R 0, -180(x, y) maps to the same point as R 0, 180(x, y).
O True
O False

Answer:

To graph an equation using the slope and y-intercept, 1) Write the equation in the form y = MX + b to find the slope m and the y-intercept (0, b). 2) Next, plot the y-intercept. 3) From the y-intercept, move up or down and left or right, depending on whether the slope is positive or negative.

Step-by-step explanation:

By using properties of triangle, it can be calculated that-

The pilot is 2740 miles from her starting position.

What is a triangle?

A triangle is a three sided two dimensional figure. A triangle has three sides and three interior angles.

Here,

The diagram has been attached

Time = 130 minutes = 2 hrs 10 minutes = [tex]2 + \frac{10}{60}[/tex] hours = [tex]\frac{13}{6}[/tex] hours

Speed = 600 miles per hour

Distance = [tex]\frac{13}{6} \times 600[/tex] = 1300 miles

Now,

Time = 145 minutes = 2 hrs 25 minutes = [tex]2 + \frac{25}{60}[/tex] hours = [tex]\frac{29}{12}[/tex] hours

Distance = [tex]\frac{29}{12}\times 600[/tex] = 1450 miles

Angle = [tex]10^{\circ}[/tex]

[tex]c^2 = 1300^2 + 1450^2 - 2\times 1300\times 1450\times cos(180-10)\\c^2 = 1690000 + 2102500 - (-3712725.2)\\c^2= 7505225.2\\c= \sqrt{7505225.2}\\c = 2740[/tex]

The pilot is 2740 miles from her starting position.

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[tex]6\frac{2}{5} - 4\frac{4}{5}[/tex]  can be solved using subtraction of simple fraction and the final result is 8/5 .

what are simple fraction ?

A fraction in which both the numerator and the denominator consist of whole numbers.

Simplest form of a fraction:

A fraction is said to be in its simplest form if 1 is the only common factor of its numerator and denominator. For example, 8/9 ,because 1 is the only common factor of 8 and 9 in this fraction.

Simplifying proper and improper fraction

We simplify fractions because it is always to work or calculate when the fractions are in the simplest form.

To solve :  [tex]6\frac{2}{5} - 4\frac{4}{5}[/tex]

We know that , in simple fraction  [tex]6\frac{2}{5} - 4\frac{4}{5}[/tex] can be written as ,

[tex]6\frac{2}{5} - 4\frac{4}{5} = \frac{32}{5} - \frac{24}{5} = \frac{8}{5}[/tex]

Hence , 8/5 is the final answer .

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Answer:

415 miles

Step-by-step explanation:

Start with the speed equation:

speed = distance/time

Now solve the speed equation for distance:

distance = speed × time

Apply the speed equation solved for distance to the two parts of the trip.

4 hours at 55 mph:

distance = 55 mph × 4 hours = 220 miles

3 hours at 65 mph:

distance = 65 mph × 3 hours = 195 miles

Add the two distances to find the total distance:

total distance = 220 miles + 195 miles = 415 miles

Answer: 415 miles

Answer:

415 miles

Step-by-step explanation:

Simon drove 55 miles per hour for 4 hours then 65 miles per hour for 3 hours.

How far did he drive?

d=rt

For the first part of the trip:

d = 55 * 4 = 220 miles

For the second part of the trip:

d = 65*3 =195 miles

Add the miles together

220+195 = 415 miles

The derivative of the function is not defined overall on the interval [1, 5]

       [tex]F(x)=\int_{a}^{x}\frac{t +1}{t - 1} dt\\\\F^{'}(x) = \frac{x+1}{x-1}[/tex]

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Answer:

Step-by-step explanation:

x + 2/4 = x + 5/5

x + 1/2 = x + 1

1/2 = 1 or 0.5 = 1

or

x + 2/4 = x + 5/5

x + 1/2 = x + 1

0 = 1/2 or 0 = 0.5

Answer:

slope = - 2

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (11, - 17) and (x₂, y₂ ) = (2, 1) ← 2 ordered pairs from the table

m = [tex]\frac{1-(-17)}{2-11}[/tex] = [tex]\frac{1+17}{-9}[/tex] = [tex]\frac{18}{-9}[/tex] = - 2

Answer:

351.5625

1,440,000

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{7 cm}\underline{General form of an Exponential Function}\\\\$y=Ae^{kt}$\\\\where:\\\phantom{ww}$\bullet$ $A$ is the initial value ($y$-intercept). \\ \phantom{ww}$\bullet$ $k$ is a constant.\\ \phantom{ww}$\bullet$ $t$ is time.\\\end{minipage}}[/tex]

Given:

(Let t = time in minutes).

If the doubling period is 15 minutes, then at t = 135 minutes, y = 180,000:

[tex]\implies 90000=Ae^{120k}[/tex]

[tex]\implies 180000=Ae^{135k}[/tex]

Divide the second equation by the first to eliminate A, and solve for k:

[tex]\implies \dfrac{180000}{90000}=\dfrac{Ae^{135k}}{Ae^{120k}}[/tex]

[tex]\implies 2=\dfrac{e^{135k}}{e^{120k}}[/tex]

[tex]\implies 2=e^{135k} \cdot e^{-120k}[/tex]

[tex]\implies 2=e^{15k}[/tex]

[tex]\implies \ln 2 = \ln e^{15k}[/tex]

[tex]\implies \ln 2 =15k \ln e[/tex]

[tex]\implies \ln 2 =15k[/tex]

[tex]\implies k=\dfrac{1}{15}\ln 2[/tex]

Substitute t = 120, y = 90000 and the found value of k into the formula and solve for A:

[tex]\implies 90000=Ae^{\left(120 \cdot \frac{1}{15}\ln 2\right)}[/tex]

[tex]\implies 90000=Ae^{\left(8\ln 2\right)}[/tex]

[tex]\implies 90000=Ae^{\ln256}[/tex]

[tex]\implies 90000=256A[/tex]

[tex]\implies A=\dfrac{90000}{256}[/tex]

[tex]\implies A=351.5625[/tex]

Therefore, the function that models the scenario is:

[tex]\large\boxed{y=351.5625e^{\left(\frac{1}{15}t \ln 2\right)}}[/tex]

So the initial population at time t = 0 was:

To find the size of the bacteria population after 3 hours, substitute t = 180 into the found formula:

[tex]\implies y=351.5625e^{\left(\frac{1}{15}(180) \ln 2\right)}[/tex]

[tex]\implies y=351.5625e^{\left(12 \ln 2\right)}[/tex]

[tex]\implies y=351.5625e^{\left(\ln 4096\right)}[/tex]

[tex]\implies y=351.5625 \cdot 4096[/tex]

[tex]\implies y=1440000[/tex]

Therefore, the size of the bacterial population after 3 hours was:

The initial population at the time t = 0 is 351.5625. And the size of the bacterial population after 3 hours is 1,440,000.

An exponential function's curve is created by a pattern of data called exponential growth, which exhibits higher increases over time.

If n₀ is the initial size of a population experiencing exponential growth, then the population n(t) at time t is modeled by the function:

n(t) = n₀(e[tex])^{rt}[/tex]

Where r is the relative rate of growth expressed as a fraction of the population.

Given:

Doubling period = 15 minutes

At t = 120 minutes, n(t) = 90,000

If the doubling period is 15 minutes, then at t = 120+15 = 135 minutes,

90000 = n₀(e[tex])^{120r}[/tex]

18000 =  n₀(e[tex])^{135r}[/tex]]

To find the r:

Take ratio of both of the equations,

90000 / 18000 = n₀(e[tex])^{120r}[/tex]  /   n₀(e[tex])^{135r}[/tex]

2 = (e[tex])^{135r}[/tex] . (e[tex])^{-120r}[/tex]

r = 1/15 ln2

Substitute the value of r, t and y.

90000 = n₀(e[tex])^{120r}[/tex]

90000 = 256n₀

n₀ = 351.5652

Now, the function

n(t) = n₀(e[tex])^{rt}[/tex]

n(t) = (351.5652)(e[tex])^{(1/15)(180)(ln2)}[/tex]

n(t) = 1440000

Therefore, the initial population at the time t = 0 is 351.5625. And the size of the bacterial population after 3 hours is 1,440,000.

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The altitude of the balloon now is 324 meters

From the question, we have the following parameters that can be used in our computation:

Initial altitude = 288 meters

Rise = 36 meters

The altitude of the balloon now is calculated as

Current altitude = Initial altitude + Rise in altitude

Substitute the known values in the above equation, so, we have the following representation

Current altitude = 288 + 36

Evaluate the sum

Current altitude = 324

Hence, the current altitude is 324 meters

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The cotangent of the angle is -√570/30

From the question, we have the following parameters that can be used in our computation:

(√30/7,-√19/7)

This means that

(x, y) = (√30/7,-√19/7)

The cot(θ) is calculated as

cot(θ) = y/x

Substitute the known values in the above equation, so, we have the following representation

cot(θ) = (-√19/7)/(√30/7)

Evaluate

cot(θ) = -√19/√30

Rationalize

cot(θ) = -√570/30

Hence, the value of cot(θ) is -√570/30

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The given equations can be simplified as :

a. -2.√15

b.  c ≥ 0

c.   x = ±2√6

d.   y < 0

e.   a > 0

How to solve inequalities ?

When solving an inequality:

a.

Given : √(3-√15)²-√(3+√15)²

   √(3-√15)²-√(3+√15)² = (3-√15)-(3+√15)

   √(3-√15)²-√(3+√15)² = 0 -2√15

   √(3-√15)²-√(3+√15)² = -2.√15

b .  

Given : 3√c² if c≥0

     3√c² if c≥0

    c ≥ 0

c.

Given: √(x²+1)²=5

     √(x²+1)²=5

      on Squaring both sides , we get

      (x²+1) = 25

      x²  = 24

      x = ±2√6

d.

Given : -5√y² if y>0

      -5√y² if y>0

       y < 0 [since , -5 < 0]

e.  

Given : 0.5√16a² if a<0

     0.5√16a² if a<0

      a > 0

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Thus after 12 minutes concentration of drug is 0.045.

The concentration C(t) of a certain drug in the bloodstream after t minutes is given by the formula [tex]c(t) = 0.05(1-e^{-0.2t} )[/tex]

Drug concentration is amongst the most important determinants of clinical response to a drug.

Drug concentration will be seen to increase in biological samples drawn from the systemic circulation when the amount of drug absorbed exceeds the amount of drug that is distributed into the extravascular tissues and the drug that is metabolized and/or excreted during this period.

Thus after 12 minutes concentration of the drug is = C(5).

Now

C(5) = [tex]0.05(1-e^{-0.2t} )[/tex]

= [tex]0.05(1-e^{-2.4} )[/tex]

= 0.05(1-0.0907)

= 0.05×0.9093

= 0.045

The drug concentration is 0.045.

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The motion of the object on the graph, can best be represented as an object that d. was at rest and is accelerating uniformly.

The object on the graph is accelerating such that the acceleration is stable and uniform. This is why the speed - time line is a straight and diagonal line to show that the speed is proportional to time.

We know that the object started from rest because at the point where time was 0, the object was not accelerating and so was not moving. As time moves on, the object increases speed, thereby accelerating.

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If x = 2, y = 6, and z = 4, which expression is equivalent to 4? à 54+0-3+2=4. D Xtra 4 ... A tree is 12 feet tall and casts a shadow 9 feet long. A building nearby.

The  GCF of each expression that was given above are: 3, 2 , 4 , and 6 which can be written as:

The GCF which isthe “greatest common factor”.  can be  defined as the largest number that is a factor of two or more numbers.

Intance of this is that the GCF of 24 and 36 is 12, and this is due to the fact that the largest factor that is shared by 24 and 36 is 12.

Option 1:

The GCF of 12y-3=3 because the common factor which is the highest factor of 12 and 3 is 3

Option2

The GCF of 4y+10=2  because the common factor which is the highest factor of 4 and 10 is 2 and so on.

Option 3:

The GCF of 28 − 8= 4 because the common factor which is the highest factor of 28 and 8 is 4

Option 4:

The GCF of 30y+18=6 because the common factor which is the highest factor of 30 and 18 is 6

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Using the linear function y = 0.6x + 1.5, he drove 20 miles to be charged $13.50

The parent linear function is f(x) = x, which is a line passing through the origin. In general, a linear function equation is f(x) = mx + c

where m is the slope of the equation and c is the y - intercept.

To solve this problem, we have to write an equation that models y = mx + c

The linear function to model this is given as;

y = 0.6x + 1.5

Assuming a trip cost 13.50, the number of miles can be calculated as;

13.50 = 0.6x + 1.5

0.6x = 13.50 - 1.5

0.6x = 12

x = 12/0.6

x = 20

The drove 20 miles

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Answer:

She Does NOT

Step-by-step explanation:

3/4 is .75 1 1/3 is 1.33 3/4*2= 1.5 which is more than 1.33

Option (b) is correct as mean of top five scorers on soccer team is 8 from given bar graph.

In statistics, in addition to the mode and median, the mean is one of the measures of central tendency. Simply put, the mean is the average of the values in the given set. It indicates that values in a particular data set are distributed equally. The three most frequently employed measures of central tendency are the mean, median, and mode. The total values provided in a datasheet must be added, and the sum must be divided by the total number of values in order to determine the mean. When all of the values are organized in ascending order, the Median is the median value of the given data. While the number in the list that is repeated a maximum of times is the mode.

Mean = (Sum of values)/(Total observations)

Using above formula, we get

Calculating mean for given bar graph,

[tex]=\frac{4+6+10+9+11}{5}\\=\frac{40}{5}\\=8[/tex]

So, mean score of five players comes out to be 8.

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Answer:  the correct answer is D

Step-by-step explanation:

Given that they are age 55 or older, it is discovered that there is a (E) 0.8181 = 81.81% probability that the person said no.

Simply put, probability refers to the likelihood that something will occur.

If we don't know how an event will turn out, one can discuss the probability or likelihood of several events.

Statistics is the study of occurrences that match a probability distribution.

So, as 36 out of 44 adults aged 55 or older chose not to answer the question, the probability is given by:

p = 36/44 = 0.8181

Therefore, given that they are age 55 or older, it is discovered that there is a (E) 0.8181 = 81.81% probability that the person said no.

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The length of string in feet she will need for her patio is equal to : L{s} = 2(x + y).

Given is Camilla who wants to attach a string of lights to the edges of her patio for a party. She does not want the string to go across the edge with the steps.

Assume the shape of the patio is a rectangle with the dimensions of [x] and [y] units long. The length of string in feet she will need will be equivalent to the perimeter of the rectangle. So, the length of string in feet she will need is equal to L{s} = 2(x + y).

Therefore, the length of string in feet she will need for her patio is equal to : L{s} = 2(x + y).

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The answers for the following trigonometric functions are:

a) Sin(A)=√15/4

b) Cos(A)=1/4

c) Cos(A+B)=(√3-√15)/8

Cos (A- B)=(√3+15)/8

d) Sin(A+ B) =(3√5+1)/8

Sin (A- B)==(3√5-1)/8

e) The quadrant of A+B and A-B is 4th quadrant

f)  Sin(2A + 2B)= (√15-6√5+4√3)/8

The trigonometric functions in mathematics are real functions that link the angle of a right-angled triangle to the ratios of two side lengths. They are also known as circular functions, angle functions, or goniometric functions. They are widely employed in all fields of geometry-related study, including geodesy, solid mechanics, celestial mechanics, and many more. Because they are some of the most basic periodic functions, Fourier analysis is frequently employed to examine periodic events.

The sine, cosine, and tangent are the trigonometric functions that are most frequently utilized in contemporary mathematics.

Given,

Cos(A) = 1/4 and Sin(B) = 1/2

4=√1+x²

1+x²=16

x²=15

x=√15

4=1+x²

x²=3

x=√3

a) Sin(A)=√15/4

Sin(B)=1/2

b) Cos(A)=1/4

Cos(B)=√3/2

c) Cos(A+B)=CosACosB-SinASinB

=(1/4)(1/2)-(√15/4)(1/2)

=(√3-√15)/8

Cos(A-B)=CosACosB+SinASinB

=(1/4)(√3/2)+(√15/4)(1/2)

=(√3+15)/8

d) Sin(A+B)+SinACosB+CosASinB

=(√15/4)(√3/2)+(1/4)(1/2)

=(3√5+1)/8

Sin(A-B)=SinACosB-SinBCosA

=(√15/4)(√3/2)-(1/4)(1/2)

=(3√5-1)/8

e) The quadrant of A+B and A -B is 4th quadrant.

f) Sin(2A+2B)=Sin2ACos2B+Cos2ASin2B

=(√15/8)(1-√3)+((4-√15)/4)(√3/2)

=(√15-3√5+4√3-3√5)/8

=(√15-6√5+4√3)/8

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The probability of getting a specific number on the first roll of the die is 1/6. The probability of getting that same number on five successive rolls is (1/6)^5 = 1/7776. Because there are six different ways to get the same number on five rolls, multiply by 6 to get the probability of the same number on five successive rolls to be 6/7776 =1/1296.

Determining the probability that all five rolls will be different starts with asking how many ways can you choose 5 numbers from six with replacement and without repetition where order does not matter, then dividing that number by the total number of outcomes in five rolls of the die.

The total number of possible rolls is easy. There are six possible outcomes for each of the five rolls, so the total number of possible combinations after 5 rolls is 6^5 = 7776.

Now if each roll has to be a different number, consider that there are six acceptable outcomes on the first roll of the die. There are only five acceptable outcomes on the second roll, four on the third, three on the fourth, and two on the fifth. Multiplying all these together gives 6x5x4x3x2 = 6! = 720 ways to get a different number on five successive rolls of the die. This probability is 720/7776 ( 0.0926 or 9.26% or 120 times greater than getting the same number on each of five rolls.

Consider a game in which six true dice are rolled. What is the probability of obtaining exactly one ace, at least one ace and exactly two aces?

Exactly 1 ace(one) =6C1 * 5^5 = 18750 / 6^6 = 0.401877572

At Least 1 ace(one) =6C1 *5^5 +6C2 * 5^4 + 6C3 * 5^3......6C6 * 5^0= 31031/6^6 = 0.6651020233

Exactly 2 aces(ones) =6C2 * 5^4 = 9375 / 6^6 = 0.200938786

If you require two specific times(e.g. first time and second time) to be 5(probability 1/6), others to be non-5(probability 1−1/6=5/6). The probabiliy is (1/6)2(5/6)3, you have C52=10 different ways to roll two 5. Therefore the answer is 10(1/6)2(5/6)3, which is approximately 0.1608.

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Answer:

Step-by-step explanation:

To solve this problem, we need to add and subtract the fractions given. To do this, we need to find a common denominator for all of the fractions.

The least common multiple of 4, 16, and 12 is 48, so we can rewrite each fraction with a denominator of 48:

1/4 = 3/12

29/16 = 87/48

9735/12 = 4047/48

Then, we can add and subtract the fractions as follows:

3/12 + 87/48 - 4047/48 = (3 - 4047)/48 = -4044/48 = -84/16

Therefore, the final answer is -84/16, or -5 and 1/16 in simplified form.

Answer:

y = 5

Step-by-step explanation:

Jocelyn buys 41 candies and 25 pretzels by solving system equation using elimination method.

What is a linear equation?

The equations with one, zero, or an infinite number of solutions are known as linear equations with two variables. Each of the two variables in these equations has the largest exponent order of 1. A two-variable linear equation has the conventional form axe + by + c = 0, where x and y are the two variables. The answers can also be expressed as ordered pairs, such as (x, y).

Given that the cost of 1 candy is $4.75 and 1 pretzel is $3.50.

Jocelyn buys 18 candies and pretzels altogether with cost $75.50.

Assume that she buys x candies and y pretzels

Therefore,

x + y = 18  ......(i)

The cost of x candies and y pretzels is 4.75x + 3.50y.

4.75x + 3.50y = 75.50  .....(ii)

Solving equation (i) and (ii) by using elimination method.

Multiply equation (i) by 4.75

4.75x + 4.75y = 85.5 ....(iii)

Subtract equation (ii) from (iii)

4.75x + 4.75y = 85.5

4.75x + 3.50y = 75.50

(-)      (-)             (-)

________________

             1.25 y = 10

                    y  = 8

Putting y = 8 in equation (i)

x + 8 = 18

x = 10

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An essential part of a business' operations is its fixed and variable expenses.

It is an expenditure that does not fluctuate, or rather, does not alter over time.

An illustration of a fixed expense is:

1. Mortgage,

2. Rent payments,

3. Utility bills etc

Let see about Variable expense:

It is a cost that typically varies based on how the business uses the goods or services.

Examples of variable costs are as follows:

1. Sales commissions

2. Direct labor costs

3. Cost of raw materials etc

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Answer:

$4.50

Step-by-step explanation:

Use a proportion:

$6.75 is to 3 bags as x is to 2 bags.

6.75/3 = x/2

3x = 2 × 6.75

x = 4.50

Answer: $4.50

Answer:

  $4.50

Step-by-step explanation:

Given 3 bags of cat food cost $6.75, you want the cost of 2 bags.

Unless there is a volume discount (or surcharge), the price is proportional to the quantity. That means 2 bags will cost 2/3 the amount that 3 bags cost.

  cost of 2 bags = 2/3 · $6.75 = $4.50

Amelia would spend $4.50 on 2 bags of cat food.