Answer:
1.is 11
2. is-44
Step-by-step explanation:
1) 2+6-7+10
= 11
2) -49+15-10
= -44
Suppose a person is riding a plane 154ft above the ground and drops a box of supplies. The height of the box
is given by the formula:
h = -16+2 + 154
After how many seconds does the box hit the ground? (round to the nearest hundredth of a second)
A formula for converting degrees Celsius ( C ) (C) to degrees Fahrenheit ( F ) (F) is given by the formula F = 9 5 C + 32. F= 5 9 C+32. Solve the formula for C C in terms of F.
Answer:
C = (5F - 160)/9
Step-by-step explanation:
Given:
F = 9/5C + 32
Solve the formula for C in terms of F
F = 9/5C + 32
F - 32 = 9/5C
C = (F - 32) ÷ 9/5
C = (F - 32) × 5/9
= (5F - 160)/9
C = (5F - 160)/9
Assume that both populations are normally distributed (a) Test whether 4 Hy at the a= 0.05 level of significance for the given sample data (b) Construct a 96% confidence interval about 14 - 12. n Population 1 19 17 3.9 Population 2 19 13.8 4.6 X 10. Moth H12 Detemine the P-value for this hypothesis test. P=0.027 (Round to three decimal places as needed) Should the null hypothesis be rejected? G A Do not reject He, there is suffichent evidence to conclude that the two populations B. Reject M, there is sufficient evidence to conclude that the two populations have different means Oc Reject He, there is not sufficient evidence to conclude that the two populations have different means . Do not reject He, there is not sufficient evidence to conclude that the two populations have different means (b) Construct a 95% confidence interval about ve different means We are 95% confident that the mean difference is between 0.027 and 0.05 (Round to two decimal places as needed, Use ascending order.)
As per the given details, we are 95% confident that the mean difference between the two populations is between -8.86 and 9.86.
Testing whether the means of two populations are significantly different, we can perform a two-sample t-test.
Given that:
Sample data for Population 1: 19, 17, 3.9
Sample data for Population 2: 19, 13.8, 4.6
Using a significance level of α = 0.05, we can conduct the two-sample t-test.
Calculating the sample means:
X1 = (19 + 17 + 3.9) / 3 = 13.3
X2 = (19 + 13.8 + 4.6) / 3 = 12.8
Calculating standard deviations (s₁ and s₂):
s₁ = sqrt(((19 - 13.3)² + (17 - 13.3)² + (3.9 - 13.3)²) / 2) ≈ 8.16
s₂ = sqrt(((19 - 12.8)² + (13.8 - 12.8)² + (4.6 - 12.8)²) / 2) ≈ 5.44
Calculating the test statistic:
t = (X1 - X2) / sqrt((s₁² / n₁) + (s₂² / n₂))
= (13.3 - 12.8) / sqrt((8.16² / 3) + (5.44² / 3))
≈ 0.489
Degrees of freedom (df) = n₁ + n₂ - 2 = 3 + 3 - 2 = 4
Since |t| = 0.489 < 2.776, we fail to reject the null hypothesis.
Constructing a 95% confidence interval for the mean difference, we can use the formula:
Confidence Interval = (X1 - X2) ± t * sqrt((s₁² / n₁) + (s₂² / n₂))
Using the given values and a confidence level of 95%:
X1 - X2 = 13.3 - 12.8 = 0.5
t (with df = 4, α/2 = 0.025) ≈ 2.776
The standard error:
SE = sqrt((s₁² / n₁) + (s₂² / n₂)) = sqrt((8.16² / 3) + (5.44² / 3)) ≈ 3.37
Confidence Interval = 0.5 ± 2.776 * 3.37
= 0.5 ± 9.36
≈ (-8.86, 9.86)
Thus, we are 95% confident that the mean difference between the two populations is between -8.86 and 9.86.
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The weight of one serving of trail mix is 2.5 ounces. How many servings are there in 22.5 ounces of trail mix?
9.0
25.0
11.5
56.25
Answer:
9 servings
There should be an answer to that. Answer: There are 9 servings. step- by- step Explanation: We would first divide 22.5/2.5. This will give us the amount of time 2.5 will go into 22.5, providing us with the amount of servings
Step-by-step explanation:
sorry if it’s too blurry but i need help with this
a steady wind blows a kite due west. the kite’s height above ground from horizontal position x − 0 to x − 80 ft is given by y − 150 2 1 sx 2 50d2. find the distance trav eled by the kite.
The equation y = 150 - 0.01x^2 represents the height of the kite above the ground as a function of its horizontal position x. The kite travels a distance of 80 ft.
The equation y = 150 - 0.01x^2 represents the height of the kite above the ground as a function of its horizontal position x. This is a downward-opening parabola, with the vertex at (0, 150) and the axis of symmetry along the y-axis.
To find the distance traveled by the kite, we need to determine the range of x over which the kite is flying. In this case, the range is from x = 0 to x = 80 ft.
The distance traveled by the kite is the difference between the initial and final positions of x. In this case, it is 80 - 0 = 80 ft.
Therefore, the kite travels a distance of 80 ft.
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Help please please help help please help!!!
Answer:
standard
Step-by-step explanation:
Geographic information systems can assist the location decision by:
A updating transportation method solutions.
B. computerizing factor-rating analysis.
C. automating center-of-gravity problems
D. combining geography with demographic analysis.
E. providing good Internet placement for virtual storefronts.
GIS can assist in location decision-making by combining geography with demographic analysis, automating center-of-gravity problems, providing spatial data for transportation planning, enhancing factor-rating analysis with spatial considerations, and indirectly informing Internet placement for virtual storefronts.
Geographic Information Systems (GIS) can assist in location decision-making by combining geography with demographic analysis (D). GIS technology enables the integration and analysis of various spatial data, including demographic information such as population density, income levels, and consumer behavior.
By overlaying geographic data with demographic data, decision-makers can gain valuable insights into the characteristics and preferences of target markets, helping them identify suitable locations for their businesses.
GIS can automate center-of-gravity problems (C) by applying spatial analysis techniques to determine optimal locations based on factors such as customer demand, transportation networks, and supply chain considerations.
By utilizing GIS, businesses can identify central points or distribution hubs that minimize transportation costs and maximize accessibility to target markets.
While GIS doesn't directly update transportation method solutions (A), it can provide valuable spatial data and analysis that inform transportation planning. This includes mapping and visualizing existing transportation infrastructure, identifying traffic patterns, and optimizing routes for efficient logistics.
Although GIS doesn't computerize factor-rating analysis (B) per se, it can enhance this process by providing a spatial dimension. Factor-rating analysis involves evaluating potential locations based on multiple factors such as cost, labor availability, and market proximity. GIS can incorporate spatial data, such as the proximity of suppliers or competitors, into the factor-rating analysis, enabling more informed decision-making.
GIS may indirectly contribute to providing good Internet placement for virtual storefronts (E). By analyzing factors such as population density, internet infrastructure, and connectivity patterns, GIS can help businesses identify areas with a high potential for online customer engagement. However, the direct responsibility of Internet placement lies more within the realm of network infrastructure and internet service providers.
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Symbolization in predicate logic. Put the following statements into symbolic notation, using the given letters as predicates. Existential quantifier and logical symbols are here for you to copy and paste: ∃x, ,V, ~, ,
Px: x is a strictly physical thing
Cx: x has consciousness
Sx: x has subjectivity
Mx: x is a mind
1. Nothing strictly physical has consciousness.
2. Minds exist.
3. All minds have consciousness and subjectivity.
4. No minds are strictly physical things.
The statements with symbolic notation using the given predicates logic are:
1. Nothing strictly physical has consciousness. ∀x(Px → ¬Cx)
2. Minds exist. ∃x(Mx)
3. All minds have consciousness and subjectivity. ∀x(Mx → (Cx ∧ Sx))
4. No minds are strictly physical things. ∀x(Mx → ¬Px)
What is a predicate logic and it's symbols?Predicate logic is a formal system of symbolic logic that extends propositional logic by introducing variables, predicates, quantifiers, and quantified statements. It allows for the representation and manipulation of relationships between objects, properties, and relations.
In predicate logic, symbols are used to represent various components:
1. Variables: Variables are used to represent individual elements or objects in a domain of discourse. They are typically denoted by lowercase letters such as x, y, z, and so on.
2. Predicates: Predicates are used to express properties or relations between objects. They are represented by uppercase letters followed by parentheses, such as P(x), Q(x, y), R(x, y, z), where x, y, z are variables.
3. Quantifiers: Quantifiers are used to express the scope of variables in a logical statement. The two main quantifiers are:
- Universal quantifier (∀): It is used to express that a statement holds for all elements in the domain. For example, ∀x P(x) means "For all x, P(x)."
- Existential quantifier (∃): It is used to express that there exists at least one element in the domain for which a statement holds. For example, ∃x P(x) means "There exists an x such that P(x)."
4. Logical symbols: Predicate logic uses logical symbols to represent logical connectives, negation, implication, and equivalence. The main logical symbols are:
- Conjunction (∧): Represents logical "and."
- Disjunction (∨): Represents logical "or."
- Negation (¬): Represents logical "not."
- Implication (→): Represents logical "if-then."
- Equivalence (↔): Represents logical "if and only if."
These symbols are used to construct complex logical statements by combining predicates, variables, and quantifiers. The goal is to provide a precise and formal language for reasoning about relationships and properties within a domain of discourse.
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e) Discuss with illustrations the terms Deterministic, Stochastic and Least squares as used in regression analysis. [6]
Regression analysis is a statistical technique used to examine the relationship between a dependent variable (Y) and one or more independent variables (X). This analysis is used to establish whether the dependent variable is affected by changes in the independent variables.
When performing regression analysis, we use various terms such as deterministic, stochastic, and least squares. Let us examine these terms and their implications in regression analysis:
Deterministic regression
Deterministic regression is a type of regression that assumes a perfect relationship between the dependent and independent variables. This type of regression analysis assumes that the independent variables have a direct linear relationship with the dependent variable. The regression equation in deterministic regression is of the form: Y=a + bX. The term a is the Y-intercept of the regression line, while b represents the slope of the regression line. A change in the value of X by one unit will result in a change in Y by b units.
Stochastic regression
Stochastic regression is a type of regression that assumes a probabilistic relationship between the dependent and independent variables. In this type of regression, the independent variable is considered to be random. The relationship between the dependent and independent variables is not perfect, but it is characterized by some random error. The regression equation in stochastic regression is of the form: Y=a + bX + ε. The term ε represents the error term in the regression equation. The error term is a random variable that represents the difference between the predicted value and the actual value.
Least squares regression
Least squares regression is a statistical method that is used to estimate the parameters of a linear regression model. This method aims to find the line of best fit for the given data set. The line of best fit is the line that minimizes the sum of the squared residuals. The residuals are the differences between the observed values and the predicted values. The least squares regression method is used in both deterministic and stochastic regressions. This method ensures that the regression line passes as close as possible to all the data points. This method can be used to estimate the values of the parameters a and b in the regression equation Y=a + bX. In conclusion, the terms deterministic, stochastic, and least squares are used in regression analysis to explain the relationship between the dependent and independent variables. These terms are crucial in regression analysis because they help us to understand the nature of the relationship between the variables.
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Rob bought a hat and 3 shirts for $35. Dan bought 2 hats and a shirt for $20.
Which system of equations can be used to find s , the cost of one shirt, and h , the cost of one hat?
Answer:
1 shirt costs $11.2 1 hat costs $10.
Step-by-step explanation:
35 divided by 3
20 divided by 2
Which of the following graphs best represents a function that has a minimum value and x-intercepts of 3 and -1?
Answer:
a
Step-by-step explanation:
Part of the graph of the function f(x) = (x – 1)(x + 7) is shown below.
Which statements about the function are true? Select three options.
The vertex of the function is at (–4,–15).
The vertex of the function is at (–3,–16).
The graph is increasing on the interval x > –3.
The graph is positive only on the intervals where x < –7 and where
x > 1.
The graph is negative on the interval x < –4.
Introduction
In mathematics, a function is a relation between two sets of values, usually denoted as a set of input values and a set of output values. One of the important aspects of a function is its vertex, which is the highest or lowest point in a graph, depending on the specific type of function. The size and position of a graph’s vertex can be important when studying the properties of a function. In this paper, we will discuss three statements about a function and determine whether or not each statement is true.
Statement 1: The vertex of the function is at (–4,–15).
The first statement being discussed is that the vertex of the function is at (–4,–15). This statement is true. By looking at the graph of the function, it can be seen that the vertex of the function is indeed located at the point (–4,–15). At this point, the graph reaches its highest or lowest point.
Statement 2: The vertex of the function is at (–3,–16).
The second statement being discussed is that the vertex of the function is at (–3,–16). Unfortunately, this statement is false. By looking at the graph of the function, it can be seen that the vertex of the function is actually located at (–4,–15). The vertex is not located at (–3,–16).
Statement 3: The graph is increasing on the interval x > –3.
The third statement being discussed is that the graph is increasing on the interval x > –3. This statement is true. By looking at the graph, it can be seen that the graph is indeed increasing on the interval x > –3. On this interval, the y-values increase as the x-values increase.
Statement 4: The graph is positive only on the intervals where x < –7 and where x > 1.
The fourth statement being discussed is that the graph is positive only on the intervals where x < –7 and where x > 1. This statement is true. By looking at the graph, it can be seen that the graph is positive only on the intervals where x < –7 and where x > 1. On these intervals, the y-values are greater than 0.
Statement 5: The graph is negative on the interval x < –4.
The fifth statement being discussed is that the graph is negative on the interval x < –4. This statement is also true. By looking at the graph, it can be seen that the graph is indeed negative on the interval x < –4. On this interval, the y-values are less than 0.
Conclusion
In this paper, we discussed three statements about a function and determined whether or not each statement was true. We found that the first statement, that the vertex of the function is at (–4,–15), is true. We also found that the second statement, that the vertex of the function is at (–3,–16), is false. Furthermore, we found that the third, fourth, and fifth statements, that the graph is increasing on the interval x > –3, that the graph is positive only on the intervals where x < –7 and where x > 1, and that the graph is negative on the interval x < –4, respectively, are all true.
A cylinder has a height of 14 centimeters and a radius of 11 centimeters. What is its
volume? Use 3.14 and round your answer to the nearest hundredth
⚠️⚠️⚠️⚠️help⚠️⚠️⚠️⚠️
Click the location of the point in the coordinate plane with the coordinates (–4, 3).
Answer:
I've put the red dot where location is.
Step-by-step explanation:
In a large population of college-educated adults, the mean IQ is 112 with standard deviation 25. Suppose 30 adults from this population are randomly selected for a market research campaign. The probability that the sample mean IQ is greater than 115 is 0.019 b.0.256 c 0.461. d.0.328 QUESTION 15 In a large population of college-educated adults, the mean IQ is 112 with standard deviation 50.62. Suppose 30 adults from this population are randomly selected for a market research campaign. The distribution of the sample mean IQ is a approximately Normal, with mean 112 and standard deviation 1.44). bapproximately Normal, with mean 112 and standard deviation 4.564. c approximately Normal, with mean 112 and standard deviation 9.241. Cd approximately Normal, with mean equal to the observed value of the sample mean and standard deviation 25.
The correct answer is:
D. 0.981.
To calculate the probability that the sample mean IQ is greater than 115, we need to use the concept of sampling distribution and the central limit theorem.
Given:
Population mean (μ) = 112
Population standard deviation (σ) = 25
Sample size (n) = 300
The mean of the sampling distribution of the sample means (μx) will be the same as the population mean (μ) which is 112.
The standard deviation of the sampling distribution (σx) can be calculated using the formula:
σx = σ / √(n)
Plugging in the values:
σx = 25 / √(300)
≈ 1.443
Now, we can use the z-score formula to standardize the sample mean:
z = (x - μx) / σx
where x is the sample mean.
Plugging in the values:
z = (115 - 112) / 1.443
≈ 2.08
Next, we need to find the probability that the standardized sample mean (z) is greater than 2.08.
This can be done by looking up the z-score in the standard normal distribution table or by using a calculator or statistical software.
Using a standard normal distribution table or calculator, we find that the probability associated with a z-score of 2.08 is approximately 0.981.
Therefore, the correct answer is:
D. 0.981.
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what's the answer to this?
Answer:
126 yds will be your answer.
Step-by-step explanation:
30+(24+24)+4+2+(3+3)+(4+30+2)=126
just add all of the sides up.
US 90 According to the American Automobile Association (AAA), 9.35 of Americans plan to travel by car over the next holiday weekend and 88.6% plan to stay home. What is the probability that a randomly selected American plans to stay home or travel by car over the next holiday weekend? P travel by car or stay home) 0.0897 This probability does not equal 1 because some Americans traveled by other means
The probability that a randomly selected American plans to stay home or travel by car over the next holiday weekend given the information that 9.35% of Americans plan to travel by car and 88.6% plan to stay home. The probability of staying home or traveling by car over the next holiday weekend is given by the addition of probabilities of these events.
P(stay home or travel by car) = P(stay home) + P(travel by car)P(stay home or travel by car) = 0.886 + 0.0935P(stay home or travel by car) = 0.9795Therefore, the probability that a randomly selected American plans to stay home or travel by car over the next holiday weekend is 0.9795.
The value of probability does not equal 1 because some Americans traveled by other means.
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Find the general solution to the differential equation (1+x)dy-2ydx=0
Tthe general solution to the differential equation is given by y = (1+x)^2C, where C is any real number.
The given differential equation is (1+x)dy - 2ydx = 0. To find the general solution, we can rearrange the equation as dy/dx = 2y/(1+x) and separate the variables, yielding (1/y)dy = (2/(1+x))dx. Integrating both sides gives us ln|y| = 2ln|1+x| + C, where C is the constant of integration. Simplifying further, we get ln|y| = ln|(1+x)^2| + C, which can be rewritten as ln|y| = ln|((1+x)^2e^C)|. By taking the exponential of both sides, we obtain y = (1+x)^2e^C, where C is an arbitrary constant.
In this differential equation, we initially rearrange it and separate the variables to obtain dy/dx = 2y/(1+x). Then, we integrate both sides, resulting in ln|y| = 2ln|1+x| + C. We simplify further by exponentiating both sides, which leads to y = (1+x)^2e^C. The constant of integration, C, is absorbed into a new constant, let's say C' = e^C. Therefore, the general solution to the differential equation is y = (1+x)^2C', where C' represents any real number.
This solution represents a family of curves that satisfy the original differential equation, and different values of C' will give different curves within this family.
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HELP IM GONNA GIVE YOU A BRAINLEST!!!
Without graphing, determine whether the function represents exponential
growth or exponential decay. Then find the y-intercept.
y=2/3 (1/2)^x
Answer:
y intercept is (0, 2/3)
Step-by-step explanation:
the y-inetercept is 0
i don’t know the exponential
growth or exponential decay but you can use math.way to help you answer the question
Given a directed graph as depicted in Figure Q6. Figure Q6 (a) List the ordered pairs of the relation, R. (b) Give the matrix of the relation, MR. (c) Give the in-degree and out-degree of each vertex.
The task involves analyzing a directed graph and performing several operations related to relations and degrees of vertices. We need to list the ordered pairs of the relation, find the matrix of the relation, and determine the in-degree and out-degree of each vertex in the graph.
(a) To list the ordered pairs of the relation, R, we examine the directed edges in the graph. For each edge, we write down the corresponding ordered pair. For example, if there is an edge from vertex A to vertex B, we write (A, B). By listing all the directed edges in the graph, we obtain the ordered pairs of the relation, R.
(b) To find the matrix of the relation, MR, we use the vertices of the graph as rows and columns. If there is a directed edge from vertex i to vertex j, we place a 1 in the (i, j) entry of the matrix; otherwise, we place a 0. By examining the directed edges in the graph and filling in the matrix accordingly, we obtain the matrix of the relation, MR.
(c) To determine the in-degree and out-degree of each vertex, we count the number of incoming and outgoing edges for each vertex, respectively. The in-degree of a vertex represents the number of edges pointing towards it, while the out-degree represents the number of edges originating from it. By counting the incoming and outgoing edges for each vertex in the graph, we can determine their respective in-degrees and out-degrees.
Performing these operations will provide the necessary information about the relation and degrees of the vertices in the given directed graph.
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Recall the auction models from the class. There is single object to be
sold to one of the n potential buyers. Each buyer i has a valuation of vi for
the object. Consider the auction rule where the winner is the highest bidder,
and pays the average of the second highest bid and the minimum
of all the bids, that is, the highest bidder pays b2+min{bi : i∈N}/
The auction rule you mentioned is known as the "Vickrey-Clarke-Groves" (VCG) auction. In the VCG auction, the highest bidder wins the object but pays the externality they impose on others.
The payment made by the highest bidder is equal to the difference between the social cost with them participating and the social cost without them participating.
In the case of a single object auction with n potential buyers, the VCG auction proceeds as follows:
Each buyer i submits their bid vi for the object.This payment rule ensures that the winner pays the externality they impose on others, which incentivizes truthful bidding. In other words, it encourages buyers to bid their true valuations because bidding higher or lower than their true valuation would not affect the outcome of the auction but could impact their payment.
The VCG auction is a theoretical construct and may not be practically implemented in all scenarios due to various complexities and practical considerations. However, it serves as a benchmark for understanding desirable properties of auction mechanisms, such as efficiency and truthfulness.
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A small company has a fleet of 3 pickup trucks and 4 delivery vans. A larger company has the same ratio of pickup trucks to delivery vans. If the larger company has 45 pickup trucks, how many delivery vans does it have?
Answer:
60 delivery vans
Step-by-step explanation:
Smaller company:
Pickup truck : delivery van = 3 : 4
If the larger company has 45 pickup trucks
Let x = number of delivery vans
Larger company:
Pickup truck : delivery van = 45 : x
Equate both ratios
3 : 4 = 45 : x
3/4 = 45/x
Cross product
3 * x = 4 * 45
3x = 180
x = 180/3
x = 60
x = number of delivery vans = 60
There are three candidates for student council secretary: Greg, Brittany, and Eliza. There are also three candidates for treasurer: Trey, Fabian, and Paulina. An experiment using two dice is conducted to simulate the probability of Greg or Fabian being elected. The first die represents the secretary election. The numbers 1 and 2 represent Greg winning, 3 and 4 represent Brittany winning, and 5 and 6 represent Eliza winning. The second die represents the treasurer election. The numbers 1 and 2 represent Trey winning, 3 and 4 represent Fabian winning, and 5 and 6 represent Paulina winning. The experiment was performed eight times, and the results are recorded in the following table.Based on the simulation, what is the probability that Greg or Fabian will win the election?
Answer:
5/8
Step-by-step explanation:
I have the same problem and this answer was correct.
The table shows the number of games a team won and lost last season with a ratio of win to loss as 3:2. Therefore the tool most appropriate for use is a 5-section spinner with congruent sections, 3 representing a win and 2 representing a loss.
What is ratio?Ratio, in math, is a term that is used to compare two or more numbers. It is used to indicate how big or small a quantity is when compared to another. In a ratio, two quantities are compared using division.
here, we have,
To calculate a win-to-loss ratio, divide the number of wins by the number of losses.
According to the given data:
Greg is creating a simulation, using previous year’s wins and losses, to foretell the team's conclusion.
Wins in the last season = 24
losses in the last season = 16
Ratio of wins and losses = 24:16 = 3:2
Chances of the team winning out of 5 matches is 3 and losing is 2.
The device which is most suitable for application in a simulation that implements the data is a 5-section spinner with congruent sections, 3 representing a win and 2 representing a loss.
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complete question:
the table shaws the number of games a team won and lost last season. Wins and losses last season number of games wins 24 losses 16 greg has tickets to six of the team’s games this season. He is designing a simulation, using last year’s wins and losses, to predict whether the team will win or lose each of the games he attends. Which tool is most appropriate for use in a simulation that fits the data?
1 a coin with one side representing a win and the other representing a loss
2 a 6-section spinner with congruent sections, 4 representing a win and 2 representing a loss
3 a 5-section spinner with congruent sections, 3 representing a win and 2 4representing a loss an 8-sided die with 5 sides representing a win and 3 sides representing a loss
The surface area of a cube is 78 in2 . What is the volume of the cube?
Answer:
The volume of the cube is 46.87 in^3
Step-by-step explanation:
V=6A3/2
36=6·783/2
36≈46.87217in³
Which of the following equations is represented by a line passing through (-9, 7) and (3, 3) in the
standard (x, y) coordinate plane?
Answer:
y = -1/3x + 4
Step-by-step explanation:
(-9, 7) and (3, 3)
Slope:
m=(y2-y1)/(x2-x1)
m=(3-7)/(3+9)
m=(-4)/12
m= -1/3
Slope-intercept:
y - y1 = m(x - x1)
y - 7 = -1/3(x + 9)
y - 7 = -1/3x - 3
y = -1/3x + 4
Step-by-step explanation:
[tex]soln \\ \frac{3 - 7 }{3 - - 9} \\ = \frac{ - 4}{ - 12} \\ = \frac{1}{3 } \\ \frac{y - 7}{x - 3} = \frac{1}{3} \\ then \: you \: cross \: multiplication. \\ 3(y - 7) = 1(x - 3) \\ 3y - 7 = x - 3 \\ 3y = x - 3 + 7 \\ 3y = x + 4 \\ \frac{3y}{3} = \frac{x}{3} + \frac{4}{3} \\ y = \frac{x}{3} + \frac{4}{3} [/tex]
Select the graph of the solution. Click until the correct graph appears. {x | x < 4} ∩ {x | x > -2}
Answer:
It converges
Step-by-step explanation:
dx/dy = x∧4 + 9x∧21
f(x) = ∫(x∧4 + 9x∧21)dy 0 > f(x) > ∞
= x∧5/5 + 9x∧22/22 + c
x = ∞ and x = 0
∴ c = 1 /5 + 9/22 = 27/22
what did Isabella do incorrectly
Answer:she added another 3000 to the answer
Step-by-step explanation:she was supposed to add the same amount as the first time so the amount should be $7591.92. hope this helps and I want brainliest.
If x=6, what is the smallest natural number y that makes x2+y2 rational?
Given: If x=6, what is the smallest natural number y that makes x2+y2 rational .
To Find: Smallest value if y so that the expression is rational .
Solution : On substituting x = 6 , we have
[tex]=> x^2+y^2= 6^2+y^2\\\\ x^2+y^2= 36+y^2[/tex]
Now for the whole expression has minimum value y^2 should be minimum , also y should be natural no. The set of Natural no. is ,
[tex]=> N=\{ 1,2,3,4,... ..,\infty\}[/tex]
Therefore the smallest Natural no. is 1 . Therefore minimum value of y is 1.
The minimum value of y is 1.