Answer:
HOW TO DO IT…
Use the correct cutting oil on the tap when cutting threads.
Turn the tap clockwise one-quarter to one-half turn, then turn back three-quarters of a turn to break the chip.
When tapping a blind hole, use the taps. in the order starting, plug, and then bottoming.
Which phrase describes an oxidizing agent? (1 point)
O a substance that provides electrons to other substances
a substance that reacts with oxyge
O a substance that provides oxygen in a reaction
O a substance that gains an electron in a reaction
A substance that gains an electron in a reaction is called as oxidizing agent.
What is an Oxidizing agent?An oxidizing agent, often known as an oxidizer or an oxidant, is a type of chemical that has the tendency to oxidize other substances, increasing their oxidation state by causing them to lose electrons. The substance losing electrons is the reducing agent and is being oxidized. The material that obtains electrons is the oxidizing agent and is being reduced. An element or compound that accepts an electron from another species in an oxidation-reduction (redox) reaction is known as an oxidizing agent (also oxidant, oxidizer, or oxidiser).
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If you are on 4.16 Chemical Reactions and have 18 questions, then go to the following on Quizlet for further help. Thanks and good luck!
Quizlet - "4.6 Chemical Reactions UT"
h t t p s : / / q u i z l e t . c o m / _ c 7 3 1 u j ? x = 1 q q t & i = 3 8 n a a s
HELP PLEASE
2. James throws a rock into a deep well with a velocity of 10.0 m/s [down]. What is the velocity of the rock 2.5 s
Answer:
vf=vi+at
Explanation:
downwards is positive
vf=vi+at
=10+9,8×2,5
=34,5m/s
In compressing the spring in a toy dart gun, 0.2 J of work is done. When the gun is fired, the spring gives its potential energy to a dart with a mass of 0.05 kg.
(a) What is the dart's kinetic energy as it leaves the gun?
0.2j
(b) What is the dart's speed?
Pleas help with part b I have tried everything I need help!!!
a) The kinetic energy of the spring is 0.2 J
b) Speed of the dart is 2.8 m/s
What is the work done?Let us recall that work is said to be done when the force that is applied moves a distance in the direction of the force. Now we know that if we compress a spring, then the spring would have a potential energy called the elastic potential energy.
Let us now answer the questions;
a) Given the fact that energy is neither created nor destroyed but is converted from one form to the other, the kinetic energy of the dart is 0.2 J. This is from the law of the conservation of energy as we all know it.
b) Recall that;
KE = 1/2mv^2
KE = kinetic energy
m = mass of the object
v = speed of the object
v = √2KE/m
v = √2 * 0.2/0.05
v = 2.8 m/s
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When an object experiences uniform circular motion, the direction of the acceleration isSelect one:A) is directed away from the center of the circular path.B) depends on the speed of the object.C) is directed toward the center of the circular path.D) in the opposite direction of the velocity vector.E) in the same direction as the velocity vector.
An object under uniform circular motion experiences a centripetal acceleration, directed towards the center of the circular trajectory.
Therefore, the correct option is:
[tex]\begin{gathered} C) \\ \text{ Is directed toward the center of the circular path.} \end{gathered}[/tex]A bicyclist decreases his speed from 6.1 meters per
second to 3.7 meters per second over a period of 17
seconds. What is his acceleration during this time?
The acceleration of the car within the time frame that have been shown in question is obtained as -0.14 m/s^2.
What is the acceleration?We define the acceleration as the rate of change of the distance of the object with time. We know that acceleration is a vector quantity thus the magnitude and the direction of the acceleration is counted as important in the process.
We have;
a = v - u/t
a = acceleration
v = final velocity
u = initial velocity
t = time taken
a = 3.7 m/s - 6.1 m/s/ 17 s
a = -0.14 m/s^2
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A plane travels 2.5 km at an angle of 35 degrees to the ground and then changes directions and travels 5.2 km at an angle of 22 degrees to the ground. what is the magnitude and direction of the plane's total displacement?
The magnitude and direction of the plane's total displacement are 7.66 km and angle of 26.2 degree respectively.
What is displacement and how the magnitude and direction is calculated out to be so ?Displacement as studied earlier is the shortest distance between initial point and final point .Here in this question is given plane is travelling with speed 2.5 km at an angle of 35 degrees to the ground and then changes direction. So , d1=2.5 , theta 1 =35 degree, d2=5.2 km , theta 2 = 22 degree, to find the resultant displacement , Rx = d1 cos theta 1 + d2 cos theta 2 = 2.5 x sin 35 degree + 5.2 x sin 22 degree = 3.38 km.By applying pythagoreon theorum , the magnitude will be , R = (Rx^2 + Ry^2 )^1/2 = 7.66 km.To find the direction , theta = tan^-1 ( Ry/Rx) = tan^-1 ( 3.38km/6.87km) = 26.2 degree.To know more about displacement visit:
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In a tug-of-war match, the blue team pulls to the right with 30 N of force while the red team pulls to the left with 20 N of force. Show the resultant graphically by adding the vectors. ASAPPPPP!!!!!
The resultant force of the two teams in the tug of war obtained by adding the vectors is 10 N.
What is resultant force?The resultant force of two or more forces is the single force that will produce the same affect as the two forces acting together.
The resultant force of the two teams performing tug of war is calculated as follows;
R = Rb - Rr
where;
R is the resultant forceRb is the force of the blue teamRr is the force of the red teamSubstitute the given parameters and solve for the resultant force.
R = 30 N - 20 N
R = 10 N
Graphically, we can present the resultant force as follows;
------10 N------> = ---------30 N--------------------> - <-----20 N---------------
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This is for Physics module 2 question 5
An archer shoots an arrow at a 77.0 m distant target, the bull's-eye of which is at same height as the release height of the arrow.
(a) At what angle must the arrow be released to hit the bull's-eye if its initial speed is 36.0 m/s? (Although neglected here, the atmosphere provides significant lift to real arrows.)
°
(b) There is a large tree halfway between the archer and the target with an overhanging branch 3.50 m above the release height of the arrow. Will the arrow go over or under the branch?
under
over
The arrow be released at an angle of 18 degrees to hit the bull's-eye if its initial speed is 36.0 m/s. The arrow go over the branch.
The path of the arrow is projectile when it is launched by the archer.
The horizontal distance to be covered by the arrow is 77 meters.
The initial velocity is 36m/s while releasing.
(a) We can use the formula,
R = U²sin2A/g
Where,
U is the initial velocity of leopard,
A is the angles at which the leopard jumped.
g is acceleration due to gravity having value 9.8m/s².
Putting all the values,
77 = (36)²sin(2A)/9.8
Sin(2A) = 77×9.8/36×36
Sin(2A) = 0.58
2A = 36°
A = 18°
The angles at which the arrow should be launcher is 18°.
(b) The length of the branch of the tree is 3.5 meters.
Whether is should come it the way or not,
We have to find the height of the arrow.
H = U²Sin(A)/2g.
Where H is the height,
H = 36×36Sin(18°)/2×9.8
H = 36×36×0.3/2×9.8
H = 19.38 meters.
The height of arrow is more than of the height of branch of tree. So it will go over the branch.
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A runner starting from rest reaches a velocity of 9.6 m/s in 2.0s. What is her average acceleration?
Answer:
Explanation:
From the given information if we assume that the runner didn't come back to her original position.
Her initial velocity = 0 m/s
Final Velocity = 9.6 m/s
Time Taken = 2 seconds
She started from rest therefore her initial time would be 0 seconds.
We know that,
Average acceleration = (final velocity - initial velocity)/(final time - initial time)
=(v-u)/t1-t0
=(9.6 - 0)/(2-0) m/s^2
=4.8 m/s^2
what does not affect the strenth of elecromagnets
A. Number of time the the wire is looped around the core
B. Size of the object being attached by the core
C.type of material in the core
D.among of material in the core
A magnetic core made of a magnetic material, such as iron, that is encircled by a wire coil. The core is magnetized by an electric current that is passed through the coil.
How do electromagnets function? What are they?Permanent magnets are not the same as electromagnets. Coils of wire with electricity running through them make up electromagnets. An electromagnet's wire coils act like magnets when an electric current flows through them because moving charges produce magnetic fields.
Electromagnets generate electricity in what way?Electrons are pushed and pulled by moving magnetic fields. Electrons in metals like copper and aluminum are slackly held. The electrons in the wire are pushed by rotating a coil of wire around a magnet, or vice versa, and an electrical current is produced.
What kind of thing is an electromagnet like?Electromagnets are a component of every machine with an electric motor. Hairdryers, CD players, power drills, electric saws, and electric mixers are a few further examples.
What exactly is a basic electromagnet?Magnets produced by electric fields are known as electromagnets. The fact that they can be turned on and off gives them an edge over normal magnets. By wrapping a wire around an iron nail and passing current through it, electromagnets can be made.
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What is the force on a 100 kg elevator that is falling freely at an acceleration of10 m/sec2?
We are told that an elevator falls freely, which means that the only force acting upon it is its weight. The weight is defined as:
[tex]W=mg[/tex]Where "m" is the mass and "g" is the acceleration of gravity. Replacing the given values:
[tex]\begin{gathered} W=(100\operatorname{kg})(10\frac{m}{s^2}) \\ W=1000N \end{gathered}[/tex]Therefore, the force that acts upon the elevator is 1000N.
Two 60.00 resistors are connected in parallel and this parallel arrangement is then connected in series with a 30.00 resistor. The combination is placed across a 120 V potential difference. What is the equivalent resistance for the entire circuit? a RT = 900 b RT12002 C RT = 30N 30Ω d RT = 60Ω
The equivalent resistance for the entire circuit is equal to 1830 Ω.
What is the resistance of resistors in series?In a series combination of resistors, the resistors are connected end-to-end. Assume two resistors, R₁ and R₂ which are connected with each other in a series then their effective resistance:
Total Resistance, R = R₁ + R₂
In a parallel combination of resistors, the resistors are connected parallel to each other.
[tex]\displaystyle \frac{1}{R} =\frac{1}{R_1} +\frac{1}{R_2}[/tex]
The resistance in parallel, R₁ = 60 Ω , R₂ = 60 Ω , R₃ = 30 Ω
The equivalent resistance for the entire circuit will be given by:
[tex]R_{eq} =R' + R_3[/tex]
[tex]\displaystyle R_{eq} = \frac{R_1R_2}{R_1+R_2} + R_3[/tex]
[tex]\displaystyle R_{eq} = \frac{60\times 60}{1+1} + 30[/tex]
R = 3600/2 +30
R = 1800 +30
R = 1830 Ω
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What is the Ksp expression for Ni3(PO4)2(s) in water?
options:
Ksp = [Ni2+]3[PO43-]2
Ksp = [Ni2+]2[PO43-]3
Ksp =(3x[Ni2+])(2x[PO43-])
Ksp =(3x[Ni2+])3(2x[PO43-])2
Answer:
A
Explanation:
What is the Ksp expression for Ni3(PO4)2(s) in water? A) Ksp = [Ni2+]3[PO4]2(s) B) Ksp = [Ni2+]2[PO43-13 C) Ksp= (3x[Ni2+])(2x[PO43-]) C) Ks
Answer 0 votes
Answe
A) Ksp = [Ni2+]3[PO4]2(s)
What is the acceleration due to gravity at the surface of a planet that is twice as dense as the earth, but whose radius is twice as large as the earth’s? Assume the earth is a perfect sphere with a volume given by 4/3 piR^3.
ANSWER:
39.2 m/s^2
STEP-BY-STEP EXPLANATION:
We have to acceleration due to gravity at the surface of planet:
[tex]\begin{gathered} g_p=\frac{GM_p}{(R_p)^2^{}},M_p=\rho_p\cdot V_p \\ g_p=\frac{G\cdot\rho_p\cdot V_p}{(R_p)^2} \\ g_p=\frac{G\cdot\rho_p\cdot\frac{4}{3}\pi(R^3_p)_{}}{(R_p)^2} \\ g_p=\frac{4}{3}\pi\cdot G\cdot\rho_p\cdot R_p \end{gathered}[/tex]Where,
Mp = mass of planet
ρp = density of planet
Rp = radius of planet
Given:
ρp = 2ρe, Rp = 2Re
where,
ρe = density of earth
Re = radius of earth
Replacing:
[tex]\begin{gathered} g_p=\frac{4}{3}\pi\cdot G\cdot2\rho_e\cdot2R_e \\ g_p=4\cdot\mleft(\frac{4}{3}\pi\cdot\: G\cdot2\rho_e\cdot2R_e\mright) \\ g_p=4\cdot g_e \\ g_e=9.8m/s^2 \\ \text{ replacing} \\ g_p=9.8\cdot4 \\ g_p=39.2m/s^2 \end{gathered}[/tex]Therefore the acceleration due to gravity on the planet is 39.2 m/s^2
What is the potential energy of a 300 Newton rock climber standing 100 meters from the base of a rock wall?
The rock possesses potential energy for gravitation. Fundamentally, gravity could cause the rock to tumble.
How are potential energy changes calculated?Height gain (h) and gravitational acceleration (g) serve as symbols for the change in gravitational potential energy (PEg). Any item close to the planet's surface has gravitational potential energy that is determined by its location within the mass-Earth system.
What is a rock's potential energy in that situation?The rock possesses potential energy for gravitation. Fundamentally, gravity could cause the rock to tumble.
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A group of physics students launched a rocket in a field at their school. They recorded the time it took for the rocket to launch into the air and come back to the ground. They calculated their average time for their rocket to land to be 12.74 seconds.
1. How long did the rocket take to reach max height?
2. What is the velocity of the rocket at max height?
3. What is the initial velocity of the rocket?
4. What was the maximum height of the rocket?
1) The time taken is 6.37 s
2) The velocity at maximum height is 0 m/s
3) The initial velocity is 62.4 m/s.
4) The maximum height is 198.66 m
What is the velocity?Let us recall that in this case, we have to use the equation of the motion that occurs under gravity In this case we have to take into account the the upwards motion is negative in the opposite direction as gravity and the down wards motion is positive and in the same direction as gravity.
1) Given that;
time is the same as the time taken to go up and come down thus the time taken to reach the maximum height is 12.74 seconds/2 = 6.37 s
2) The velocity of the rocket at the maximum height is zero because it momentarily comes to rest.
3) The initial velocity of the rocket is;
v = u - gt
At the maximum height v = 0 m/s
u = gt
u = 9.8 m/s^2 * 6.37 s
u = 62.4 m/s
4) The maximum height is obtained from;
v^2 = u^2 - 2gh
v = 0 m/s
u^2 = 2gh
h = u^2/2g
h = (62.4 m/s)^2/2 * 9.8 m/s^2
h = 198.66 m
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NEED ANSWERS ASAP!! PLEASE
The motion of an object with constant acceleration exists defined by a set of equations comprehended as the kinematic equations. The distance of the drone with respect to the ground exists 13.95886 m/s.
What is a kinematic equation?The motion of an object with constant acceleration exists defined by a set of equations comprehended as the kinematic equations. Integrals, derivatives, and rates of change must all be understood in order to solve kinematics problems.
A branch of physics named kinematics, which originated in classical mechanics, described how points, bodies, and systems of bodies move without taking into account the forces that exists responsible for their motion.
If a drone flies 13.8 m/s due East with respect to the wind and the wind is blowing 2.1 m/s due North, the speed of the drone with respect to the ground is its displacement.
Displacement is calculated using Pythagoras theorem.
d² = 13.8 ² + 2.1²
simplifying the above equation, we get
d² = 190.44 + 4.41
d² = 194.85
Square root both sides, we get
√d² = √194.85
d = 13.95886 m/s
Therefore, the distance of the drone with respect to the ground is 13.95886 m/s.
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A pot of water is heated using a camping stove. The stove supplies 115,000 J of energy to the 0.54 kg of water. Given that the specific heat capacity of water is 4180 J/kg °C, calculate the increase in temperature of the water to two significant figures.
The increase in the temperature of the water, given that 115000 J of heat energy was supplied to it is 50.95 °C
How to determine the increase in temeperatureFrom the question given above, the following were obtained:
Heat supplied (Q) = 115000 JMass of water (M) = 0.54 KgSpecific heat capacity of water (C) = 4180 J/KgºC Increase in temperature (ΔT) =?The increase in the temperature of the water can be obtained as follow:
Q = MCΔT
115000 = 0.54 × 4180 × ΔT
115000 = 2257.2 × ΔT
Divide both sides by 2257.2
ΔT = 115000 / 2257.2
ΔT = 50.95 °C
From the above calculation, we can conclude that the temperature increase of the water is 50.95 °C
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The snow leopard (Uncia uncia) is an endangered species that lives in the mountains of central Asia. It is thought to be the longest jumper in the animal kingdom. If a snow leopard jumps at 35.0° above the horizontal and lands 96.0 m away on flat ground, what was its initial speed?
The initial speed of the Snow Leopard was 35m/s if it jumped at an angle of 35 degrees.
When a leopard jumps. It's path will be a parabola which is corresponding to a projectile.
The angle at which the leopard jumped is 35°.
The horizontal range of the projectile is 96 meters.
We can use the formula for horizontal range R of the projectile,
R = U²sin2A/g
Where,
U is the initial velocity of leopard,
A is the angles at which the leopard jumped.
g is acceleration due to gravity having value 9.8m/s².
Putting all the values,
96 = U²sin(70°)/9.8
U² = 96×9.8/0.77
U² = 1222
U = 34.9 m/s
Nearly 35 m/s.
The initial speed of leopard is 35m/s.
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A rocket is fired at an angle from the top of a tower of height h0 = 36.8 m . Because of the design of the engines, its position coordinates are of the form x(t)=A+Bt2 and y(t)=C+Dt3, where A, B, C , and D are constants. Furthermore, the acceleration of the rocket 1.20 s after firing is a=( 3.30 i^+ 2.50 j^)m/s2. Take the origin of coordinates to be at the base of the tower.
What are the x- and y-components of the rocket's velocity 12.2 s after it is fired?
Enter your answers numerically separated by a comma.
How fast is it moving 12.2 s after it is fired?
What is the position vector of the rocket 12.2 s after it is fired?
36.8 (m) are the x- and y-components of the rocket's velocity 12.2 s after it is fired.
0.41 m / s³ is the position vector of the rocket 12.2 s after it is fired
What does acceleration mean?Any process where the velocity varies is referred to as acceleration. There are only two ways to accelerate: increasing your speed or changing your direction, or altering both. This happens because speed is both a speed and a guidance.
Briefing:This is an exercise in kinematics in two dimensions, the easiest way to solve it is to work each axis independently
To find the other two constants we must know the acceleration formula,
a = dv / dt = d²v / dt²
vₓ = dx / dt = 2Bt
d²x / dt² = 2B
aₓ = 2B= dy / dt = 3D t2
d²y / dt² = 6D t
They give us the acceleration for time t = 1.20s
aₓ = 2B = 3.30 m / s2
B = 1.65 m / s²
ay = 6D t = 2.50
D = 3.00 / 6 1
D = 0.41 m / s³
The acceleration vector is
a = aₓ i ^ + j ^
a = 3.3 i ^ + 2.5 t j ^
v = vx i ^ + vyj ^
v = 3.3 t i ^ + 1.25 t²
velocity for t= 12.2 s
v = 3.3 t i ^ + 1.25 t²
v = 3.3 10 i^ + 1.5 10² j^
v= (33 i^ + 150 j^ ) m/s
Position for t = 12.2 s
x = 1.65 t² = 7 10²
x = 165 m
y = 36.8 +0.41 t³ = 36.8 + 0.41 10³
y = 446.8 m
D = (165 i ^ + 446.8 j ^) m
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module 2 question 13
Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts a force of 75.0 N, the second a force of 90.0 N, friction is 12.0 N, and the mass of the third child plus wagon is 22.0 kg.
(a) What is the system of interest if the acceleration of the child in the wagon is to be calculated? (Select all that apply.)
the children outside the wagon
the child in the wagon
the wagon
(b) Draw a free body diagram, including the weight and all other forces acting on the system. (Do this on paper. Your instructor may ask you to turn in this diagram.)
(c) Calculate the acceleration.
m/s2
(d) What would the acceleration be if friction is 15.0 N?
The acceleration of children will be 0.136m/s²
We are given that,
The first child exert force= F₁ = 75.0 N
The second child exerts force = F₂ = 90.0N
The friction force = Fₓ = 12.0 N
The mass of the third child = m = 22.0 kg
The first child & second child exert force 75 N and 90 N which are acting in opposite direction.
Therefore, the net force = F₂ - F₁ = 90 - 75 = 15 N
Friction force Fₓ would be act in the direction opposite to the direction of net force. So that the friction force will act in the direction in which the first child F₁ (75 N) is acting .
Total force acting in the direction of the second child= F₁+ Fₓ=75+12= 87 N
Net force acing on the third child F = 90 - 87 = 3 N
Therefore, the acceleration of the child can be calculated by the Newton's second law of motion i.e.
F = ma
a = F /m
a = 3N /22kg
a = 0.136 m/s²
Thus, the acceleration of the child will be 0.136 m/s²
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A 4.91 kg bucket of water is raised from a well by a rope. The upward acceleration of the bucket is 3.37 m/s2. It will be helpful if you can properly draw a free-body diagram. Find the force exerted by the rope on the bucket.
Answer:
F=ma
=(4,91kg)(3,37m/s)
=16,55N
Explanation:
Free body diagram- the only 2 forces that are acting on the bucket is the tension in the rope and the weight
The tension in the rope could also be called "Force applied" and is acting upwards since it's pulling the bucket upwards.
There also has to be a force acting downwards on the bucket and that is the Weight.
Which one of the following is not a step used for balancing chemical
equations?
A. Write the chemical equation using formulas and symbols.
B. Choose coefficients that will balance the equation.
C. Determine how long the reaction will take.
D. Count the atoms in each substance in the reactants and products.
Answer: C. Determine how long the reaction will take.
Which saturated solution has the highest concentration of S2- ions at 25oC?
options:
NiS; Ksp = 3x10-21
CoS; Ksp = 5x10-22
FeS; Ksp = 4x10-19
SnS; Ksp = 1x10-26
Answer:
according to me the fourth one is the right answer
You are designing an experiment to determine the acceleration of a motorized toy car over 1 meter of distance. You perform the following steps in your experiment:
1. Release the toy car from rest.
2. Take a video of the car accelerating.
3. Determine the time the car took to reach 1 meter using the video.
If you followed the steps above, could you determine the acceleration of the toy car?
Yes, if one follows the mentioned steps, they could determine the toy car's acceleration from the data of time taken in the video.
a = v / t
v = d / t
a = Acceleration
v = Velocity
d = Distance
t = Time
d = 1 m
Let the video time recorded from the video be x s.
t = x s
v = 1 / x
a = 1 / x / x
a = 1 / x² m / s²
Velocity is the rate of change of distance. Its unit is m / s. It is denoted as v. Acceleration is defined as the rate of change in velocity with respect to time. Its unit is m / s². It is denoted as a.
Therefore, if I follow steps given, I could determine the acceleration of the toy car as 1 / x² m / s²
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An electron of mass 9.11×10^−31 kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 1.40 cm away. It reaches the grid with a speed of 4.0×10^6 m/s. The accelerating force is constant.
A)Find the acceleration. (m/s)
B)Find the time to reach the grid. (s)
C)Find the net force. (You can ignore the gravitational force on the electron). (N)
A. The acceleration of the electron is 5.71×10¹⁴ m/s²
B. The time taken for the electron to reach the grid is 7.01×10⁻⁹ s
C. The net force of the electron is 5.20×10⁻¹⁶ N
A. How to determine the acceleration of the electron
The acceleration can be obtained as illustrated below:
Initial velocity (u) = 0 m/sFinal velocity (v) = 4.0×10⁶ m/sDistance (s) = 1.4 cm = 1.4 / 100 = 0.014 mAcceleration (a) =?v² = u² + 2as
(4.0×10⁶)² = 0² + (2 × a × 0.014)
(4.0×10⁶)² = 0 + 0.028a
(4.0×10⁶)² = 0.028a
Divide both side by 0.028
a = (4.0×10⁶)² / 0.028
a = 5.71×10¹⁴ m/s²
B. How to determine the time
The time taken for the electron to reach the grid can be obtained as follow:
Initial velocity (u) = 0 m/sFinal velocity (v) = 4.0×10⁶ m/sAcceleration (a) = 5.71×10¹⁴ m/s²Time (t) =?a = (v – u) / t
5.71×10¹⁴ = (4.0×10⁶ – 0) / t
5.71×10¹⁴ = 4.0×10⁶ / t
Cross multiply
5.71×10¹⁴ × t = 4.0×10⁶
Divide both sides by 5.71×10¹⁴
t = 4.0×10⁶ / 5.71×10¹⁴
t = 7.01×10⁻⁹ s
C. How to determine the net force
Mass (m) = 9.11×10⁻³¹ KgAcceleration (a) = 5.71×10¹⁴ m/s²Net force (F) =?Net force = mass × acceleration
Net force = 9.11×10⁻³¹ × 5.71×10¹⁴
Net force = 5.20×10⁻¹⁶ N
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tia types 66 words in 3 minutes.she wants to know how many words she can type in 5 and 10 minutes
Divide 66 words by 3 minutes to find the typing rate per minute. Then, multiply the typing rate by 5 minutes and 10 minutes to find how many words she can type during those time intervals, respectively.
Typing rate:
[tex]\frac{66\text{ words}}{3\text{ minutes}}=22\text{ words per minute}[/tex]Words typed in 5 minutes:
[tex](22\text{ words per minute)(5minutes)=110 words}[/tex]Words typed in 10 minutes:
[tex](22\text{ words per minute)(10 minutes)=220 words}[/tex]Therefore, Tia can type 110 words in 5 minutes and 220 words in 10 minutes.
HELP Momentum quiz
State True or False
1. Concurrent forces give one net resultant force.
2. Newton’s first law of motion is the principle of momentum.
3. In Newton’s second law, F = m * a, F is measured in Newton.
4. Mass and weight are interchangeable.
5. The product of mass and velocity for an object gives us its _______.
6. The force of gravity on an object determines its _______.
(1) Concurrent forces give one net resultant force. (TRUE)
(2) Newton’s first law of motion is the principle of momentum. (FALSE)
(3) In Newton’s second law, F = m * a, F is measured in Newton. (TRUE)
(4) Mass and weight are interchangeable. (FALSE)
(5) The product of mass and velocity for an object gives us its momentum.
(6) The force of gravity on an object determines its weight.
What are concurrent forces?If the forces applied to a body are such that their lines of action meet at a single point, then they are called concurrent forces.
Concurrent forces give one net resultant force. (true)
The Newton's second law of motion states that, the force applied to an object is directly proportional to the change in momentum of the object.
F ∝ Δmv
F = mv/t
F = m(v/t)
F = ma
Newton’s first law of motion is the principle of momentum. (false)
In Newton’s second law, F = ma, F is measured in Newton. This statement is true.
Mass is the quantity of matter contained in a body while weight is the measure of the effect of gravitation force on an object.
Mass and weight are interchangeable. (false)
The product of mass and velocity for an object gives us its momentum.
The force of gravity on an object determines its weight.
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All points on the chain of a bicycle have the same linear speed. Is the magnitude of the linear acceleration also the same for all points on the chain? How are the angular accelerations of the two sprockets related?
The magnitude of the linear acceleration is zero for all points on the chain. The angular accelerations of the two sprockets can be related as α[tex]_{Front}[/tex] / α[tex]_{Rear}[/tex] = ω[tex]_{Front}[/tex] * t[tex]_{Rear}[/tex] / ω[tex]_{Rear}[/tex] * t[tex]_{Front}[/tex]
There are two set of point that is needed to be taken into consideration. The points in between the two sprockets and points in which the chain is in contact with the sprocket. In the former set of points, the linear velocity is constant. So its linear acceleration will be zero. In the latter set of points, the tangential velocity ( Linear velocity in circular motion ) is constant. So the tangential acceleration ( Linear acceleration in circular motion ) will be zero.
Since the chain is constantly changing direction while on the sprocket, it will always have angular acceleration.
α = ω / t
α = Angular acceleration
ω = Angular velocity
t = Time
α[tex]_{Front}[/tex] / α[tex]_{Rear}[/tex] = ω[tex]_{Front}[/tex] * t[tex]_{Rear}[/tex] / ω[tex]_{Rear}[/tex] * t[tex]_{Front}[/tex]
Therefore,
The magnitude of the linear acceleration is zero for all points on the chain.The angular accelerations of the two sprockets can be related as α[tex]_{Front}[/tex] / α[tex]_{Rear}[/tex] = ω[tex]_{Front}[/tex] * t[tex]_{Rear}[/tex] / ω[tex]_{Rear}[/tex] * t[tex]_{Front}[/tex]To know more about angular acceleration
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Given the two reactions:
CuCl(s) + Cl- (aq) <=> [CuCl2]- (aq)
K = 5.2x10-2
Cu+ (aq) + 2Cl-(aq) <=> [CuCl2]- (aq)
Kf = 3.0x105
What is the value of Ksp for CuCl?
Answer:
the value of ksp is 7.8×18