Question 18 (5 points)
If two lines are perpendicular to the same line, then they are
to each other.
A) congruent
B) perpendicular
C) parallel
D) complementary

Answers

Answer 1
two lines are perpendicular to the same line so they are parallel .

Related Questions

Which type of sequence is shown? 5, 10, 15, 20, 25, . . .

geometric
both arithmetic and geometric
arithmetic
neither arithmetic nor geometric

Answers

Answer:

Arithmetic Sequence

Step-by-step explanation:

In Arithmetic sequence each term increases by adding/subtracting some constant k. This is in contrast to a geometric sequence where each term increases by dividing/multiplying some constant k.

Arithmetic sequence.

3 cm
.
.
5 cm
If the base is halved and the height is quadrupled, then which of the following statements
about its area will be true?

Answers

Answer:

I think 7

Step-by-step explanation:

if the moon is purple then what toothpaste do u use on your but

I need help in this algebra problem plz

Answers

Answer:

X+2

Step-by-step explanation:

What's another name for qualitative variables?

Answers

Answer:

A qualitative variable, also called a categorical variable, is a variable that isn't numerical.

A qualitative variable, also called a categorical variable, is a variable that isn't numerical. It describes data that fits into categories.

Enter the measure of YVZ in degrees

Answers

Answer:

(3x+5)+(2x) = 90

5x + 5 = 90

5x = 85

x = 17

YVZ = 3×17 +5

=56°

Yeah the answer is just had the same question 56

Question 7 (5 points)
Find the distance between a point (-3, 4) and a vertical line at x = 4.
A) -7
B) 8
O
C) 1
OD 7

Answers

Answer:

D.7

Step-by-step explanation:

[tex] 4 - ( - 3) = 4 + 3(because \: - \times - ) \: it \: is \: positive \\ = 7[/tex]

(NO LINKS) A space shuttle travels at 2.6 x 10,000 feet per second. An hour is 3.6 x 1,000 seconds. This expression can be used to find the number of feet the space shuttle travels in an hour. How many feet does the shuttle travel in an hour?

Answers

Answer:

1) 7.22 ft in a hr & 2) Choice C.  y = 0.50x + 2

Step-by-step explanation:

1) Space shuttle

2.6 x 10,000 = 26,000ft

3.6 x 1,000 = 3,600 seconds = 1 hr

26,000/3,600 = 7.22 ft in a hr

2) Taxi company

y = 0.50x + 2

please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

√11 = 3.31....

option 1. Irrational: √11 = 3.3

Answer:

Irrational [tex]\sqrt{11}[/tex] = 3.3

Step-by-step explanation:

Have a nice day!! :)

A sample of 1300 computer chips revealed that 50% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 47% of the chips do not fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that do not fail is different from the stated percentage. Make the decision to reject or fail to reject the null hypothesis at the 0.01 level.

Answers

Answer:

The pvalue of the test is 0.03 > 0.01, which means that we fail to reject the null hypothesis at the 0.01 level.

Step-by-step explanation:

The company's promotional literature states that 47% of the chips do not fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that do not fail is different from the stated percentage.

This means that at the null hypothesis we test that the proportion is 47% = 0.47, that is:

[tex]H_0: p = 0.47[/tex]

And at the alternate hypothesis, we test that the proportion is different from 47%, that is:

[tex]H_a: p \neq 0.47[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

47% is tested at the null hypothesis:

This means that [tex]\mu = 0.47, \sigma = \sqrt{0.47*0.53}[/tex]

A sample of 1300 computer chips revealed that 50% of the chips do not fail in the first 1000 hours of their use.

This means that [tex]n = 1300, X = 0.5[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.5 - 0.47}{\frac{\sqrt{0.47*0.53}}{\sqrt{1300}}}[/tex]

[tex]z = 2.17[/tex]

Pvalue of the test and decision:

The pvalue of the test is the probability that the proportion differs from 0.47 by at least 0.5 - 0.47 = 0.03, which is P(|Z| > 2.17), which is 2 multiplied by the pvalue of Z = -2.17

Z = -2.17 has a pvalue of 0.015

2*0.015 = 0.03

The pvalue of the test is 0.03 > 0.01, which means that we fail to reject the null hypothesis at the 0.01 level.

the y coordinate is 7 more than the x coordinate

Answers

Answer:

if you have the value of x then y =x +7

A trader buys 30 shirts for #x each. He sells
them all for #y each. What is his profit​

Answers

if he buys 30 for x amount and sells them for y then you would take y and subtract 30x and your left with the answer = y-30x.


Find the sum of the following arithmetic series:
(a) 6-5-16 - .... -115 (b) 21
(c) 13 + 6 -1 - .... -106
Find the sum of the first 500 odd numbers.

Answers

Answer:

12345678910

Step-by-step explanation:

CHARRRRRRRRR joke lang bestie

Evaluate the expression: -(8 - 12) + 6° + (-4)2.

Answers

Answer:

-4 + 6°

Step-by-step explanation:

- (8 - 12) + 6° + (- 4)2 = - ( - 4) + 6° - 8 = 4 + 6° - 8 = - 4 + 6°

PLS ANSWER QUICK! Thanks!

Answers

Answer:

The correct answer would be [tex]a=\sqrt{c^2-b^2}[/tex]

Step-by-step explanation:

given [tex]a^2+b^2=c^2[/tex] we want to solve for a

How?

We can do this by using basic algebra ( isolating the variable (a ))

Step 1 subtract [tex]b^2[/tex] from each side

[tex]a^2+b^2-b^2=a^2\\c^2-b^2=c^2-b^2[/tex]

now we have [tex]a^2=c^2-b^2[/tex]

step 2 take the square root of each side

[tex]\sqrt{a^2} =a\\\sqrt{c^2-b^2} =\sqrt{c^2-b^2}[/tex]

we're left with [tex]a=\sqrt{c^2-b^2}[/tex]

Hence your answer is A

The quadrilateral shown is a rectangle. What is m∠ZVY?
A) 39°
B) 59°
C) 61°
D) 119°

Answers

Answer: hey bro i can solve this for you but you need to show the quadrilateral. without it i can't solve it.

Step-by-step explanation:

Help me out pls, i’m new to this whole hypotenuse thing

Answers

Answer:

x = 6.5

Step-by-step explanation:

Reference angle = 54°

Length of Side opposite to 54° = x

Hypotenuse = 8 cm

Recall: SOHCAHTOA.

Apply SOH:

Sin 54 = Opp/Hyp

Sin 54 = x/8

x = 8*sin 54

x = 6.47213595 ≈ 6.5 cm (nearest tenth)

mong 500 marriage license applications chosen at random in a givenyear, there were 48 in which the woman was at least one year older than the man, and among400 marriage license applications chosen at random six years later, there were 68 in which thewoman was at least one year older than the man. Construct a 99% confidence interval for thedifference between the corresponding true proportions of marriage license applications in whichthe woman was at least one year older than the man. Interpret the CI in the context of theproblem.

Answers

Answer:

CI 99% = (  0,022  ;  0,126 )

Step-by-step explanation:

First sample  

n₁  = 500

x₁  = 48

p₁ = x₁ / n₁   =  48 / 500      p₁  =  0,096      p₁  = 9,6 %

Second sample

n₂  = 400

x₂  = 68

p₂ = x₂ / n₂   =  68 / 400      p₂  =  0,17       p₂  = 17 %

CI = 99 %    significance level α = 1 %     α  = 0,01

z(c)  for α = 0,01  is from z- table    z(c) = 2,325

CI  =  ( p₂ - p₁ ) ±  z(c) *√ p*q* ( 1/n₁  +  1 / n₂ )

Where

p₂  -  p₁  =  0,17 - 0,096 = 0,074

p = ( x₁ + x₂ )  / n₁ + n₂

p =  ( 48  +  68  ) /( 500 + 400)

p = 116/ 900     p = 0,1288     and   q = 1 - p     q  = 0,8712

z(c) *√ p*q* ( 1/n₁  +  1 / n₂ ) = 2,325 * √ 0,1288*0,8712 ( 1 / 500 + 1/ 400)

2,235 * 0,02247

z(c) *√ p*q* ( 1/n₁  +  1 / n₂ ) = 0,052

Then

CI 99 %  =  0,074  ±  0,052

CI 99% = (  0,022  ;  0,126 )

The difference between the groups shows that the proportion in the second group was bigger than in the first group.

The CI in the context of the problem is  CI 99% = (  0,022  ;  0,126 )

What will be the Solution of This problem?

Given first sample is  

n₁  = 500

x₁  = 48

  [tex]P_{1} =\dfrac{X_{1} }{n_{1} }[/tex]      [tex]P_{1} =\dfrac{48}{500}[/tex]      

p₁  =  0,096      p₁  = 9,6 %

Given second sample

n₂  = 400

x₂  = 68

[tex]P_{2} =\dfrac{X_{2} }{n_{2} }[/tex]      [tex]P_{2} =\dfrac{68}{400}[/tex]        

p₂  =  0,17       p₂  = 17 %

Since given CI = 99 %    so significance level  α = 1 %     α  = 0,01

From Z-Table  z(c)  for α= 0,01  is = 2,325

CI  =   [tex](P_{2} -P_{1}[/tex]   ±    [tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )[/tex]  

Where

p₂  -  p₁  =  0,17 - 0,096 = 0,074

[tex]P= \dfrac{X_{1} +X_{2} }{n_{1}+n_{2} }[/tex]

[tex]P=\dfrac{48+68}{500+400}[/tex]

[tex]P=\dfrac{116}{900}[/tex]

p = 0,1288     and   q = 1 - p     q  = 0,8712

[tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )[/tex]  [tex]2325\times\sqrt[2]{0.1288\times 0.8712} (\dfrac{1}{500_{} } +\dfrac{1}{400_{} } )[/tex]

  [tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )=0.052[/tex]

Then

CI 99 %  =  0,074  ±  0,052

CI 99% = (  0,022  ;  0,126 )

Hence the difference between the groups shows that the proportion in the second group was bigger than in the first group.

To know more about Chi square follow

https://brainly.com/question/4543358

Which set of numbers is in DESCENDING order?
* 1 point
WILL GIVE BRANLIEST
55, -8, -2, -282

55, -2, -8, -282

-282, -8, -2, 55

-282, 55, -8, -2

Answers

C) -282, -8, -2, 55
Answer ^

Plsssss help it is khan academy!!!

Answers

The inequality is in the direction of the arrow
The arrow is like this <——— so the inequality is <
It is an open circle so that means -1 is not included
x<-1
Or choice A

18 out of 20 to percentage

Answers

Answer:

90%

Step-by-step explanation:

That would be 90% as it is equivalent to 9/10 or 90/100

4 * (3.4+2)-(56 divided by 7)= 13.6, please give an explanation to this problem!!

Answers

Answer:

[tex]=13.6[/tex]

Step-by-step explanation:

[tex]\mathrm{Remove\:parentheses}:\quad \left(a\right)=a[/tex]

[tex]=4\left(3.4+2\right)-\frac{56}{7}[/tex]

[tex]=21.6-8[/tex]

[tex]\mathrm{Subtract\:the\:numbers:}\:21.6-8=13.6[/tex]

[tex]=13.6[/tex]

Question 3 (Fill-In-The-Blank Worth 3 points) (04.04) Point R is at (2, 1.2) and Point T is at (2, 2.5) on a coordinate grid. The distance between the two points is such as 8.2.) (Input numbers and decimal point only, Answer for Blank 1:​

Answers

9514 1404 393

Answer:

  1.3

Step-by-step explanation:

The two points are on the same vertical line, so the distance between them is the distance between their y-coordinates:

  2.5 -1.2 = 1.3

The distance between the two points is 1.3 units.

Someone please help me answer this!1

Answers

Answer:

16 km is the answer

Step-by-step explanation:

a (Colton to parents' house) = 12 km

b = ?

c (parents' house to grandparents' house) = 20 km

According to the Pythagoras theorem,

a² + b² = c²

12² + b² = 20²

144 + b² = 400

b² = 400 - 144

b² = 256

b = 16

∴ Colton is 16 km away from his grandparents' house.

The average of an electrician's hourly wage and a plumber's hourly wage is $33. One day a contractor hires an electrician for 7hr of work and the plumber for 4hr of work and pays a total of $396 in wages. Find the hourly wage for the electrician and for the plumber.

Answers

Answer:

Electrician = 44

Plumber = 22

Step-by-step explanation:

Let :

Electrician Hourly wage = x

Plumber's hourly wage = y

Average = 33

(x + y ) /2 = 33

x + y = 66 - - - - (1)

7x + 4y = 396 - - - (2)

From (1)

x = 66 - y

Put x = 66 - y in (2)

7(66-y) + 4y = 396

462 - 7y + 4y = 396

-3y = - 66

y = 22

x = 66 - 22

x = 44

Electrician = 44

Plumber = 22

What is the volume of the solid generated when the region in the first quadrant bounded by the graph of y=x^3, the x-axis, and the vertical line x=2 is revolved about the x-axis?
Show work.

A
[tex]4[/tex]
B
[tex] \frac{128}{7} [/tex]
C
[tex]4\pi[/tex]
D
[tex] \frac{128\pi}{7} [/tex]

Answers

Answer:

The first thing we need to do is to find the area bounded by:

y = x^3

y = 0

between:

x = 0 and x = 2

This is the integral of the given function between x = 0 and x = 2, written as:

[tex]\int\limits^2_0 {x^3} \, dx = \frac{2^4}{4} - \frac{0^4}{4} = 2^2 = 4[/tex]

This means that the area of the bounded region is 4 square units.

Now, if we do a full rotation around the x-axis, the volume generated will be equal to the area that we obtained times 2*pi units.

The volume is:

V = (4 square units)*(2*pi units) = 8*pi cubic units.

(Notice that no option coincides with this, there may be a mistake in the options)

Find the slope of the line.
Please Help

Answers

the slope should be y=3x

what is the value of x?

Answers

2x+2=3x-52
2x-3x=-52-2
-x=-54
x=54

will someone help me with this?

Answers

height of movable brigde 37cm

width of movable brigde 85 cm

Giving brainliest!!!!!

Answers

Answer: V = 434cm³

6 x 10 x 5 = 300
4/3 x π x r x 4³ = 268.08257310633

268.08257310633 + 300 = 434.041286553

Answer:

434 [tex]cm^3[/tex]

Step-by-step explanation:

volume of bottom: 6 x 10 x 5 = 300 [tex]cm^3[/tex]

volume of top:

[tex]V = (\frac{4}{3}\pi r^3)/2\\\\= (\frac{4}{3}\pi(4)^3)/2\\[/tex]

≈ 134.041 [tex]cm^3[/tex]

300 + 134.041 = 434.041

they want to the nearest tenth, so it would just be 434.0

A student records the repair cost for 22 randomly selected dryers. A sample mean of $98.78 and standard deviation of $15.49 are subsequently computed. Determine the 95% confidence interval for the mean repair cost for the dryers. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Answers

Answer:

The critical value that should be used is T = 2.0796.

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 22 - 1 = 21

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0796, which is the critical value that should be used.

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.0796\frac{15.49}{\sqrt{22}} = 6.868[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912

The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

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