rank the labeled protons (ha-hd) in order of increasing acidity, starting with the least acidic.

a) The number of moles of KCl formed is 0.51 moles.

b) The number of molecules of KCl is 1.38 * 10^22 molecules.

c) The mass of the potassium chlorate 8.94 g.

We know that we can be able to use the stoichiometry of the reaction to be able to find the amount of the KCl that is formed. The first step is to write down the reaction equation as it has been shown;

[tex]2KClO_{3} ----- > 2KCl + 3O_{2}[/tex].

We can see that we can be able to apply the principles of stoichiometry as stated earlier.

a) Number of moles of the potassium chlorate = 62 g/122.55 g/mol

= 0.51 moles

Then we have the number of the moles of the KCl as 0.51 moles.

b) Number of moles of the potassium chlorate =  2.85 g/122.55 g/mol

= 0.023 moles

If 2 moles of potassium chlorate produces 2 moles of KCl then 0.023 moles produces 0.023 moles of KCl.

Number of molecules of KCl = 0.023 moles * 6.02 * 10^23

= 1.38 * 10^22 molecules

c) If the number of moles of oxygen is; 3.54 g/32 g/mol = 0.11 moles

If 2 moles of potassium chlorate produces 3 moles of oxygen

x moles of potassium chlorate produces  0.11 moles

x = 2 * 0.11/3

= 0.073 moles

Mass of the potassium chlorate =  0.073 moles * 122.55 g/mol

= 8.94 g

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90 g CH₃NH₃Cl should be dissolved in the solution to turn it into a buffer with pH.

90 g CH₃NH₃Cl should be used by the student to dissolve in the solution and to turn methylamine into a buffer with pH.

A 1.70 M of methylamine solution, weighing 450 mL, is delivered to a graduate student in chemistry.

Methylamine (weak base) has a Kb value of 4.4 x 104.

To create a buffer solution with a pH of 10.40 out of the methylamine solution, we should know how much CH₃NH₃Cl should the student dissolve in it.

We will use the Henderson-Hasselbach equation:

pH = pKa + log

So first we use Kb to calculate Ka and then calculate pKa:

Ka = Kw/Kb

⇒ Ka = 1x10⁻¹⁴/4.4x10⁻⁴ = 2.27x10⁻¹¹

pKa = -log(Ka) = 10.64

Now we can calculate the concentration of the salt, CH₃NH₃Cl:

pH = pKa + log (methylamine/salt)

10.40 = 10.64 + log (1.7/salt)

-0.24 = log (1.7/salt)

10⁻²⁴ = log (1.7/salt)

[Salt] = 2.95 M

Now, using the final volume and CH₃NH₃Cl's molecular weight, we can determine its mass and moles by,

450 mL ⇒ 450/1000 = 0.450 L

2.95 M × 0.450 L = 1.3275 mol CH₃NH₃Cl

1.3275 mol CH₃NH₃Cl × 67.45 g/mol = 89.54 g CH₃NH₃Cl

After rounding off to 2 significant digits it becomes 90 g CH₃NH₃Cl

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There are approximately 0.000486 moles of hydrogen present in the sample.

To find the number of moles of hydrogen present in the sample, you need to use the ideal gas law equation, which is PV = nRT where P is the pressure of the gas (in atm), V is the volume of the gas (in L), n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas (in K). First, you need to convert the pressure from torr to atm. You can do this by dividing the pressure in torr by 760, since 1 atm is equal to 760 torr. In this case, the pressure in atm would be: P = 764.5 torr / 760 = 1.0059 atm Next, you need to convert the volume from ml to L. You can do this by dividing the volume in ml by 1000, since 1 L is equal to 1000 ml. In this case, the volume in L would be: V = 30.42 ml / 1000 = 0.03042 L Finally, you need to convert the temperature from degrees Celsius to Kelvin. You can do this by adding 273.15 to the temperature in Celsius. In this case, the temperature in K would be:T = 25.58 degrees Celsius + 273.15 = 298.73 K Now that you have all the necessary values, you can plug them into the ideal gas law equation to solve for the number of moles of hydrogen: n = (PV) / (RT) = (1.0059 atm * 0.03042 L) / (8.31 J/mol*K * 298.73 K) = 4.86 x 10^-4 mol Therefore, there are approximately 0.000486 moles of hydrogen present in the sample

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The pressure of gas canister at 1250° Celsius is 312 atm which is more than the total internal pressure. Hence, it will explode.

Calculating the pressure of the volume of gas after being heated to 1250° Celsius. This will be done through ideal gas equation which is as follows -

PV = nRT, where P is pressure, V is volume, n is number of moles, R is gas constant and T is temperature.

Converting temperature to Kelvin

T = 1250 + 273

T = 1523 K

P = 3.5×0.082×1523/1.4

Performing multiplication on Right Hand Side of the equation

P = 437.1/1.4

Performing division on Right Hand Side of the equation

P = 312.2 atm

The gas canister will explode as the pressure exceeds.

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An unsusual dining experience I had was at an eatery that provided a live band as well as had wel dressed security personnel who danced to wecome their customers.

The restauarant stood out for me because of the quality of the food and the entertainment. Hence, I decised to alway visit the restaurant anytime I visist the area.

The additional tasks include:

Diners are individuals who are eating out in a restaurant or eatery.

Diners are usually out to get the best dining experience.

In recent times,  Diners are not only interested in a good meal these days; they often want to enjoy entertainment as well.

Hence, eateries or restuarants are now seeking out new ways to provide entertainment to their customers.

They do so by providing the best of meals in great environments as well providing an accompanying entertainment.

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The vapor pressure of the glucose solution at 25°C is 20.16 mmHg.

To answer this question, we need to use Raoult's Law. Raoult's Law states that the vapor pressure of a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution.

In this case, the solvent is water and the solute is glucose. We can use the given information to calculate the mole fraction of water in the solution:

Mole fraction of water = (72.0 g H2O) / (72.0 g H2O + 18.0 g C6H12O6) = 0.8

We can then use Raoult's Law to calculate the vapor pressure of the glucose solution:

Vapor pressure of glucose solution = (Vapor pressure of pure water) * (Mole fraction of water in solution)

= (25.2 mmHg) * (0.8)

= 20.16 mmHg

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The pH will fall below 7.00. Ammonia makes up 0.050 moles. In water, a polar solvent, an ionic solute dissolves because the polar water molecules draw the ions into solution, where they hydrate.

This means that equal amounts of moles of sodium hydroxide and hydrochloric acid are needed for a full neutralization to produce a neutral solution, or a solution with a pH of 7 at ambient temperature. As a result, a substance's molar mass, also known as its molecular mass or Mm, is equal to its atomic or molecular weight stated in grams. Determine the pH of a solution that contains 0.20 M ammonium chloride and 0.10 M aqueous ammonia. As you are aware, sodium hydroxide and hydrochloric acid have a mole ratio of 1:1 for neutralization.

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The formula for pH at a weak acid-strong base titration's equivalence point must be used to determine the pH at each stage of the titration:

[tex]pH = pK_a + log \frac{[A^-]}{[HA]}[/tex]

where pK a is the weak acid's acid dissociation constant, [A-] is the concentration of the acid's conjugate base, and [HA] is the acid's concentration.

The weak acid (formic acid) is at a concentration of 0.100 M at the start of the titration (0 mL of additional base), and the conjugate base (formate ion) is at a concentration of 0.00 M, resulting in a pH of:

[tex]pH = pK_a + log \frac{[A^-]}{[HA]} [/tex]

[tex]= pK_a + log \frac{0}{0.100} [/tex]

= pK_a + log(0)

We are unable to determine the pH at this time since the logarithm of 0 is undefinable.

The weak acid concentration falls as the titration goes along and more base is added, while the conjugate base concentration rises. The concentration of the weak acid is 15.0 mL when 15.0 mL of additional base is used.

[tex]0.100 M - \frac{0.200 M \times15 mL }{50 mL} [/tex]

= 0.080 M,

and the concentration of the conjugate base is

[tex] \frac{0.200 M \times 15 mL}{50 mL} [/tex]

= 0.060 M. The pH at this point is:

[tex]pH = pK_a + log \frac{[A^-]}{[HA]}[/tex]

[tex]= pK_a + log \frac{0.060}{0.080} [/tex]

= pK_a + log(0.75)

= pK_a + (-0.122)

You may use the same formula and the appropriate numbers for [A-] and [HA] to determine the pH at the other points in the titration.

It should be noted that the pH at the equivalence point (when the ratio of acid to base is equal) will be the same as the weak acid's pK a. Since the concentration of the weak acid is zero at the equivalence point, the pH is:

[tex]pH = pK_a + log \frac{[A^-]}{[HA]}[/tex]

[tex]= pK_a + log \frac{[A^-]}{0}[/tex]

[tex]= pK_a + log([A^-])[/tex]

The pH at the equivalence point will be lower than the pK a of the weak acid since the logarithm of a number less than 1 has a negative value. Beyond the equivalence point, adding more base will cause the pH to continue to drop.

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Answer:

an article published by a university or a government agency

and

an article published in 2015 and updated a week ago

Explanation:

Both of these meet the criteria for a credible source. Cites with Advertisements, blogposts, and anonymous cites do not

Answer:

The IUPAC names for Ascorbic Acid, Fructose, and Glucose are L-ascorbic acid, D-fructose, and D-glucose, respectively.

Explanation:

IUPAC (International Union of Pure and Applied Chemistry) names are standardized names used to identify chemical compounds. These names are based on the structure of the compound, and they provide a unique and unambiguous way to identify each compound.

The IUPAC name for Ascorbic Acid is L-ascorbic acid. Ascorbic acid is a compound with the chemical formula C6H8O6. It is a white, crystalline solid that is soluble in water. The "L" in the name indicates that the compound has a specific configuration of atoms, which is called the L-configuration.

The IUPAC name for Fructose is D-fructose. Fructose is a simple sugar with the chemical formula C6H12O6. It is a sweet-tasting substance that is commonly found in fruits and honey. The "D" in the name indicates that the compound has a specific configuration of atoms, which is called the D-configuration.

The IUPAC name for Glucose is D-glucose. Glucose is a simple sugar with the chemical formula C6H12O6. It is a sweet-tasting substance that is commonly found in plants and is an important source of energy for living organisms. The "D" in the name indicates that the compound has a specific configuration of atoms, which is called the D-configuration.

Answer:

The IUPAC name for ascorbic acid is 2-(1,2-dihydroxyethyl)-4,5-dihydroxyfuran-3-one.

The IUPAC name for fructose is (2R,3S,4R,5R)-2-(hydroxymethyl)-3,4,5-trihydroxytetrahydrofuran-3-ulose.

The IUPAC name for glucose is (2R,3R,4S,5S)-2-(hydroxymethyl)-3,4,5-trihydroxytetrahydrofuran-3-ulose.

The empirical formula is obtained by compositons: Cl2Zn for the empircal formula of a compound, given that the compound is found to be 47.9% zinc and 52.1% chlorine by mass

Calculate the molar mass of each element: Cl=35.453, Zn=65.409

Cl=1.469551236848, Zn=0.73231512482992 when expressed in moles.

Identify the least mole value: 0.73231512482992

Multiplying all elements by their lowest value Cl=2.0067197672451, Zn=1

rounding to the nearest whole number Cl=2, Zn=1

Cl[tex]_{2}[/tex]Zn for the empircal formula

The empirical formula, which is defined as the ratio of compositons of the least whole number of the components included in the formula, is the simplest formula for a compound compositons. The simplest formula is another name for it.

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The periodic table would element x be found is 1.

Atomic number or number of protons in an atom. The number of neutrons and the number of electrons is often the same as the number of protons but varies from atom to atom.

The current periodic table has 18 vertical columns called groups, arranged from left to right, and 7 horizontal rows called periods. Elements of this group form salts. They are noble gases and inert under normal conditions. It is called the periodic table because of the arrangement of the elements. You'll notice they are in rows and columns.

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NO+: Nitrogen mono-oxide ion is the exception.

The octet rule refers to the characteristic  feature of any atom to have preference for possessing eight electrons in the valence shell or outer shell.

RnCl2: Radon Chloride

The central Rn atom is bound to 2 Cl atom and itself has two lone pairs. Hence the number of electrons in valance shell is: (2*2) +(2*2) =8; It fulfils Octet rule.

CF4: Carbon tetrafluoride

The central Carbon atom is bound four F atoms. Hence the number of electrons in valance shell is: (2*4) = 8: Fulfils Octet rule.

N2: Nitrogen

N atom is bound to another N atom through triple bond and the substance also have one lone pair. Hence the number of electrons in valance shell is: (3*2) + 2 =8: Fulfils octet rule.

NO+: Nitrogen mono-oxide ion

In case the ion stays in a form of N+ bound to O atom through a double bond, the nitrogen molecule here would have six molecules in valance shall and would not obey Octet rule.

But in case the substance stays as N having a triple bond with O+, both the atom having 8 electrons in valance shell would fulfil octet rule.

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The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.

The electrochemical cell is the cell that is capable of generating the electrical energy from the chemical reactions or by the use of the electrical energy to cause the chemical reaction. The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.  

There are the two types of the electrochemical cells is as follows : the galvanic called the electrolytic cells. the galvanic cell is also called as the voltaic cell.

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An alloy is made of two or more different metals.These metals are of different sizes. This cause a distortion in the system and leads to a slide of of atoms when a force is applied and make it brittle.

Alloys are mixed metals. They are widely used in constructions, in electronic devices and in other industries due to their potential application superior over the pure metals.

There are atoms of various sizes in an alloy. The layers of atoms in pure metal are distorted by the smaller or larger atoms. This indicates that more force is needed to get the layers to slide over one another. Compared to pure metal, the alloy is tougher and more durable.

The irregularity of the atoms that make up high-entropy alloys is what gives is their immense strength. When the alloy is deformed, this disorder makes it difficult for the alloy's dislocation flaws to migrate through its crystal structure. But under adequate pressure, this also makes the alloy highly brittle.

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The age of that rock will be A. 2,000 million years.

The half-life period can be mathematically represented as follows,

t1/2 = 0.693/ Decay Constant

Half-life and the radioactive decay rate constant λ are inversely proportional which means the shorter the half-life, the larger λ and the faster the decay.

Decay Constant = 0.693/1000 * 106 years = 6.93*10-10 yr-1

We know that the radioactive decay equation as,

N = N0 e- (Decay Constant * Time)

N/N0 = 1/3 = e(6.93*10-10 yr-1 * time)

Time = 1600 * 106 years.

Time=2,000 million years

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Complete question:

The Half-Life Of A Radioactive Isotope Is 1,000 Million Years. Scientists Testing A Rock Sample Discover That The Sample Contains Three Times As Many Daughter Atoms As Parent Isotopes. What Is The Age Of The Rock? A. 2,000 Million B. 1,000 Million C. 500 Million D. 250 Million

There are 2.66 x 10⁹ years old rocks.

Solution:

Since the formation rock U-238 gradually converts to Pb-206.

The half-life for the conversion of U-238 to Pb-206 is, t1/2 = 4.50 x 109 years

Now t1/2 = 0.693 / k = 4.50 x 10⁹ years

= k = 0.693 / 4.50 x 109 years  = 1.54 x 10-10 year-1

Given the mass of Pb-206 formed = 0.438

Hence moles of Pb-206 formed = mass / molecular mass = 0.438 / 206 = 0.0021262 mol Pb

The radioactive disintegration reaction is

U-238  ---- > Pb-206

1 mol ---------1 mol

1 moles of U-238 forms 1 mol of Pb-206.

Hence 0.0021262 mol Pb that would be formed by the moles of U-238  = 0.0021262 mol U-238

Hence mass of U-238 = (0.0021262 mol U-238) x (238 g/mol U-238) = 0.506 g U-238

Hence initial amount of U-238, N0 = 1.506 g

Current amount of U-238, Nt = 1.00 g

Now applying the integrated equation for first-order reaction

ln(N0/Nt) = kt

= t = (1/k) x ln(N0/Nt) = (1 / 1.54 x 10-10 year-1) x ln(1.506 g / 1.00 g) = 2.66 x 10⁹ years.

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478 cal of heat is applied to a glass plate with a mass of 90 g, and the temperature of the plate increases will be 26.6 g⁻¹.°C⁻¹

The amount of heat applied = 478 cal

The specific heat capacity of glass = 0.2 cal g⁻¹.°C⁻¹

Mass of glass = 90 g

Temperature increased ΔT = ?

We will calculate the change in temperature by using the following equation

    Q = mcΔT

Rearrange the equation for ΔT

    ΔT = Q / mc

    ΔT = 478 cal / 90 * 0.2 cal g⁻¹.°C⁻¹

   ΔT =  478 cal / 18 g⁻¹.°C⁻¹

   ΔT = 26.6 g⁻¹.°C⁻¹

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Is the highest force between molecules Option a) water. hydrogen bonds are responsible for holding nucleotide bases together in DNA and RNA.

When a hydrogen atom is bound to either an oxygen, nitrogen, or fluorine atom, a peculiar type of dipole-dipole interaction takes place. In another molecule, the partially negative end of the oxygen, nitrogen, or fluorine is drawn to the partially positive end of the hydrogen atom.

A significant amount of energy is needed to break a hydrogen bond since it is a rather powerful force of attraction between molecules. This explains why substances like hydrogen fluoride (H, F) and water, H2O, have melting and boiling temperatures that are incredibly high. For instance, hydrogen bonds hold the nucleotide bases in DNA and RNA together, which is a crucial function of hydrogen bonds in biology.

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If 4 moles of zinc hydroxide react, The reaction consumes2 moles of sulfuric acid The reaction produces _2_ moles of zinc sulfate and _2__ moles of water

Zinc sulfate is the inorganic compound with the components ZnSO4 and traditionally recognised as "white vitriol".

It is at the World Health Organization's List of Essential Medicines, a listing of the maximum vital remedy wanted in a simple fitness system.neutralization reactionThe given response is a neutralization response. Zinc oxide (base) reacts with sulfuric acid (acid) to shape zinc sulfate (salt) and water.

When sulfuric acid reacts with zinc hydroxide, zinc sulfate and water are produced. The balanced equation for this response is: H2SO4(aq)+Zn(OH)2(s)=ZnSO4(aq)+2H2O(1) If three moles of zinc hydroxide react, The response consumes _____ moles of sulfuric acid.

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Answer:

ammonium carbonate option e

Potassium hydroxide will have the greatest total ion concentration at 25°C. The correct option is (C)

The total ion concentration is the sum of the molar concentration of all the ions in a solution. A solution of a compound will produce ions when dissolved in water, and the sum of the molar concentration of all the ions is known as the total ion concentration.

Potassium hydroxide (KOH) is a strong base that fully dissociates in water to produce potassium ions (K+) and hydroxide ions (OH-).So, if we add 1.0 mole of KOH to 1.0 L of water, we will obtain a 1.0 molar solution of KOH in which the molar concentration of K+ and OH- will both be 1.0 M.

On the other hand, ammonium carbonate, calcium phosphate, potassium chloride, and iron (II) nitrate will produce fewer ions in solution since they do not fully dissociate, so their total ion concentration will be lower.

Hence, we can say that, when 1.0 mole of the following compounds is added to 1.0 L of water, potassium hydroxide will have the greatest total ion concentration at 25°C.

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37.4 ml of volume of 0.209 M KMnO4 solution is needed to prepare 487. ml of 0.0158 m KMnO4.

we need to use the concept of dilution. Dilution is the process of preparing a lower concentration solution by adding more solvent (in this case, water) to a concentrated solution. The concentration of a dilute solution can be calculated using the following formula:

C1 * V1 = C2 * V2

where C1 is the concentration of the original (concentrated) solution, V1 is the volume of the original solution, C2 is the concentration of the dilute solution, and V2 is the volume of the dilute solution.

In this case, we are given that the concentration of the original solution is 0.209 M and the concentration of the dilute solution is 0.0158 M. We are also given that the volume of the dilute solution is 487 mL. We can use these values to solve for the volume of the original solution as follows:

V1 = (C2 * V2) / C1

= (0.0158 M * 487 mL) / 0.209 M

= 37.4 mL

Therefore, the volume of the 0.209 M KMnO4 solution needed to prepare 487 mL of 0.0158 M KMnO4 is 37.4 mL.

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If an isotope with a mass number of 124 in a sample of 5.63 g decays at a rate of 0.300 ci, its half-life is 5.00*10^4years, as is described below.

Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half life decay time varies depending on the element. The entire number of protons and neutrons (collectively known as nucleons), which make up an atomic nucleus, is known as the mass number (symbol A, from the German word Atomgewicht [atomic weight]). It is roughly equivalent to the atomic mass of the atom, also known as its isotopic mass, given in atomic mass units.The response to the posed query is included below.

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Yes it could, but you'd have to set up the process very carefully.

I see two major challenges right away:

1).  Displacement of water would not be a wise method, since rock salt

is soluble (dissolves) in water.  So as soon as you start lowering it into

your graduated cylinder full of water, its volume would immediately start

to decrease.  If you lowered it slowly enough, you might even measure

a volume close to zero, and when you pulled the string back out of the

water, there might be nothing left on the end of it.

So you would have to choose some other fluid besides water ... one in

which rock salt doesn't dissolve.  I don't know right now what that could

be.  You'd have to shop around and find one.

2).  Whatever fluid you did choose, it would also have to be less dense

than rock salt.  If it's more dense, then the rock salt just floats in it, and

never goes all the way under.  If that happens, then you have a tough

time measuring the total volume of the lump.

So the displacement method could perhaps be used, in principle, but

it would not be easy.

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The percent of the carbon in the octane that is not fully oxidized is 3.8%. This is due to incomplete combustion of the octane, resulting in the production of carbon monoxide (CO) and other pollutants.

The combustion of octane is a highly exothermic reaction. For every three oxygen molecules (O2) that are consumed, eight carbon dioxide molecules (CO2) and eighteen water molecules (H2O) are produced. The theoretical energy output of the complete combustion of octane is 3.7 megajoules per kilometer (MJ/km).

However, due to incomplete combustion, not all of the octane is fully oxidized. Incomplete combustion of octane results in the formation of carbon monoxide (CO) and other pollutants. In a gasoline-powered vehicle, 1.7 grams per kilometer (g/km) of CO is often emitted due to incomplete combustion.

To determine the percent of the carbon in the octane that is not fully oxidized, we can use the following equation:

Percent Carbon Not Fully Oxidized = (CO emission rate (g/km) / Carbon content of octane (g/km)) x 100

In our example, the CO emission rate is 1.7 g/km and the carbon content of octane is 44.1 g/km. Thus, the percent of the carbon in the octane that is not fully oxidized is 3.8%. This means that 3.8% of the carbon in the octane is not being completely oxidized in the combustion process, resulting in the formation of CO and other pollutants.

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A compound forms a dense yellow precipitate when treated with iodine and sodium hydroxide. the compound must be: Acetophenone methyl ketone.

Sodium hydroxide is every now and then known as caustic soda or lye. it's by far a common ingredient in cleaners and soaps. At room temperature, sodium hydroxide is white, odorless strong. Liquid sodium hydroxide is colorless and has no odor. it could react violently with strong acids and with water.

Sodium hydroxide, also known as lye and caustic soda, is an inorganic compound with the formula NaOH. it is a white stable ionic compound that includes sodium cations Na⁺ and hydroxide anions OH⁻.

Manufacturers may additionally use sodium hydroxide to provide soaps, rayon, paper, products that explode, dyes, and petroleum merchandise. different obligations which can use sodium hydroxide include processing cotton cloth, steel cleaning and processing, oxide coating, electroplating, and electrolytic extraction.

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Two isotopes of the same element only have these differences: atomic mass

Isotopes are forms of an element that have the same number of protons and electrons but differing numbers of neutrons. The various isotopes of an element have varying weights depending on the amount of neutrons present in each isotope.

Chemically speaking, an element's isotopes are nearly or completely identical. The chemical behaviours of several isotopes are quite similar. But each isotope has a unique set of physical characteristics, including as mass, melting or boiling temperature, density, and freezing point. Any isotope's physical characteristics are mostly influenced by its mass.

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Answer:

Yellow, Purple

Explanation:

5. The law of conservation of mass essentially states that the total 'mass' that you started with equals to the total 'mass' at the end. Take the burning of a tree, for example. Although the tree loses mass, the mass of carbon dioxide and other molecules increases proportionally to the rate of tree mass loss. Abiding by this law in a chemical reaction, we should expect the amount of shapes on each side to be equal, although they may not necessarily be in the same form. This is only shown in the 'Yellow' square.

6. We want the same amount of stuff on the left as we do on the right. There is 2 Nitrogen and 2 Hydrogen on the left. There is 1 Nitrogen and 3 Hydrogen on the right. To balance these amounts out, we'd need to multiply a few things:

1 Nitrogen by 2 on the right to make things even, meaning that now there is 2 Nitrogen and 6 Hydrogen on the right. To balance this out on the left, we need to multiply the 2 Hydrogen by 3 to yield 6 Hydrogen.

As such, the new equation is N2+ 3H2 --> 2NH3.

Do we have the same amount of stuff on the left as we do on the right? Yes! So the equation is balanced.

The empirical formula for the given compound is Al₂Se₃.

Step 1: Write the data given

Mass of the sample of Aluminium = 7.300 grams

Mass of the definite compound = 39.35 grams

Molar mass of the Aluminium = 26.98 g/mol

Molar mass of the Selenium = 78.96 g/mol

Step 2: Calculate the mass of selenium

Mass of selenium = mass of compound - mass of aluminium

Mass of selenium = 39.35 - 7.3 = 32.05 grams

Step 3: Calculate the number moles of Al

Moles Al = Mass Al/ Molar mass Al

Moles Al = 7.300 grams / 26.98 g/mol

Moles Al = 0.2706 moles

Step 4: Calculate the number moles of Se

Moles Se = Mass Se / Molar mass Se

Moles Se =32.05 g / 78.96 g/mol

Moles Se = 0.4059 moles

Step 5: Divide through the smallest amount of moles

Aluminium: 0.2706 / 0.2706 = 1

Selenium: 0.4059/0.2706 = 1.5

This means for each moles of aluminium, we have 1.5 moles of selenium.

For each 2 moles of aluminium, we have 3 moles of selenium

The empirical formula is Al₂Se₃  

Hence, the compound is aluminium(III) selenide.

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Answer:

Therefore, temperature is equals to 373 divided by 273, which comes out to be 1.37 density, is given as 0.65 gram per mel. Therefore, the volume of 3 ml liquid when evaporated is equals to 3 into 0.65, divided by molar mass multiplied by 22.4 multiplied by 1.37.