1000 kg through a vertical distance of 5 m is 49000 j .
Calculation :
Work done by any object . will be stored in the form of energy .
Energy stored = Work done = Force * Distance
= Mass * acceleration * Distance
As lift moving up force is acting on it due to gravity,
force = Mass * acceleration due gravity
Energy = Mass * acceleration due gravity* Distance
= 1000 kg * 9.8 m/sec² * 5m
= 49000 joule
energy as the ability to do work. Modern civilization is possible because humans have learned to convert energy from one form to another and use it for work.
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in pushing a load, a woman exerts a force as given by the graph. what was the total work done by the woman?
The total work done by the woman is 1000J.
The work done by a force is defined as the product of the displacement component of the force and the magnitude of that displacement. method. Work can be calculated by multiplying the force and the displacement in the direction of the force as
When a person pushes against a wall the displacement of the wall is zero because the wall does not move when a force is applied to it. The work done by a force is the product of the component of the force applied to the body in the direction of displacement and displacement.
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a 25 kg bear slides, from rest, 12 m down a lodgepole pine tree, moving with a speed of 5.6 m/s just before hitting the ground. (u) what change occurs in the gravitational potential ener
The gravitational potential energy of the bear decreases as the bear slides from top to bottom of the pine tree.
Given that,
Mass of the bear = 25 kg
Speed of the bear = 5.6 m/s
Height from which the bear slides = 12 m
Gravitational potential energy depends on the height of the bear. As the bear slides from top to bottom, the height keeps decreasing gradually. The formula for gravitational potential energy is P.E = m* g* h
where, m is the mass of the bear
g is the acceleration due to gravity
h is the height at which the bear stays
From the above relation, it is clear that, potential energy is directly proportional to the height of the object.
Thus, gravitational potential energy of the bear decreases as the bear slides down the pine tree.
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if the internal energy of a thermodynamic system is increased by j while j of expansion work is done, how much heat was transferred and in which direction, to or from the system?
U=q+w In other words, heat (q) and work (w) are added to define internal energy (w). Now that you are exerting force on your surroundings to do expansion work, you are losing energy and are aware that x joules of work are being lost by the system.
You may now connect those in and find a heat solution. The symbol on your heat indicates which way the flow was. Positive indicates that internal energy increased, which caused the system to gain heat; negative indicates that internal energy decreased, which caused the system to lose heat if that was the case.
like as U=300 and Work=75
The terms exothermic and endothermic simply denote whether heat is entering or exiting the system. Therefore, in this instance, we may conclude that it is endothermic since it absorbed heat because q ends up being 375, which is positive.
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An air conditioner uses a compressor to raise the temperature and pressure of _____. A. The outside air
B. The refridgerant
C. The inside air
Answer:
B. The refridgerant
Explanation:
this allows the refrigerant to absorb or release heat
a 1.6-kg grindstone in the shape of a uniform cylinder of radius 0.20 m acquires a rotational rate of 24 rev/s from rest over a 6.0-s interval at constant angular acceleration. calculate the torque delivered by the motor.
Stone weight in kilograms, m = 1.6 0.2 m is the radius. The rotational rate torque of a di is = I I
What is the circumference of a shape?It is the circumference of a circle. A radius can indeed be defined as a line drawn around the circle's perimeter from any point to its center. Depending on whether you know the circle's diameter, circumference, or area, you can calculate the radius using one of three formulas.
How do radius and diameter work?The diameter of a circle cuts through the center, whereas the radius circumscribes the circle from edge to edge. The size of a circle essentially divides it in two.
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if the moment of inertia of the shaded area about the a-a' axis is 18e6mm^4 what is the moment of inertia about the b-b' axis
The moment of inertia about the b-b' axis is 24.6E6 mm^4.
To find the moment of inertia of the shaded area about the B-B' axis, we can use the formula I = ∑m*r^2, where m is the mass of each particle in the shaded area, r is the distance of each particle from the B-B' axis, and the sum is taken over all particles in the shaded area.
We are given that the moment of inertia of the shaded area about the A-A' axis is
18E6 mm^4,and that the area of the shaded region is
A = 6E3 mm^2.We are also given the distances
ds = 50 mm and d₂ = 10 mm,which correspond to the distances of the two particles in the shaded region from the B-B' axis.
The mass of each particle in the shaded region can be calculated by dividing the total mass of the region (which is equal to the product of the area and the density of the material) by the number of particles. Since the density of the material is not given, we cannot calculate the mass of each particle.
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Complete Question:
If the moment of inertia of the shaded area about the A-A' axis is 18E6 mm, what is the moment of inertia about the B-B' axis?
Given: A6E3 mm², ds-50 mm, d₂-10 mm
a. none of these answers
B. 21.2E6 mm^4
C 25.2E6 mm^4
D. 26.3E6 mm^4
E. 24.6E6 mm^4
You live on a busy street, but as a music lover, you want to reduce the traffic noise.Part A If you install special sound reflecting windows that reduce the sound intensity level by 20.0 dB, by what factor have you reduced the sound intensity?Part B If, instead, you reduce the intensity by half, what change (in dB) do you make in the sound intensity level?
A. You have decreased the sound intensity by 0.01 factor if you install special sound-reflecting windows that lower the level of sound intensity by 20.0 dB.
B. No, Instead, if you cut the intensity in half, there is no difference in the sound intensity level (measured in dB).
To calculate the sound intensity reduction factor, use the relationship between loudness and intensity. Calculate the change in sound intensity using the reduced intensity. The following chart shows the relationship between the change in loudness and the level of sound intensity.
dl = 10log(I/I1)
Here, dl represents the change in loudness, I represents sound intensity, and I1 represents the reference sound intensity in air.
I =(I1/2)
(A) The following is the expression for a reduction in sound volume:
10log*(I/I1) divided by 20 equals dl.
(I/I1)
The negative symbol denotes a drop in sound volume.
log(I/I1) = -20/10
I/I1 = 10^(-20)
I/I1 = 1/100
I/I1 = 0.01
The reduction is thus 0.01 as a result.
B) The initial and ending values of the sound intensity parameters affect how loud the sound is. Sound is louder and its waves are more intense. Loudness increases by 10 times for every 10dB increase in sound intensity. The intensity is reduced by a factor of two from its initial value, hence the change in sound intensity is negative. The strength of the ear's perception of sound is referred to as sound loudness.
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